AQA GCSE Combined Science: Trilogy Biology Paper 1 (Higher), 2019: Question 3

13 marks · Standard Demand difficulty · Extended Answer

Interpret and use data from a potometer investigation to explain transpiration, calculate rate of water uptake, plot results and predict the effect of different environmental conditions.

Practise this question

Question

The question page shows a potometer diagram labelled with a plant shoot, a reservoir of water, a tap, a capillary tube containing an air bubble, water, and a millimetre scale from 0 to 100 mm. Text explains that the rate of water uptake is the distance the air bubble moves in a given time, followed by a method using moist air at 25 degrees Celsius, repositioning the bubble to 0 mm, recording bubble position every minute for 5 minutes, and repeating in different conditions. A table lists investigations A: moist air at 25 degrees Celsius, B: dry air at 15 degrees Celsius, and C: dry air at 25 degrees Celsius; later parts ask how to reset the bubble, why narrow tubing is used, calculate rate from a graph for investigation A, plot table data for investigation B on a graph of bubble position against time, draw a line for investigation C, and explain why the bubble would not move in the dark. Figure 4 is a graph with time in minutes on the x-axis from 0 to 5 and position of air bubble in mm on the y-axis up to just over 100, showing investigation A as a straight line from the origin to about 66 mm at 5 minutes.
Question text

03 A student used a potometer to investigate the rate of water uptake in a plant shoot.

Figure 3 shows a potometer.

Figure 3

As the shoot takes in water the air bubble moves.

The rate of water uptake is the distance the air bubble moves in a given time.

This is the method used.

1. Place the potometer in moist air at 25 °C

2. Position the air bubble at 0 mm in the capillary tube.

3. Record the position of the air bubble in the capillary tube every minute

for 5 minutes. 11

4. Repeat steps 2 and 3 with the potometer in different conditions.

Table 3 shows the conditions used.

Table 3

Investigation Conditions

A Moist air at 25 °C

B Dry air at 15 °C

C Dry air at 25 °C

03.1 After investigation A the air bubble had moved part way along the capillary tube.

*10* Suggest how the student moved the air bubble back to 0 mm for the start of

investigation B.

[1 mark]

03.2 Capillary tubing is very narrow.

Explain why narrow tubing was used.

[2 marks]

Figure 4 shows the results for investigation A.

Figure 4

The cross-sectional area of the capillary tube was 0.8 mm2

03.3

Calculate the rate of water uptake for investigation A in mm3/min

[3 marks]

13 Rate = mm3/min

03.4 Table 4 shows the results from investigation B.

Table 4

Time in minutes Position of air bubble in mm

*12* 0 0

2 16

3 22

4 30

5 42

Plot the data from Table 4 on Figure 4.

You should:

• draw a line of best fit

• label the line B.

[3 marks]

03.5 Investigation C was carried out in dry air at 25 °C

Draw a line on Figure 4 to show the results you would expect for investigation C.

Label the line C.

[1 mark]

03.6 The investigations were carried out in daylight.

The air bubble would not move if the investigations were done in the dark.

Explain why.

[3 marks]

Mark scheme

Show the mark scheme The mark scheme is a table with columns for question number, answers, extra information, mark, and AO/specification reference. It gives: 03.1 opening and closing the tap so water enters from the reservoir; 03.2 narrow tubing makes the air bubble move further or faster for a given time so resolution is improved; 03.3 reads 66 over 5 or 13.2 mm per minute from the graph, then multiplies by 0.8 to give 10.56 mm cubed per minute; 03.4 awards marks for correctly plotted points and a suitable line of best fit; 03.5 expects a straight line from 0,0 steeper than A for investigation C; 03.6 credits no photosynthesis in the dark, so stomata close and there is little or no transpiration. The total shown is 13 marks.

AO /

Question Answers Extra information Mark

Spec. Ref.

AO3

03.1 opened and closed the tap (so allow opened the tap (carefully / 1 4.2.3.2

water enters from reservoir) gently)

03.2 air bubble moves further (in a allow air bubble moves faster 1 AO3

given time) 4.2.3.2

(so) resolution is improved allow it is easier to see a small 1

change (in volume)

ignore is easier to measure

unqualified

allow measurements are more

accurate

ignore to make test more

accurate

ignore references to precision or

validity

an answer of 10.56 (mm3/min) AO2

03.3 scores 3 marks 4.2.3.2

66 allow tolerance of ± ½ square 1

5 allow full marks from calculation

from other correct pairs of

or readings

13.2 (mm/min) allow value in range 13 to 13.4

for only

ignore or 12.6

13.2 × 0.8 allow their calculated value in the 1

range from 12 to 14 x 0.8

10.56 (mm3/min) allow 10.6 or 11 1

AO2

03.4 points plotted correctly allow +/- ½ a square 2 4.2.3.2

allow 1 mark for 4/5 correct plots

10 suitable line of best fit 1

AO3

03.5 straight line starting at 0,0 with a 1 4.2.3.2

steeper gradient than A

03.6 no photosynthesis allow plants need light for 1 AO1

photosynthesis

(so) stomata closed (as no 1 AO2

carbon dioxide needed)

(so) no transpiration allow very little transpiration or 1 AO2

little water lost 4.2.3.2

4.4.1.2

Total 13

How to answer it

Potometer and Water Uptake

AQA GCSE Combined Science: Trilogy
What this question tests

Using a potometer to measure transpiration indirectly, understanding why the apparatus is set up the way it is, reading and using graph data, calculating rate, plotting points accurately, and explaining how light affects transpiration.

