AQA GCSE Chemistry Chemistry Paper 1 (Higher), June 2025: Question 2

11 marks · Standard Demand difficulty · Short Answer

Describe the bonding in calcium sulfide, the structure and bonding of graphite, and the properties of small molecules and polymers.

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Question

Question 2 on structure and bonding. Figure 2 shows an ionic lattice diagram for calcium sulfide with Ca and S ions represented as grey and black spheres. Question 02.1 asks for the empirical formula of calcium sulfide for 1 mark. Question 02.2 asks to describe what happens when a calcium atom reacts with a sulfur atom in terms of electrons and ions for 4 marks. Figure 3 shows three layers of graphite, each containing hexagonal rings of carbon atoms. Question 02.3 asks to describe the structure and bonding of graphite for 4 marks. Question 02.4 asks to give one reason why substances consisting of small molecules do not conduct electricity for 1 mark. Question 02.5 presents a multiple-choice question asking why poly(ethene) has a higher melting point than methane, with four tick-box options.
Question text

02 This question is about structure and bonding.

Calcium sulfide is an ionic compound.

Figure 2 represents the structure of calcium sulfide.

Figure 2

02.1 Determine the empirical formula of calcium sulfide.

[1 mark]

Empirical formula 6

02.2 Calcium is in Group 2 of the periodic table.

Sulfur is in Group 6 of the periodic table.

Describe what happens when a calcium atom reacts with a sulfur atom.

Answer in terms of electrons and ions.

[4 marks]

Figure 3 shows the structure of graphite.

Figure 3

02.3 Describe the structure and bonding of graphite.

*06* [4 marks]

Extra space

02.4 Substances that consist of small molecules do not conduct electricity.

Give one reason why.

*07* [1 mark]

02.5 Methane consists of small molecules.

Poly(ethene) is a polymer.

Why does poly(ethene) have a higher melting point than methane?

[1 mark]

Tick ( ) one box.

Poly(ethene) has more covalent bonds to break than methane.

Poly(ethene) has no intermolecular forces to overcome.

Poly(ethene) has stronger covalent bonds to break than methane.

Poly(ethene) has stronger intermolecular forces to overcome

than methane.

Mark scheme

Show the mark scheme Mark scheme for Question 2 with a total of 11 marks. 02.1 awards 1 mark for 'CaS'. 02.2 awards 4 marks for: calcium loses electrons, sulfur gains electrons, transfer of two electrons, and calcium forms positive ions and sulfur forms negative ions. 02.3 uses a 2-level marking grid (Level 2: 3-4 marks, Level 1: 1-2 marks) with indicative points including giant structure, layers of hexagonal rings, 3 bonds per carbon, delocalised electrons, and strong covalent bonds. 02.4 awards 1 mark for 'the molecules do not have an overall electric charge' or no ions / no delocalised electrons. 02.5 awards 1 mark for 'poly(ethene) has stronger intermolecular forces to overcome than methane'.

Question 2

AO /

Question Answers Extra information Mark

Spec. Ref.

02.1 CaS 1 AO2

4.2.1.3

AO /

Spec. Ref.

02.2 calcium (atom) loses electrons 1 AO2

4.2.1.1

4.2.1.2

sulfur (atom) gains electrons 1

reference to transfer of two 1

electrons

calcium forms positive ions and allow Ca2+ (ions) and S2- (ions) 1

sulfur forms negative ions are formed

allow calcium ions and sulfide

ions are formed

AO /

Question Answers Mark

Spec. Ref.

02.3 Level 2: Scientifically relevant facts, events or processes are 3–4 AO1

identified and given in detail to form an accurate account. 4.2.1.1

4.2.1.4

4.2.2.6

Level 1: Facts, events or processes are identified and simply 1–2 4.2.3.2

stated but their relevance is not clear.

