AQA GCSE Combined Science: Trilogy Biology Paper 2 (Higher), 2019: Question 6

14 marks · Standard Demand difficulty · Extended Answer

Answer questions about homeostasis, blood glucose control, diabetes test data, insulin concentrations, and why starving children may die after eating lychee fruits.

Practise this question

Question

The question page is headed 'This question is about homeostasis' and contains five parts worth 14 marks in total. Part 06.1 asks for a definition of homeostasis; 06.2 asks for the hormone released when blood glucose concentration falls too low; 06.3 gives a hospital glucose tolerance test method in bullet points and shows Figure 4, a line graph of blood glucose concentration in mmol/dm^3 against time from 09:00 to 13:00 for Person A and Person B, plus a boxed key stating normal blood glucose concentrations: fasting 3.5 to 5.5 mmol/dm^3 and non-fasting 4.0 to 7.8 mmol/dm^3. Person B starts above Person A, rises sharply to about 13 mmol/dm^3 after the glucose drink, then falls slowly to about 12 by 13:00; Person A rises to about 9.7 then falls to about 8.0 by 13:00, and students are asked to describe how the graph shows Person B has diabetes using data from the figure. Part 06.4 shows Table 4 with fasting blood insulin concentrations in arbitrary units for Person A as 280, Person B as 20, and a normal range of 50 to 175, then asks students to suggest which type of diabetes each person has and give a reason. Part 06.5 describes toxic hypoglycaemia syndrome in starving children after eating many lychee fruits, stating the fruit contains a molecule that stops a liver enzyme working and that this enzyme normally converts stored fats into glucose, then asks for an explanation of why starving children may die but children who have eaten during the day are not affected.
Question text

06 This question is about homeostasis.

06.1 Define the term homeostasis.

[2 marks]

06.2 Name the hormone released if the blood glucose concentration falls too low.

[1 mark]

Two people were sent to a hospital to find out if they have diabetes.

This is the method used at the hospital.

• Do not eat or drink after midnight. This is called fasting.

• Measure blood glucose concentration at 9.30 am

• Drink a glucose solution at 10.00 am

• Measure blood glucose concentration for the next 3 hours.

Figure 4 shows the results.

Figure 4

Person A and person B have diabetes.

06.3 Describe how Figure 4 shows that person B has diabetes.

Use data from Figure 4.

[3 marks]

06.4 Person A and person B had a test to measure the concentration of insulin in their

blood when they were fasting.

Table 4 shows the results.

Table 4

Person Fasting blood insulin concentration

in arbitrary units

A 280

B 20

Normal range 50–175

Suggest which type of diabetes person A and person B have.

Give a reason for each answer.

[2 marks]

Person A

Type of diabetes

Reason

Person B

Type of diabetes

Reason

*0256.*5 Toxic hypoglycaemia syndrome (THS) has caused the deaths of hundreds of starving

children in some tropical countries.

• The starving children have had nothing to eat all day.

• The starving children then eat many lychee fruits.

• The lychee fruits contain a molecule which stops an enzyme in the liver working.

• This enzyme normally converts stored fats into glucose.

Children who have eaten during the day are not affected by eating many lychee fruits.

Starving children may die from eating many lychee fruits but children who have eaten

during the day are not affected.

Explain why.

[6 marks]

Mark scheme

Show the mark scheme The mark scheme is a table listing accepted answers, extra information, marks, and AO/specification references for questions 06.1 to 06.5, totalling 14 marks. For 06.1, homeostasis is defined as regulation or maintenance of internal conditions for optimum cell or enzyme activity; 06.2 accepts glucagon only. For 06.3, credit is given for stating that Person B has fasting blood glucose above the normal range, reaches a very high concentration after the glucose drink, and does not return to normal after 3 hours or falls slowly after the peak, with one mark for using correct data from the graph compared with the normal ranges. For 06.4, Person A is Type 2 because insulin is being produced in high amounts but body cells do not respond properly, and Person B is Type 1 because not enough insulin is produced; for 06.5, marking points include depleted glycogen stores in starving children, reliance on a liver enzyme to release glucose from fats, enzyme inhibition causing low or no glucose, insufficient respiration, and the contrast that non-starving children still have glycogen stores so glucagon can continue releasing glucose into the blood.

AO /

Question Answers Extra information Mark

Spec. Ref.

