AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), 2020: Question 5

14 marks · Standard Demand difficulty · Extended Answer

Answer questions about cooling and freezing ice cream using the particle model, thermal conductivity, specific heat capacity, and specific latent heat of fusion, including calculating the mass of the mixture.

Practise this question

Question

The question page is a Physics item about making ice cream by cooling a liquid mixture until it freezes. Parts 05.1 and 05.2 are one-mark multiple-choice questions: one asks for the motion of particles in solid ice cream with options including stationary, move freely, and vibrate about fixed positions; the other asks how kinetic energy and potential energy change as a liquid is cooled and frozen, shown as a four-row table of paired options. A labelled diagram called Figure 6 shows a cross-section of a bowl with liquid coolant at minus 20 degrees Celsius in the walls, an inner metal surface, an outer plastic surface, and the ice-cream mixture inside; later parts ask students to explain why the different thermal conductivities of metal and plastic matter, explain one other desirable property of the coolant, and calculate the mass of the mixture from data: initial temperature plus 20 degrees Celsius, freezing point minus 1.5 degrees Celsius, total energy transferred 165 kJ, specific heat capacity 3500 J/kg degrees Celsius, and specific latent heat of fusion 255000 J/kg, with the answer required to 2 significant figures.
Question text

05 Ice cream is made by cooling a mixture of liquid ingredients until they freeze.

05.1 Which statement describes the motion of the particles in solid ice cream?

[1 mark]

Tick ( ) one box.

They are stationary.

They move freely.

They vibrate about fixed positions.

05.2 How do the kinetic energy and the potential energy of the particles change as a liquid

is cooled and frozen?

[1 mark]

Tick ( ) one box.

Kinetic energy Potential energy

Decreases Decreases

Decreases Does not change

Does not change Decreases

Does not change Does not change17

Figure 6 shows a bowl used for making ice cream.

The walls of the bowl contain a liquid coolant.

The bowl is cooled to –20 °C before the mixture is put in the bowl.

The bowl causes the mixture to cool down and freeze.

Figure 6

05.3 Explain why the different thermal conductivities of metal and plastic are important in

the design of the bowl.

[4 marks]

Metal

Plastic

05.4 The liquid coolant has a freezing point below –20 °C

Explain one other property that the liquid coolant should have.

[2 marks]

05.5 The initial temperature of the mixture was +20 °C. The mixture froze at –1.5 °C.

A total of 165 kJ of internal energy was transferred from the mixture to cool and

freeze it.

specific heat capacity of the mixture = 3500 J/kg °C

specific latent heat of fusion of the mixture = 255 000 J/kg

Calculate the mass of the mixture.

Give your answer to 2 significant figures.

[6 marks]

Mass (2 significant figures) = kg

Mark scheme

Show the mark scheme The mark scheme is a table with columns for question number, answers, extra information, mark, and AO/specification reference. It gives the accepted answers: for 05.1, particles vibrate about fixed positions; for 05.2, both kinetic energy and potential energy decrease; for 05.3, metal has high thermal conductivity so energy is transferred quickly from the mixture, while plastic has low thermal conductivity so energy transfer from the surroundings to the coolant is reduced; for 05.4, the coolant should have a high specific heat capacity so it can absorb a large amount of energy with only a small temperature change. For 05.5, the scheme shows conversion of 165 kJ to 165000 J, use of energy equations for cooling and freezing, combining them into 165000 = 330250 m, and obtaining m = 0.499621 kg, rounded to 0.50 kg, with alternative partial-credit routes listed.

AO /

Question Answers Extra information Mark

Spec. Ref.

05.1 they vibrate about fixed 1 AO1

positions. 6.3.1.1

05.2 kinetic energy decreases 1 AO1

potential energy decreases 6.3.2.1

05.3 metal: has a high thermal 1 AO2

conductivity 6.1.2.1

which increases the rate of allow ice cream for mixture 1

energy transfer from the mixture

plastic: has a low thermal 1

conductivity

which reduces the rate of 1

energy transfer from the

surroundings (to the liquid

coolant at –20°C)

ignore references to insulation

throughout

05.4 a high specific heat capacity 1 AO2

6.3.2.2

so it can absorb a large amount 1

of energy with only a small

temperature change

165 kJ = 165000 J 1 AO2

05.5 6.3.2.2

ΔE = m × 3500 × 21.5 1 6.3.2.3

and 6.1.1.3

ΔE = m × 255000

165000 = 75250 m + 255000 m this mark may be awarded if E is 1

or incorrectly/not converted

165000 = 330250 m

165000 this mark may be awarded if E is 1

m =

75250 + 255000 incorrectly/not converted

or

165000 allow an answer consistent with

m = their value of E

330250

m = 0.499621 (kg) 1

m = 0.50 (kg) this answer only 1

If no marks awarded other than

the first marking point:

either

165 000 = m × 3500 × 21.5

scores 1 mark

m = 2.192… scores 1 mark

m = 2.2 (kg) scores 1 mark.

these marks may be awarded if

E is incorrectly/not converted

or

165 000 = m × 255 000 scores 1

mark

m = 0.647 scores 1 mark

m = 0.65kg scores 1 mark.

these marks may be awarded if

E is incorrectly/not converted

Total 14

How to answer it

Ice Cream: Particles, Thermal Conductivity and Energy Change

What this question tests

This question checks your knowledge of particle motion in solids, changes in kinetic and potential energy during freezing, thermal conductivity in materials, a simple property of a coolant, and a two-stage energy calculation using E = mcΔT and E = mL .

Part (a) — 05.1: Motion of particles in a solid

Which statement describes the motion of the particles in solid ice cream?

✅ Correct answer

They vibrate about fixed positions.

This is the only correct tick box for a solid.

