AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), 2020: Question 7
8 marks · Standard Demand difficulty · Extended Answer
Explain why a kangaroo can jump higher as its speed increases and calculate the spring constant of a tendon modeled as a spring from energy transfer and extension data.
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Question text
07 Kangaroos are large animals that travel by jumping.
Figure 8 shows a kangaroo.
Figure 8
Each leg of a kangaroo has a tendon connected to a muscle. Each tendon can be
modelled as a spring.
When a jumping kangaroo lands on the ground, the tendons stretch.
07.1 Figure 9 shows a sketch graph of how the maximum tendon length during a jump
changes with the speed of the kangaroo.
Figure 9
Explain why a kangaroo can jump higher as its speed increases.
[3 marks]
*22* 24
07.2 A kangaroo has a maximum gravitational potential energy during one jump of 770 J
When the kangaroo lands on the ground 14% of the maximum gravitational potential
energy is transferred to elastic potential energy in one tendon.
The tendon has an unstretched length of 35.0 cm
When the kangaroo lands on the ground the tendon stretches to a length of 42.0 cm
Calculate the spring constant of the tendon.
[5 marks]
Spring constant = N/m
Mark scheme
Show the mark scheme
AO /
Question Answers Extra information Mark
Spec. Ref.
07.1 the (maximum tendon) allow the tendons stretch more 1 AO3
extension increases (as speed (as speed increases) 6.1.2.2
increases)
so the elastic potential energy allow so the (elastic) force 1
increases increases
which is transferred to 1
gravitational potential energy
07.2 E = 770 × 0.14 allow E = 107.8 (J) 1 AO2
6.1.1.2
extension = 0.070m 1
107.8 = 0.5 × k × 0.0702 this mark may be awarded if 1
extension is incorrectly/not
converted and/or if the efficiency
equation has not been applied
107.8 this mark may be awarded if 1
k = 2 × 2
0.070 extension is incorrectly/not
converted and/or if the efficiency
equation has not been applied
k = 44 000 (N/m) this mark may be awarded if 1
extension is incorrectly/not
converted
this mark may not be awarded if
the efficiency equation has not
been applied
Total 8
How to answer it
Kangaroo tendons as springs
Question overview
Part 07.1 — Why can a kangaroo jump higher as its speed increases? [3 marks]
✅ Correct answer
- The maximum tendon extension increases as speed increases.
- This means more elastic potential energy is stored in the tendon.
- That energy is then transferred to gravitational potential energy, so the kangaroo can jump higher.
💡 Key knowledge
- A tendon can be modelled as a spring.
- More extension = more energy stored in the spring.
- When the tendon recoils, stored elastic energy can be transferred to movement and then to gravitational potential energy.
🧠 Exam technique
- Use a chain of explanation: speed → extension → elastic potential energy → jump height.
- To get full marks, make sure each step links logically to the next.
- Short, clear physics statements are better than vague descriptions.
❌ Common errors
- Saying only “it goes higher because it goes faster” without explaining why.
- Mixing up elastic potential energy and gravitational potential energy.
- Not mentioning that the tendon stretches more.
- Using “force” alone without linking it to stored energy.
How the marks are awarded
- 1 mark for saying the tendon extension increases as speed increases.
- 1 mark for saying elastic potential energy increases.
- 1 mark for saying this energy is transferred to gravitational potential energy.
Part 07.2 — Calculate the spring constant of the tendon [5 marks]
💡 Key knowledge
- Use the spring energy equation: E = 0.5 × k × e²
- E = elastic potential energy in joules (J)
- k = spring constant in N/m
- e = extension in metres (m)
🧠 Exam technique
- Always convert cm to m before substituting into the equation.
- Write the working clearly so you can pick up method marks.
- Check that your final unit is N/m .
❌ Common traps
- Using the full length of the tendon instead of the extension.
- Forgetting to convert 7.0 cm into 0.070 m.
- Using 770 J instead of 14% of 770 J.
- Leaving the answer in the wrong unit.
📐 Calculation steps
- Find the elastic potential energy transferred to one tendon:
E = 770 × 0.14 = 107.8 J - Find the extension of the tendon:
Unstretched length = 35.0 cm
Stretched length = 42.0 cm
extension = 42.0 - 35.0 = 7.0 cm = 0.070 m - Substitute into the spring energy equation:
107.8 = 0.5 × k × 0.070² - Rearrange to find k :
k = 2 × 107.8 / 0.070² - Calculate:
k = 43,959.18...
So, to an appropriate number of significant figures:
k = 44,000 N/m
✅ Final answer
Spring constant = 44,000 N/m
How the 5 marks are awarded
- 1 mark for calculating the elastic potential energy: 770 × 0.14
- 1 mark for finding the extension as 0.070 m
- 1 mark for substituting into E = 0.5 × k × e²
- 1 mark for rearranging correctly to find k
- 1 mark for the correct final answer 44,000 N/m
❌ Calculation mistakes that lose marks
- Using 35.0 cm or 42.0 cm directly in the equation instead of the extension.
- Writing 7.0 m instead of 0.070 m .
- Forgetting the factor of 0.5 in the spring equation.
- Giving the answer without units.
- Rounding too early in the working.
Top-mark answer model
How a full-mark 07.1 response could sound
As the kangaroo’s speed increases, the tendons stretch more. This means more elastic potential energy is stored in the tendon. The elastic energy is then transferred to gravitational potential energy, so the kangaroo can jump higher.
How a full-mark 07.2 response could sound
The energy transferred to one tendon is 770 × 0.14 = 107.8 J . The extension is 42.0 - 35.0 = 7.0 cm = 0.070 m . Using E = 0.5 × k × e² , 107.8 = 0.5 × k × 0.070² . Rearranging gives k = 2 × 107.8 / 0.070² = 44,000 N/m .
Topics
Physics · P1: Energy · P5: Forces
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 1 (Higher), 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.