AQA GCSE Combined Science: Trilogy Chemistry Paper 2 (Foundation), 2022: Question 7
10 marks · Standard Demand difficulty · Extended Answer
Compare the processes for obtaining potable water from different sources and calculate the concentration of a sodium chloride solution.
Practise this questionQuestion
Question text
07.1 Water that is safe to drink is called potable water.
Compare how easily potable water can be obtained from:
• waste water (sewage)
• ground water (fresh water).
[6 marks]
A scientist produced potable water from 150 cm3 of salty water.
07.2 Which process can be used to produce potable water from salty water?
[1 mark]
Tick ( ) one box.
Distillation
Electrolysis
Filtration
Sterilisation
07.3 The salty water contains sodium chloride.
The scientist collected 2.40 g of sodium chloride from 150 cm3 of salty water.
Calculate the concentration of sodium chloride in grams per dm3
[3 marks]
Concentration of sodium chloride = g/dm3
Mark scheme
Show the mark scheme
Question 7
AO /
Question Answers Mark
Spec. Ref.
07.1 Level 2: Scientifically relevant features are identified, the way(s) in 4–6 AO1
which they are similar / different is made clear and (where 5.10.1.3
appropriate) the magnitude of the similarity / difference is noted.
Level 1: Relevant features are identified and differences noted. 1–3
No relevant content 0
Indicative content
ground water waste water
easier to obtain more difficult to obtain
fewer processes more processes
takes less time takes more time
filtered through filter beds screening and grit removal
to remove insoluble particles to remove large particles
sedimentation
to produce sewage sludge and
effluent
aerobic biological treatment of
effluent
to reduce solid waste
sterilised and then sterilised
using chlorine, ozone or uv using chlorine, ozone or uv
light light
to kill bacteria to kill bacteria
sludge is anaerobically
digested
by specific bacteria
to remove organic matter
AO /
Question Answers Extra information Mark
Spec. Ref.
07.2 distillation 1 AO1
5.10.1.2
AO /
Spec. Ref.
07.3 (conversion) 1 AO2
150 3 5.3.2.5
( =) 0.15 (dm )
1000
(concentration =) allow correct use of incorrect / 1
2.40 no conversion
0.15
= 16 (g/dm3)
OR
(conversion)
1000
(1)
= 6.67 (1)
(6.67 × 2.4)
= 16 (g/dm3) (1)
OR
(concentration =)
2.4
(1)
= 0.016 (1)
(conversion)
(0.016 × 1000)
= 16 (g/dm3) (1)
Total Question 7 10
How to answer it
Potable Water: Sources, Treatment, and Concentration
This question assesses your understanding of potable water (safe drinking water). You need to compare the industrial processes used to treat ground water versus waste water, identify methods for desalination, and perform a concentration calculation involving unit conversions.
Comparing Ground Water and Waste Water
6 Marks - Extended Writing
💡 Key Knowledge
- Ground Water: Found in rocks/aquifers. Treatment is simple: 1. Filter through sand/gravel beds. 2. Sterilise.
- Waste Water: Contains sewage and organic matter. Treatment is complex: 1. Screening (large bits). 2. Sedimentation (sludge and effluent). 3. Aerobic biological treatment.
- Sterilising agents: Chlorine, Ozone, or UV light.
🧠 Exam Technique
This is a Level of Response question. To get 5-6 marks, you must compare both sources and explain why one is easier than the other.
Use comparative words: "In contrast," "However," "Whereas," or "More/Less."
✅ Model Answer Structure
Ground water is easier and faster to treat because it has fewer stages. It only requires filtering through filter beds to remove insoluble solids and then sterilising to kill bacteria.
In contrast, waste water is more difficult and takes more time. It requires screening to remove large objects, sedimentation to produce sewage sludge and effluent, and aerobic biological treatment to reduce organic matter. Like ground water, it must also be sterilised at the end using chlorine, ozone, or UV light.
Desalination
1 Mark
✅ Correct Answer
Distillation
🧠 Examiner Insight
Students often confuse filtration with distillation. Filtration only removes insoluble solids (like sand). Salt is dissolved, so you must use distillation or reverse osmosis to remove it.
Concentration Calculation
3 Marks
📐 Step-by-Step Calculation
The Goal: Find concentration in g/dm³.
- Step 1: Convert Volume to dm³
There are 1000 cm³ in 1 dm³.
150 / 1000 = 0.15 dm³ (1 Mark) - Step 2: Use the Concentration Formula
Concentration = Mass / Volume
Concentration = 2.40 g / 0.15 dm³ (1 Mark) - Step 3: Final Answer
16 g/dm³ (1 Mark)
❌ Common Errors
- The "Divide by 100" Trap: Many students divide by 100 instead of 1000 when converting cm³ to dm³.
- Wrong Order: Dividing volume by mass (0.15 / 2.40) instead of mass by volume.
- Ignoring Units: Always check if the question asks for g/dm³ or mol/dm³. This one asks for grams.
🧠 Top Tip
If you get the conversion wrong but use your wrong number correctly in the next step, you can still get 2 out of 3 marks (Error Carried Forward). Always show your working!
Topics
Chemistry · C10: Using Resources · C3: Quantitative Chemistry
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 2 (Foundation), 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.