💡 Key knowledge

  • In a solid, particles are packed closely together in a fixed arrangement.
  • They cannot move freely from place to place.
  • They only vibrate around their fixed positions.

🧠 Exam technique

For 1 mark, choose the option that matches the particle model for a solid. Use the word vibrate — it is the key examiner clue.

❌ Common errors

  • Stationary is too absolute — particles still move, but only by vibrating.
  • Move freely describes a liquid or gas, not a solid.

Part (b) — 05.2: Energy changes when a liquid freezes

How do the kinetic energy and the potential energy of the particles change as a liquid is cooled and frozen?

✅ Correct answer

Kinetic energy decreases
Potential energy decreases

Tick the row: Decreases / Decreases

💡 Key knowledge

  • Cooling means particles lose energy, so their kinetic energy decreases.
  • When the liquid freezes, particles become more ordered and closer together, so potential energy decreases.

🧠 Exam technique

Think in two parts: cooling lowers kinetic energy, and freezing lowers potential energy. The correct answer must include both changes.

❌ Common errors

  • Choosing does not change for either energy is wrong because freezing involves energy loss.
  • Mixing up kinetic and potential energy is a very common mistake.

Part (c) — 05.3: Why metal and plastic are both used in the bowl

Explain why the different thermal conductivities of metal and plastic are important in the design of the bowl.

✅ Correct answer

Metal: has a high thermal conductivity, so it transfers energy from the mixture to the cold coolant quickly.

Plastic: has a low thermal conductivity, so it reduces energy transfer from the surroundings into the coolant/mixture.

💡 Key knowledge

  • High thermal conductivity = energy passes through quickly.
  • Low thermal conductivity = energy passes through slowly.
  • The metal inner surface helps the mixture lose energy faster.
  • The plastic outer surface helps reduce unwanted warming from outside.

🧠 Exam technique

  • To score full marks, link the property to the effect on energy transfer.
  • Use phrases like increases the rate and reduces the rate.
  • Remember the question is about why the materials are used, not just what they are.

❌ Common errors

  • Just writing “metal is a good conductor” may not be enough unless you explain the effect.
  • Just saying “plastic is an insulator” is weaker than saying it has low thermal conductivity.
  • Do not only talk about “insulation” — the mark scheme accepts references to insulation, but the safest answer is thermal conductivity plus energy transfer.

Examiner-style answer for full marks

Metal has a high thermal conductivity, so energy is transferred quickly from the mixture to the cold coolant. Plastic has a low thermal conductivity, so less energy is transferred from the surroundings into the bowl.

How marks are awarded: each correct property plus its linked effect can earn credit.

Part (d) — 05.4: Property of the liquid coolant

The liquid coolant has a freezing point below −20 °C. Explain one other property that the liquid coolant should have.

✅ Correct answer

The coolant should have a high specific heat capacity.

That means it can absorb a large amount of energy with only a small temperature change.

💡 Key knowledge

  • Specific heat capacity tells you how much energy is needed to change temperature.
  • A high specific heat capacity helps the coolant absorb energy without warming up too quickly.

🧠 Exam technique

For this 2-mark style explanation, give the property and then explain its effect. The key phrase is large amount of energy with only a small temperature change.

❌ Common errors

  • Vague answers like “it should stay cold” do not name a science property.
  • Do not repeat the freezing point idea — the question asks for one other property.

Part (e) — 05.5: Calculating the mass of the mixture

The mixture cools from +20 °C to −1.5 °C and then freezes.

📐 Calculations — step by step

  1. Convert energy to joules: 165 kJ = 165000 J
  2. Find the temperature change before freezing:
    ΔT = 20 − (−1.5) = 21.5 °C
  3. Energy removed while cooling:
    E = mcΔT
    E = m × 3500 × 21.5
    E = 75250m
  4. Energy removed while freezing:
    E = mL
    E = m × 255000
    E = 255000m
  5. Total energy removed:
    165000 = 75250m + 255000m
    165000 = 330250m
  6. Solve for mass:
    m = 165000 ÷ 330250
    m = 0.4996...
  7. Answer to 2 significant figures:
    m = 0.50 kg

✅ Correct answer

Mass = 0.50 kg (2 s.f.)

Final answer must be in kg and rounded to 2 significant figures.

💡 Key knowledge

  • Use E = mcΔT for heating/cooling without a change of state.
  • Use E = mL for freezing or melting.
  • Total energy is the sum of the energy for cooling and the energy for freezing.

🧠 Exam technique

  • Always convert kJ to J.
  • Use the correct temperature change: 20 − (−1.5) = 21.5, not 18.5.
  • Show substitution clearly to gain method marks.
  • Keep units consistent: J, J/kg °C, and kg.
  • Round only at the end to the required significant figures.

❌ Common errors

  • Forgetting to include both cooling and freezing energies.
  • Using 18.5 °C instead of 21.5 °C.
  • Not converting 165 kJ to 165000 J.
  • Giving the mass in grams instead of kilograms.
  • Rounding too early and losing accuracy.

How the mark scheme rewards this calculation

  • Method marks are available for using the correct equations and setting up the total energy correctly.
  • Accuracy marks are earned for the correct final value.
  • If energy conversion is wrong, later marks may still be available if your method is consistent.

Quick recap: the full answer pattern

✅ Part (a)

Solid particles vibrate about fixed positions.

✅ Part (b)

Kinetic energy decreases and potential energy decreases.

✅ Part (c)

Metal has high thermal conductivity; plastic has low thermal conductivity.

✅ Part (d)

Coolant should have a high specific heat capacity.

✅ Part (e)

Mass = 0.50 kg

Topics

Physics · P1: Energy · P3: Particle Model of Matter

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 1 (Higher), 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.