AQA GCSE Combined Science: Trilogy Biology Paper 1 (Higher), 2019: Question 5
18 marks · Standard Demand difficulty · Extended Answer
Calculate the real length of a root hair from microscope magnification, describe how to use a microscope at ×50, and use results about nitrate ion uptake with and without oxygen to explain absorption and the role of nitrates in plant growth.
Practise this questionQuestion
Question text
05 Figure 8 shows a root hair viewed using a microscope.
Figure 8
05.1 The root hair was viewed at a magnification of ×50
The image length of the root hair X–Y is 43 mm
Calculate the real length of the root hair in micrometres (μm).
[4 marks]
19Real length = μm
05.2 A microscope has a ×5 eyepiece lens.
Describe how to use this microscope to observe a prepared slide of root hair cells at a
magnification of ×50
[4 marks]
Root hair cells absorb water and mineral ions from the soil.
A scientist investigated the rate of nitrate ion uptake by two seedlings.
Figure 9 shows how the investigation was set up.
Figure 9
The scientist determined the mass of nitrate ions absorbed by each seedling
every 30 minutes for 4 hours.
Table 5 shows the results.
Table 5
Total mass of nitrate ions absorbed
Time in by seedling in arbitrary units
hours
With oxygen added With no oxygen added
00 0
0.5 100 60
1.0 145 95
1.5 170 105
2.0 195 115
2.5 215 120
3.0 235 125
3.5 250 130
4.0 265 21 130
05.3 Describe the changes in the rate of absorption of nitrate ions for the seedling
with no oxygen added.
Use information from Table 5.
[3 marks]
05.4 Explain what the results in Table 5 show about how nitrate ions are absorbed.
[4 marks]
05.5 Nitrate ions are essential for plants to grow.
Describe how nitrate ions are used in a plant to help the plant grow.
[3 marks]
Mark scheme
Show the mark scheme
AO /
Question Answers Extra information Mark
Spec. Ref.
an answer of 860 (μm) scores 4 AO1
05.1 marks 3×AO2
43 4.1.1.5
50= 1
size of real object
43 1
(size of real object =)
(size of real object =) 0.86 (mm) 1
(size of real object =) 860 (μm) allow correct conversion of their 1
calculated value
if no other marks awarded allow
1 mark for
size of image
magnification=
size of real object
AO /
Question Answers Mark
Spec. Ref.
AO1
Level 2: Scientifically relevant facts, events or processes are 3–4
05.2 4.1.1.2
identified and given in detail to form an accurate account.
AO1
Level 1: Facts, events or processes are identified and simply 1–2
stated but their relevance is not clear.
No relevant content 0
Indicative content
• place slide on stage
• use lowest power / ×4 objective lens (initially)
• adjust mirror or switch light on so light passes through slide
• move stage as close to lens as possible
• slide must not touch lens
• turn focussing knob so slide moves away from lens
• turn focussing knob until image comes into focus
• use fine focus to get clear image
• change objective lens to ×10
• ×5 eyepiece and ×10 objective lenses (gives total magnification
of ×50)
• refocus slide using focussing knob
For Level 2 reference to how to focus the slide / cells and achieve
magnification of ×50 is required
16 allow ‘it’ for rate AO3
05.3 any three from: 3 4.1.3.3
4.2.3.2
• (rate) fastest in the first 0.5 allow fastest rate is 120 units per
hours hour (at start)
• (rate gradually) decreases allow mean rate over 3.5 hours is
after first 0.5 hours 37.14 units per hour
or
(rate gradually) decreases
throughout the investigation
• rate is constant between 1.0
and 2.0 hours
or
rate is constant between 2.0
and 3.5 hours
• (rate) becomes zero allow (rate) is zero after 3.5
between 3.0 and 3.5 hours hours
05.4 more nitrate ions are absorbed allow nitrate ions absorbed faster 1 AO3
in the presence of oxygen in the presence of oxygen
(which suggests) they are 1 AO2
absorbed by active transport /
uptake
which requires energy from do not accept energy produced / 1 AO1
respiration created / made
some nitrate ions absorbed by 1 AO2
diffusion 4.1.3.3
or 4.2.3.2
some nitrate ions absorbed (by
active transport / uptake)
requiring energy from anaerobic
respiration
or
some nitrate ions absorbed by
active transport / uptake using
oxygen already dissolved in the
solution
05.5 nitrate ions are used with 1 AO1
glucose 4.4.1.3
4.4.2.3
to form amino acids 1
(which are) used to synthesise 1
proteins (needed for growth)
Total 18
How to answer it
Root hair microscopy and nitrate uptake
Question focus
Using magnification, microscope technique, and nitrate uptake in plants
💡 Key knowledge
- magnification = image size ÷ real size
- use consistent units before calculating
- a microscope is used safely by starting on the lowest power
- oxygen is needed for respiration, which provides energy for active transport
- nitrate ions are used to make amino acids and then proteins
🧠 Exam technique
- Always show your working for calculations.
