AQA GCSE Combined Science: Trilogy Chemistry Paper 2 (Higher), 2020: Question 7

7 marks · Standard Demand difficulty · Extended Answer

Describe how a reversible reaction reaches equilibrium and explain how increasing pressure and temperature affect the equilibrium position for 2NO2(g) ⇌ N2O4(g) using the figure provided.

Practise this question

Question

The question page is labelled question 07 and states that it is about equilibrium. Part 07.1 asks 'Describe how a reaction reaches equilibrium' for 2 marks with lined space for an answer. Part 07.2 gives the reversible equation 2 NO2(g) ⇌ N2O4(g), says nitrogen dioxide gas reacts to form dinitrogen tetroxide gas, and asks for the effect on equilibrium position of increasing pressure for 2 marks. Part 07.3 includes Figure 7, a graph with temperature on the x-axis and percentage of dinitrogen tetroxide, N2O4, on the y-axis; the curve decreases as temperature increases, and the question asks to explain the effect of increasing temperature on the equilibrium position using the figure for 3 marks.
Question text

07 This question is about equilibrium.

07.1 Describe how a reaction reaches equilibrium.

[2 marks]

Nitrogen dioxide gas reacts to form dinitrogen tetraoxide gas.

The reaction is reversible.

The equation for the reaction is:

2 NO2(g) ⇌ N2O4(g)

07.2 Explain the effect on the equilibrium position of increasing the pressure.

[2 marks]

07.3 Figure 7 shows the change in the percentage of dinitrogen tetroxide (N2O4) in the

equilibrium mixture as the temperature of the equilibrium mixture is changed.

Figure 7

Explain the effect on the equilibrium position of increasing the temperature.

Use Figure 7.

[3 marks]

Mark scheme

Show the mark scheme The mark scheme is a table with columns for Question, Answers, Extra information, Mark, and AO/Spec reference. For 07.1, marks are awarded for stating that equilibrium is reached in a closed or sealed system where reactants and products cannot escape, and when the forward and reverse reactions occur at the same rate. For 07.2, marks are awarded for saying increased pressure shifts equilibrium to the right because there are fewer moles or molecules on the right-hand side. For 07.3, marks are awarded for stating that increasing temperature shifts equilibrium to the left, because the forward reaction is exothermic or the backward reaction is endothermic, so the percentage of N2O4 decreases.

AO /

Question Answers Extra information Mark

Spec. Ref.

07.1 when a reversible reaction allow when a reversible reaction 1 AO1

occurs in apparatus which occurs in a sealed system 5.6.2.3

prevents the escape of

reactants and products

(equilibrium is reached) when 1

the forward and reverse

reactions occur at (exactly) the

same rate

07.2 (as pressure increases) AO2

the equilibrium position shifts to allow (as pressure increases) 1 5.6.2.4,

the right hand side the percentage of product / 5.6.2.6

dinitrogen tetroxide / N2O4 5.6.2.7

increases

(because) there are less moles / allow (because) there are more 1

molecules (of dinitrogen moles / molecules (of nitrogen

tetroxide) on right hand side dioxide) on left hand side

07.3 (as temperature increases)

equilibrium position shifts to left 1 AO2

hand side

(because the forward) reaction 1 AO2

is exothermic

or

(because) the backward

reaction is endothermic

(so) the percentage of product / 1 AO3

dinitrogen tetroxide / N2O4

decreases 5.6.2.4

5.6.2.6

5.6.2.7

Total 7

How to answer it

Equilibrium in NO₂ and N₂O₄

What this question tests

You need to describe dynamic equilibrium, explain how pressure changes the equilibrium position, and use Le Chatelier’s principle to explain how temperature affects the percentage of N₂O₄. Marks are awarded for clear scientific statements, not vague descriptions.

Question overview

Reversible reaction: 2 NO₂(g) ⇌ N₂O₄(g)

💡 Key knowledge

  • Equilibrium happens in a sealed system.
  • It is dynamic: the forward and reverse reactions still happen.
  • At equilibrium, the rate of the forward reaction = rate of the reverse reaction.
  • Changing pressure or temperature can move the equilibrium position.

🧠 Exam technique

  • Use the exact phrase “same rate” for equilibrium.
  • For pressure, compare the number of gas molecules on each side.
  • For temperature, link your answer to whether the forward reaction is exothermic.
  • Always say which side the equilibrium shifts to.

