AQA GCSE Combined Science: Trilogy Chemistry Paper 1 (Higher), 2020: Question 4

12 marks · Standard Demand difficulty · Short Answer

Answer a set of short questions about acid reactions, preparing a soluble salt by reacting zinc oxide with hydrochloric acid, crystallisation, neutralisation, pH changes, balancing an equation, and hydrogen ion concentration after dilution.

Practise this question

Question

A chemistry exam page headed question 04 states that the question is about acids, alkalis and bases. It contains eight short-answer parts: adding state symbols to the equation ZnO + 2HCl to form ZnCl2 and H2O; suggesting one way to speed up the reaction; identifying how to tell when hydrochloric acid is fully reacted when it is the limiting reactant; explaining how to obtain zinc chloride solution from the mixture; describing how to produce zinc chloride crystals from the solution; suggesting the starting and ending pH when sulfuric acid is added to sodium hydroxide until in excess; balancing the equation NaOH + H2SO4 to form sodium sulfate and water; and a multiple-choice item asking for the new hydrogen ion concentration after dilution increases pH by 1 from 1.0 mol/dm^3. The page includes blank answer lines, the chemical equations, pH response spaces, and four tick-box options: 100, 10, 0.10 and 0.010 mol/dm^3.
Question text

04 This question is about acids, alkalis and bases.

A student reacted zinc oxide powder with hydrochloric acid to produce

zinc chloride solution.

04.1 Complete the equation for the reaction by writing the state symbols.

[2 marks]

ZnO( ) + 2HCl( ) → ZnCl2( ) + H2O( )

04.2 Give one way that the student could speed up the reaction between zinc oxide

powder and hydrochloric acid.

[1 mark]

Hydrochloric acid was the limiting reactant.

04.3 How could the student know when all the hydrochloric acid has reacted?

[1 mark]

04.4 How could the student obtain zinc chloride solution from the reaction mixture when all

the hydrochloric acid has reacted?

[1 mark]

04.5 Describe how zinc chloride crystals are produced from zinc chloride solution.

[2 marks]

Sulfuric acid and sodium hydroxide react to produce sodium sulfate.

04.6 Sulfuric acid is gradually added to sodium hydroxide solution.

The pH of the mixture changes as the sulfuric acid is added until in excess.

Suggest the pH at:

• the start before sulfuric acid is added

• the end when sulfuric acid is in excess.

[2 marks]

pH at start =

pH at end =

04.7 Complete the symbol equation for the preparation of sodium sulfate.

You should balance the equation.

[2 marks]

NaOH + H SO → 12 +

04.8 A solution of hydrochloric acid had a hydrogen ion concentration of 1.0 mol/dm3

Water was added to the hydrochloric acid until the pH increased by 1

What was the hydrogen ion concentration of the hydrochloric acid after water had

been added?

[1 mark]

Tick ( ) one box.

*11* 3

100 mol/dm

10 mol/dm3

0.10 mol/dm3

0.010 mol/dm3

Mark scheme

Show the mark scheme The mark scheme is a table listing answers, extra information, marks, and AO/specification references for question 04. It gives the state symbols ZnO(s), HCl(aq), ZnCl2(aq), and H2O(l); acceptable rate increases as heating or increasing acid concentration; completion of reaction shown by zinc oxide or solid remaining; filtration to obtain zinc chloride solution; heating then leaving to crystallise or cool to form crystals; pH ranges of 12 to 14 at the start and 0 to 3 at the end; the balanced equation 2NaOH + H2SO4 to Na2SO4 + 2H2O; and the dilution answer 0.10 mol/dm^3. Notes include partial credit for some sections, guidance on ignored and unacceptable responses, and a total of 12 marks.

AO /

Question Answers Extra information Mark

Spec. Ref.

