AQA GCSE Chemistry Chemistry Paper 1 (Higher), June 2025: Question 2
11 marks · Standard Demand difficulty · Short Answer
Describe the bonding in calcium sulfide, the structure and bonding of graphite, and the properties of small molecules and polymers.
Practise this questionQuestion
Question text
02 This question is about structure and bonding.
Calcium sulfide is an ionic compound.
Figure 2 represents the structure of calcium sulfide.
Figure 2
02.1 Determine the empirical formula of calcium sulfide.
[1 mark]
Empirical formula 6
02.2 Calcium is in Group 2 of the periodic table.
Sulfur is in Group 6 of the periodic table.
Describe what happens when a calcium atom reacts with a sulfur atom.
Answer in terms of electrons and ions.
[4 marks]
Figure 3 shows the structure of graphite.
Figure 3
02.3 Describe the structure and bonding of graphite.
*06* [4 marks]
Extra space
02.4 Substances that consist of small molecules do not conduct electricity.
Give one reason why.
*07* [1 mark]
02.5 Methane consists of small molecules.
Poly(ethene) is a polymer.
Why does poly(ethene) have a higher melting point than methane?
[1 mark]
Tick ( ) one box.
Poly(ethene) has more covalent bonds to break than methane.
Poly(ethene) has no intermolecular forces to overcome.
Poly(ethene) has stronger covalent bonds to break than methane.
Poly(ethene) has stronger intermolecular forces to overcome
than methane.
Mark scheme
Show the mark scheme
Question 2
AO /
Question Answers Extra information Mark
Spec. Ref.
02.1 CaS 1 AO2
4.2.1.3
AO /
Spec. Ref.
02.2 calcium (atom) loses electrons 1 AO2
4.2.1.1
4.2.1.2
sulfur (atom) gains electrons 1
reference to transfer of two 1
electrons
calcium forms positive ions and allow Ca2+ (ions) and S2- (ions) 1
sulfur forms negative ions are formed
allow calcium ions and sulfide
ions are formed
AO /
Question Answers Mark
Spec. Ref.
02.3 Level 2: Scientifically relevant facts, events or processes are 3–4 AO1
identified and given in detail to form an accurate account. 4.2.1.1
4.2.1.4
4.2.2.6
Level 1: Facts, events or processes are identified and simply 1–2 4.2.3.2
stated but their relevance is not clear.
No relevant content 0
Indicative content
• giant structure
• layers
• of hexagonal rings
• each (carbon) atom forms three bonds
• has no covalent bonds between layers
• with delocalised electrons
• one delocalised electron from each carbon atom
10 • the bonds are covalent
• with shared (pairs of) electrons
• the (covalent) bonds are strong
AO /
Spec. Ref.
02.4 the molecules do not have an allow there are no ions 1 AO1
(overall electric) charge 4.2.2.4
allow there are no delocalised
electrons
AO /
Spec. Ref.
02.5 poly(ethene) has stronger 1 AO1
intermolecular forces to 4.2.2.4
overcome than methane 4.2.2.5
Total Question 2 11
How to answer it
Structure, Bonding & Chemical Properties
What this question tests
This question assesses foundational knowledge and application across ionic, giant covalent, and simple molecular structures from AQA Specification 4.2:
- Empirical Formulas: Deducing the simplest whole-number ratio of ions in an ionic lattice.
- Ionic Bonding Mechanism: Explaining electron transfer, ion charges, and outer shell changes between Group 2 metals and Group 6 non-metals.
- Giant Covalent Structures: Accurately detailing the layer structure, bonding type, and delocalised electrons in graphite.
- Electrical Conductivity: Linking the presence or absence of mobile charged particles (ions or delocalised electrons) to conductivity in molecular substances.
- Intermolecular Forces: Explaining difference in melting points based on molecule size and intermolecular forces.
Empirical Formula of Calcium Sulfide
Deducing chemical formula from an ionic lattice representation
✅ Correct Answer
CaS
💡 Key Knowledge
The empirical formula is the simplest whole-number ratio of atoms or ions in a compound.
- Calcium is in Group 2 → forms Ca²⁺
- Sulfur is in Group 6 → forms S²⁻
- Ratio is 1:1, giving the formula CaS .
🧠 Exam Technique
Always write chemical symbols with correct case (capital C , lowercase a , capital S ). Do not include charges in an empirical formula (e.g. do not write Ca²⁺S²⁻).
❌ Common Errors
- Counting the total spheres in the diagram and writing something like Ca₁₄S₁₃ .
- Incorrect capitalisation like CAS or cas .