No relevant content 0

Indicative content

• giant structure

• layers

• of hexagonal rings

• each (carbon) atom forms three bonds

• has no covalent bonds between layers

• with delocalised electrons

• one delocalised electron from each carbon atom

10 • the bonds are covalent

• with shared (pairs of) electrons

• the (covalent) bonds are strong

AO /

Spec. Ref.

02.4 the molecules do not have an allow there are no ions 1 AO1

(overall electric) charge 4.2.2.4

allow there are no delocalised

electrons

AO /

Spec. Ref.

02.5 poly(ethene) has stronger 1 AO1

intermolecular forces to 4.2.2.4

overcome than methane 4.2.2.5

Total Question 2 11

How to answer it

Structure, Bonding & Chemical Properties

Topic Summary

What this question tests

This question assesses foundational knowledge and application across ionic, giant covalent, and simple molecular structures from AQA Specification 4.2:

  • Empirical Formulas: Deducing the simplest whole-number ratio of ions in an ionic lattice.
  • Ionic Bonding Mechanism: Explaining electron transfer, ion charges, and outer shell changes between Group 2 metals and Group 6 non-metals.
  • Giant Covalent Structures: Accurately detailing the layer structure, bonding type, and delocalised electrons in graphite.
  • Electrical Conductivity: Linking the presence or absence of mobile charged particles (ions or delocalised electrons) to conductivity in molecular substances.
  • Intermolecular Forces: Explaining difference in melting points based on molecule size and intermolecular forces.
Part 02.1 • 1 Mark

Empirical Formula of Calcium Sulfide

Deducing chemical formula from an ionic lattice representation

✅ Correct Answer

CaS

💡 Key Knowledge

The empirical formula is the simplest whole-number ratio of atoms or ions in a compound.

  • Calcium is in Group 2 → forms Ca²⁺
  • Sulfur is in Group 6 → forms S²⁻
  • Ratio is 1:1, giving the formula CaS .

🧠 Exam Technique

Always write chemical symbols with correct case (capital C , lowercase a , capital S ). Do not include charges in an empirical formula (e.g. do not write Ca²⁺S²⁻).

❌ Common Errors

  • Counting the total spheres in the diagram and writing something like Ca₁₄S₁₃ .
  • Incorrect capitalisation like CAS or cas .
Mark Scheme: CaS [1 mark] (AO2, 4.2.1.3)
Part 02.2 • 4 Marks

Reaction of Calcium with Sulfur

Describing ionic bonding in terms of electron transfer and formed ions

✅ 4-Mark Model Answer

  1. Calcium (atom) loses electrons [1]
  2. Sulfur (atom) gains electrons [1]
  3. There is a transfer of two electrons [1]
  4. Calcium forms a positive ion (or Ca²⁺ ) and sulfur forms a negative ion (or S²⁻ ) [1]

💡 Key Knowledge

  • Metals lose electrons from their outer shell to form positive cations.
  • Non-metals gain electrons into their outer shell to form negative anions.
  • Group 2 elements have 2 outer electrons to lose. Group 6 elements need 2 electrons to complete a full shell of 8.

🧠 Structure Your Answer

When an exam prompt says "in terms of electrons and ions", check off both:

  • Electrons: Who loses? Who gains? Exactly how many?
  • Ions: Name each ion and state its charge (positive/negative or Ca²⁺/S²⁻).

❌ Common Errors

  • Saying calcium and sulfur "share" electrons (confusing ionic with covalent bonding).
  • Saying electrons are transferred, but failing to specify two electrons.
  • Calling the negative ion "sulfate" instead of "sulfide" or "sulfur ion".
Mark Scheme: calcium loses electrons [1] • sulfur gains electrons [1] • transfer of two electrons [1] • calcium forms positive ions AND sulfur forms negative ions (or Ca²⁺ and S²⁻) [1]
Part 02.3 • 4 Marks

Structure and Bonding of Graphite

Extended description of a giant covalent allotrope

💡 Indicative Marking Points (AO1)

