AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), 2020: Question 5
14 marks · Standard Demand difficulty · Extended Answer
Answer questions about cooling and freezing ice cream using the particle model, thermal conductivity, specific heat capacity, and specific latent heat of fusion, including calculating the mass of the mixture.
Practise this questionQuestion
Question text
05 Ice cream is made by cooling a mixture of liquid ingredients until they freeze.
05.1 Which statement describes the motion of the particles in solid ice cream?
[1 mark]
Tick ( ) one box.
They are stationary.
They move freely.
They vibrate about fixed positions.
05.2 How do the kinetic energy and the potential energy of the particles change as a liquid
is cooled and frozen?
[1 mark]
Tick ( ) one box.
Kinetic energy Potential energy
Decreases Decreases
Decreases Does not change
Does not change Decreases
Does not change Does not change17
Figure 6 shows a bowl used for making ice cream.
The walls of the bowl contain a liquid coolant.
The bowl is cooled to –20 °C before the mixture is put in the bowl.
The bowl causes the mixture to cool down and freeze.
Figure 6
05.3 Explain why the different thermal conductivities of metal and plastic are important in
the design of the bowl.
[4 marks]
Metal
Plastic
05.4 The liquid coolant has a freezing point below –20 °C
Explain one other property that the liquid coolant should have.
[2 marks]
05.5 The initial temperature of the mixture was +20 °C. The mixture froze at –1.5 °C.
A total of 165 kJ of internal energy was transferred from the mixture to cool and
freeze it.
specific heat capacity of the mixture = 3500 J/kg °C
specific latent heat of fusion of the mixture = 255 000 J/kg
Calculate the mass of the mixture.
Give your answer to 2 significant figures.
[6 marks]
Mass (2 significant figures) = kg
Mark scheme
Show the mark scheme
AO /
Question Answers Extra information Mark
Spec. Ref.
05.1 they vibrate about fixed 1 AO1
positions. 6.3.1.1
05.2 kinetic energy decreases 1 AO1
potential energy decreases 6.3.2.1
05.3 metal: has a high thermal 1 AO2
conductivity 6.1.2.1
which increases the rate of allow ice cream for mixture 1
energy transfer from the mixture
plastic: has a low thermal 1
conductivity
which reduces the rate of 1
energy transfer from the
surroundings (to the liquid
coolant at –20°C)
ignore references to insulation
throughout
05.4 a high specific heat capacity 1 AO2
6.3.2.2
so it can absorb a large amount 1
of energy with only a small
temperature change
165 kJ = 165000 J 1 AO2
05.5 6.3.2.2
ΔE = m × 3500 × 21.5 1 6.3.2.3
and 6.1.1.3
ΔE = m × 255000
165000 = 75250 m + 255000 m this mark may be awarded if E is 1
or incorrectly/not converted
165000 = 330250 m
165000 this mark may be awarded if E is 1
m =
75250 + 255000 incorrectly/not converted
or
165000 allow an answer consistent with
m = their value of E
330250
m = 0.499621 (kg) 1
m = 0.50 (kg) this answer only 1
If no marks awarded other than
the first marking point:
either
165 000 = m × 3500 × 21.5
scores 1 mark
m = 2.192… scores 1 mark
m = 2.2 (kg) scores 1 mark.
these marks may be awarded if
E is incorrectly/not converted
or
165 000 = m × 255 000 scores 1
mark
m = 0.647 scores 1 mark
m = 0.65kg scores 1 mark.
these marks may be awarded if
E is incorrectly/not converted
Total 14
How to answer it
Ice Cream: Particles, Thermal Conductivity and Energy Change
This question checks your knowledge of particle motion in solids, changes in kinetic and potential energy during freezing, thermal conductivity in materials, a simple property of a coolant, and a two-stage energy calculation using E = mcΔT and E = mL .
Part (a) — 05.1: Motion of particles in a solid
Which statement describes the motion of the particles in solid ice cream?
✅ Correct answer
They vibrate about fixed positions.
💡 Key knowledge
- In a solid, particles are packed closely together in a fixed arrangement.
- They cannot move freely from place to place.
- They only vibrate around their fixed positions.
🧠 Exam technique
For 1 mark, choose the option that matches the particle model for a solid. Use the word vibrate — it is the key examiner clue.
❌ Common errors
- Stationary is too absolute — particles still move, but only by vibrating.
- Move freely describes a liquid or gas, not a solid.
Part (b) — 05.2: Energy changes when a liquid freezes
How do the kinetic energy and the potential energy of the particles change as a liquid is cooled and frozen?
✅ Correct answer
Kinetic energy decreases
Potential energy decreases
💡 Key knowledge
- Cooling means particles lose energy, so their kinetic energy decreases.
