AQA GCSE Combined Science: Trilogy Physics Paper 2 (Foundation), November 2021: Question 7

10 marks · Standard Demand difficulty · Short Answer

Questions covering vectors, velocity-time graph interpretation to determine acceleration, Newton's second law calculation of mass, and evaluating real-time tracking data in sports.

Practise this question

Question

Question 7 comprises seven parts based on a rugby player wearing a tracking device. Figure 9 shows two rugby players in action with an arrow pointing to the tracking device on a player's back. 07.1 asks for the definition of a vector quantity from three tick boxes. 07.2 asks to identify a vector quantity from displacement, distance, time, and work done. Figure 10 shows a velocity-time graph starting at (0, 0), rising linearly to (1.6, 4.0), staying constant at 4.0 m/s until 3.4 s, and dropping steeply to 0 m/s at 3.6 s. 07.3 asks to determine acceleration between 0 and 1.6 s. 07.4 asks to describe motion between 3.4 and 3.6 s. 07.5 asks for the equation relating acceleration, mass, and resultant force. 07.6 asks to calculate the mass given an acceleration of 25 m/s² and a force of 1800 N. 07.7 asks for an advantage of transmitting tracking data live during the game.
Question text

07 Professional rugby players wear a tracking device that measures their velocity

and acceleration.

Figure 9 shows a player wearing a tracking device.

The player is tackling another player who is running with the ball.

Figure 9

07.1 Velocity and acceleration are both vector quantities.

What is a vector quantity?

[1 mark]

Tick ( ) one box.

A quantity with both magnitude and direction

A quantity with direction only

A quantity with magnitude only 25

07.2 Which of the following is a vector quantity?

[1 mark]

Tick ( ) one box.

Displacement

Distance

Time

Work done 26

Figure 10 shows a velocity–time graph for the player running with the ball.

Figure 10

07.3 Determine the acceleration of the player between 0 and 1.6 s.

[2 marks]

Acceleration = m/s2

07.4 Describe the motion of the player between 3.4 s and 3.6 s.

[1 mark]

The force exerted on the player when she is tackled causes her to accelerate.

*0267.*5 Write down the equation which links acceleration (a), mass (m) and

resultant force (F).

[1 mark]

07.6 The player accelerates at 25 m/s2 when a resultant force of 1800 N acts on her.

Calculate the mass of the player.

[3 marks]

Mass = kg

07.7 The tracking device sends data to a computer during the game.

Suggest one advantage of the data being sent during the game.

[1 mark]

Mark scheme

Show the mark scheme Mark scheme table for Question 7 totaling 10 marks: 07.1 awards 1 mark for 'a quantity with both magnitude and direction'. 07.2 awards 1 mark for 'displacement'. 07.3 awards 2 marks for gradient = (4 - 0)/(1.6 - 0) and acceleration = 2.5 m/s² (allowing a = Δv / t). 07.4 awards 1 mark for 'constant deceleration' (allowing large deceleration or decelerates to a stop). 07.5 awards 1 mark for 'resultant force = mass × acceleration' or 'F = ma'. 07.6 awards 3 marks: 1 mark for substitution (1800 = m × 25), 1 mark for rearrangement (m = 1800 / 25), and 1 mark for answer 72 (kg). 07.7 awards 1 mark for 'performance can be monitored during the game' (allowing do not have to wait until end of game to download data).

AO /

Question Answers Extra information Mark

Spec. Ref.

07.1 a quantity with both magnitude 1 AO1

and direction 6.5.1.1

07.2 displacement 1 AO1

6.5.4.1.1

07.3 (4 – 0) 1 AO2

gradient =

(1.6 - 0) 6.5.4.1.5

acceleration = 2.5 m/s2 1

allow use of a = Δv / t

07.4 constant deceleration allow large deceleration 1 AO2

allow decelerates to a stop 6.5.4.1.5

07.5 resultant force = mass × allow force = mass × 1 AO1

acceleration acceleration 6.5.4.2.2

or

F = ma

07.6 1800 = m × 25 1 AO2

6.5.4.2.2

1800

m = 1

m = 72 (kg) 1

07.7 performance can be monitored allow do not have to wait until 1 AO3

during the game the end of the game to 6.6.2.4

download data

Total 10

How to answer it

Forces and Motion: Rugby Tracking Device Analysis

📋 What this question tests

This 10-mark question evaluates core physics knowledge from Forces and Motion:

  • Defining and distinguishing scalar and vector quantities.
  • Extracting data from and interpreting velocity-time graphs (gradient = acceleration, steep negative gradient = rapid deceleration).
  • Recalling and rearranging Newton's Second Law: F = m × a .
  • Real-world evaluation of digital tracking technologies in sports analytics.
Question 07.1 • 1 Mark

Definition of a Vector Quantity

Identifying key properties of vectors

✅ Correct Answer

A quantity with both magnitude and direction (Tick box 1)

Award 1 mark for correctly ticking this option.

