AQA GCSE Chemistry Chemistry Paper 2 (Higher), June 2025: Question 1

11 marks · Standard Demand difficulty · Short Answer

Describe and analyze an experimental method to determine the mass and mean concentration of dissolved solids in different sea water samples.

Practise this question

Question

Exam paper showing Question 01 about an experiment to determine the mass of dissolved solids in sea water. The 6-step method describes weighing an empty evaporating basin, measuring 10.0 cm³ of sea water using a burette, evaporating the water, reweighing, and calculating the mass for samples A, B, C, and D. Questions 01.1 through 01.4 ask why a burette was chosen, the dependent variable, how to ensure complete evaporation, and how the dissolved mass was calculated. Table 1 lists the masses of dissolved solids: A is 0.35 g, B is 0.37 g, C is 0.33 g, and D is 0.34 g. Question 01.5 asks to calculate the mean concentration in g/dm³ using a given formula (5 marks). Question 01.6 asks why the samples contain different masses of solids.
Question text

01 A student investigated the mass of dissolved solids in sea water.

This is the method used.

1. Weigh an empty evaporating basin.

2. Measure 10.0 cm3 of sea water sample A into the evaporating basin

using a burette.

3. Heat the evaporating basin until all the water seems to have evaporated.

4. Weigh the evaporating basin and contents.

5. Calculate the mass of dissolved solids in the sample.

6. Repeat steps 1 to 5 with sea water samples B, C and D.

01.1 Why did the student use a burette rather than a measuring cylinder to measure

10.0 cm3 of each sample?

[1 mark]

01.2 What was the dependent variable in this investigation?

[1 mark]

01.3 Describe how the student could make sure all of the water had evaporated in step 3.

[2 marks]

01.4 How did the student calculate the mass of dissolved solids in each sea water sample?

[1 mark]

Table 1 shows the results.

Table 1

Sea water sample A B C D

Mass of dissolved solids in grams 0.35 0.37 0.33 0.34

01.5 Calculate the mean concentration of dissolved solids in 10.0 cm3 samples of

sea water A, B, C and D.

Use Table 1 and the equation:

3 mean mass of dissolved solids (g)

mean concentration of dissolved solids (g/dm ) = 3

volume of sample (dm )

Give your answer in g/dm3.

[5 marks]

Mean concentration = g/dm3

01.6 Suggest why sea water samples A, B, C and D contain different masses

of dissolved solids.

[1 mark]

Mark scheme

Show the mark scheme Mark scheme for Question 1 outlining 11 total marks: 01.1 accepts burette being more accurate or having higher resolution (1 mark); 01.2 accepts mass of dissolved solids (1 mark); 01.3 awards 2 marks for heating and reweighing until constant mass; 01.4 awards 1 mark for subtracting mass of empty basin from final mass; 01.5 provides 5 marks for finding the mean mass (0.3475 g), converting 10 cm³ to 0.01 dm³, and dividing to get 34.75 g/dm³ (along with alternative valid calculation pathways); 01.6 awards 1 mark for stating that samples were collected from different locations.

Question 1

AO /

Question Answers Extra information Mark

Spec. Ref.

01.1 (a burette is) more accurate allow (a burette has) a higher 1 AO3

(than a measuring cylinder) resolution 4.10.1.2

RPA8

ignore precise

AO /

Spec. Ref.

01.2 the mass of (dissolved) solids 1 AO1

4.10.1.2

RPA8

AO /

Spec. Ref.

01.3 reheat (the evaporating basin 1 AO3

and contents) 4.10.1.2

RPA8

(and reweigh) until constant 1

mass

allow for 2 marks

heat to constant mass

AO /

Spec. Ref.

01.4 subtract the mass of the (empty) allow subtract initial mass from 1 AO1

evaporating basin from the the final mass 4.10.1.2

mass of the evaporating basin RPA8

and contents (at the end of the

experiment)

AO /

Spec. Ref.

01.5 (allow mean mass =) (allow mean mass =) 1 AO2

0.35 + 0.37 + 0.33 + 0.34 1.39 4.3.2.5

44 4.10.1.2

RPA8

= 0.3475 (g) 1

(conversion 10 cm3 =) 0.01 dm3 1

0.3475 allow correct use of incorrectly 1

(mean concentration =)

0.01 determined mean mass

allow correct use of incorrect /

no conversion of volume

= 34.75 (g/dm3) allow 34.75 (g/dm3) correctly 1

rounded to at least 2 significant

figures

alternative approach 1

(conversion 10 cm3 =)

0.01 dm3 (1)

(concentrations =)

0.35 0.37 0.33 0.34 allow correct use of incorrect /

(1) no conversion of volume

0.01 0.01 0.01 0.01

= 35 37 33 34 (1)

(mean concentration =) (allow mean concentration =)

35 + 37 + 33 + 34 139

(1)

allow correct use of incorrectly

determined concentrations

= 34.75 (g/dm3) (1) allow 34.75 (g/dm3) correctly

rounded to at least 2 significant

figures

8 alternative approach 2 using

total mass and total volume

(total mass =

0.35 + 0.37 + 0.33 + 0.34 =)

1.39 (g) (1)

(total volume =

10 + 10 + 10 + 10 =)

40 cm3 (1)

(conversion 40 cm3 =)

0.04 dm3 (1)

1.39 allow correct use of incorrectly

(mean concentration =) (1)

0.04 determined total mass

allow correct use of incorrect /

no conversion of total volume

= 34.75 (g/dm3) (1) allow 34.75 (g/dm3) correctly

rounded to at least 2 significant

figures

AO /

Spec. Ref.