- When the liquid freezes, particles become more ordered and closer together, so potential energy decreases.
🧠 Exam technique
Think in two parts: cooling lowers kinetic energy, and freezing lowers potential energy. The correct answer must include both changes.
❌ Common errors
- Choosing does not change for either energy is wrong because freezing involves energy loss.
- Mixing up kinetic and potential energy is a very common mistake.
Part (c) — 05.3: Why metal and plastic are both used in the bowl
Explain why the different thermal conductivities of metal and plastic are important in the design of the bowl.
✅ Correct answer
Metal: has a high thermal conductivity, so it transfers energy from the mixture to the cold coolant quickly.
Plastic: has a low thermal conductivity, so it reduces energy transfer from the surroundings into the coolant/mixture.
💡 Key knowledge
- High thermal conductivity = energy passes through quickly.
- Low thermal conductivity = energy passes through slowly.
- The metal inner surface helps the mixture lose energy faster.
- The plastic outer surface helps reduce unwanted warming from outside.
🧠 Exam technique
- To score full marks, link the property to the effect on energy transfer.
- Use phrases like increases the rate and reduces the rate.
- Remember the question is about why the materials are used, not just what they are.
❌ Common errors
- Just writing “metal is a good conductor” may not be enough unless you explain the effect.
- Just saying “plastic is an insulator” is weaker than saying it has low thermal conductivity.
- Do not only talk about “insulation” — the mark scheme accepts references to insulation, but the safest answer is thermal conductivity plus energy transfer.
Examiner-style answer for full marks
Metal has a high thermal conductivity, so energy is transferred quickly from the mixture to the cold coolant. Plastic has a low thermal conductivity, so less energy is transferred from the surroundings into the bowl.
How marks are awarded: each correct property plus its linked effect can earn credit.
Part (d) — 05.4: Property of the liquid coolant
The liquid coolant has a freezing point below −20 °C. Explain one other property that the liquid coolant should have.
✅ Correct answer
The coolant should have a high specific heat capacity.
That means it can absorb a large amount of energy with only a small temperature change.
💡 Key knowledge
- Specific heat capacity tells you how much energy is needed to change temperature.
- A high specific heat capacity helps the coolant absorb energy without warming up too quickly.
🧠 Exam technique
For this 2-mark style explanation, give the property and then explain its effect. The key phrase is large amount of energy with only a small temperature change.
❌ Common errors
- Vague answers like “it should stay cold” do not name a science property.
- Do not repeat the freezing point idea — the question asks for one other property.
Part (e) — 05.5: Calculating the mass of the mixture
The mixture cools from +20 °C to −1.5 °C and then freezes.
📐 Calculations — step by step
- Convert energy to joules: 165 kJ = 165000 J
- Find the temperature change before freezing:
ΔT = 20 − (−1.5) = 21.5 °C - Energy removed while cooling:
E = mcΔT
E = m × 3500 × 21.5
E = 75250m - Energy removed while freezing:
E = mL
E = m × 255000
E = 255000m - Total energy removed:
165000 = 75250m + 255000m
165000 = 330250m - Solve for mass:
m = 165000 ÷ 330250
m = 0.4996... - Answer to 2 significant figures:
m = 0.50 kg
✅ Correct answer
Mass = 0.50 kg (2 s.f.)
💡 Key knowledge
- Use E = mcΔT for heating/cooling without a change of state.
- Use E = mL for freezing or melting.
- Total energy is the sum of the energy for cooling and the energy for freezing.
🧠 Exam technique
- Always convert kJ to J.
- Use the correct temperature change: 20 − (−1.5) = 21.5, not 18.5.
- Show substitution clearly to gain method marks.
- Keep units consistent: J, J/kg °C, and kg.
- Round only at the end to the required significant figures.
❌ Common errors
- Forgetting to include both cooling and freezing energies.
- Using 18.5 °C instead of 21.5 °C.
- Not converting 165 kJ to 165000 J.
- Giving the mass in grams instead of kilograms.
- Rounding too early and losing accuracy.
How the mark scheme rewards this calculation
- Method marks are available for using the correct equations and setting up the total energy correctly.
- Accuracy marks are earned for the correct final value.
- If energy conversion is wrong, later marks may still be available if your method is consistent.
Quick recap: the full answer pattern
✅ Part (a)
Solid particles vibrate about fixed positions.
✅ Part (b)
Kinetic energy decreases and potential energy decreases.
✅ Part (c)
Metal has high thermal conductivity; plastic has low thermal conductivity.
✅ Part (d)
Coolant should have a high specific heat capacity.
✅ Part (e)
Mass = 0.50 kg
Topics
Physics · P1: Energy · P3: Particle Model of Matter
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 1 (Higher), 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.