AQA GCSE Combined Science: Trilogy Chemistry Paper 1 (Higher), 2019: Question 1
9 marks · Standard Demand difficulty · Short Answer
Determine the reactivity order of calcium, magnesium, zinc and copper with hydrochloric acid, identify control and independent variables, predict beryllium's reactivity from the periodic table, and calculate concentration in g per dm³.
Practise this questionQuestion
Question text
01 This question is about reactions of metals.
Figure 1 shows what happens when calcium, copper, magnesium and zinc are added
to hydrochloric acid.
Figure 1
01.1 What is the order of decreasing reactivity of these four metals?
[1 mark]
Tick ( ) one box.
Zn Ca Cu Mg
Ca Cu Mg Zn
Cu Zn Ca Mg
Ca Mg Zn Cu 3
A student wants to make a fair comparison of the reactivity of the metals with
hydrochloric acid.
01.2 Name two variables that must be kept constant.
[2 marks]
*02* 2
01.3 What is the independent variable in this reaction?
[1 mark]
01.4 Predict the reactivity of beryllium compared with magnesium.
Give a reason for your answer.
Use the periodic table.
[2 marks]
Reason
A solution of hydrochloric acid contains 3.2 g of hydrogen chloride in 50 cm3
01.5
Calculate the concentration of hydrogen chloride in g per dm3
[3 marks]
Concentration = g per dm3
Mark scheme
Show the mark scheme
AO /
Question Answers Extra information Mark
Spec. Ref.
01.1 Ca Mg Zn Cu 1 AO3
5.4.1.2
01.2 any two from: 2 AO3
5.4.1.2
• mass (of metal / element) allow weight
• surface area (of metal / ignore size
element) ignore length
• concentration (of acid) ignore pH
ignore strength
• volume (of acid)
• temperature (of acid) ignore room temperature
01.3 (type of) metal / element 1 AO2
5.4.1.2
01.4 allow converse answers for AO3
magnesium 5.1.2.3
5.1.2.5
MP2 only if MP1 is correct 5.4.1.2
(beryllium is) less reactive 1
any one from: 1
• greater attraction between
nucleus and outer electrons
• more energy is needed to
remove electrons
• loss of electrons is more
difficult
• outer electrons closer to
nucleus
• less shielding
allow higher in group
allow reactivity increases down
the group
ignore reactivity series 7
01.5 an answer of 64 (g per dm3) AO2
scores 3 marks 5.3.2.5
an incorrect answer for one
step does not prevent
allocation of marks for
subsequent steps
50 3
(dm ) 1
1000
= 0.05 (dm3) 1
3.2 3
( ) = 64 (g per dm ) 1
0.05
alternative approach:
3.2
(1)
= 0.064 (1)
(× 1000) = 64 (g per dm3) (1)
alternative approach:
1000
(1)
= 20 (1)
(× 3.2) = 64 (g per dm3) (1)
an answer of 0.16 / 0.064 / 0.64
/ 6.4 / 6.4 × 10–5 (g per dm3)
gains 2 marks
Total 9
How to answer it
Reactivity of Metals with Hydrochloric Acid
Overall question focus
This is a standard demand GCSE question. The marks come from a mix of recall, explanation, planning a fair test, and one multi-step calculation. The biggest scoring points are: knowing the reactivity order, keeping a test fair, and converting units correctly.
Part 01.1 – Ordering the metals by reactivity
Tick the correct order of decreasing reactivity
✅ Correct answer
Ca Mg Zn Cu
So the correct tick is Ca Mg Zn Cu.
💡 Key knowledge
- More reactive metals react more vigorously with acids.
- Calcium is more reactive than magnesium, zinc, and copper.
- Copper is the least reactive here and does not react with dilute hydrochloric acid.
🧠 Exam technique
Use the pattern of bubbles. More bubbles = more hydrogen gas made = faster reaction = more reactive metal.
To score the mark, you only need the correct order in the box.
❌ Common errors
- Putting copper above zinc because it is “heavier” or “looks more shiny”.
- Mixing up magnesium and zinc.
- Writing the right metals but in the wrong order.
