AQA GCSE Combined Science: Trilogy Chemistry Paper 2 (Higher), 2022: Question 1

10 marks · Standard Demand difficulty · Short Answer

Identify errors in a paper chromatography setup, draw conclusions from chromatogram results, explain why a dye did not move, and calculate solvent distance using an Rf value.

Practise this question

Question

A chemistry exam question on paper chromatography is split into four parts labelled 01.1 to 01.4. Figure 1 shows a chromatography tank containing solvent and a strip of chromatography paper with five spots on a horizontal start line labelled red colour, blue colour, green colour, yellow colour and brown ink; the solvent level is drawn above the start line and the start line is labelled as drawn in ink, with no lid shown on the tank. Figure 2 shows a completed chromatogram from a correct setup: red has one low spot, blue has one high spot, green remains on the start line, yellow has one mid-height spot, and brown ink has four spots matching red, blue and yellow plus one extra spot. The written questions ask for two setup errors and the problem caused by each, two conclusions about the colours in brown ink, a multiple-choice reason why green stayed on the start line, and a calculation of solvent distance using Rf = distance moved by colour divided by distance moved by solvent with values Rf = 0.24 and colour distance = 1.8 cm.
Question text

01 A student investigated the colours in a brown ink using chromatography.

01.1 Figure 1 shows the apparatus used.

Figure 1

Give two errors made by the student.

Describe the problem each error would cause.

[4 marks]

Error 1

Problem 1

Error 2

Problem 2

A different student set up the apparatus correctly.

Figure 2 shows the results.

Figure 2

01.2 Give two conclusions the student can make from Figure 2 about the four colours

in the brown ink.

[2 marks]

01.3 Why was the green colour still on the start line at the end of the experiment?

[1 mark]

Tick ( ) one box.

The experiment was left for too long.

The green colour was insoluble in the solvent.

The green spot contained too many colours.

The green spot was too small.

01.4 A student calculated the Rf value of a colour to be 0.24

The colour moved 1.8 cm from the start line.

Calculate the distance the solvent moved.

Use the equation:

distance moved by colour

Rf =

distance moved by solvent

[3 marks]

Distance moved by solvent = cm

Mark scheme

Show the mark scheme The mark scheme is a table for Question 1 with answers, extra information, marks and specification references. For 01.1, acceptable error-problem pairs include start line drawn in ink so the ink mixes with or moves in the solvent, solvent above the start line so the colours dissolve, and no lid on the tank so the solvent evaporates; this part is worth 4 marks. For 01.2, accepted conclusions include that brown ink contains red, blue and yellow, contains an unknown colour, does not contain green, and that blue is most soluble or red least soluble; 01.3 awards 1 mark for saying the green colour was insoluble in the solvent; 01.4 shows the calculation 0.24 = 1.8 divided by distance moved by solvent, giving 1.8/0.24 = 7.5 cm for 3 marks.

Question 1

AO /

Question Answers Extra information Mark

Spec. Ref.

01.1 any two pairs from: 4 AO3

5.8.1.3

RPA12

(start) line drawn in ink (1) allow (start) line should be

drawn in pencil

(so ink) will mix with solvent (1) allow the ink will move up the

paper

the solvent is above the (start) allow the solvent should be

line (1) below the (start) line

(so) colours / ink will dissolve (1)

no lid on tank (1)

(so) solvent will evaporate (1)

AO /

Spec. Ref.

01.2 any two from: 2 AO3

5.8.1.3

• (the brown ink) contains the RPA12

blue, yellow and red (colours)

• (the brown ink) contains an

unknown colour

• (the brown ink) does not

contain green ink

• blue (colour) is the most allow blue (colour) has the

soluble highest Rf value

or

red (colour) is the least allow red (colour) has the lowest

soluble Rf value

ignore green colour is insoluble

AO /

Spec. Ref.

01.3 the green colour was insoluble 1 AO2

in the solvent 5.8.1.3

RPA12

AO /

Spec. Ref.

01.4 1.8 1 AO2

0.24 =

distance moved by solvent 5.8.1.3

RPA12

(distance moved by solvent =) 1

1.8

0.24

= 7.5 (cm) 1

Total Question 1 10

How to answer it

Chromatography in Brown Ink

What this question tests

You need to spot errors in chromatography setup, interpret a chromatogram, identify what the results show about an ink mixture, and use the Rf equation to calculate an unknown distance. Marks are awarded for clear scientific reasons, not just naming the error.

Question 01.1 — Two errors in the chromatography setup

Give two errors made by the student. Describe the problem each error would cause. [4 marks]

✅ Correct answers

Any two pairs of error + problem from the list below score full marks.

