AQA GCSE Chemistry Chemistry Paper 1 (Higher), June 2025: Question 4
11 marks · Standard Demand difficulty · Short Answer
Answer questions on the properties, reactivity trends, and displacement reactions of Group 7 elements (halogens).
Practise this questionQuestion
Question text
04 The elements in Group 7 of the periodic table are known as the halogens.
Figure 4 shows information about some of the elements in Group 7.
Figure 4
04.1 Predict the boiling point of chlorine.
Use Figure 4.
[1 mark]
°C
04.2 What is the state of fluorine at –250 °C?
Use Figure 4.
[1 mark]
Astatine (At) is an element in Group 7.
04.3 What is the number of electrons in the outer shell of an astatine atom?
[1 mark]
04.4 Hydrogen reacts with astatine to produce hydrogen astatide.
Predict the formula of hydrogen astatide.
[1 mark]
04.5 Explain the trend in reactivity of the elements going down Group 7.
[4 marks]
Extra space
04.6 A more reactive halogen can displace a less reactive halogen from
a solution of its salt.
Write a balanced equation for the reaction between bromine and potassium iodide.
[3 marks]
+ ⟶ +
Mark scheme
Show the mark scheme
Question 4
AO /
Question Answers Extra information Mark
Spec. Ref.
04.1 –34 °C allow a value in the range 1 AO3
–70 to –20 °C 4.1.2.6
AO /
Spec. Ref.
04.2 solid allow (s) 1 AO3
4.1.2.6
4.2.2.1
AO /
Spec. Ref.
04.3 7 1 AO1
4.1.2.1
4.1.2.6
AO /
Spec. Ref.
04.4 HAt 1 AO2
4.1.2.1
4.1.2.6
AO /
Spec. Ref.
04.5 allow energy level for shell
reactivity decreases (going 1 AO1
down the group) 4.1.2.6
(because) the outer shell / allow (because) the atoms 1
electrons become further from become larger
the nucleus
allow (because) the atoms have
more shells
(so) there is less (electrostatic) allow (so) there is more 1
attraction between the nucleus shielding between the outer
and the outer electron(s) electron(s) and the nucleus
(so) gaining an electron is more 1
difficult
AO /
Spec. Ref.
04.6 Br2 + 2KI ⟶ I2 + 2KBr allow multiples 3 AO2
4.1.1.1
allow 1 mark for Br2 and I2 4.1.2.6
allow 1 mark for KI and KBr
ignore state symbols
Total Question 4 11
How to answer it
AQA GCSE Chemistry: Group 7 (Halogens) Properties & Trends
Interpreting melting and boiling point bar charts, deducing physical states at specific temperatures, relating group number to outer-shell electrons, predicting chemical formulae for unfamiliar elements (astatine), explaining the decrease in reactivity down Group 7 using atomic structure, and constructing balanced halogen displacement equations.
Part 04.1: Predicting Chlorine's Boiling Point
1 Mark • Assessment Objective: AO3
✅ Correct Answer
Any value in the range: -70 °C to -20 °C
Examiner actual value: -34 °C
🧠 Exam Technique
- Check the key: Boiling points are represented by white bars.
- Look at the trend: Boiling point increases down the group from fluorine (-188 °C) to bromine (+59 °C).
- Chlorine's boiling point must be between fluorine's and bromine's, and comfortably above chlorine's own melting point (-101 °C).
❌ Common Errors
- Reading the shaded bar (melting point: -101 °C) instead of boiling point.
- Forgetting the minus sign (writing 34 °C instead of -34 °C ).
- Predicting a value lower than its melting point (a substance cannot boil at a lower temperature than it melts).
Part 04.2: State of Fluorine at -250 °C
1 Mark • Assessment Objective: AO3 / AO1
✅ Correct Answer
Solid (or allow (s) )
💡 Key Knowledge: State Rules
- Temperature < Melting Point → Solid
- Temperature between MP and BP → Liquid
- Temperature > Boiling Point → Gas
Fluorine melts at approx. -220 °C . Because -250 °C is lower (colder) than its melting point, it must be a solid.
