AQA GCSE Combined Science: Trilogy Chemistry Paper 1 (Higher), 2018: Question 1
8 marks · Standard Demand difficulty · Short Answer
Answer questions about the electrolysis of copper chloride solution, including products at the electrodes, reactivity of copper, and calculations using experimental results and concentration data.
Practise this questionQuestion
Question text
01 This question is about electrolysis.
A student investigates the mass of copper produced during electrolysis of
copper chloride solution.
Figure 1 shows the apparatus.
Figure 1
01.1 Which gas is produced at the positive electrode (anode)?
[1 mark]
Tick one box.
carbon dioxide
chlorine
hydrogen
oxygen 3
01.2 Copper is produced at the negative electrode (cathode).
What does this tell you about the reactivity of copper?
[1 mark]
Tick one box.
Copper is less reactive than hydrogen
Copper is less reactive than oxygen
Copper is more reactive than carbon
Copper is more reactive than chlorine
Table 1 shows the student’s results.
Table 1
Total mass of copper produced in mg
Time in mins Experiment 1 Experiment 2 Experiment 3 Mean
10.60 0.58 0.62 0.60
21.17 1.22 1.21 1.20
42.40 2.41 2.39 2.40
53.02 X 3.01 3.06
01.3 Determine the mean mass of copper produced after 3 minutes.
[1 mark]
4 Mass = mg
01.4 Calculate the mass X of copper produced in Experiment 2 after 5 minutes.
Use Table 1 on page 3
[2 marks]
Mass X = mg
The copper chloride solution used in the investigation contained 300 grams per dm3 of
01.5
solid CuCl dissolved in 1 dm3 of water.
The student used 50 cm3 of copper chloride solution in each experiment.
Calculate the mass of solid copper chloride used in each experiment.
[3 marks]
Mass = g
Mark scheme
Show the mark scheme
AO /
Question Answers Extra information Mark
Spec. Ref.
01.1 chlorine 1 AO2
5.4.3.4
01.2 copper is less reactive than 1 AO2
hydrogen 5.4.3.4
01.3 1.8 (mg) allow an answer in range 1.7‒ 1 AO3
1.9 5.4.3.4
01.4 an answer of 3.15 (mg) scores 2 AO2
marks 5.4.3.4
3.02 + 3.01 + x allow any other suitable method 1
= 3.06
3.15 (mg) 1
if no other mark awarded allow
9.18 for 1 mark
01.5 an answer of 15 (g) scores 3 AO2
marks 5.3.2.5
50 1
or or 0.05
1000 20
(0.05) × 300 the second mark is dependent 1
on the first mark being scored
15 (g) 1
or
300 3
or or 0.03 (1)
1000 10
(0.3) × 50 (1) the second mark is dependent
on the first mark being scored
15 (g) (1)
if no other mark awarded allow
150 or 15 000 for 1 mark
Total 8
How to answer it
Electrolysis of Copper Chloride
This question checks your knowledge of electrolysis, including which products form at each electrode, how reactivity affects what is discharged, and how to use tables of results and simple proportions to calculate means and scaled masses. You need to read data carefully, use the correct units, and show clear calculation steps.
Question overview
Electrolysis of copper chloride solution
The student uses inert carbon electrodes in copper chloride solution and measures the mass of copper formed. The question is worth 8 marks in total and mixes recall with simple calculations.
Part (a) 01.1 — Gas produced at the positive electrode (anode)
✅ Correct answer
chlorine
💡 Key knowledge
- In electrolysis of copper chloride solution, chloride ions go to the anode.
- At the anode, chloride ions are oxidised to form chlorine gas.
- For AQA GCSE, with aqueous copper chloride and inert electrodes, the anode product is chlorine.
🧠 Exam technique
- Match the electrode name to the correct ion/product.
- The positive electrode is the anode.
- If you are unsure, think: chloride → chlorine.
❌ Common errors
- Choosing oxygen because students confuse aqueous electrolysis with water splitting.
- Mixing up anode and cathode.
- Writing chloride instead of chlorine — the mark is for the gas formed.
Part (b) 01.2 — What copper being formed at the cathode tells you about reactivity
✅ Correct answer
copper is less reactive than hydrogen
💡 Key knowledge
- At the cathode, positive ions are reduced.
- If copper is deposited from solution, copper ions are being discharged instead of hydrogen.
- This shows copper is less reactive than hydrogen.
🧠 Exam technique
This is a reactivity series idea. If a metal is extracted during electrolysis from an aqueous solution, it means the metal is less reactive than hydrogen.