Part 01.2 – Fair test: control variables
Name two variables that must be kept constant
✅ Correct answers
- Same volume of hydrochloric acid
- Same concentration of hydrochloric acid
- Same mass of metal
- Same size/surface area of metal pieces
- Same temperature
Any two sensible control variables score the 2 marks.
💡 Key knowledge
A fair test means only the type of metal should change. Everything else must stay the same so the results can be compared properly.
🧠 Exam technique
Good answers are specific. For example:
same volume of acid is better than just same acid .
❌ Common errors
- Saying “same metal” — that changes the variable being tested.
- Writing “keep it constant” without saying what it is.
- Using vague answers like “same conditions” with no detail.
Part 01.3 – Independent variable
What is the independent variable in this reaction?
✅ Correct answer
The type of metal used.
💡 Key knowledge
The independent variable is the thing you deliberately change. Here, the student changes the metal to see how it reacts with hydrochloric acid.
🧠 Exam technique
If a question asks about variables, link your answer to the experiment:
metal is the thing being compared; the acid is kept the same.
❌ Common errors
- Saying “hydrochloric acid” — that is not the thing being changed.
- Saying “the reaction” — too vague.
Part 01.4 – Predicting beryllium’s reactivity
Predict the reactivity of beryllium compared with magnesium. Give a reason using the periodic table.
✅ Correct answer
Beryllium is less reactive than magnesium.
Reason: They are both in Group 2, and reactivity increases down the group. Beryllium is above magnesium in the periodic table, so it is less reactive.
💡 Key knowledge
- Group 2 metals all have 2 outer electrons.
- Down Group 2, atoms get larger and the outer electrons are further from the nucleus.
- Because of this, the outer electrons are lost more easily, so reactivity increases down the group.
🧠 Exam technique
To get both marks, include:
- a comparison word: more or less reactive
- a periodic table reason: beryllium is above magnesium in Group 2
❌ Common errors
- Saying beryllium is more reactive because it is “higher up” without the Group 2 trend.
- Giving no comparison with magnesium.
- Confusing Group 2 with Group 1 trends.
Part 01.5 – Concentration calculation
Calculate the concentration of hydrogen chloride in g per dm³
📐 Calculations step-by-step
- Write down the mass and volume given: 3.2 g in 50 cm³.
- Convert the volume to dm³: 50 cm³ = 0.050 dm³.
- Use concentration = mass ÷ volume.
- Calculate: 3.2 ÷ 0.050 = 64.
Answer = 64 g per dm³
💡 Key knowledge
For concentration in g per dm³:
concentration = mass ÷ volume
Make sure the volume is in dm³, not cm³.
🧠 Exam technique
Show the conversion clearly to earn method marks:
50 cm³ ÷ 1000 = 0.050 dm³
Always include units in the final answer.
❌ Common errors
- Using 50 cm³ directly in the calculation.
- Dividing the wrong way round.
- Writing 64 g/cm³ instead of 64 g/dm³.
- Missing the unit completely.
Important note about the mark scheme image
The mark scheme shown in the image appears to include a different worked example for this part, but for this question’s given values the correct calculation is:
3.2 g ÷ 0.050 dm³ = 64 g per dm³
Quick examiner insight
💡 What top answers did well
- Used the reactivity pattern correctly from the metal observations.
- Gave specific control variables for a fair test.
- Explained beryllium using Group 2 and the periodic table.
- Showed the calculation method with correct unit conversion.
❌ Where students lose marks
- Confusing independent and control variables.
- Being too vague in explanation questions.
- Forgetting to convert cm³ to dm³.
- Not giving the final unit.
Final answer checklist
- 01.1: Ca Mg Zn Cu
- 01.2: Any two control variables, e.g. same volume and concentration of acid
- 01.3: Type of metal used
- 01.4: Beryllium is less reactive than magnesium because reactivity increases down Group 2
- 01.5: 64 g per dm³
Topics
Chemistry · C4: Chemical Changes · C1: Atomic Structure and the Periodic Table · C3: Quantitative Chemistry
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 1 (Higher), 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.