❌ Common Errors
- Confusing negative numbers: thinking -250 is higher than -220.
- Writing "gas" purely from recall that fluorine is a gas at room temperature, without checking the temperature given in the question.
Parts 04.3 & 04.4: Outer Electrons & Formula Prediction (Astatine)
2 Marks Total (1 mark each) • Assessment Objective: AO1 & AO2
✅ Correct Answers
04.3: 7
04.4: HAt
💡 Periodic Table Patterns
- Group number = number of outer shell electrons. Astatine is in Group 7, so it has 7 outer electrons.
- Because all Group 7 halogens need 1 electron to complete their octet, they form 1 single covalent bond with hydrogen:
HF, HCl, HBr, HI → therefore HAt.
❌ Common Errors
- Writing total electrons instead of outer shell electrons.
- Incorrect capitalisation or stoichiometry: e.g. H₂At , Hat , or HAt₂ .
Part 04.5: Explaining the Trend in Reactivity Down Group 7
4 Marks • Assessment Objective: AO1 (Spec 4.1.2.6)
✅ Model 4-Mark Response
Point 1: Going down Group 7, reactivity decreases.
Point 2: The atoms get larger / have more electron shells, so the outer shell is further from the nucleus.
Point 3: There is weaker electrostatic attraction between the nucleus and the incoming outer electron (due to greater distance and more shielding).
Point 4: Therefore, it is harder / more difficult to gain an electron.
🧠 How to Structure 4-Mark Periodic Explanations
- Trend statement: State clearly whether reactivity increases or decreases.
- Atomic size: Mention atomic radius / number of shells / distance from nucleus.
- Nuclear attraction: Describe attraction to the incoming electron (mention shielding).
- Electron transfer: Group 7 elements react by gaining an electron, so state how easily this happens.
❌ Common Errors & Misconceptions
- Confusing Group 1 and Group 7: Stating that halogens "lose an electron" to react. Group 7 elements gain an electron!
- Vague statements like "it has less pull" without specifying what is pulling what (nucleus pulls outer electron).
- Saying "reactivity increases down the group" (which is true for Group 1 metals, but the opposite for Group 7).
• Mark 1: Reactivity decreases (down the group)
• Mark 2: Outer shell / electrons become further from the nucleus (allow: atoms become larger / have more shells)
• Mark 3: Less (electrostatic) attraction between nucleus and outer electron(s) (allow: more shielding)
• Mark 4: Gaining an electron is more difficult
Part 04.6: Halogen Displacement Balanced Equation
3 Marks • Assessment Objective: AO2 (Spec 4.1.1.1, 4.1.2.6)
✅ Balanced Chemical Equation
Br₂ + 2KI → I₂ + 2KBr
📐 Step-by-Step Construction
- Identify reactants:
Bromine is a diatomic element → Br₂
Potassium iodide consists of K⁺ and I⁻ → KI - Identify products:
Bromine is more reactive than iodine, displacing it.
Displaced iodine forms diatomic molecules → I₂
Potassium bromide salt forms → KBr - Balance the atoms:
2 bromine atoms on left require 2KBr on right.
2 iodine atoms on right require 2KI on left.
❌ Common Calculation & Formula Traps
- Writing halogens as monatomic: Br instead of Br₂ , or I instead of I₂ .
- Inventing incorrect salt formulae to force balancing without coefficients: e.g. writing KBr₂ or K₂I . K is always +1, halides are always -1!
- Incorrect casing: ki or kbr will lose marks.
• 1 mark: correct formulae for both diatomic halogens ( Br₂ and I₂ )
• 1 mark: correct formulae for both salts ( KI and KBr )
• 1 mark: correct balancing ( Br₂ + 2KI → I₂ + 2KBr ). Allow multiples (e.g. 2Br₂ + 4KI → 2I₂ + 4KBr). State symbols are not required.
Topics
Chemistry · C1: Atomic Structure and the Periodic Table · C2: Bonding, Structure and the Properties of Matter
Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.