  • Error: start line drawn in ink
    Problem: the ink would mix with the solvent / move up the paper.
  • Error: solvent is above the start line
    Problem: the colours / ink would dissolve into the solvent immediately.
  • Error: no lid on the tank
    Problem: the solvent would evaporate.
Marking tip: you need one error and one effect for each pair.

💡 Key knowledge

  • The start line should be drawn in pencil, not ink.
  • The solvent level must be below the start line.
  • The tank should have a lid to stop the solvent evaporating.
  • In chromatography, substances separate because they have different solubilities.

🧠 Exam technique

  • Always use the phrase "because" or "so" to link the error to the problem.
  • Write your answer in clear pairs:
    Error 1 → Problem 1
    Error 2 → Problem 2
  • The examiner awards marks for a correct scientific consequence, not just for spotting the picture detail.

❌ Common errors

  • Saying only “the setup is wrong” without explaining what happens.
  • Writing “use pencil” as the answer, when the student actually used ink.
  • Forgetting the consequence, e.g. “solvent above the line” without saying the ink dissolves.
  • Choosing “the lid is missing” but not stating evaporation.

Question 01.2 — Conclusions from the chromatogram

Give two conclusions the student can make from Figure 2 about the four colours in the brown ink. [2 marks]

✅ Correct answers

You can choose any two of these:

  • The brown ink contains blue, yellow and red.
  • The brown ink contains an unknown colour.
  • The brown ink does not contain green.
  • Blue is the most soluble / has the highest Rf.
  • Red is the least soluble / has the lowest Rf.

💡 Key knowledge

  • If a spot in the brown ink ends at the same height as a known colour, they are the same substance.
  • Different heights mean the substances are different.
  • Higher spot = usually more soluble in the solvent.
  • Lower spot = usually less soluble.

🧠 Exam technique

  • Use evidence from the spots shown in Figure 2.
  • Good answers compare the brown ink spots with the single-colour spots.
  • For top marks, use scientific wording like same height, same substance, soluble, and Rf.

❌ Common errors

  • Saying the brown ink contains green, because a green spot is shown on the reference line — it does not.
  • Calling the unknown spot “another colour” without linking it to evidence.
  • Mixing up the meaning of high and low spots.

Question 01.3 — Why did the green colour stay on the start line?

Tick one box. [1 mark]

✅ Correct answer

The green colour was insoluble in the solvent.

💡 Key knowledge

  • If a substance is insoluble, it does not dissolve in the solvent.
  • So it cannot move up the paper.

🧠 Exam technique

  • For multiple-choice science questions, eliminate the options that do not explain the result.
  • The key idea here is dissolving: if it does not dissolve, it stays at the start line.

❌ Common errors

  • “The experiment was left too long” — time does not explain a spot staying on the start line.
  • “The green spot was too small” — size does not stop movement.
  • “The green spot contained too many colours” — not the reason for staying still.

Question 01.4 — Calculate the distance moved by the solvent

Rf = distance moved by colour ÷ distance moved by solvent. The colour moved 1.8 cm and Rf = 0.24. [3 marks]

📐 Calculations — step by step

  1. Write the equation:
    Rf = distance moved by colour ÷ distance moved by solvent
  2. Substitute the numbers:
    0.24 = 1.8 ÷ distance moved by solvent
  3. Rearrange to find the solvent distance:
    distance moved by solvent = 1.8 ÷ 0.24
  4. Calculate:
    distance moved by solvent = 7.5 cm

✅ Correct answer

7.5 cm

The mark scheme allows this final value only if the working shows the correct rearrangement.

💡 Key knowledge

  • Rf values are always a ratio.
  • Use the same unit for both distances — here, cm.
  • Final answers should be given with the correct unit.

🧠 Exam technique

  • If the question gives an equation, use it exactly.
  • Show the rearrangement clearly to gain method marks.
  • Check your answer: the solvent must travel further than the colour for Rf = 0.24, so 7.5 cm makes sense.

❌ Common errors

  • Doing 1.8 × 0.24 instead of dividing.
  • Using no units.
  • Reversing the ratio.
  • Rounding to an unsuitable value or forgetting that Rf has no unit, while distance does.

What the examiner wanted overall

💡 Top-level response features

  • Accurate chromatography vocabulary.
  • Clear links between setup errors and their effects.
  • Correct interpretation of spots as substances in the ink.
  • Correct use of the Rf equation and rearrangement.

🧠 How marks were awarded

  • 01.1: 2 marks available for each correct error-effect pair.
  • 01.2: 1 mark for each valid conclusion from the chromatogram.
  • 01.3: 1 mark for the correct explanation.
  • 01.4: marks for correct method and final answer.

❌ Biggest trap

Students often describe what they can see in the diagram, but the examiner wants the scientific consequence of each mistake or result.

Topics

Chemistry · Required Practicals · C8: Chemical Analysis · Chemistry Required Practicals

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 2 (Higher), 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.