Question overview

Investigating the rate of water uptake in a plant shoot using a potometer

This question is mainly about practical biology and data skills. You need to: explain a simple method, understand why certain features of the apparatus are needed, calculate a rate from a graph, and compare different environmental conditions.

Part (a) 03.1 — Resetting the bubble for investigation B

✅ Correct answer

Open and close the tap so that water from the reservoir moves the air bubble back to 0 mm.

💡 Key knowledge

  • The reservoir contains water that can be used to push the bubble back.
  • This lets each investigation start from the same position.

🧠 Exam technique

For 1 mark, give the action clearly. Words like open the tap and water enters from the reservoir match the mark scheme.

❌ Common errors

  • Only saying “reset it” without explaining how.
  • Talking about changing the bubble with air instead of using the reservoir.

Part (b) 03.2 — Why narrow capillary tubing was used

✅ Correct answer

The air bubble moves further in a given time, so the resolution is improved and small changes are easier to measure.

💡 Key knowledge

  • Narrow tubing makes movement of the bubble easier to see.
  • A small change in water uptake gives a bigger movement on the scale.
  • This makes measurements more accurate.

🧠 Exam technique

The mark scheme rewards a cause and effect answer: narrow tube → bubble moves more → easier to measure / better resolution.

❌ Common errors

  • Saying “it is more precise” without explaining why.
  • Using vague phrases like “better” with no science point.
  • Talking about validity, which the mark scheme does not credit here.

Part (c) 03.3 — Calculating the rate of water uptake in investigation A

📐 Calculations: step-by-step

  1. Read the graph carefully: at 5 minutes, the air bubble has moved to about 66 mm.
  2. Find the rate in mm/min:
    rate = distance ÷ time = 66 ÷ 5
  3. 66 ÷ 5 = 13.2 mm/min
  4. Convert to mm³/min using the cross-sectional area of the tube:
    13.2 × 0.8 = 10.56 mm³/min

Final answer: 10.56 mm³/min
Accept 10.6 or 11.

✅ Correct answer

Rate = 10.56 mm³/min

💡 Key knowledge

  • Rate = distance ÷ time.
  • Use the graph reading correctly before calculating.
  • Because the answer is in volume per minute, multiply by the tube area.

🧠 Exam technique

  • Show working clearly to get method marks.
  • Include units at each stage: mm/min, then mm³/min.
  • If your graph reading is slightly off, you can still gain marks for the correct method.

❌ Common calculation traps

  • Using 63 ÷ 5 instead of 66 ÷ 5.
  • Forgetting to multiply by 0.8.
  • Leaving the answer in mm/min instead of mm³/min.
  • Writing the wrong units or no units at all.
Examiner note: full marks were available for a correct calculation from the graph, then multiplying by the cross-sectional area. Even if the graph reading varied slightly, a correct method could still score.

Part (d) 03.4 — Plotting the results for investigation B

✅ Correct answer

Plot these points accurately and draw a suitable line of best fit:

  • (0, 0)
  • (1, 6)
  • (2, 16)
  • (3, 22)
  • (4, 30)
  • (5, 42)

🧠 Exam technique

  • Points must be plotted correctly, usually within about half a square.
  • Then draw a sensible line of best fit — not join-the-dots.
  • Label the line B.

💡 Key knowledge

A line of best fit should show the overall trend and pass close to the points. It should be smooth and suitable for the data.

❌ Common errors

  • Joining each point with straight line segments.
  • Missing the origin point (0,0).
  • Labeling the wrong line or forgetting the label.
Examiner note: students gained marks for correctly plotted points and then an appropriate line of best fit. A few inaccurate points could still score some credit if most of the data were correct.

Part (e) 03.5 — Predicting the line for investigation C

✅ Correct answer

Draw a straight line starting at 0,0 with a steeper gradient than A, and label it C.

💡 Key knowledge

Dry air at 25 °C causes faster transpiration than moist air, so the air bubble should move more quickly.

🧠 Exam technique

You do not need exact points here — just the correct shape, start, and relative steepness.

❌ Common errors

  • Starting the line above 0,0.
  • Drawing a curve instead of a straight line.
  • Making line C less steep than A.

Part (f) 03.6 — Why the bubble would not move in the dark

✅ Correct answer

  • No photosynthesis happens in the dark.
  • So the stomata close because carbon dioxide is not needed.
  • So there is no transpiration, or very little water loss.

💡 Key knowledge

In daylight, stomata are open for gas exchange. In the dark, photosynthesis stops, so the stomata close and water vapour loss from the leaves is reduced.

🧠 Exam technique

This is a 3-mark chain of reasoning. Try to link the ideas in order: dark → no photosynthesis → stomata close → little/no transpiration → bubble does not move.

❌ Common errors

  • Saying only “plants need light” without linking it to transpiration.
  • Confusing transpiration with photosynthesis.
  • Forgetting the stomata connection.
Examiner insight: top answers gave a full chain of explanation, not just one short statement. The best responses clearly linked dark conditions to closed stomata and then to no water movement.

Overall examiner advice

💡 What examiners wanted

  • Accurate practical knowledge of a potometer.
  • Clear use of units and correct graph reading.
  • Reasoned explanations, especially for light/dark and transpiration.

🧠 How to get full marks

  • Answer exactly what is asked: action, reason, calculation, or graph feature.
  • Use scientific vocabulary: transpiration, stomata, resolution.
  • Show working in calculations and always include units.

❌ Biggest traps

  • Not reading the graph carefully.
  • Giving vague statements with no biology link.
  • Forgetting that the potometer measures water uptake indirectly, not transpiration directly.

Topics

Biology · B2: Organisation · B4: Bioenergetics

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Biology Paper 1 (Higher), 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.