06.1 regulation / control / allow keeping the internal 1 AO1

maintenance of internal conditions (of a cell / body) the 4.5.1

conditions (of a cell / body) same

for optimum (cell / enzyme allow description of optimum 1

activity) functioning (of cell / body)

06.2 glucagon correct spelling only 1 AO1

4.5.3.2

06.3 any two from: 2 AO3

• fasting blood glucose is 4.5.3.2

higher than normal range

• reached a very high

concentration after glucose

drink

• did not return to normal after

3 hours

or

fell slowly after reaching

peak.

use of correct data in allow ± half a small square for 1

comparison to normal ranges values quoted from the graph

given for any of the above points

ignore references to person A

06.4 type of diabetes must be correct AO3

4.5.3.2

(person A has Type) 2 1

(pancreas) producing (lots of) allow cells becoming resistant to

insulin but body cells cannot insulin for respond to insulin.

respond to it. do not accept the person has

become resistant to insulin

(person B has Type) I 1

(pancreas) not producing

enough insulin (to control

concentration of glucose in the

blood)

AO /

Spec. Ref.

06.5 starving children have used up allow starving children have 1 AO1

their glycogen stores no / low glycogen stores AO2

4.4.2.1

(so) would need (liver enzyme) 1 4.5.3.2 17

to release glucose from fats

as enzyme is stopped from allow no working enzyme leads 1

working they get low / no to hypoglycaemia

glucose

(cell) respiration is insufficient allow starving children use 1

(so they die) proteins to release energy

(which leads to death)

children that are not starving 1

have glycogen stores in liver /

muscle

(so) glucagon will continue to 1

release glucose (into the blood

for them)

Total 14

How to answer it

Homeostasis, diabetes and THS

Standard Demand
What this question tests

You need to define homeostasis, recall the hormone that raises blood glucose, interpret a graph using normal ranges, identify Type 1 and Type 2 diabetes from insulin data, and explain why starving children are at risk from toxic hypoglycaemia syndrome.

Question 06: Homeostasis and blood glucose control

Focus: definitions, graph interpretation, diabetes types, and a 6-mark explanation

Part (a) — Define the term homeostasis

✅ Correct answer

Homeostasis is the regulation/control of the internal conditions of the body to keep them stable.

For full marks, you can also mention that this is to keep conditions optimum for enzyme activity.

💡 Key knowledge

  • Homeostasis means keeping the internal environment constant.
  • Examples include blood glucose, temperature, and water balance.
  • AQA often rewards the idea of internal conditions staying the same or being kept at optimum levels.

🧠 Exam technique

  • If the question says “define”, give a short, accurate statement.
  • Use the word internal and either control or regulation.
  • Adding “for optimum cell/enzyme function” can secure the second mark.

❌ Common errors

  • Just saying “keeping the body healthy” is too vague.
  • Describing a process, but not defining the term.
  • Forgetting that homeostasis is about internal conditions.
Mark scheme link: 2 marks available — one for regulation/control of internal conditions, one for optimum functioning.

Part (b) — Name the hormone released if blood glucose falls too low

✅ Correct answer

Glucagon

💡 Key knowledge

  • Glucagon is released by the pancreas when blood glucose is too low.
  • It causes the liver to release glucose into the blood.
  • This helps blood glucose rise back to normal.

🧠 Exam technique

This is a recall mark: spelling must be correct enough to be unambiguous.

❌ Common errors

  • Insulin is wrong here — insulin lowers blood glucose.
  • “Adrenaline” is not the expected answer for this question.

Part (c) — Describe how Figure 4 shows that person B has diabetes

✅ Correct answer

Person B’s blood glucose is already above the normal fasting range before the glucose drink.

After the drink, it rises to a very high level of about 13.2 mmol/dm³.

It does not return to the normal range after 3 hours and is still about 12.0 mmol/dm³.

💡 Key knowledge

  • Normal fasting blood glucose: 3.5–5.5 mmol/dm³
  • Normal non-fasting blood glucose: 4.0–7.8 mmol/dm³
  • Diabetes is suggested when blood glucose stays above the normal range.

🧠 Exam technique

  • Use data from the graph for full credit.
  • Compare person B’s values with the normal range.
  • You only needed any two strong points for the marks, but adding a third makes the answer secure.

