AQA GCSE Combined Science: Trilogy Chemistry Paper 1 (Higher), 2018: Question 8

10 marks · Standard Demand difficulty · Short Answer

Answer questions about reactions of iron and magnesium with hydrochloric acid and iron chloride, including naming a product, separating unreacted iron, calculating the mass of iron produced, and identifying the species reduced with a reduction half-equation.

Practise this question

Question

The question page is headed 'This question is about iron' and contains four parts labelled 08.1 to 08.4. Part 08.1 states that iron reacts with dilute hydrochloric acid to produce iron chloride solution and one other product, then asks to name the other product for 1 mark; part 08.2 asks how any unreacted iron can be separated from the mixture for 1 mark. Part 08.3 shows the balanced symbol equation '3 Mg + 2 FeCl3 → 2 Fe + 3 MgCl2', gives 0.120 g of magnesium reacting with excess iron chloride solution and relative atomic masses Mg = 24 and Fe = 56, then asks for the mass of iron produced in mg for 5 marks with working space. Part 08.4 repeats the same equation and asks which species is reduced, including the half equation for the reduction, for 3 marks.
Question text

08 This question is about iron.

Iron reacts with dilute hydrochloric acid to produce iron chloride solution and one

other product.

08.1 Name the other product.

[1 mark]

08.2 Suggest how any unreacted iron can be separated from the mixture.

[1 mark]

Magnesium reacts with iron chloride solution.

3 Mg + 2 FeCl3 2 Fe + 3 MgCl2

08.3 0.120 g of magnesium reacts with excess iron chloride solution.

Relative atomic masses (Ar): Mg = 24 Fe = 56

Calculate the mass of iron produced, in mg

[5 marks]

Mass of iron =20 mg

08.4 Explain which species is reduced in the reaction between magnesium and

iron chloride.

3 Mg + 2 FeCl3 2 Fe + 3 MgCl2

Your answer should include the half equation for the reduction.

[3 marks]

Mark scheme

Show the mark scheme The mark scheme is a table with columns for question number, answers, extra information, mark, and AO/specification reference. For 08.1 it accepts hydrogen or H2; for 08.2 it accepts filtration or filter, with magnet or decant also allowed. For 08.3 it awards method marks for calculating moles of magnesium from 0.12 divided by 24, using the 2 to 3 stoichiometric ratio to find moles of iron, multiplying by 56 to find mass, and converting 0.1866 g to 187 mg; alternative proportional methods are also shown. For 08.4 it identifies Fe3+ as the species reduced, states reduction is gain of electrons or a change in oxidation state from +3 to 0, and gives the half-equation 'Fe3+ + 3e- → Fe'.

AO /

Question Answers Extra information Mark

Spec. Ref.

08.1 hydrogen or H2 allow hydrogen gas 1 AO1

5.4.2.1

ignore H without the 2 subscript

08.2 filtration / filter allow magnet or decant 1 AO1

5.1.1.2

ignore heating

08.3 an answer of 185‒190 (mg) AO2

scores 5 marks 5.3.2.2

an answer of 0.185‒0.19 scores

4 marks

0.12

(Mg) or 0.005 (moles) mark is for ÷ by 24 1

(Fe) × 0.005 = 0.00333(moles) mark is for × 1

(mass Fe) = 0.00333 × 56 mark is for × 56 1

= 0.1866 (g) 1

= 187 (mg) 1

an answer of 280 (mg) scores 4

marks

an answer of 0.280 scores 3

marks (no ratio from equation)

184 scores 0 [=(3×24) + (2×56)]

OR

0.12

(Mg) = (1)

(3 × 24 =) 72

= 0.00166 or (moles) (1)

(mass of Fe) = 0.00166

or × 112 (2 × 56) (1)

= 0.1866 (g) (1)

187 (mg) (1)

AO / 20

Spec. Ref.

08.3 OR

cont.

72 g Mg 112g Fe (1)

1 g Mg or 1.56 g Fe (1)

0.12 g Mg × 0.12 (1)

= 0.1866 (g) (1)

= 187 (mg) (1)

08.4 Fe3+ 1 AO2

(because) reduction is gain of allow change in oxidation state / 1 AO1

electrons (+)3 to 0

Fe3+ + 3e(-) Fe 1 AO2

5.4.1.2

5.4.1.4

Total 10

How to answer it

Iron reactions with hydrochloric acid and displacement
What this question tests
This question checks whether you can identify products of a metal + acid reaction, suggest a separation method, use a balanced equation to do a mass calculation, and explain reduction in terms of electron gain and oxidation state.

