AQA GCSE Combined Science: Trilogy Chemistry Paper 2 (Higher), 2020: Question 7
7 marks · Standard Demand difficulty · Extended Answer
Describe how a reversible reaction reaches equilibrium and explain how increasing pressure and temperature affect the equilibrium position for 2NO2(g) ⇌ N2O4(g) using the figure provided.
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Question text
07 This question is about equilibrium.
07.1 Describe how a reaction reaches equilibrium.
[2 marks]
Nitrogen dioxide gas reacts to form dinitrogen tetraoxide gas.
The reaction is reversible.
The equation for the reaction is:
2 NO2(g) ⇌ N2O4(g)
07.2 Explain the effect on the equilibrium position of increasing the pressure.
[2 marks]
07.3 Figure 7 shows the change in the percentage of dinitrogen tetroxide (N2O4) in the
equilibrium mixture as the temperature of the equilibrium mixture is changed.
Figure 7
Explain the effect on the equilibrium position of increasing the temperature.
Use Figure 7.
[3 marks]
Mark scheme
Show the mark scheme
AO /
Question Answers Extra information Mark
Spec. Ref.
07.1 when a reversible reaction allow when a reversible reaction 1 AO1
occurs in apparatus which occurs in a sealed system 5.6.2.3
prevents the escape of
reactants and products
(equilibrium is reached) when 1
the forward and reverse
reactions occur at (exactly) the
same rate
07.2 (as pressure increases) AO2
the equilibrium position shifts to allow (as pressure increases) 1 5.6.2.4,
the right hand side the percentage of product / 5.6.2.6
dinitrogen tetroxide / N2O4 5.6.2.7
increases
(because) there are less moles / allow (because) there are more 1
molecules (of dinitrogen moles / molecules (of nitrogen
tetroxide) on right hand side dioxide) on left hand side
07.3 (as temperature increases)
equilibrium position shifts to left 1 AO2
hand side
(because the forward) reaction 1 AO2
is exothermic
or
(because) the backward
reaction is endothermic
(so) the percentage of product / 1 AO3
dinitrogen tetroxide / N2O4
decreases 5.6.2.4
5.6.2.6
5.6.2.7
Total 7
How to answer it
Equilibrium in NO₂ and N₂O₄
You need to describe dynamic equilibrium, explain how pressure changes the equilibrium position, and use Le Chatelier’s principle to explain how temperature affects the percentage of N₂O₄. Marks are awarded for clear scientific statements, not vague descriptions.
Question overview
Reversible reaction: 2 NO₂(g) ⇌ N₂O₄(g)
💡 Key knowledge
- Equilibrium happens in a sealed system.
- It is dynamic: the forward and reverse reactions still happen.
- At equilibrium, the rate of the forward reaction = rate of the reverse reaction.
- Changing pressure or temperature can move the equilibrium position.
🧠 Exam technique
- Use the exact phrase “same rate” for equilibrium.
- For pressure, compare the number of gas molecules on each side.
- For temperature, link your answer to whether the forward reaction is exothermic.
- Always say which side the equilibrium shifts to.
07.1 Describe how a reaction reaches equilibrium. [2 marks]
✅ Correct answer
A reversible reaction reaches equilibrium in a sealed system when the forward and reverse reactions happen at exactly the same rate.
💡 Key knowledge
- Dynamic equilibrium means the reaction has not stopped.
- The concentrations of reactants and products stay constant, but not necessarily equal.
- “Sealed system” matters because substances cannot escape.
❌ Common errors
- Saying the reaction stops at equilibrium.
- Writing only “reactants = products” without mentioning rate.
- Forgetting the idea of a sealed system.
07.2 Explain the effect on the equilibrium position of increasing the pressure. [2 marks]
✅ Correct answer
As pressure increases, the equilibrium position shifts to the right-hand side, so the percentage of N₂O₄ increases.
This is because there are fewer moles of gas on the right side: 2 NO₂(g) ⇌ N₂O₄(g) .
💡 Key knowledge
- Left side has 2 moles of gas.
- Right side has 1 mole of gas.
- Higher pressure favours the side with fewer gas molecules.
🧠 Exam technique
- Always mention the equilibrium position and the reason.
- Use the equation to compare molecules on each side.
- “Shifts right” is the clearest phrase for full marks.
❌ Common errors
- Saying pressure “increases the rate” without describing the shift.
- Claiming it shifts to the side with more gas molecules.
- Not linking pressure to the percentage of product.
07.3 Explain the effect on the equilibrium position of increasing the temperature. Use Figure 7. [3 marks]
✅ Correct answer
As temperature increases, the equilibrium position shifts to the left-hand side.
This is because the forward reaction is exothermic, so increasing temperature favours the backward endothermic reaction.
Therefore, the percentage of N₂O₄ decreases, which matches Figure 7.
💡 Key knowledge
- Figure 7 shows that the percentage of N₂O₄ goes down as temperature rises.
- For an exothermic forward reaction, heat is like a product.
- Increasing temperature shifts equilibrium to the side that uses up heat — the endothermic side.
🧠 Exam technique
- Use the graph in your answer: “the percentage of N₂O₄ decreases.”
- Make the cause-and-effect chain clear:
temperature rises → equilibrium shifts left → less N₂O₄. - Top answers name the reaction type: exothermic or endothermic.
❌ Common errors
- Saying temperature “increases the rate” only, without discussing equilibrium position.
- Mixing up exothermic and endothermic.
- Ignoring the graph and not stating that the percentage of N₂O₄ decreases.
📐 Calculations / data skills
There are no numerical calculations in this question, but you still need to handle the data in Figure 7 correctly.
- Read the trend: the curve slopes down as temperature increases.
- State the equilibrium shift: left.
- State the effect on product: percentage of N₂O₄ decreases.
Trap: do not describe the graph without linking it to equilibrium. The mark scheme wants the chemistry explanation, not just a graph description.
Best full-mark answers
07.1 model answer
In a sealed system, a reversible reaction reaches dynamic equilibrium when the forward and reverse reactions happen at exactly the same rate.
07.2 model answer
Increasing pressure shifts the equilibrium to the right, because there are fewer moles of gas on the right-hand side. This increases the amount of N₂O₄.
07.3 model answer
Increasing temperature shifts the equilibrium to the left because the forward reaction is exothermic. The percentage of N₂O₄ decreases, as shown in Figure 7.
Final examiner tips
🧠 How to secure marks
- Use the equation: 2 NO₂(g) ⇌ N₂O₄(g)
- Refer to rate in equilibrium questions.
- For pressure, compare the number of gas molecules.
- For temperature, remember: increase temperature → favours endothermic direction.
❌ Top traps from examiner reports
- Using “equal amounts” instead of “equal rates”.
- Forgetting that equilibrium is in a closed/sealed system.
- Saying “pressure pushes the reaction” without explaining the gas mole difference.
- Not using the figure to support the temperature answer.
Topics
Chemistry · C6: The Rate and Extent of Chemical Change
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 2 (Higher), 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.