❌ Common errors

  • Only saying “the line goes up” — that is not enough.
  • Referring to person A when the question is about person B.
  • Not stating that the values are outside the normal range.

📐 Using the graph properly

  • Read values carefully from the y-axis in mmol/dm³.
  • At about 09:30, person B is around 8.2 mmol/dm³, which is above the fasting range.
  • After the drink, the peak is about 13.2 mmol/dm³.
  • At 13:00, it is still about 12.0 mmol/dm³, which is still very high.

Part (d) — Suggest which type of diabetes person A and person B have

✅ Correct answers

Person A: Type 2 diabetes

Reason: the pancreas is producing lots of insulin, but body cells cannot respond properly to it, so glucose stays too high.

Person B: Type 1 diabetes

Reason: the pancreas is not producing enough insulin to control blood glucose.

💡 Key knowledge

  • Type 1 = little or no insulin produced.
  • Type 2 = insulin is produced but body cells become resistant / do not respond properly.
  • The insulin table supports the diagnosis:
    • Person A = 280 units, above normal range 50–175
    • Person B = 20 units, below normal range 50–175

🧠 Exam technique

  • You needed the type of diabetes and a reason for each person.
  • Make sure the reason matches the type.
  • Use the table data as evidence — that is what gets you the mark.

❌ Common errors

  • Mixing up Type 1 and Type 2.
  • Saying “resistant to insulin” for Type 1 — that is wrong.
  • Just writing “high insulin” or “low insulin” without linking it to the type.

Part (e) — Explain why starving children may die after eating many lychee fruits

6 marks: this is a chain-of-reasoning explanation

✅ Correct answer

A strong answer should include these linked points:

  • Starving children have used up their glycogen stores in the liver and muscles.
  • They need the liver enzyme to release glucose from fats.
  • The lychees contain a molecule that stops this enzyme working.
  • So the children cannot release enough glucose.
  • Blood glucose falls too low, causing hypoglycaemia.
  • There is not enough glucose for cell respiration, so they may die.

💡 Key knowledge

  • Glycogen is the stored form of carbohydrate in liver and muscle.
  • When blood glucose is low, glucagon causes the liver to release glucose.
  • If the enzyme is blocked, glucose cannot be made/released quickly enough.
  • Cells need glucose for respiration to release energy.
  • Children who have eaten during the day are less affected because they still have glycogen stores.

🧠 Exam technique

  • For 6 marks, write a logical sequence of cause and effect.
  • Use words like because, so, and therefore.
  • Include the idea of low glucose leading to insufficient respiration.
  • Explain the difference between starving children and children who have eaten: the latter still have fuel stores available.

❌ Common errors

  • Only saying “they get poisoned” without explaining the biology.
  • Forgetting glycogen stores.
  • Not linking blocked enzyme action to low blood glucose.
  • Stopping at “they get low glucose” without explaining why that is dangerous.

📐 Step-by-step structure for full marks

  1. Starving children have little or no glycogen left.
  2. They rely on liver pathways to maintain blood glucose.
  3. The lychee molecule inhibits the liver enzyme.
  4. Glucose is not released/made from fats.
  5. Blood glucose drops too low, causing hypoglycaemia.
  6. Cells cannot respire enough, so the child may die.

Examiner insight: what separates top answers

Top responses did not just mention “low blood glucose”. They explained the full chain from used-up glycogen to blocked enzyme to glucose not being released to insufficient respiration. Students who included the contrast with children who had eaten during the day showed a deeper understanding and gained the final marks.

Quick revision snapshot

💡 Key facts to memorise

  • Homeostasis = maintaining internal conditions.
  • Low blood glucose → glucagon.
  • Type 1 = not enough insulin.
  • Type 2 = insulin resistance.
  • Hypoglycaemia = dangerously low blood glucose.

🧠 How to score well

  • Use correct scientific terms.
  • Quote data from graphs and tables.
  • Compare to the normal range.
  • For explanations, build a cause-and-effect chain.

❌ Biggest traps

  • Insulin vs glucagon confusion.
  • Mixing up Type 1 and Type 2 diabetes.
  • Not using graph numbers.
  • Writing isolated statements instead of a linked explanation.

Topics

Biology · B5: Homeostasis and Response · B4: Bioenergetics

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Biology Paper 2 (Higher), 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.