04.1 ZnO(s) + HCl (aq) → ZnCl2 (aq) + H2O (l) 2 AO2

5.2.2.2

allow 1 mark for 2/3 5.4.2.3

correct state symbols RPA8

04.2 any one from: 1 AO1

• warm / heat the mixture 5.4.2.2

• increase the concentration of the 5.4.2.3

(hydrochloric) acid RPA8

ignore add a catalyst

ignore stir

ignore powder

ignore add more zinc oxide

do not accept volume /

amount of (hydrochloric)

acid

do not accept increase the

surface area

04.3 zinc oxide remains ignore colour 1 AO1

or 5.3.2.4

solid remains 5.4.2.2

allow zinc oxide is added 5.4.2.3

until in excess RPA8

04.4 filtration / filter 1 AO1

5.4.2.2

5.4.2.3

RPA8

04.5 do not accept heat to

dryness

heat 1 AO1

5.4.2.2

5.4.2.3

leave to crystallise / cool allow leave to evaporate 1 RPA8

some water

04.6 must be in this order

(at start) value in range 12–14 1 AO1

AO2.2

(at end) value in range 0–3 1 5.4.2.2

5.4.2.4

04.7 2 NaOH + H2SO4 → Na2SO4 + 2 H2O 2 AO2

5.1.1.1

allow 1 mark for 5.4.2.2

Na2SO4 and H2O

04.8 0.10 mol/dm3 1 AO3

5.4.2.2

5.4.2.4

Total 12

How to answer it

Acids, Alkalis and Bases: Zinc Oxide, Sulfuric Acid and pH

What this question tests

Writing correct symbol equations with state symbols, knowing how to speed up a reaction, understanding what happens when a limiting reactant is used up, separating a soluble salt from a mixture, making crystals from a solution, balancing neutralisation equations, and linking pH to hydrogen ion concentration.

Overall question focus

This is a low-demand GCSE chemistry question because most parts test direct recall. To score well, use the exact science words, include state symbols, and show that you understand simple practical methods like filtration, evaporation and crystallisation.

Part (a) / 04.1

Complete the equation with state symbols

ZnO( ) + 2HCl( ) → ZnCl₂( ) + H₂O( )

✅ Correct answer

ZnO(s) + 2HCl(aq) → ZnCl₂(aq) + H₂O(l)

Full marks: 2 marks. You needed the correct state symbols. The equation is already balanced.

💡 Key knowledge

  • Zinc oxide is a solid, so (s) .
  • Hydrochloric acid is in aqueous solution, so (aq) .
  • Zinc chloride is soluble, so (aq) .
  • Water is a liquid, so (l) .

🧠 Exam technique

  • Check all 4 state symbols carefully.
  • Remember: aq means dissolved in water.
  • Even if the chemistry is right, missing symbols can lose marks.

❌ Common errors

  • Writing (l) for hydrochloric acid.
  • Writing (s) for zinc chloride.
  • Forgetting the 2 in front of HCl.
  • Using the wrong symbol for water, such as (aq) .
Part (b) / 04.2

One way to speed up the reaction

✅ Correct answers

Any one of these gains the mark:

  • Warm / heat the mixture
  • Increase the concentration of hydrochloric acid

💡 Key knowledge

  • Higher temperature means particles move faster and collide more often.
  • Higher concentration means more acid particles in the same volume, so more collisions.

🧠 Exam technique

The mark scheme accepted warm the mixture or increase concentration. Be precise: “add a catalyst” is not correct here.

❌ Common errors

  • “Add more zinc oxide” — not accepted.
  • “Increase surface area” — not accepted for this mark.
  • “Stir it” — ignored by the mark scheme.
  • “Add a catalyst” — ignored.
Part (c) / 04.3

How to know when all the hydrochloric acid has reacted

✅ Correct answer

Zinc oxide remains / solid remains.

💡 Key knowledge

Hydrochloric acid is the limiting reactant, so once it is used up, some zinc oxide is left over as a solid.

🧠 Exam technique

The mark scheme allowed “zinc oxide remains” or “solid remains.” The key idea is that there must be some visible unused solid.

❌ Common errors

  • Saying the solution “turns colourless” — colour was ignored.
  • Saying “all reactants are used up” — not true here.
  • Saying “bubbles stop” — this is not the mark scheme answer.
Part (d) / 04.4

How to obtain zinc chloride solution from the mixture

✅ Correct answer

Filtration / filter.

