AQA GCSE Combined Science: Trilogy Chemistry Paper 1 (Higher), 2019: Question 4

11 marks · Standard Demand difficulty · Short Answer

Answer a set of short questions about the periodic table, including early element arrangement, Mendeleev’s table, trends in halogen boiling points, noble gas reactivity, and calculating the number of atoms in 1 g of argon.

Practise this question

Question

A chemistry exam page labelled question 04 states that the question is about elements in the periodic table. It contains six short-answer parts: arranging elements in early periodic tables, how Mendeleev dealt with wrongly grouped elements, explaining why the boiling points of fluorine, chlorine and bromine are low, explaining the trend in those boiling points using a table of values (-186, -34 and +59 degrees Celsius), explaining why neon is unreactive with its electronic structure, and calculating the number of atoms in 1 g of argon using Avogadro’s constant 6.02 × 10^23 per mole and relative atomic mass Ar = 40. The page includes answer lines and a small data table headed Table 2 with columns for element and boiling point in degrees Celsius.
Question text

04 This question is about elements in the periodic table.

04.1 What order did scientists use to arrange elements in early periodic tables?

[1 mark]

04.2 In the early periodic tables some elements were placed in the wrong groups.

Mendeleev overcame this in his periodic table.

Give one way Mendeleev did this.

[1 mark]

Table 2 shows the boiling points of fluorine, chlorine and bromine.

Table 2

Element Boiling point in °C

Fluorine –186

Chlorine –34

Bromine +59

04.3 Explain why the boiling points in Table 2 are low.

[2 marks]

04.4 Explain the trend in the boiling points in Table 2.

[3 marks]

04.5 Explain why neon is unreactive.

Give the electronic structure of neon in your answer.

[2 marks]

*0124.*6 How many atoms are there in 1 g of argon?

The Avogadro constant is 6.02 × 1023 per mole.

Relative atomic mass (Ar): Ar = 40

[2 marks]

Number of atoms in 1 g =

Mark scheme

Show the mark scheme The provided mark scheme image does not match the question image. It shows answers for a different chemistry question about copper extraction from low-grade ores, calculating moles of CuSO4, comparing reaction profiles, carbon dioxide balance for ethanol, and the definition of sustainable development, with a total of 12 marks. Because it is unrelated to the periodic table question shown, it does not provide valid marking points for this question.

AO /

Question Answers Extra information Mark

Spec. Ref.

04.1 atomic weight do not accept atomic mass or Ar 1 AO1

5.1.2.2

04.2 left gaps / spaces 1 AO1

5.1.2.2

or

changed the order based on

atomic weights

allow placed them in correct

groups according to properties

do not accept reference to

atomic number

04.3 weak forces between the allow weak intermolecular bonds 1 AO1

molecules do not accept incorrect AO3

or references to covalent bonds 5.1.2.6

weak intermolecular forces 5.2.2.4

(so) little energy required to allow (so) little energy required 1

overcome / break the forces to separate the molecules

between molecules

or

(so) little energy required to allow (so) little energy required

overcome / break the to overcome / break the

intermolecular forces intermolecular bonds

ignore less energy

04.4 allow converse explanation in AO1

terms of boiling point AO3

(the) molecules get larger going 1 5.1.2.6

down the group 5.2.2.4

(so the) forces between the 1

molecules increase

or

(so the) intermolecular forces

increase

(so the) boiling points increase allow (so) more energy is 1

going down the group needed to separate the

or molecules

(so the) boiling points increase

with increasing relative atomic

mass

04.5 2,8 allow diagram or description 1 AO1

5.1.2.4

(so) stable arrangement of 1

electrons

or

(so) full outer shell

04.6 an answer of 1.51 × 1022 scores AO2

2 marks 5.3.2.1

1 23 1

× 6.02 × 10

or

0.025 × 6.02 × 1023

1.51 × 1022 22 1

allow 1.505 × 10

Total 11

How to answer it

Periodic Tables: Early ideas, trends and atoms in argon

What this question tests

This question checks recall of periodic table history, explanation of group trends, understanding of electron structure, and a short mole-style calculation. You need to give clear facts, use correct scientific language, and show working for the atoms calculation.

Overall focus: AO1 recall + AO2 explanation + one calculation

Question overview

The marks are spread across five short parts. Most answers are one- or two-mark responses, so the key is to be precise and not overcomplicate simple ideas.

Part (a) / 04.1

What order did scientists use to arrange elements in early periodic tables?

✅ Correct answer

By increasing atomic mass (also called relative atomic mass).

1 mark: state the order clearly and simply.

💡 Key knowledge

  • Early periodic tables were arranged by atomic weight / atomic mass.
  • Mendeleev later improved the table by using patterns in properties, not just mass.

🧠 Exam technique

  • Use the exact phrase increasing atomic mass for full credit.
  • If you say “order of mass”, that is usually acceptable if the meaning is clear.

❌ Common errors

  • Saying atomic number — this is the modern periodic table, not the early one.
  • Saying “sorted by reactivity” — not the original arrangement.

Part (b) / 04.2

Give one way Mendeleev overcame the problem of elements being in the wrong groups.

✅ Correct answers

  • He left gaps for elements not yet discovered.
  • He moved some elements so that elements with similar properties were in the same group.
  • He predicted properties of undiscovered elements.
1 mark: any one clear method earns the mark.

💡 Key knowledge

Mendeleev noticed the pattern of properties repeated. If the mass order did not fit the properties, he sometimes changed the order so the groups made chemical sense.

