AQA GCSE Chemistry Chemistry Paper 1 (Higher), June 2025: Question 7

11 marks · Standard Demand difficulty · Extended Answer

Evaluate hydrazine versus hydrogen in fuel cells, draw its dot-and-cross diagram, compare molecular models, and calculate an unknown bond energy.

Practise this question

Question

Question 7 consists of four parts based on hydrazine (N2H4). Part 07.1 provides Table 2 comparing hydrogen and hydrazine in terms of state at room temperature, hazards, fuel cell reaction equation, voltage produced, and catalyst needed, asking students to evaluate hydrazine's use (4 marks). Figure 6 shows a 3D ball-and-stick model of hydrazine. Part 07.2 asks to complete an outer-shell dot-and-cross diagram of hydrazine in Figure 7 (2 marks). Part 07.3 asks for one advantage of the ball-and-stick model over the dot-and-cross diagram (1 mark). Part 07.4 presents the balanced displayed formula equation for N2H4 reacting with O2 to form N2 and 2 H2O, states the overall energy released forming bonds is 581 kJ/mol greater than energy needed to break bonds, and gives Table 3 with bond energies to calculate the unknown N–N bond energy X (4 marks).
Question text

07 Hydrazine (N2H4) is a compound of nitrogen and hydrogen.

07.1 Scientists are researching the use of hydrazine in fuel cells.

Table 2 gives some information about the use of hydrogen and hydrazine in fuel cells.

Table 2

Hydrogen Hydrazine

State at room temperature Gas Liquid

Hazards Explosive Toxic

Equation for fuel cell reaction 2 H2 + O2 ⟶ 2 H2O N2H4 + O2 ⟶ N2 + 2 H2O

Voltage produced in volts 1.23 1.61

Catalyst needed for reaction Platinum None

Evaluate the use of hydrazine instead of hydrogen in a fuel cell.

[4 marks]

Extra space

Figure 6 shows a model of the hydrazine molecule.

Figure 6

07.2 Complete the dot and cross diagram for hydrazine in Figure 7.

Show the outer shell electrons only.

[2 marks]

Figure 7

07.3 Give one advantage of the ball and stick model in Figure 6 compared to the

dot and cross diagram.

[1 mark]

07.4 Figure 8 shows the displayed formula equation for the reaction of

hydrazine with oxygen.

Figure 8

The reaction is exothermic.

The energy released forming new bonds is 581 kJ/mol greater than the energy

needed to break existing bonds.

Table 3 shows some bond energies.

Table 3

Calculate the bond energy (X) of the bond.

[4 marks]

X = kJ/mol

Mark scheme

Show the mark scheme The mark scheme provides criteria for Question 7: 07.1 is marked via Level 2 (3–4 marks) and Level 1 (1–2 marks) based on evaluation linking storage, hazards, products, voltage, and catalyst costs. 07.2 gives 1 mark for a bonded electron pair in each overlap and 1 mark for each nitrogen having one non-bonded electron pair (lone pair). 07.3 awards 1 mark for showing the 3D shape or arrangement in space. 07.4 awards up to 4 marks for bond energy calculation: calculating bonds broken as (2062 + X), bonds formed as 2801, setting up 581 = 2801 - (2062 + X), and solving to give X = 158 kJ/mol.

Question 7

AO /

Question Answers Mark

Spec. Ref.

07.1 Level 2: A judgement, strongly linked and logically supported by a 3–4 AO3

sufficient range of correct reasons, is given. 4.5.2.2

Level 1: Some logically linked reasons are given. There may also 1–2

be a simple judgement.

No relevant content 0

Indicative content

• hydrazine is liquid so easier to store / transport

o because takes up less space

• both have significant dangers

• both produce harmless products

• hydrazine produces a higher voltage so fewer cells will be

needed (to produce the same voltage)

o so the battery would be lighter

• hydrazine needs no catalyst so costs may be less

• hydrogen uses platinum as a catalyst which is a rare metal

• judgement

AO /

Question Answers Extra information Mark

Spec. Ref.

