AQA GCSE Combined Science: Trilogy Chemistry Paper 1 (Higher), 2018: Question 6

12 marks · Standard Demand difficulty · Short Answer

Identify the products of thermal decomposition of Group 2 carbonates and use relative formula mass and a graph of gas volume against mass heated to calculate a metal identity, gradient, and the relative formula mass of another carbonate.

Practise this question

Question

A chemistry exam question worth 12 marks about Group 2 metal carbonates thermally decomposing to form a metal oxide and a gas. Part 06.1 asks for the formula of each product when calcium carbonate, CaCO3, is heated; part 06.2 gives a relative formula mass of 197 and atomic masses C = 12 and O = 16, then asks the student to calculate the relative atomic mass of the Group 2 metal and name it. Figure 8 is a straight-line graph of volume of gas in cubic centimetres on the y-axis against mass of Group 2 carbonate heated in grams on the x-axis, running approximately from the origin to about 2.0 g and 330 cm3; part 06.3 asks for the gradient and unit, and part 06.4 states that 24 dm3 of gas is produced when one mole of Group 2 carbonate is heated and asks for the relative formula mass of carbonate W using the graph.
Question text

06 Group 2 metal carbonates thermally decompose to produce a metal oxide and a gas.

06.1 Give the formula of each product when calcium carbonate (CaCO3) is heated.

[2 marks]

and

06.2 The relative formula mass (Mr) of a Group 2 metal carbonate is 197

Relative atomic masses (Ar): C = 12 O = 16

Calculate the relative atomic mass (Ar) of the Group 2 metal in the metal carbonate.

Name the Group 2 metal.

[3 marks]

Relative atomic mass (Ar) =

Metal

Figure 8 shows the volume of gas produced when a different Group 2

carbonate, W, is heated.

Figure 8

06.3 Calculate the gradient of the line in Figure 8

Give the unit.

[3 marks]

Gradient

15 Unit

24 dm3 of gas is produced when one mole of a Group 2 carbonate is heated.

06.4

Determine the relative formula mass of the Group 2 carbonate W.

Use Figure 8

[4 marks]

Relative formula mass (Mr) =

Mark scheme

Show the mark scheme The mark scheme is a table with columns for question, answers, extra information, mark, and AO/specification references. For 06.1 it awards CaO and CO2; for 06.2 it shows calculating the carbonate part as 60, subtracting from 197 to get 137, and naming barium. For 06.3 it credits measuring rise over run from the graph and gives a gradient of about 167 cm3/g, allowing 160 to 174; for 06.4 it reads about 1.45 g for 240 cm3 from the graph, uses the ratio 24000/240 = 100, then calculates about 145 for the relative formula mass, allowing a range of 140 to 150 or an equivalent method using the gradient.

AO /

Question Answers Extra information Mark

Spec. Ref.

06.1 CaO either order 1 AO1

ignore names 5.3.1.3

CO2 1

06.2 an answer of 137 scores the 2 AO2

calculation marks 5.3.1.2

5.3.1.3

[12 + (3 × 16)] 1

5.1.1.5

or 60

(197 − 60 =) 137

barium or Ba barium or Ba without working 1

scores this mark

06.3 an answer of 160‒174 scores AO2

the 2 calculation marks 5.3.1.2

5.3.1.3

(working) Y increase and X y- 80‒ 162‒ 248‒ 330‒ 1

increase measured from graph axis 85 170 252 335

ΔY x-

and substitution into 0.5 1.0 1.5 2.0

axis

ΔX

160‒ 162‒ 165‒ 165‒

=

170 170 168 168

(answer) 167 allow answer in range 160‒174 1

3 allow cm3 g–1

(units) cm /g 1

if no other mark awarded allow 1

ΔX

mark for the inverse ( )

ΔY

or 0.006

AO /

Spec. Ref.

06.4 an answer of 140‒150 scores 4 AO3

marks 5.3.1.2

5.3.1.3

an answer of 0.14‒0.15 scores

3 marks

(from graph)

volume to 240 cm3 mass allow answer based on any 1

= 1.45 g reading from the graph

(eg 250 cm3 = 1.5 g) 14

1 24 000 allow ratio from their volume 1

ratio is (ie )

100 240

24 000

eg

100 × 1.45 24 000 1

� � × 1.5

allow range 140‒150 1

or

allow method using answer from

question 06.3

y (rearrangement of y = mx where

x = (1) m = answer from question 06.3)

m

24 (dm3) to 24 000 (cm3) (1)

24 000

(1)

answer from question 06.3

144 (1) allow range 140‒150

Total 12

How to answer it

Thermal Decomposition of a Group 2 Carbonate

What this question tests

You need to know the products of thermal decomposition, use relative formula mass calculations, read a graph accurately, calculate a gradient, and use proportional reasoning to scale from a graph to a whole mole.

Full marks come from: correct formulas, correct arithmetic, correct graph reading, correct units, and clear working.

Overall mark focus: 12 marks

Question 06 overview

Group 2 metal carbonates decompose on heating to give a metal oxide and carbon dioxide: metal carbonate → metal oxide + carbon dioxide .

This question then uses the graph to estimate the identity of an unknown carbonate, W, from its gas production.

06.1 Give the formula of each product when calcium carbonate (CaCO₃) is heated. [2 marks]

✅ Correct answers

  • CaO
  • CO₂

Marks: 1 for each correct product formula. Either order is fine.