🧠 Exam technique

  • Say why he did it if you can: to keep similar elements together.
  • “Left gaps” is the safest one-mark answer.

❌ Common errors

  • Writing that he used atomic number — that was done later.
  • Saying he “ignored mistakes” without explaining the method.

Part (c) / 04.3

Explain why the boiling points in Table 2 are low.

✅ Correct answer

Fluorine, chlorine and bromine are simple molecules made of small molecules. The forces between the molecules are weak, so little energy is needed to overcome them.

2 marks: identify simple molecular structure + weak intermolecular forces / low energy needed.

💡 Key knowledge

  • These halogens exist as diatomic molecules: F₂, Cl₂, Br₂.
  • Boiling point depends on intermolecular forces, not the bonds inside the molecules.

🧠 Exam technique

  • For 2 marks, include both the type of structure and the reason it boils easily.
  • Use the phrase weak intermolecular forces if possible.

❌ Common errors

  • Saying “weak covalent bonds” — these are not broken when boiling.
  • Saying “they are gases so have low boiling points” without explanation.
  • Talking about reactivity instead of structure and forces.

Part (d) / 04.4

Explain the trend in the boiling points in Table 2.

✅ Correct answer

The boiling points increase down the group. As the molecules get larger, they have more electrons, so the intermolecular forces become stronger. Therefore, more energy is needed to separate the molecules.

3 marks: trend + larger molecules/more electrons + stronger intermolecular forces/more energy.

💡 Key knowledge

  • Fluorine has the lowest boiling point, then chlorine, then bromine.
  • Down Group 7, molecules get bigger and have more electrons.
  • Stronger intermolecular forces means a higher boiling point.

🧠 Exam technique

  • Use the pattern in the table: F₂ < Cl₂ < Br₂.
  • For full marks, link the trend to the size of molecules and the strength of forces.

❌ Common errors

  • Saying boiling points increase because the atoms get “heavier” only — this is not enough by itself.
  • Mixing up intermolecular forces with chemical bonds.
  • Forgetting to state the trend is down the group.

Part (e) / 04.5

Explain why neon is unreactive. Give the electronic structure of neon in your answer.

✅ Correct answer

Neon has the electronic structure 2,8. Its outer shell is full, so it is stable and does not need to gain, lose or share electrons. Therefore, neon is unreactive.

2 marks: electronic structure + full outer shell / stable / no need to react.

💡 Key knowledge

  • Neon is a noble gas.
  • Noble gases are unreactive because they already have a full outer electron shell.
  • For neon, the correct shell arrangement is 2,8.

🧠 Exam technique

  • If asked for electronic structure, include it clearly in the answer, not just in your head.
  • To get both marks, give the structure and the reason for unreactivity.

❌ Common errors

  • Saying “it has eight electrons” without mentioning the shell structure.
  • Writing the wrong structure, such as 2,7 or 2,8,1.
  • Saying “it does not react because it is a gas” — being a gas is not the reason.

Part (f) / 04.6

How many atoms are there in 1 g of argon?

📐 Calculations: step-by-step

  1. Find the number of moles:
    moles = mass ÷ Mr = 1 ÷ 40 = 0.025 mol
  2. Use Avogadro’s constant:
    number of atoms = 0.025 × 6.02 × 10^23
  3. Calculate:
    = 1.505 × 10^22
  4. Round suitably:
    = 1.5 × 10^22 atoms
2 marks: correct method + correct final answer with units.

✅ Correct answer

1.5 × 10^22 atoms

Accept any answer equivalent to this, provided the method is shown clearly.

🧠 Exam technique

  • Always use Mr properly: argon has Ar = 40.
  • Write the formula carefully: moles = mass ÷ Mr.
  • Remember to multiply by 6.02 × 10^23 to get particles/atoms.
  • Give the final answer in standard form if possible.

❌ Common errors

  • Using 1 ÷ 6.02 × 10^23 straight away — you must find moles first.
  • Dividing by 40 and then forgetting to multiply by Avogadro’s constant.
  • Using the wrong unit or forgetting that atoms are counted, not measured in g.
  • Writing 0.025 atoms — that is moles, not atoms.

Examiner insight: what students did well and where marks were lost

💡 What got marks

  • Short, precise factual answers for parts (a), (b) and (e).
  • Using correct science words like intermolecular forces and full outer shell.
  • Showing the full calculation method in part (f).

❌ What lost marks

  • Mixing up atomic mass with atomic number.
  • Talking about covalent bonds instead of intermolecular forces.
  • Giving only the trend but not the explanation in part (d).
  • Forgetting to include the electronic structure of neon.

🧠 Top-tip for full marks

If a question asks explain, try to write two linked ideas: the science fact and the reason it matters. For calculations, show each stage so you can earn method marks even if the final number is slightly wrong.

Quick revision recap

✅ Answers at a glance

  • (a) Increasing atomic mass
  • (b) Left gaps / rearranged elements by properties
  • (c) Simple molecules + weak intermolecular forces
  • (d) Boiling points increase down Group 7 because molecules get larger and forces get stronger
  • (e) Neon = 2,8 and full outer shell
  • (f) 1.5 × 10^22 atoms

💡 Key phrases to remember

  • atomic mass
  • intermolecular forces
  • full outer shell
  • moles = mass ÷ Mr
  • Avogadro’s constant = 6.02 × 10^23

Topics

Chemistry · C1: Atomic Structure and the Periodic Table · C2: Bonding, Structure and the Properties of Matter · C3: Quantitative Chemistry

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 1 (Higher), 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.