07.2 allow any combination of x, o, AO2

e(−), for electrons 4.2.1.4

bonded pair of electrons in each 1

overlap

each nitrogen atom with 2 non- do not accept if extra electrons 1

bonded electrons on hydrogen atom(s)

MP2 is dependent upon the

award of MP1

an answer of

scores 2 marks

AO /

Spec. Ref.

07.3 (the ball and stick model) 1 AO1

shows the shape (of the 4.2.1.4

molecule)

or

(the ball and stick model) is 3-D

AO /

Spec. Ref.

07.4 (bonds broken = AO2

(4 × 391) + 498 + X =) 4.5.1.3

2062 + X 1

(bonds formed =

945 + (4 × 464) =)

2801 1

581 = 2801 - (2062 + X) allow correct use of incorrectly 1

determined values of bonds

broken and / or bonds made

(X =) 158 (kJ/mol) 1

Total Question 7 11

How to answer it

Hydrazine Fuel Cells, Covalent Bonding & Bond Energy

📋 What this question tests

This question assesses higher-tier core chemistry skills across two fundamental units:

  • Chemical Cells & Evaluation (Unit 4.5): Comparing fuel cell reactants using tabular data (physical properties, safety, cost, output voltage, environmental impact) to reach a justified judgement.
  • Covalent Bonding & Molecular Representations (Unit 4.2): Drawing outer-shell dot-and-cross diagrams for a polyatomic molecule and evaluating 2D vs 3D molecular models.
  • Bond Energy Calculations (Unit 4.5): Calculating an unknown single bond energy ( X ) using the principle of ΔH = Bonds Broken − Bonds Formed .

Part 07.1: Evaluating Hydrazine vs Hydrogen in Fuel Cells

4 Marks • AO3 (Evaluate & Conclude)

Level of Response (1–4 Marks)

✅ Model Answer & Key Comparison Points

  • Storage & Transport: Hydrazine is a liquid, making it significantly easier and safer to transport and store than compressed hydrogen gas (takes up less volume, no heavy high-pressure tanks).
  • Hazards: Both pose safety hazards; hydrogen is highly explosive/flammable, whereas hydrazine is toxic.
  • Products: Both reactions produce non-polluting, harmless products (hydrogen makes only H₂O; hydrazine makes non-toxic N₂ and H₂O).
  • Electrical Performance: Hydrazine produces a higher voltage (1.61 V vs 1.23 V), meaning fewer cells are needed to achieve the required output, leading to lighter battery packs.
  • Cost / Materials: Hydrazine requires no catalyst, reducing manufacturing costs; hydrogen requires an expensive, scarce platinum catalyst.
  • Judgement: "Overall, hydrazine is better for portable transport because it produces a higher voltage, is cheaper due to requiring no catalyst, and being a liquid makes it far easier to store than pressurised hydrogen gas, despite its toxicity."

🧠 Exam Technique: Securing Level 2 (3–4 Marks)

  • Always include both sides: You must state advantages and disadvantages or compare both fuels directly.
  • Add explanatory links: Do not just copy the table! Don't just say "hydrazine is a liquid"; explain "so it takes up less space and is easier to store". Don't just say "needs no platinum"; add "so it is cheaper".
  • Give a final judgement: Level 2 strictly requires a concluding sentence stating which is better and why.
Mark Scheme Breakdown:
• Level 2 (3–4 marks): A sustained, reasoned judgement supported by a balanced range of correct comparisons.
• Level 1 (1–2 marks): Isolated factual comparisons without full links, or lacking an overall judgement.