💡 Key knowledge

Filtration separates an insoluble solid from a liquid. Here, the excess zinc oxide stays on the filter paper and the zinc chloride solution passes through.

🧠 Exam technique

If asked for a method, one word is enough: filtration. If explaining in a longer answer, mention the solid residue and the filtrate.

❌ Common errors

  • Writing “evaporation” here — that is for making crystals, not separating the solid first.
  • Writing “decanting” — not the expected answer.
Part (e) / 04.5

How to make zinc chloride crystals from zinc chloride solution

✅ Correct answer

Heat the solution, then leave it to cool / crystallise.

💡 Key knowledge

  • Gently heat to evaporate some water.
  • Do not heat to dryness.
  • Leave the solution to cool so crystals form.

🧠 Exam technique

For 2 marks, include both stages: heat/evaporate some water and cool/leave to crystallise.

❌ Common errors

  • Saying “heat to dryness” — specifically not accepted.
  • Only saying “leave to cool” — this gives only part of the answer.
  • Forgetting that some water must be removed first.
Part (f) / 04.6

Suggest the pH at the start and at the end

✅ Correct answers

  • pH at start: 12–14
  • pH at end: 0–3

💡 Key knowledge

  • Sodium hydroxide is an alkali, so it starts with a high pH.
  • Sulfuric acid in excess makes the mixture acidic, so pH becomes low.
  • The values had to be in this order: start high, end low.

🧠 Exam technique

The mark scheme accepted a range, not one exact number. As long as your answers are in the correct ranges and in the right order, you score.

❌ Common errors

  • Mixing up acid and alkali values.
  • Giving the same pH twice.
  • Forgetting that excess acid makes the final pH low.
Part (g) / 04.7

Complete and balance the equation for sodium sulfate

✅ Correct answer

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

💡 Key knowledge

  • Sodium hydroxide neutralises sulfuric acid.
  • Products are a salt, sodium sulfate, and water.
  • Balance the atoms on both sides.

🧠 Exam technique

The mark scheme allowed 1 mark for getting Na₂SO₄ and H₂O correct. To get both marks, the full balanced equation must be correct.

❌ Common errors

  • Forgetting the 2 in front of NaOH.
  • Writing NaSO₄ instead of Na₂SO₄.
  • Putting the wrong number of water molecules.
Part (h) / 04.8

Hydrogen ion concentration after the pH increases by 1

📐 Calculation / reasoning

Original hydrogen ion concentration = 1.0 mol/dm³

  1. A rise in pH by 1 means the hydrogen ion concentration goes down by a factor of 10.
  2. So divide 1.0 by 10 .
  3. 1.0 ÷ 10 = 0.10 mol/dm³

✅ Correct answer

0.10 mol/dm³

💡 Key knowledge

  • Each increase of 1 in pH means a tenfold decrease in hydrogen ion concentration.
  • Keep the units: mol/dm³ .
  • The correct option was 0.10 mol/dm³.

❌ Common calculation traps

  • Choosing 10 mol/dm³ or 100 mol/dm³ instead of dividing by 10.
  • Writing 0.01 mol/dm³ — that would be a pH increase of 2, not 1.
  • Forgetting that pH and hydrogen ion concentration change in opposite directions.

Examiner-style summary: how to get full marks

🧠 What top answers did well

  • Used the exact chemistry wording from the specification.
  • Included correct state symbols.
  • Gave practical methods in the right order: filter first, then crystallise.
  • Understood pH changes in terms of acid/alkali and concentration.

❌ Where students lost marks

  • Missing or incorrect state symbols.
  • Wrong practical method for separating a salt solution.
  • Saying “heat to dryness” when crystals were needed.
  • Confusing pH values and concentration changes.

Topics

Chemistry · Required Practicals · C4: Chemical Changes · C3: Quantitative Chemistry · Chemistry Required Practicals

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 1 (Higher), 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.