AQA GCSE Combined Science: Trilogy Physics Paper 2 (Higher), 2021: Question 5
13 marks · Standard Demand difficulty · Extended Answer
Explain and compare medical imaging uses of infrared, visible light, X-rays and gamma rays, and calculate force using work done and distance in an X-ray tube.
Practise this questionQuestion
Question text
05 Different parts of the electromagnetic spectrum are used in medical imaging.
Figure 8 shows an image of a person’s hand taken with an infrared camera.
Figure 8
05.1 Explain why the infrared camera is able to show that parts of the hand are at
different temperatures.
[2 marks]
05.2 Infrared has a range of wavelengths from 700 nm to 1 mm.
Which part of the electromagnetic spectrum would have waves with a wavelength of
6.5 × 10–7 m?
[1 mark]
Tick ( ) one box.
Infrared
Microwaves
Radio waves
Visible light 19
05.3 Figure 9 shows X-rays and gamma rays being used for medical imaging.
Figure 9
X-rays Gamma rays
To use X-rays for medical imaging, a machine produces a very brief burst of X-rays.
To use gamma rays for medical imaging, a radioactive isotope is injected into the
patient’s blood. The isotope is circulated around the body in the blood. The isotope
emits gamma rays.
Compare the potential risks to a patient of using X-rays and gamma rays for
medical imaging.
[4 marks]
X-rays are produced by colliding high-energy electrons into a metal target.
The electrons have high energy because they are accelerated to high speeds.
Only a small proportion of the kinetic energy of an electron is converted into an X-ray
when it collides with the metal target.
05.4 An electron is accelerated through a distance of 15 mm.
The work done on the electron is 1.2 × 10–13 J.
Calculate the force on the electron.
[3 marks]
Force = N
05.5 The metal target is made from tungsten.
Tungsten has the highest melting point of any metal.
Explain why using tungsten as the metal target enables the X-ray machine to be
more powerful.
[3 marks]
Mark scheme
Show the mark scheme
AO /
Question Answers Extra information Mark
Spec. Ref.
05.1 different temperatures emit 1 AO1
different intensities of infrared
which are represented (on the 1 AO3
infrared camera) as different
shades / colours 6.6.2.4
allow wavelength / frequency /
amount for intensity throughout
05.2 visible light 1 AO3
6.6.2.1
05.3 both ionising radiation so some 1 AO1
risk of cancer
the whole body is irradiated by 1 AO3
gamma rays
when an X-ray is taken only part 1
of the body is exposed AO3
exposure time for gamma rays 1
is longer AO3
6.6.2.3
05.4 1.2 × 10−13 = F × 0.015 1 AO2
6.5.2
1.2 × 10-13
F = allow a correct rearrangement 1
0.015 using an incorrectly / not
converted value of s
allow 8 ×10−12 1
F = 8.0 ×10−12 N
allow a correct calculation using
an incorrectly / not converted
value of s
05.5 some of the energy of the 1 AO1
electrons causes heating
(therefore) increasing the 1 AO3
temperature
(so using tungsten) allows more allow (so using tungsten) 1 AO3
electrons to be collided per enables more energy per
second than using any other second to be transferred than 6.5.2
metal using any other metal
Total 13
How to answer it
You need to explain how infrared images show temperature differences, identify the correct EM wave from a wavelength, compare risks from X-rays and gamma rays, calculate force using work and distance, and explain why tungsten is used as an X-ray target.
Part (a) / 05.1 — Why the infrared camera shows different temperatures
✅ Correct answer
Different temperatures emit different intensities of infrared radiation, and the camera shows these as different shades or colours.
💡 Key knowledge
- All objects emit infrared radiation.
- Hotter objects emit more infrared radiation.
- The camera detects the infrared and converts it into a visible image using shades/colours.
🧠 Exam technique
For 2 marks, you need both ideas:
- temperature changes the intensity of infrared emitted
- the camera displays this as different shades/colours
❌ Common errors
- Saying the camera “measures heat directly” — it detects infrared radiation.
- Saying different parts have different “brightness” without linking it to intensity of infrared.
- Forgetting the camera converts the signal into colours/shades.
