AQA GCSE Combined Science: Trilogy Physics Paper 2 (Higher), 2020: Question 7

8 marks · Standard Demand difficulty · Extended Answer

Explain and calculate the magnetic force on a current-carrying wire in a magnetic field using balance readings and a force-current graph, then determine the magnetic flux density.

Practise this question

Question

The question page shows an investigation where a wire is clamped between the poles of a permanent magnet and connected to a power supply, with the magnet resting on a top pan balance reading 252.3 g. Part 07.1 asks why an increased balance reading when the switch is closed shows there is an upward force on the wire; part 07.2 gives a table of balance readings, 252.3 g with the switch open and 254.8 g with the switch closed, and asks how to use them to determine the force on the wire. Part 07.3 shows a graph of force in newtons against current in amps with a straight best-fit line rising from near the origin to about 0.021 N at 0.70 A, states that the wire length in the magnetic field is 0.125 m, and asks for the magnetic flux density.
Question text

07 A student clamped a wire between the poles of a permanent magnet.

The student investigated how the force on the wire varied with the current in the wire.

Figure 13 shows the equipment used.

Figure 13

The top pan balance was used to determine the force on the wire.

07.1 When the switch was closed the reading on the top pan balance increased.

Explain why the increased reading showed that there was an upward force on

the wire.

[2 marks]

07.2 Table 3 shows the readings on the top pan balance with the switch open and with the

switch closed.

Table 3

Switch Mass in grams

Open 252.3

Closed 254.8

Explain how the values in Table 3 can be used to determine the size of the force on

the wire.

*18* [2 marks]

07.3 The student varied the current in the wire and calculated the force acting on the wire.

Figure 14 shows the results.

Figure 14

The length of the wire in the magnetic field was 0.125 m

Determine the magnetic flux density.

[4 marks]

Magnetic flux density = T

Mark scheme

Show the mark scheme The mark scheme is a table with rows for questions 07.1 to 07.3 and a total of 8 marks. For 07.1 it awards marks for stating that the downward force on the balance increased and therefore the wire experiences an equal and opposite upward force; for 07.2 it awards marks for finding the mass difference 254.8 minus 252.3 equals 2.5 g, converting to kilograms, and multiplying by gravitational field strength to get 0.02375 N. For 07.3 it awards marks for calculating the graph gradient as (0.0210 minus 0.0) divided by (0.70 minus 0.02) to get about 0.031, using 0.031 = B × 0.125, and obtaining B = 0.25 T, with allowance for equivalent significant figures.

AO /

Question Answers Extra information Mark

Spec. Ref.

07.1

the downward force on the allow when there is a current in 1 AO3

balance increased the wire there is a magnetic field 6.7.2.2

around the wire (which causes a 6.5.4.2.3

magnetic force)

therefore the wire must 1

experience an equal and

opposite force (which is

upwards)

07.2

calculate the difference between allow 254.8 – 252.3 = 2.5 1 AO1

the two mass readings 6.7.2.2

convert to kg and multiply by allow (2.5 / 1000) × 9.8 = 1

gravitational field strength 0.02375 (N)

07.3

(0.0210 – 0.0) 1 AO3

gradient =

(0.70 – 0.02)

allow answer correctly given to 1 AO3

gradient = 0.031 any number of significant figures

allow correct substitution using 1 AO2

0.031 = B × 0.125 correctly calculated value given

to any number of significant

figures

allow answer correctly given to 1 AO2

B = 0.25 T any number of significant figures

any rounding must be correct for 6.7.2.2

subsequent marks to be

awarded.

max 2 marks if a pair of

readings from the graph are

used instead of gradient

calculation

Total 8

How to answer it

Magnetic force on a current-carrying wire

What this question tests
Understanding why a wire in a magnetic field experiences a force, how a top-pan balance can detect that force, and how to use a graph to calculate magnetic flux density using F = BIL .
Overall focus: forces, graph reading, and rearranging the magnetic force equation

💡 Key knowledge

  • A current in a wire creates a magnetic field around the wire.
  • In a magnetic field, the wire experiences a force.
  • The force on the wire and the force on the balance are equal and opposite.
  • Use F = BIL when the current is at right angles to the magnetic field.

