AQA GCSE Chemistry Chemistry Paper 1 (Higher), June 2025: Question 4

11 marks · Standard Demand difficulty · Short Answer

Answer questions on the properties, reactivity trends, and displacement reactions of Group 7 elements (halogens).

Practise this question

Question

Question 4 contains a bar chart showing the melting and boiling points in degrees Celsius of fluorine, chlorine, bromine, and iodine. For fluorine, melting point is around -220 °C and boiling point is around -188 °C. For chlorine, only the melting point is shown around -101 °C. For bromine, melting point is around -7 °C and boiling point is around 59 °C. For iodine, melting point is around 114 °C and boiling point is around 184 °C. Six sub-questions follow: predicting chlorine's boiling point, determining the physical state of fluorine at -250 °C, stating outer shell electrons of astatine, predicting the formula of hydrogen astatide, explaining the reactivity trend down Group 7 (4 marks), and completing a balanced chemical equation for bromine reacting with potassium iodide (3 marks).
Question text

04 The elements in Group 7 of the periodic table are known as the halogens.

Figure 4 shows information about some of the elements in Group 7.

Figure 4

04.1 Predict the boiling point of chlorine.

Use Figure 4.

[1 mark]

°C

04.2 What is the state of fluorine at –250 °C?

Use Figure 4.

[1 mark]

Astatine (At) is an element in Group 7.

04.3 What is the number of electrons in the outer shell of an astatine atom?

[1 mark]

04.4 Hydrogen reacts with astatine to produce hydrogen astatide.

Predict the formula of hydrogen astatide.

[1 mark]

04.5 Explain the trend in reactivity of the elements going down Group 7.

[4 marks]

Extra space

04.6 A more reactive halogen can displace a less reactive halogen from

a solution of its salt.

Write a balanced equation for the reaction between bromine and potassium iodide.

[3 marks]

+ ⟶ +

Mark scheme

Show the mark scheme Mark scheme for Question 4 lists accepted answers: 04.1: -34 °C (allow range -70 to -20 °C); 04.2: solid / (s); 04.3: 7; 04.4: HAt; 04.5 (4 marks): reactivity decreases down the group, outer shell further from nucleus, less electrostatic attraction between nucleus and outer electrons, gaining an electron is more difficult; 04.6 (3 marks): Br2 + 2 KI -> I2 + 2 KBr.

Question 4

AO /

Question Answers Extra information Mark

Spec. Ref.

04.1 –34 °C allow a value in the range 1 AO3

–70 to –20 °C 4.1.2.6

AO /

Spec. Ref.

04.2 solid allow (s) 1 AO3

4.1.2.6

4.2.2.1

AO /

Spec. Ref.

04.3 7 1 AO1

4.1.2.1

4.1.2.6

AO /

Spec. Ref.

04.4 HAt 1 AO2

4.1.2.1

4.1.2.6

AO /

Spec. Ref.

04.5 allow energy level for shell

reactivity decreases (going 1 AO1

down the group) 4.1.2.6

(because) the outer shell / allow (because) the atoms 1

electrons become further from become larger

the nucleus

allow (because) the atoms have

more shells

(so) there is less (electrostatic) allow (so) there is more 1

attraction between the nucleus shielding between the outer

and the outer electron(s) electron(s) and the nucleus

(so) gaining an electron is more 1

difficult

AO /

Spec. Ref.

04.6 Br2 + 2KI ⟶ I2 + 2KBr allow multiples 3 AO2

4.1.1.1

allow 1 mark for Br2 and I2 4.1.2.6

allow 1 mark for KI and KBr

ignore state symbols

Total Question 4 11

How to answer it

AQA GCSE Chemistry: Group 7 (Halogens) Properties & Trends

📌 What this question tests

Interpreting melting and boiling point bar charts, deducing physical states at specific temperatures, relating group number to outer-shell electrons, predicting chemical formulae for unfamiliar elements (astatine), explaining the decrease in reactivity down Group 7 using atomic structure, and constructing balanced halogen displacement equations.

Part 04.1: Predicting Chlorine's Boiling Point

1 Mark • Assessment Objective: AO3

✅ Correct Answer

Any value in the range: -70 °C to -20 °C

Examiner actual value: -34 °C

🧠 Exam Technique

  • Check the key: Boiling points are represented by white bars.
  • Look at the trend: Boiling point increases down the group from fluorine (-188 °C) to bromine (+59 °C).
  • Chlorine's boiling point must be between fluorine's and bromine's, and comfortably above chlorine's own melting point (-101 °C).

❌ Common Errors

  • Reading the shaded bar (melting point: -101 °C) instead of boiling point.
  • Forgetting the minus sign (writing 34 °C instead of -34 °C ).
  • Predicting a value lower than its melting point (a substance cannot boil at a lower temperature than it melts).
Mark scheme: Allow any value from -70 to -20 °C (1 mark).