Part 07.2: Dot and Cross Diagram for Hydrazine (N₂H₄)

2 Marks • AO2 (Application of Knowledge)

✅ Correct Diagram Description

The diagram has 5 overlapping bond regions (four N–H overlaps and one central N–N overlap):

  • Shared pairs (bonds): Place 1 pair of electrons (one dot, one cross) in each of the four N–H overlaps, and 1 pair in the central N–N overlap.
  • Lone pairs: Place 1 non-bonding pair (2 dots or 2 crosses) on the outer ring of each Nitrogen atom.
  • Hydrogen shells: Hydrogen must contain only the 2 shared electrons in its overlap (no non-bonded electrons).
Mark Allocation:
• 1 Mark: Exactly one shared pair of electrons in every overlap.
• 1 Mark: Each Nitrogen atom has 2 non-bonded electrons (dependent on getting bonding pairs correct).

❌ Common Errors to Avoid

  • Adding electrons to Hydrogen: Hydrogen only needs 2 electrons to fill its outer shell. Adding extra lone pairs to H forfeits Mark 2!
  • Forgetting Nitrogen's lone pairs: Nitrogen is in Group 5. It uses 3 electrons to form single bonds, leaving 2 non-bonding valence electrons (1 lone pair).
  • Double bonding the N–N: Hydrazine contains a single N–N bond, not a double bond.

Part 07.3: Advantage of the Ball and Stick Model

1 Mark • AO1 (Recall & Understanding)

✅ Accepted Answers

  • It shows the 3D arrangement / 3D shape of the molecule.
  • It shows the bond angles / spatial orientation in space.
Mark Scheme: Accept: "shows the shape (of the molecule)" OR "shows it is 3-D".

💡 Examiner Tip

Dot-and-cross diagrams are 2D flat projections and incorrectly make molecules look planar. Ball-and-stick models show realistic spatial orientations (such as the non-planar, pyramidal arrangement around each nitrogen atom).

Part 07.4: Bond Energy Calculation (Solving for X)

4 Marks • AO2 (Calculation & Problem Solving)

📐 Step-by-Step Bond Energy Method

Equation: N₂H₄ + O₂ → N₂ + 2H₂O  |  Exothermic: bonds formed release 581 kJ/mol more than bonds broken.

Step 1: Calculate Energy Needed to Break Bonds (Reactants)
• 1 × (N–N) = X
• 4 × (N–H) = 4 × 391 = 1564 kJ/mol
• 1 × (O=O) = 1 × 498 = 498 kJ/mol
Total Bonds Broken = X + 1564 + 498 = (2062 + X) kJ/mol [1 Mark]
Step 2: Calculate Energy Released by Forming Bonds (Products)
• 1 × (N≡N) = 1 × 945 = 945 kJ/mol
• 2 × H₂O has 4 × (O–H) = 4 × 464 = 1856 kJ/mol
Total Bonds Formed = 945 + 1856 = 2801 kJ/mol [1 Mark]
Step 3: Set up the Energy Balance Equation
The question states that forming new bonds is 581 kJ/mol greater than breaking bonds:
Energy Formed − Energy Broken = 581
2801 − (2062 + X) = 581 [1 Mark]
(Alternatively: Energy Broken − Energy Formed = −581 kJ/mol)
Step 4: Solve for X
2801 − 2062 − X = 581
739 − X = 581
X = 739 − 581
X = 158 kJ/mol [1 Mark]

❌ Calculation Traps to Watch Out For

  • Counting O–H bonds as 2 instead of 4: Notice the big stoichiometric balancing number: 2 H–O–H means there are 2 molecules of water, giving 4 O–H bonds in total!
  • Bracket sign error: Subtracting (2062 + X) means both terms become negative: 2801 − 2062 − X . Students who write 2801 − 2062 + X end up with completely wrong answers.
  • Exothermic sign confusion: Because it is exothermic, ΔH is −581 . If using Broken − Formed = ΔH , you must equate to −581 , not +581 .

💡 Quick Self-Check

Is your answer physically sensible? Single covalent bonds between period 2 elements (like N–N or C–C) generally range between 150 to 350 kJ/mol. An answer of 158 kJ/mol fits right in line with expectations.

Topics

Chemistry · C2: Bonding, Structure and the Properties of Matter · C5: Energy Changes

Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.