🧠 Exam technique

  • Link the balance reading to a change in force.
  • Use the graph gradient, not just one point, for part (c).
  • Show unit conversions clearly: g → kg, then use weight = mass × g .
  • Give the final value to a sensible number of significant figures.

Part (a) — Why did the balance reading increase? [2 marks]

Explain why the increased reading showed that there was an upward force on the wire.

✅ Correct answer

The downward force on the balance increased, so the wire must have experienced an equal and opposite upward force.

💡 Key knowledge

  • When the switch is closed, current flows in the wire.
  • The wire in the magnetic field experiences a magnetic force.
  • By Newton’s third law, the force on the wire and the force on the balance are equal and opposite.

🧠 How marks are awarded

  • 1 mark for saying the balance reading went up because the downward force on the balance increased.
  • 1 mark for stating the wire had an equal and opposite upward force.

❌ Common errors

  • Just saying “the wire was pushed up” without linking to the balance.
  • Saying “the magnet pushed the wire up” without explaining the equal and opposite force.
  • Talking about “weight” instead of the force change caused by the current.

Part (b) — Using the table to find the force [2 marks]

Explain how the values in Table 3 can be used to determine the size of the force on the wire.

📐 Calculations

  1. Find the difference in mass: 254.8 g − 252.3 g = 2.5 g
  2. Convert to kilograms: 2.5 g = 0.0025 kg
  3. Calculate the force using F = mg
  4. F = 0.0025 × 9.8 = 0.0245 N

Accept: 0.02375 N if using 2.5/1000 × 9.8, depending on rounding.

✅ Correct answer

Work out the difference between the two masses, convert it to kg, then multiply by gravitational field strength to get the force.

🧠 Exam technique

  • Use the change in mass, not the total mass.
  • State the equation F = mg .
  • Include units: g, kg, N.

❌ Common errors

  • Using 254.8 g on its own instead of the difference.
  • Forgetting to convert grams to kilograms.
  • Writing the answer in grams, not newtons.

Part (c) — Determining magnetic flux density from the graph [4 marks]

Determine the magnetic flux density.

📐 Calculations: step-by-step

  1. Find the gradient of the force-current graph.
  2. Use two well-separated points on the straight line, for example:
    (0.02 A, 0.0 N) and (0.70 A, 0.0210 N)
  3. Calculate gradient:
    (0.0210 − 0.0) ÷ (0.70 − 0.02) = 0.031
  4. Use F = BIL so gradient = BL
  5. Substitute 0.031 = B × 0.125
  6. Rearrange:
    B = 0.031 ÷ 0.125 = 0.248 T
  7. Final answer: B = 0.25 T

✅ Correct answer

Magnetic flux density = 0.25 T

💡 Key knowledge

  • The graph is a straight line through the origin, showing force is directly proportional to current.
  • For a wire at right angles to the field: F = BIL
  • The gradient of an F – I graph is BL .
  • Given L = 0.125 m , you can find B .

🧠 Exam technique

  • Use the gradient of the best-fit line, not a single plotted point.
  • Choose points far apart to reduce error.
  • Write the substitution clearly so the examiner can follow the method.
  • Round only at the end, and keep units throughout.

❌ Common errors

  • Using a pair of data points instead of the gradient: this can limit marks.
  • Forgetting that gradient = force ÷ current.
  • Using 0.125 as the gradient by mistake.
  • Giving the answer in the wrong unit or with too many premature rounding steps.

Quick full-mark answers

Part (a)

The downward force on the balance increased, so the wire must have experienced an equal and opposite upward force.

Part (b)

Find the difference in mass, convert it to kg, then multiply by gravitational field strength to get the force.

Part (c)

Gradient = 0.031 , then 0.031 = B × 0.125 , so B = 0.25 T .

Final examiner tips

  • This is a classic physics practical-method question: explain the force, use the table, then use the graph.
  • The strongest answers always link cause → measurement → conclusion.
  • For graph questions, a clear gradient method is what unlocks the higher marks.
  • Always check that your final unit is correct: force in N, magnetic flux density in T.
Total marks for the question: 8

Topics

Physics · P7: Magnetism and Electromagnetism · P5: Forces

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 2 (Higher), 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.