Part 04.2: State of Fluorine at -250 °C

1 Mark • Assessment Objective: AO3 / AO1

✅ Correct Answer

Solid (or allow (s) )

💡 Key Knowledge: State Rules

  • Temperature < Melting Point → Solid
  • Temperature between MP and BP → Liquid
  • Temperature > Boiling Point → Gas

Fluorine melts at approx. -220 °C . Because -250 °C is lower (colder) than its melting point, it must be a solid.

❌ Common Errors

  • Confusing negative numbers: thinking -250 is higher than -220.
  • Writing "gas" purely from recall that fluorine is a gas at room temperature, without checking the temperature given in the question.
Mark scheme: solid (allow 's') (1 mark).

Parts 04.3 & 04.4: Outer Electrons & Formula Prediction (Astatine)

2 Marks Total (1 mark each) • Assessment Objective: AO1 & AO2

✅ Correct Answers

04.3: 7

04.4: HAt

💡 Periodic Table Patterns

  • Group number = number of outer shell electrons. Astatine is in Group 7, so it has 7 outer electrons.
  • Because all Group 7 halogens need 1 electron to complete their octet, they form 1 single covalent bond with hydrogen:
    HF, HCl, HBr, HI → therefore HAt.

❌ Common Errors

  • Writing total electrons instead of outer shell electrons.
  • Incorrect capitalisation or stoichiometry: e.g. H₂At , Hat , or HAt₂ .
Mark scheme: 04.3: 7 (1 mark). 04.4: HAt (1 mark). Capital letters must be accurate (H and A capitalised, t lower case).

Part 04.5: Explaining the Trend in Reactivity Down Group 7

4 Marks • Assessment Objective: AO1 (Spec 4.1.2.6)

✅ Model 4-Mark Response

Point 1: Going down Group 7, reactivity decreases.

Point 2: The atoms get larger / have more electron shells, so the outer shell is further from the nucleus.

Point 3: There is weaker electrostatic attraction between the nucleus and the incoming outer electron (due to greater distance and more shielding).

Point 4: Therefore, it is harder / more difficult to gain an electron.

🧠 How to Structure 4-Mark Periodic Explanations

  1. Trend statement: State clearly whether reactivity increases or decreases.
  2. Atomic size: Mention atomic radius / number of shells / distance from nucleus.
  3. Nuclear attraction: Describe attraction to the incoming electron (mention shielding).
  4. Electron transfer: Group 7 elements react by gaining an electron, so state how easily this happens.

❌ Common Errors & Misconceptions

  • Confusing Group 1 and Group 7: Stating that halogens "lose an electron" to react. Group 7 elements gain an electron!
  • Vague statements like "it has less pull" without specifying what is pulling what (nucleus pulls outer electron).
  • Saying "reactivity increases down the group" (which is true for Group 1 metals, but the opposite for Group 7).
Mark scheme breakdown:
• Mark 1: Reactivity decreases (down the group)
• Mark 2: Outer shell / electrons become further from the nucleus (allow: atoms become larger / have more shells)
• Mark 3: Less (electrostatic) attraction between nucleus and outer electron(s) (allow: more shielding)
• Mark 4: Gaining an electron is more difficult

Part 04.6: Halogen Displacement Balanced Equation

3 Marks • Assessment Objective: AO2 (Spec 4.1.1.1, 4.1.2.6)

✅ Balanced Chemical Equation

Br₂ + 2KI → I₂ + 2KBr

📐 Step-by-Step Construction

  1. Identify reactants:
    Bromine is a diatomic element → Br₂
    Potassium iodide consists of K⁺ and I⁻ → KI
  2. Identify products:
    Bromine is more reactive than iodine, displacing it.
    Displaced iodine forms diatomic molecules → I₂
    Potassium bromide salt forms → KBr
  3. Balance the atoms:
    2 bromine atoms on left require 2KBr on right.
    2 iodine atoms on right require 2KI on left.

❌ Common Calculation & Formula Traps

  • Writing halogens as monatomic: Br instead of Br₂ , or I instead of I₂ .
  • Inventing incorrect salt formulae to force balancing without coefficients: e.g. writing KBr₂ or K₂I . K is always +1, halides are always -1!
  • Incorrect casing: ki or kbr will lose marks.
Mark scheme breakdown:
• 1 mark: correct formulae for both diatomic halogens ( Br₂ and I₂ )
• 1 mark: correct formulae for both salts ( KI and KBr )
• 1 mark: correct balancing ( Br₂ + 2KI → I₂ + 2KBr ). Allow multiples (e.g. 2Br₂ + 4KI → 2I₂ + 4KBr). State symbols are not required.

Topics

Chemistry · C1: Atomic Structure and the Periodic Table · C2: Bonding, Structure and the Properties of Matter

Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.