- For “describe” questions, give several clear points from the table.
- For “explain” questions, link cause → process → result.
- Use the wording in the mark scheme: active transport, respiration, protein synthesis.
❌ Common errors
- Forgetting to convert mm to µm
- Writing the inverse formula the wrong way round
- Skipping from low power straight to high power on the microscope
- Saying nitrate ions are used to make glucose or starch
- Not linking oxygen to aerobic respiration and energy
Part (a) 05.1 — Calculate the real length of the root hair
4 marks
✅ Correct answer
Real length = 860 µm
This is the full-mark answer from the mark scheme.
📐 Calculations step-by-step
- Use the magnification equation:
magnification = image size ÷ real size - Rearrange to find the real size:
real size = image size ÷ magnification - Substitute in the values:
real size = 43 mm ÷ 50 - Calculate:
43 ÷ 50 = 0.86 mm - Convert mm to µm:
0.86 mm = 860 µm
🧠 How marks are awarded
- 1 mark for using the correct magnification relationship
- 1 mark for rearranging correctly
- 1 mark for getting 0.86 mm
- 1 mark for converting to 860 µm
The mark scheme says that an answer of 860 µm scores 4 marks.
❌ Common traps
- Using 43 × 50 instead of dividing
- Leaving the answer in mm when the question asks for µm
- Writing 86 µm because of a conversion error
- Not showing any working, which can lose method marks
💡 Key knowledge
Unit conversion reminder:
- 1 mm = 1000 µm
- So 0.86 mm × 1000 = 860 µm
Part (b) 05.2 — Describe how to use the microscope
4 marks
✅ Correct answer
A strong 4-mark response could include:
- Place the slide on the stage and secure it.
- Start with the lowest power objective lens (for example ×4).
- Adjust the light / mirror so light passes through the slide.
- Use the coarse focus to move the slide close to the lens, then focus until the image appears.
- Use the fine focus to get a clear image.
- Change to the ×10 objective lens.
- Refocus carefully to reach a total magnification of ×50 with the ×5 eyepiece.
🧠 Examiner tip
To reach top marks, you must explain how to focus the slide/cells and how to achieve the required magnification of ×50.
The mark scheme accepts a sequence like:
- ×5 eyepiece + ×10 objective = ×50 total magnification
- Use the fine focus after the image is found
❌ Common errors
- Starting on high power
- Forgetting to mention focusing
- Saying “move the slide towards the lens” without describing careful focusing
- Not showing how you get from ×5 to ×50
💡 Key knowledge
Suggested full sequence:
- Put the slide on the stage.
- Use the lowest-power objective lens first.
- Turn on/adjust the light so the specimen is illuminated.
- Use coarse focus to bring the image into view.
- Use fine focus to sharpen the image.
- Switch to the ×10 objective lens.
- Refocus so the total magnification is ×50.