❌ Common errors
- Picking a statement about oxygen, carbon, or chlorine — these are not relevant here.
- Saying copper is more reactive because it is “being produced”. The correct comparison is with hydrogen.
Part (c) 01.3 — Mean mass of copper after 3 minutes
✅ Correct answer
1.8 mg
📐 Calculation
Use the pattern in the table:
- At 1 min, mean = 0.60 mg
- At 2 min, mean = 1.20 mg
- At 4 min, mean = 2.40 mg
The mean increases by about 0.60 mg per minute, so at 3 minutes:
1.20 + 0.60 = 1.80 mg
🧠 Exam technique
- For a missing mean, use the trend in the data if the table is regular.
- Write the answer with the correct unit: mg.
- Marks are usually for the final value, so a sensible estimate earns credit.
❌ Common errors
- Writing 1.8 g instead of 1.8 mg.
- Giving 1.2 mg because it is the previous table entry.
- Forgetting that the question asks for the mean, not one experiment value.
Part (d) 01.4 — Calculate X in Experiment 2 after 5 minutes
✅ Correct answer
X = 3.15 mg
📐 Calculation step-by-step
- Use the mean formula:
(3.02 + 3.01 + X) ÷ 3 = 3.06
- Multiply both sides by 3:
3.02 + 3.01 + X = 9.18
- Add the known results:
6.03 + X = 9.18
- Subtract:
X = 9.18 - 6.03 = 3.15 mg
🧠 Exam technique
- Always use the mean = total ÷ number of values idea.
- Check that all values are in the same unit before calculating.
- The mark scheme allows a full-mark method if the final answer is correct, even if you use another sensible approach.
❌ Common errors
- Adding the numbers but forgetting to divide by 3.
- Using 3.06 as the answer instead of the missing value.
- Arithmetic slips: 3.02 + 3.01 = 6.03, not 6.03? Double-check carefully.
- Writing the final answer without mg.
📐 Why 3.15 mg gets 2 marks
The mark scheme gives:
- 1 mark for setting up the correct mean equation
- 1 mark for the correct final value of 3.15 mg
This means even if your working is slightly untidy, a correct final answer can still secure full credit.
Part (e) 01.5 — Mass of solid copper chloride used in 50 cm³
✅ Correct answer
15 g
📐 Calculation step-by-step
Given: 300 g per dm³
Need: mass in 50 cm³
- Convert volume to dm³:
50 cm³ = 50 ÷ 1000 = 0.05 dm³
- Use proportion:
0.05 × 300 = 15
- State the final answer with unit:
15 g
💡 Key knowledge
- 1 dm³ = 1000 cm³
- Concentration in g per dm³ means “grams in 1 dm³”.
- To find the mass in a smaller volume, multiply the concentration by the fraction of a dm³.
🧠 Exam technique
- Always convert volumes before multiplying.
- Use ratio thinking: 50 cm³ is 1/20 of 1000 cm³, so the mass is 1/20 of 300 g.
- Show the unit in the final line: g, not dm³ or cm³.
❌ Common errors
- Using 50 ÷ 1000 but then forgetting to multiply by 300.
- Confusing cm³ with dm³.
- Writing 0.15 g or 150 g from place-value slips.
- Leaving out the unit: the answer must be 15 g.
📐 Alternative method accepted by the mark scheme
You could also scale the other way:
300 g in 1000 cm³ → 0.3 g in 1 cm³
0.3 × 50 = 15 g
The examiner allows any suitable method as long as the proportion is correct and the final answer is 15 g.
Examiner insight: what earned marks
💡 What top answers did well
- Used the exact product name: chlorine.
- Linked copper deposition to the reactivity series: less reactive than hydrogen.
- Showed working clearly in calculations, especially for the missing value and the mass from concentration.
- Included correct units: mg and g.
❌ Where students lost marks
- Wrong gas at the anode, especially oxygen.
- Confusing reactivity with charge or electrode polarity.
- Arithmetic slips in the mean calculation.
- Not converting cm³ to dm³ in the concentration question.
Quick revision summary
💡 Remember
- Anode = positive, cathode = negative
- Chloride ions → chlorine gas
- Copper deposited means copper is less reactive than hydrogen
- Mean = total ÷ number of values
- 1 dm³ = 1000 cm³
🧠 Full-marks habit
Always write the exact scientific term, show clear working, and finish with the correct unit. That is the simplest way to secure the marks in this question.
Topics
Chemistry · C3: Quantitative Chemistry · C4: Chemical Changes
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 1 (Higher), 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.