01.6 the samples were taken from 1 AO3

different places 4.10.1.2

Total Question 1 11

How to answer it

Determining Dissolved Solids in Sea Water (RPA 8)

📋 What this question tests

This question assesses practical skills from Required Practical Activity 8: Analysis and Purification of Water Samples. You must demonstrate an understanding of apparatus accuracy (burette vs measuring cylinder), identifying scientific variables, the classic technique of heating to constant mass, mass-by-difference calculations, unit conversions (cm³ to dm³), concentration calculations, and evaluating experimental differences between real-world samples.

Question 01.1

Apparatus Selection: Burette vs Measuring Cylinder

1 Mark

✅ Correct Answer

A burette is more accurate (or has a higher resolution) than a measuring cylinder.

❌ Common Errors

Writing that a burette is "more precise" or "more reliable". The mark scheme explicitly states: ignore precise. Accuracy or resolution are the required scientific terms.

Mark Allocation: [1 mark] for stating "more accurate" OR "higher resolution".

Question 01.2

Identifying the Dependent Variable

1 Mark

✅ Correct Answer

The mass of (dissolved) solids.

💡 Key Knowledge

  • Independent variable: What the experimenter changes (the sea water sample A, B, C, D).
  • Dependent variable: What is measured (the mass of dissolved solids remaining).
  • Control variable: What is kept the same (the volume of water used: 10.0 cm³).
Mark Allocation: [1 mark] for identifying mass of (dissolved) solids.

Question 01.3

Ensuring Complete Evaporation

2 Marks

✅ Correct Answer

  • Reheat the evaporating basin and contents [1 mark]
  • Reweigh until the mass is constant [1 mark]

Note: Stating "heat to constant mass" earns both marks directly.

🧠 Exam Technique: Key Laboratory Phrase

Whenever an exam asks how to ensure all water has evaporated or a thermal decomposition is complete, the standard response is always: "Heat, reweigh, and repeat until the mass remains constant."

❌ Common Errors

Saying "look closely to see if there is no liquid left" or "heat it for a longer time". Visual inspection does not prove dryness because trapped moisture cannot be seen.

Mark Allocation: [1 mark] for reheating. [1 mark] for reweighing until mass remains constant.

Question 01.4

Determining Mass of Dissolved Solids

1 Mark

✅ Correct Answer

Subtract the mass of the empty evaporating basin from the mass of the evaporating basin and contents at the end.

(Or: "Subtract initial mass from final mass")

💡 Key Knowledge

This method is known as weighing by difference:

Mass of dissolved solid = (Basin + solid) − (Empty basin)

Mark Allocation: [1 mark] for correctly describing subtraction of initial/empty basin mass from final basin + residue mass.

Question 01.5

Calculation: Mean Concentration in g/dm³

5 Marks

📐 Step-by-Step Calculation

Given Data:

  • Sample masses: A = 0.35 g, B = 0.37 g, C = 0.33 g, D = 0.34 g
  • Volume of sample = 10.0 cm³
  • Formula: mean concentration (g/dm³) = mean mass of dissolved solids (g) ÷ volume of sample (dm³)

Step 1: Calculate the mean mass of dissolved solids

Total mass = 0.35 + 0.37 + 0.33 + 0.34 = 1.39 g [1 mark]

Mean mass = 1.39 ÷ 4 = 0.3475 g [1 mark]

Step 2: Convert volume from cm³ to dm³

To convert cm³ to dm³, divide by 1000:

Volume = 10.0 ÷ 1000 = 0.01 dm³ [1 mark]

Step 3: Calculate the mean concentration

Mean concentration = 0.3475 g ÷ 0.01 dm³ [1 mark]

Mean concentration = 34.75 g/dm³ [1 mark]

(Allow rounding to at least 2 significant figures, e.g. 34.8 or 35 g/dm³)

🧠 Alternative Method (Equal Marks)

Calculate total mass and total volume:

  • Total mass = 1.39 g
  • Total volume = 4 × 10.0 cm³ = 40.0 cm³ = 0.04 dm³
  • Concentration = 1.39 ÷ 0.04 = 34.75 g/dm³

❌ Calculation Traps

  • Forgetting the volume conversion: Dividing by 10 instead of 0.01 gives an answer 1000 times too small (0.03475 g/dm³).
  • Arithmetic slips: Forgetting to divide by 4 when calculating the mean mass.
Mark Allocation: [1] Mean mass expression (1.39 / 4) • [1] Mean mass value (0.3475 g) • [1] Volume conversion (0.01 dm³) • [1] Substitution into equation • [1] Final answer (34.75 g/dm³).

Question 01.6

Explaining Differences in Results

1 Mark

✅ Correct Answer

The sea water samples were taken from different places / locations (or different depths / different sources).

❌ Common Errors

Blaming "human error" or "student did not heat properly". The question asks why the sea water samples themselves contain different masses of solids, not why experimental error occurred.

Mark Allocation: [1 mark] for stating samples were collected from different locations/places.

Topics

Chemistry · Required Practicals · Required Practicals · C3: Quantitative Chemistry · C10: Using Resources

Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 2 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.