Part (c) 05.3 — Describe changes in the rate of nitrate absorption
3 marks
✅ Correct answer points
- The rate is fastest in the first 0.5 hours.
- The rate decreases gradually after the first 0.5 hours.
- The rate is constant between 1.0 and 2.0 hours or between 2.0 and 3.5 hours.
- The rate becomes zero between 3.0 and 3.5 hours.
📐 Working from the table
You can support your answer with changes in absorbed mass over time:
- With oxygen: 0 to 100 in the first 0.5 h = fastest start
- 100 to 145 from 0.5 to 1.0 h = slower than the start
- 145 to 170 and 170 to 195 etc. = roughly steady increase for a time
- 250 to 265 from 3.5 to 4.0 h = very small increase, so rate is almost zero
🧠 Exam technique
For this kind of question, don’t just list numbers. Turn the numbers into statements about rate:
- “increases quickly”
- “slows down”
- “stays constant”
- “stops”
The mark scheme gives credit for any three correct observations.
❌ Common errors
- Talking only about total mass, not rate
- Ignoring the time intervals
- Saying the rate is constant for the whole experiment
- Giving vague statements like “it changes” without describing how
Part (d) 05.4 — Explain what the results show about nitrate absorption
4 marks
✅ Correct answer
- More nitrate ions are absorbed in the presence of oxygen.
- This suggests nitrate ions are absorbed by active transport.
- Active transport needs energy from respiration.
- With oxygen there is more aerobic respiration, so more energy is available.
- Some nitrate ions may also be absorbed by diffusion.
💡 Key knowledge
Why oxygen matters:
- Oxygen allows aerobic respiration.
- Respiration releases energy in plant cells.
- That energy is needed for active transport of nitrate ions.
- Without oxygen, less energy is released, so uptake is lower.
🧠 How to gain all 4 marks
- Make a clear comparison between the two set-ups.
- Use the term active transport.
- Say where the energy comes from: respiration.
- Include a qualifier such as “some nitrate ions may still be absorbed by diffusion”.
❌ Common misconceptions
- Saying oxygen is used to “make energy” directly
- Writing “energy from oxygen” instead of energy from respiration
- Confusing active transport with diffusion
- Forgetting that some ions may be absorbed by diffusion or other routes
✅ A model 4-mark response
More nitrate ions are absorbed when oxygen is present, which suggests that nitrate ions are absorbed by active transport. Active transport requires energy from respiration. With oxygen, aerobic respiration can happen, so more energy is available for absorption. Some nitrate ions may also be absorbed by diffusion.
Part (e) 05.5 — Describe how nitrate ions are used in plant growth
3 marks
✅ Correct answer
- Nitrate ions are used with glucose.
- They are used to form amino acids.
- Amino acids are used to make proteins, which are needed for growth.
💡 Key knowledge
Plant growth needs proteins because they are used to make new cells and tissues. Nitrate ions are an essential source of nitrogen for making amino acids.
🧠 Examiner tip
This is a chain of ideas, so write it in order:
nitrate ions + glucose → amino acids → proteins → growth
❌ Common errors
- Saying nitrate ions are used to make glucose
- Stopping at “amino acids” without mentioning proteins
- Forgetting to link proteins to growth
Quick score booster summary
💡 Must-remember facts
- magnification = image size ÷ real size
- 1 mm = 1000 µm
- Start microscopy on the lowest power
- Oxygen supports aerobic respiration
- Respiration provides energy for active transport
- Nitrates are needed to make amino acids and proteins
🧠 Final exam advice
- For calculations: write the formula, substitute numbers, calculate, convert units.
- For descriptions: quote or refer to the table data.
- For explanations: link oxygen → respiration → energy → active transport.
- Use scientific terms exactly for best marks.
Topics
Biology · Required Practicals · B1: Cell Biology · B4: Bioenergetics
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Biology Paper 1 (Higher), 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.