Question overview

Key skills

  • Recall of common reaction products
  • Separation methods for mixtures
  • Mole ratio calculations from equations
  • Reduction as gain of electrons

How marks are awarded

  • 1-mark recall answers need the exact correct idea
  • Calculation marks are step-by-step: method marks + final answer mark
  • In the redox part, you need the species, the reason, and the half-equation
Part 08.1

08.1 Name the other product.

✅ Correct answer

Hydrogen or H₂

1 mark for the correct product. “Hydrogen gas” is also accepted.

💡 Key knowledge

  • Metal + acid → salt + hydrogen
  • Here, iron reacts with hydrochloric acid to form iron chloride solution and hydrogen

❌ Common errors

  • Writing just H instead of H₂
  • Giving oxygen or water
  • Forgetting that the question asks for the other product
Part 08.2

08.2 Suggest how any unreacted iron can be separated from the mixture.

✅ Correct answer

Filtration / use a filter

1 mark. The mark scheme also accepts magnet or decant.

💡 Key knowledge

  • Unreacted iron is a solid
  • The product is a solution, so a solid-liquid separation method is needed
  • If using filtration, the iron stays as residue in the filter paper

🧠 Exam technique

  • Give the method name, not a vague description
  • If you say magnet, it works because iron is magnetic
  • “Heat it” is not needed and does not score here

❌ Common errors

  • Saying evaporation — that would remove the liquid, not separate the iron
  • Writing a long explanation but not naming the method
  • Thinking the iron is dissolved in the solution
Part 08.3

08.3 Calculate the mass of iron produced, in mg.

📐 Calculations: step-by-step

  1. Find moles of magnesium:
    moles = mass ÷ Ar = 0.120 ÷ 24 = 0.005 mol
  2. Use the equation ratio:
    3 Mg : 2 Fe
    So moles of Fe = 0.005 × 2/3 = 0.00333 mol
  3. Find mass of iron in grams:
    mass = moles × Ar = 0.00333 × 56 = 0.1866 g
  4. Convert to mg:
    0.1866 g = 187 mg
Final answer: 187 mg

✅ Correct answer

187 mg

  • Acceptable range in the mark scheme: 185–190 mg for full marks
  • Answers like 0.187 g are mathematically correct but the question asks for mg

💡 Key knowledge

  • Equation: 3 Mg + 2 FeCl₃ → 2 Fe + 3 MgCl₂
  • Use the balanced equation to get the reacting ratio
  • Relative atomic masses: Mg = 24, Fe = 56

🧠 Exam technique

  • Always show each stage clearly for method marks
  • Use the ratio from the balanced equation, not just the masses
  • Keep units consistent: g at the start, then convert to mg at the end
  • Round sensibly: 0.1866 g → 0.187 g → 187 mg

❌ Common errors

  • Ignoring the 3:2 ratio and using a 1:1 ratio
  • Using 24 and 56 as if they were the ratio directly
  • Forgetting to convert grams to milligrams
  • Writing 184 mg from a wrong calculation path — the mark scheme gives 0 marks for this

Alternative method that also scores full marks

Use the mass ratio from the equation:

72 g Mg → 112 g Fe

So 0.12 g Mg → (112 ÷ 72) × 0.12 = 0.1866 g = 187 mg

This method gets the same full credit if the working is clear.
Part 08.4

08.4 Explain which species is reduced in the reaction between magnesium and iron chloride.

✅ Correct answer

Fe³⁺ is reduced.

Reduction is gain of electrons:

Fe³⁺ + 3e⁻ → Fe

3 marks: species, explanation, and half-equation.

💡 Key knowledge

  • Reduction means gain of electrons
  • Fe³⁺ gains 3 electrons to become Fe
  • Oxidation state changes from +3 to 0

🧠 Exam technique

  • Name the ion: Fe³⁺, not just “iron”
  • Link the answer to electron gain
  • Write the half-equation exactly and balance charge

❌ Common errors

  • Saying magnesium is reduced — magnesium is actually oxidised
  • Writing Fe → Fe³⁺ which is oxidation, not reduction
  • Forgetting the 3 electrons in the half-equation

How the marks are awarded here

  • 1 mark: correct species, Fe³⁺
  • 1 mark: explains reduction as gain of electrons or change in oxidation state (+3 to 0)
  • 1 mark: correct half-equation Fe³⁺ + 3e⁻ → Fe

Quick revision summary

Essential facts

  • Iron + acid → salt + hydrogen
  • Unreacted iron can be separated by filtration or a magnet
  • Use balanced equations for mole ratios
  • Reduction = gain of electrons

Top-mark habits

  • Use the equation ratio, not guesswork
  • Show units throughout
  • Write the half-equation neatly and balanced
  • Convert g to mg at the end when asked

Topics

Chemistry · C3: Quantitative Chemistry · C4: Chemical Changes

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 1 (Higher), 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.