💡 Key Knowledge

  • Magnitude: Size, numerical value, or amount (e.g. 5 m).
  • Direction: Where it points (e.g. North, forward, -y direction).
  • A scalar has magnitude only.

❌ Common Errors

Confusing "magnitude only" (which is a scalar) with "magnitude and direction". No physical quantity has "direction only".

Question 07.2 • 1 Mark

Identifying Vector Quantities

Selecting the vector from a given list

✅ Correct Answer

Displacement (Tick box 1)

Award 1 mark for selecting Displacement.

💡 Scalar vs Vector Pairs

  • Displacement = Vector (distance with a direction)
  • Distance = Scalar
  • Time = Scalar
  • Work done / Energy = Scalar

🧠 Exam Tip

Pair vectors and scalars in your revision: Distance / Displacement, Speed / Velocity, Mass / Weight.

Question 07.3 • 2 Marks

Acceleration from a Velocity-Time Graph

Calculating gradient between 0 s and 1.6 s

📐 Step-by-Step Calculation

  1. Identify points from graph:
    At t = 0 s, v = 0 m/s
    At t = 1.6 s, v = 4.0 m/s
  2. Use acceleration formula / gradient:
    a = Δv / t = (4.0 - 0) / (1.6 - 0)
  3. Calculate value:
    a = 4.0 / 1.6 = 2.5 m/s²
1 mark: Setting up gradient / formula: (4 - 0) / (1.6 - 0)
1 mark: Correct answer: 2.5 (m/s²)

🧠 Exam Technique

  • Check the grid axis scale carefully: on the time axis, 5 small squares = 0.5 s, so each small square = 0.1 s.
  • The peak occurs exactly 1 small square past 1.5, which is 1.6 s.
  • Gradient of a velocity-time graph always equals acceleration.

❌ Common Errors

Misreading the peak time as 1.5 s or miscounting grid divisions, which leads to 4 / 1.5 = 2.67 m/s² .

Question 07.4 • 1 Mark

Describing Motion (3.4 s to 3.6 s)

Interpreting a steep negative slope

✅ Acceptable Answers

  • Constant deceleration
  • Large / rapid deceleration
  • Decelerating to a stop / rest
  • Note: "Constant negative acceleration" is also accepted.
Award 1 mark for identifying deceleration / slowing down.

❌ Common Errors

  • Stating "stationary" — the player only becomes stationary at 3.6 s, but during 3.4–3.6 s they are slowing down.
  • Saying "accelerating backwards" without clarifying direction or deceleration.
Question 07.5 • 1 Mark

Equation: Force, Mass, and Acceleration

Recalling Newton's Second Law

✅ Correct Answer

resultant force = mass × acceleration

or in symbols: F = m × a (or F = ma)

Award 1 mark for the correct word or symbol equation.

💡 Key Knowledge

This is one of the equations you must recall from memory for AQA GCSE Physics. It is not given on the standard physics equation sheet.

Question 07.6 • 3 Marks

Calculating Mass

Applying Newton's Second Law with rearrangement

📐 Step-by-Step Calculation

  1. Substitute values into equation:
    1800 = m × 25
  2. Rearrange to make mass (m) the subject:
    m = 1800 / 25
  3. Calculate final answer:
    m = 72 kg
Mark 1: Correct substitution: 1800 = m × 25
Mark 2: Correct rearrangement: m = 1800 / 25
Mark 3: Correct answer: 72 (kg)

🧠 Exam Technique: Sanity Check

Always check whether your answer is physically reasonable! A rugby player weighing 72 kg makes sense. If your calculation gives 45 000 kg or 0.014 kg, you multiplied instead of dividing!

❌ Common Trap

Multiplying the numbers together: 1800 × 25 = 45 000 . Always write out the formula first to ensure correct rearrangement.

Question 07.7 • 1 Mark

Advantage of Live Data Transmission

Real-time sports monitoring

✅ Acceptable Answers

  • Performance can be monitored during the game / in real time.
  • Do not have to wait until the end of the game to download data.
  • Coaches can make immediate tactical or substitution decisions based on fatigue/impacts.
Award 1 mark for a clear advantage linked to real-time data reception.

❌ Common Errors

Vague answers like "it's faster" or "it saves time" without linking to in-game monitoring or not having to wait until full-time.

Topics

Physics · P5: Forces

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 2 (Foundation), November 2021. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.