Structure Points:
  • Giant covalent lattice
  • Arranged in layers
  • Consists of hexagonal rings (rings of 6 carbon atoms)
  • No covalent bonds between layers (weak intermolecular forces between layers)
Bonding Points:
  • Bonds are covalent (shared pairs of electrons)
  • Covalent bonds are strong
  • Each carbon atom forms three covalent bonds
  • One delocalised electron per carbon atom (free to move throughout the structure)

✅ Model Answer (Level 2: 4 Marks)

"Graphite has a giant covalent structure composed of carbon atoms arranged in layers of hexagonal rings. Each carbon atom forms three strong covalent bonds by sharing pairs of electrons. There are no covalent bonds between the layers, only weak forces. Each carbon atom has one unused outer electron, resulting in delocalised electrons that can move through the layers."

🧠 Level of Response Criteria

  • Level 2 (3–4 marks): Relevant points from both structure and bonding are identified and linked clearly to form a detailed, coherent account.
  • Level 1 (1–2 marks): Isolated points stated without clear distinction or incomplete detail (e.g. mentions "layers" and "covalent bonds" only).

❌ Common Misconceptions in Graphite Descriptions

  • Confusing with Diamond: Writing that each carbon forms four bonds. In graphite, carbon only forms three bonds.
  • Talking about properties instead of structure: Explaining that graphite is slippery or conducts electricity without describing the structural features causing it. The question asks to describe structure and bonding.
  • Vague bonding: Calling bonds "ionic" or confusing covalent bonds within layers with the weak attractions between layers.
Mark Scheme: Level 2 (3-4 marks): Scientifically relevant facts identified and given in detail. Level 1 (1-2 marks): Facts stated but relevance not clear. (AO1, 4.2.1.1, 4.2.1.4, 4.2.2.6, 4.2.3.2)
Part 02.4 • 1 Mark

Electrical Conductivity in Small Molecules

Explaining why simple molecular substances are electrical insulators

✅ Correct Answer (Any one of the following)

  • The molecules do not have an overall electric charge.
  • There are no free ions.
  • There are no delocalised electrons.

💡 Key Rule for Conduction

For any substance to conduct electricity, it must contain charged particles that are free to move:

  • Metals/Graphite → delocalised electrons
  • Molten/Aqueous Ionic → mobile ions
  • Small molecules → neutral molecules, no free charges!

❌ Insufficient Answers

  • "They have strong covalent bonds" (Irrelevant to conductivity).
  • "Electrons can't move" (Too vague — must specify that there are no delocalised electrons or no free ions).

🧠 Exam Tip

Always state the specific particle! Don't just write "no charge"; write "the molecules have no overall charge" or "there are no free ions".

Mark Scheme: the molecules do not have an (overall electric) charge / allow there are no ions / allow there are no delocalised electrons [1 mark] (AO1, 4.2.2.4)
Part 02.5 • 1 Mark

Melting Points: Polymers vs Small Molecules

Comparing intermolecular forces in methane and poly(ethene)

✅ Correct Choice

[ ✓ ] Poly(ethene) has stronger intermolecular forces to overcome than methane.

💡 Why is this true?

Poly(ethene) molecules are very large polymer chains compared to tiny methane ( CH₄ ) molecules.

As molecular size increases, the strength of the intermolecular forces increases, meaning more energy is needed to overcome them and melt the substance.

❌ The Classic "Bond-Breaking" Trap

Notice the two distractor options on the exam paper:

  • "Poly(ethene) has more covalent bonds to break than methane." — FALSE! Melting a molecular substance does not break covalent bonds.
  • "Poly(ethene) has stronger covalent bonds to break than methane." — FALSE! Covalent bonds remain intact when polymers or small molecules melt.
  • "Poly(ethene) has no intermolecular forces to overcome." — FALSE! All molecular substances have intermolecular forces.
Mark Scheme: poly(ethene) has stronger intermolecular forces to overcome than methane [1 mark] (AO1, 4.2.2.4, 4.2.2.5)

Topics

Chemistry · C2: Bonding, Structure and the Properties of Matter

Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.