💡 Key knowledge

  • Group 2 carbonates decompose when heated.
  • The metal part becomes the metal oxide.
  • The carbonate part gives carbon dioxide.

Equation: CaCO₃ → CaO + CO₂

🧠 Exam technique

  • Use correct symbols and formulas, not names.
  • Make sure the oxygen count is correct: carbonate turns into oxide + CO₂.

❌ Common errors

  • Writing CaCO₃ again instead of the products.
  • Giving CaCO or CO instead of CO₂.
  • Writing names only — the mark scheme wants formulas.

06.2 The relative formula mass (Mᵣ) of a Group 2 metal carbonate is 197. [3 marks]

Given: Aᵣ: C = 12, O = 16

📐 Calculations: step-by-step

  1. Work out the mass of the carbonate part, CO₃:
    12 + (3 × 16) = 60
  2. Subtract this from the total Mᵣ:
    197 − 60 = 137
  3. The Group 2 metal has relative atomic mass 137, so the metal is barium.

The mark scheme says an answer of 137 scores both calculation marks, then barium / Ba scores the final mark.

✅ Correct answers

  • Relative atomic mass = 137
  • Metal = barium (or Ba)

💡 Key knowledge

  • A carbonate contains CO₃ , so its formula mass includes 1 carbon and 3 oxygens.
  • For a Group 2 carbonate, the formula is MCO₃ .
  • So: Ar of metal = Mr of carbonate − Mr of CO₃ .

❌ Common errors

  • Using 12 + 16 instead of 12 + (3 × 16).
  • Forgetting to subtract the carbonate mass from 197.
  • Not naming the metal after finding 137.
  • Saying Ba without working is allowed for the name mark, but you need working for the calculation marks.

06.3 Calculate the gradient of the line in Figure 8. Give the unit. [3 marks]

📐 Calculations: step-by-step

  1. Choose two clear points from the line. Example from the graph: (0, 0) and (2.0, 330) or similar points on the line.
  2. Use the gradient formula:
    gradient = change in y ÷ change in x
  3. Substitute values:
    gradient = 330 ÷ 2.0 = 165
  4. Suitable answers from the mark scheme are in the range 160–174, with the expected answer about 167.
  5. Unit:
    cm³/g

✅ Correct answers

  • Gradient = 167 (acceptable range 160–174)
  • Unit = cm³/g or cm³ g⁻¹

If no other mark is awarded, the inverse gradient Δx/Δy or 0.006 can earn 1 mark only.

🧠 Exam technique

  • Use points far apart to reduce rounding error.
  • Read the axes carefully: x-axis is mass of carbonate (g), y-axis is volume of gas (cm³).
  • State the unit clearly: gradient means y divided by x, so the unit is cm³ per g.

❌ Common errors

  • Using the wrong axis order: mass ÷ volume instead of volume ÷ mass.
  • Forgetting the unit or writing just cm³.
  • Using points that are too close together and getting an inaccurate gradient.
  • Missing the idea that marks can still be awarded for a correct method even if the final number is slightly off.

06.4 24 dm³ of gas is produced when one mole of a Group 2 carbonate is heated. Determine the relative formula mass of the Group 2 carbonate W. [4 marks]

💡 Key knowledge

  • At room temperature, 1 mole of gas = 24 dm³.
  • From the graph, you need the mass of W that gives 240 cm³ of gas, then scale up to 24 dm³.
  • Remember: 24 dm³ = 24 000 cm³.

📐 Calculations: step-by-step

  1. Read from the graph:
    When volume = 240 cm³, mass of carbonate ≈ 1.45 g.
  2. Use proportional scaling:
    24 000 ÷ 240 = 100
  3. Multiply the mass by 100:
    1.45 × 100 = 145
  4. So the relative formula mass of carbonate W is about 145.

The mark scheme accepts answers in the range 140–150. It also allows a method using your gradient answer from 06.3.

✅ Correct answer

Relative formula mass (Mᵣ) = 145

Acceptable range: 140–150

🧠 Exam technique

  • Convert units carefully: 24 dm³ = 24 000 cm³.
  • Show the ratio clearly. Examiners reward a correct proportional method.
  • If you use the gradient method, rearrange y = mx to x = y ÷ m .

❌ Common errors

  • Using 24 instead of 24 000.
  • Reading the graph inaccurately.
  • Forgetting to scale from the graph reading to one mole of gas.
  • Mixing up whether the graph gives gas volume per gram or grams per gas volume.

Examiner insight: what got marks?

💡 What top responses did

  • Gave precise formulas in 06.1: CaO and CO₂.
  • Showed clear subtraction in 06.2 and identified barium.
  • Used a sensible pair of points for the gradient in 06.3 and included units.
  • Converted 24 dm³ to 24 000 cm³ in 06.4 and used proportional scaling correctly.

❌ Where students lost marks

  • Wrong product formula in 06.1.
  • Arithmetic errors in calculating CO₃ mass.
  • Gradient given without unit, or with the axes reversed.
  • Not converting dm³ to cm³ before scaling in 06.4.

🧠 Quick checklist for full marks

  • Products? Oxide + CO₂
  • Carbonate mass? 12 + 3×16 = 60
  • Metal mass? 197 − 60 = 137
  • Gradient? rise ÷ run and include units
  • Scaling? 24 dm³ = 24 000 cm³

Topics

Chemistry · C1: Atomic Structure and the Periodic Table · C3: Quantitative Chemistry · C5: Energy Changes

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 1 (Higher), 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.