07.1 Describe how a reaction reaches equilibrium. [2 marks]

✅ Correct answer

A reversible reaction reaches equilibrium in a sealed system when the forward and reverse reactions happen at exactly the same rate.

Mark points: 1 mark for a reversible reaction in a sealed system; 1 mark for forward and reverse reactions at the same rate.

💡 Key knowledge

  • Dynamic equilibrium means the reaction has not stopped.
  • The concentrations of reactants and products stay constant, but not necessarily equal.
  • “Sealed system” matters because substances cannot escape.

❌ Common errors

  • Saying the reaction stops at equilibrium.
  • Writing only “reactants = products” without mentioning rate.
  • Forgetting the idea of a sealed system.

07.2 Explain the effect on the equilibrium position of increasing the pressure. [2 marks]

✅ Correct answer

As pressure increases, the equilibrium position shifts to the right-hand side, so the percentage of N₂O₄ increases.

This is because there are fewer moles of gas on the right side: 2 NO₂(g) ⇌ N₂O₄(g) .

Mark points: 1 mark for shifting right / more N₂O₄; 1 mark for fewer gas molecules on the right.

💡 Key knowledge

  • Left side has 2 moles of gas.
  • Right side has 1 mole of gas.
  • Higher pressure favours the side with fewer gas molecules.

🧠 Exam technique

  • Always mention the equilibrium position and the reason.
  • Use the equation to compare molecules on each side.
  • “Shifts right” is the clearest phrase for full marks.

❌ Common errors

  • Saying pressure “increases the rate” without describing the shift.
  • Claiming it shifts to the side with more gas molecules.
  • Not linking pressure to the percentage of product.

07.3 Explain the effect on the equilibrium position of increasing the temperature. Use Figure 7. [3 marks]

✅ Correct answer

As temperature increases, the equilibrium position shifts to the left-hand side.

This is because the forward reaction is exothermic, so increasing temperature favours the backward endothermic reaction.

Therefore, the percentage of N₂O₄ decreases, which matches Figure 7.

Mark points: 1 mark for shifting left; 1 mark for exothermic forward / endothermic backward; 1 mark for N₂O₄ percentage decreases using the figure.

💡 Key knowledge

  • Figure 7 shows that the percentage of N₂O₄ goes down as temperature rises.
  • For an exothermic forward reaction, heat is like a product.
  • Increasing temperature shifts equilibrium to the side that uses up heat — the endothermic side.

🧠 Exam technique

  • Use the graph in your answer: “the percentage of N₂O₄ decreases.”
  • Make the cause-and-effect chain clear:
    temperature rises → equilibrium shifts left → less N₂O₄.
  • Top answers name the reaction type: exothermic or endothermic.

❌ Common errors

  • Saying temperature “increases the rate” only, without discussing equilibrium position.
  • Mixing up exothermic and endothermic.
  • Ignoring the graph and not stating that the percentage of N₂O₄ decreases.

📐 Calculations / data skills

There are no numerical calculations in this question, but you still need to handle the data in Figure 7 correctly.

  1. Read the trend: the curve slopes down as temperature increases.
  2. State the equilibrium shift: left.
  3. State the effect on product: percentage of N₂O₄ decreases.

Trap: do not describe the graph without linking it to equilibrium. The mark scheme wants the chemistry explanation, not just a graph description.

Best full-mark answers

07.1 model answer

In a sealed system, a reversible reaction reaches dynamic equilibrium when the forward and reverse reactions happen at exactly the same rate.

07.2 model answer

Increasing pressure shifts the equilibrium to the right, because there are fewer moles of gas on the right-hand side. This increases the amount of N₂O₄.

07.3 model answer

Increasing temperature shifts the equilibrium to the left because the forward reaction is exothermic. The percentage of N₂O₄ decreases, as shown in Figure 7.

Final examiner tips

🧠 How to secure marks

  • Use the equation: 2 NO₂(g) ⇌ N₂O₄(g)
  • Refer to rate in equilibrium questions.
  • For pressure, compare the number of gas molecules.
  • For temperature, remember: increase temperature → favours endothermic direction.

❌ Top traps from examiner reports

  • Using “equal amounts” instead of “equal rates”.
  • Forgetting that equilibrium is in a closed/sealed system.
  • Saying “pressure pushes the reaction” without explaining the gas mole difference.
  • Not using the figure to support the temperature answer.

Topics

Chemistry · C6: The Rate and Extent of Chemical Change

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 2 (Higher), 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.