Part (b) / 05.2 — Wavelength in the EM spectrum
✅ Correct answer
Visible light
💡 Key knowledge
Infrared has wavelengths from 700 nm to 1 mm. 6.5 × 10⁻⁷ m = 650 nm , which is shorter than 700 nm, so it is in the visible range.
🧠 Exam technique
Always convert units first. If you do not convert nm to m or vice versa, it is easy to choose the wrong section of the spectrum.
❌ Common errors
- Choosing infrared because the number looks “small”.
- Forgetting that 1 nm = 10⁻⁹ m .
- Not checking the infrared lower limit of 700 nm.
Part (c) / 05.3 — Comparing risks from X-rays and gamma rays
✅ Correct answer
Both X-rays and gamma rays are ionising radiation, so both can damage cells and increase the risk of cancer. Gamma rays are generally riskier because the whole body is irradiated and the exposure time is longer. With X-rays, only part of the body is exposed.
💡 Key knowledge
- Ionising means they can remove electrons from atoms/molecules, damaging cells.
- Damage to DNA can lead to mutations and cancer.
- Gamma-ray imaging involves a radioactive isotope in the blood, so radiation comes from inside the body.
- X-ray imaging uses a machine to send a short burst at the target area only.
🧠 Exam technique
This is a compare question, so you must mention both methods. Strong answers compare:
- the radiation type risk: both are ionising
- the body area exposed: gamma rays affect the whole body, X-rays only part
- the exposure time: gamma rays last longer
❌ Common errors
- Saying one is “safe” — both carry risk.
- Missing the idea that gamma rays can expose the whole body.
- Not using the word ionising.
- Writing only similarities or only differences, not a comparison.
Part (d) / 05.4 — Calculating force from work done and distance
📐 Calculation
Given:
- Work done = 1.2 × 10⁻¹³ J
- Distance = 15 mm = 0.015 m
Formula: Work done = Force × distance
Rearrange: Force = Work done ÷ distance
Answer: F = 1.2 × 10⁻¹³ ÷ 0.015 = 8.0 × 10⁻¹² N
💡 Key knowledge
- Use SI units: work in joules, distance in metres, force in newtons.
- 15 mm must be converted to 0.015 m.
- Final answer should be given to 2 significant figures here, matching the data.
🧠 Exam technique
- Write the formula first.
- Substitute the numbers clearly.
- Show the unit conversion.
- Check the final unit is N.
❌ Common calculation traps
- Using 15 instead of 0.015.
- Forgetting the division and multiplying instead.
- Leaving the answer in joules or millimetres.
- Rounding too early and losing accuracy.
Part (e) / 05.5 — Why tungsten makes the X-ray target more powerful
✅ Correct answer
When the electrons hit the tungsten target, some of their energy is transferred to heating. Tungsten has a very high melting point, so it can get very hot without melting. This means more electrons can be collided with the target per second, so more energy per second can be transferred and the X-ray machine can be more powerful.
💡 Key knowledge
- Not all kinetic energy becomes X-rays; much of it becomes thermal energy.
- A target in an X-ray tube must withstand high temperatures.
- Tungsten is suitable because it has the highest melting point of any metal.
🧠 Exam technique
To reach full marks, link the material property to the effect on the machine:
- electron collisions cause heating
- tungsten does not melt easily
- therefore more electrons can hit the target each second / more energy per second can be transferred
❌ Common errors
- Saying tungsten “creates more X-rays” without explaining the heating issue.
- Talking only about “being strong” without mentioning the high melting point.
- Missing the idea of more collisions per second or more energy per second.
Quick full-mark recap
💡 Must-know facts
- Infrared cameras show temperature by detecting different infrared intensities.
- 6.5 × 10⁻⁷ m is visible light.
- X-rays and gamma rays are both ionising and can increase cancer risk.
- Gamma imaging usually exposes the whole body for longer.
- Force = work done ÷ distance
- Tungsten is used because it can withstand very high temperatures.
🧠 How to score well
- Use the correct science word: intensity, ionising, melting point.
- For compare questions, always give both sides.
- For calculations, show units and conversions.
- For explanation questions, link cause → effect → result.
Topics
Physics · P5: Forces · P6: Waves · P4: Atomic Structure
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 2 (Higher), 2021. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.