Reaction of Calcium with Sulfur
Describing ionic bonding in terms of electron transfer and formed ions
✅ 4-Mark Model Answer
- Calcium (atom) loses electrons [1]
- Sulfur (atom) gains electrons [1]
- There is a transfer of two electrons [1]
- Calcium forms a positive ion (or Ca²⁺ ) and sulfur forms a negative ion (or S²⁻ ) [1]
💡 Key Knowledge
- Metals lose electrons from their outer shell to form positive cations.
- Non-metals gain electrons into their outer shell to form negative anions.
- Group 2 elements have 2 outer electrons to lose. Group 6 elements need 2 electrons to complete a full shell of 8.
🧠 Structure Your Answer
When an exam prompt says "in terms of electrons and ions", check off both:
- Electrons: Who loses? Who gains? Exactly how many?
- Ions: Name each ion and state its charge (positive/negative or Ca²⁺/S²⁻).
❌ Common Errors
- Saying calcium and sulfur "share" electrons (confusing ionic with covalent bonding).
- Saying electrons are transferred, but failing to specify two electrons.
- Calling the negative ion "sulfate" instead of "sulfide" or "sulfur ion".
Structure and Bonding of Graphite
Extended description of a giant covalent allotrope
💡 Indicative Marking Points (AO1)
- Giant covalent lattice
- Arranged in layers
- Consists of hexagonal rings (rings of 6 carbon atoms)
- No covalent bonds between layers (weak intermolecular forces between layers)
- Bonds are covalent (shared pairs of electrons)
- Covalent bonds are strong
- Each carbon atom forms three covalent bonds
- One delocalised electron per carbon atom (free to move throughout the structure)
✅ Model Answer (Level 2: 4 Marks)
"Graphite has a giant covalent structure composed of carbon atoms arranged in layers of hexagonal rings. Each carbon atom forms three strong covalent bonds by sharing pairs of electrons. There are no covalent bonds between the layers, only weak forces. Each carbon atom has one unused outer electron, resulting in delocalised electrons that can move through the layers."
🧠 Level of Response Criteria
- Level 2 (3–4 marks): Relevant points from both structure and bonding are identified and linked clearly to form a detailed, coherent account.
- Level 1 (1–2 marks): Isolated points stated without clear distinction or incomplete detail (e.g. mentions "layers" and "covalent bonds" only).
❌ Common Misconceptions in Graphite Descriptions
- Confusing with Diamond: Writing that each carbon forms four bonds. In graphite, carbon only forms three bonds.
- Talking about properties instead of structure: Explaining that graphite is slippery or conducts electricity without describing the structural features causing it. The question asks to describe structure and bonding.
- Vague bonding: Calling bonds "ionic" or confusing covalent bonds within layers with the weak attractions between layers.
Electrical Conductivity in Small Molecules
Explaining why simple molecular substances are electrical insulators
✅ Correct Answer (Any one of the following)
- The molecules do not have an overall electric charge.
- There are no free ions.
- There are no delocalised electrons.
💡 Key Rule for Conduction
For any substance to conduct electricity, it must contain charged particles that are free to move:
- Metals/Graphite → delocalised electrons
- Molten/Aqueous Ionic → mobile ions
- Small molecules → neutral molecules, no free charges!
❌ Insufficient Answers
- "They have strong covalent bonds" (Irrelevant to conductivity).
- "Electrons can't move" (Too vague — must specify that there are no delocalised electrons or no free ions).
🧠 Exam Tip
Always state the specific particle! Don't just write "no charge"; write "the molecules have no overall charge" or "there are no free ions".
Melting Points: Polymers vs Small Molecules
Comparing intermolecular forces in methane and poly(ethene)
✅ Correct Choice
[ ✓ ] Poly(ethene) has stronger intermolecular forces to overcome than methane.
💡 Why is this true?
Poly(ethene) molecules are very large polymer chains compared to tiny methane ( CH₄ ) molecules.
As molecular size increases, the strength of the intermolecular forces increases, meaning more energy is needed to overcome them and melt the substance.
❌ The Classic "Bond-Breaking" Trap
Notice the two distractor options on the exam paper:
- "Poly(ethene) has more covalent bonds to break than methane." — FALSE! Melting a molecular substance does not break covalent bonds.
- "Poly(ethene) has stronger covalent bonds to break than methane." — FALSE! Covalent bonds remain intact when polymers or small molecules melt.
- "Poly(ethene) has no intermolecular forces to overcome." — FALSE! All molecular substances have intermolecular forces.
Topics
Chemistry · C2: Bonding, Structure and the Properties of Matter
Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.