AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), 2022: Question 3

10 marks · Standard Demand difficulty · Short Answer

Describe and calculate energy changes for a child bouncing on a trampoline, including energy stores, elastic potential energy in springs, and the meaning of work done.

Practise this question

Question

The question page shows Figure 5 with two simple drawings of a round trampoline supported by legs and surrounded by springs. In position A, a child is above the trampoline at maximum height; in position B, the child is standing at the lowest point on the depressed trampoline, with labels pointing to the sheet of material and stretched springs. Part 03.1 asks for descriptions of the changes to the stores of energy of the child, springs, and surroundings as the child moves from A to B, for 4 marks. Part 03.2 states that at position A each spring is stretched by 0.056 m and has elastic potential energy 4.9 J, and at position B the elastic potential energy of each spring is 8.1 J; it asks the student to calculate the extension of each spring at B using the Physics Equations Sheet, for 5 marks. Part 03.3 asks, in multiple-choice format, what the work done by the child is equal to, with options: the average force applied by the child, the maximum force applied by the child, the total energy store of the child, or the total energy transferred by the child.
Question text

03 A trampoline is made from a sheet of material held in place by stretched springs.

Figure 5 shows a child on a trampoline.

Figure 5

03.1 Position A shows the child’s maximum height above the trampoline.

Position B shows the lowest position reached by the child when landing on

the trampoline.

Describe the changes to the stores of energy of the:

• child

• springs

• surroundings

as the child moves from position A to position B.

[4 marks]

Child

Springs

Surroundings

*12* 14

03.2 When the child is at position A, each trampoline spring is stretched by 0.056 m

The elastic potential energy of each spring is 4.9 J

When the child is at position B, the elastic potential energy of each spring

increases to 8.1 J

Calculate the extension of each spring when the child is at position B.

Use the Physics Equations Sheet.

[5 marks]

Extension = m

03.3 As the child bounces on the trampoline the child does work.

What is the work done by the child equal to?

[1 mark]

Tick ( ) one box.

The average force applied by the child

The maximum force applied by the child

The total energy store of the child

The total energy transferred by the child

Mark scheme

Show the mark scheme The mark scheme is a table with columns for question number, answers, extra information, mark allocation, and AO/specification references. For 03.1 it awards marks for stating that the child's gravitational potential energy decreases, the child's kinetic energy increases then decreases to zero, the springs' elastic potential energy increases, and the surroundings' internal or thermal energy store increases; notes allow statements about dissipation and ignore some irrelevant descriptions. For 03.2 it shows the method using elastic potential energy equals one half k e squared: first 4.9 = 0.5 × k × 0.056 squared to find k = 3125 N/m, then 8.1 = 0.5 × 3125 × e squared, giving e = square root of 2 × 8.1 over 3125 = 0.072 m, with marks for substitution, rearrangement, and final answer. For 03.3 the correct multiple-choice answer is that work done equals the total energy transferred by the child.

Question 3

AO /

Question Answers Extra information Mark

Spec. Ref.

ignore descriptions of energy

03.1 transfers before the child AO1

reaches position A 6.1.1.1

Child 6.1.2.1

gravitational potential energy 1

decreases

kinetic energy increases and 1

then decreases (to zero)

Springs

elastic potential energy ignore references to kinetic 1

increases energy of the springs

Surroundings

internal / thermal store of energy allow energy is dissipated 1

increases allow (average) kinetic energy of

the particles increases

AO /

Spec. Ref.

At position A

03.2 4.9 = 0.5 × k × 0.0562 1 AO2

6.1.1.2

2×4.9 1

k = 2 = 3125 (N/m)

0.056

At position B

8.1 = 0.5 × 3125 × e2 allow a correct substitution of an 1

incorrectly calculated value of k

using 0.056 m and 4.9 J

allow e2 = 0.005184 1

2×8.1

e=�� � allow a correct re-arrangement

3125

using an incorrectly calculated

value of k

e = 0.072 (m) allow an answer consistent with 1

their calculated value of k

AO /

Spec. Ref.

03.3 the total energy transferred by 1 AO1

the child 6.1.1.4

Total Question 3 10

How to answer it

Trampoline Energy Stores

What this question tests

Energy stores, energy transfers, elastic potential energy, and using the equation E = 0.5 × k × e²

Students need to describe how energy changes as a child falls onto a trampoline, then calculate spring extension from elastic potential energy. The final part checks understanding that work done = energy transferred.

Question 03.1 — Changes in energy stores from position A to position B

✅ Correct answers

  • Child: gravitational potential energy decreases.
  • Child: kinetic energy increases and then decreases to zero at position B.
  • Springs: elastic potential energy increases.
  • Surroundings: internal/thermal energy store increases (energy is dissipated).

💡 Key knowledge

  • At the top, the child has the most gravitational potential energy.
  • As the child falls, that energy is transferred into kinetic energy.
  • When the trampoline stretches, the springs store more elastic potential energy.
  • Some energy is wasted to the surroundings as thermal energy due to friction and air resistance.

🧠 Exam technique

  • Use the exact language of energy stores.
  • For 4 marks, one clear point is needed for each of: child, springs, surroundings.
  • It is fine to say energy is “dissipated” for the surroundings.

❌ Common errors

  • Saying the child’s kinetic energy only increases — it must then decrease to zero at the lowest point.
  • Talking about “energy transferred” without naming the store.
  • Saying the springs have kinetic energy — the mark scheme wants elastic potential energy.
  • Ignoring the surroundings: this lost mark is common.
How marks are awarded: 1 mark for a correct change in the child’s store, 1 for the child’s kinetic energy, 1 for the springs, and 1 for the surroundings.

Question 03.2 — Calculate the extension of each spring at position B

📐 Calculations — step by step

  1. Use the elastic potential energy equation:
    E = 0.5 × k × e²
  2. Find the spring constant, k, using position A:
    4.9 = 0.5 × k × 0.056²
  3. Rearrange:
    k = (2 × 4.9) / 0.056²
  4. Calculate k:
    k = 9.8 / 0.003136 = 3125 N/m
  5. Use position B energy:
    8.1 = 0.5 × 3125 × e²
  6. Rearrange for e:
    e² = (2 × 8.1) / 3125 = 0.005184
  7. Square root:
    e = √0.005184 = 0.072 m

Extension = 0.072 m

✅ Correct answer

Extension of each spring at position B = 0.072 m

This matches the mark scheme answer. Full marks come from showing the substitution, rearrangement, and final value with the correct unit.

💡 Key knowledge

  • Elastic potential energy depends on extension.
  • The equation is E = 0.5 × k × e² .
  • k is the spring constant in N/m.
  • e is the extension in m.

🧠 Exam technique

  • Use the values from position A to find k first.
  • Then use the value at position B to find the new extension.
  • Write units clearly. Final answer must be in metres.
  • Show every rearrangement step for method marks.

❌ Common calculation traps

  • Forgetting the 0.5 in the equation.
  • Using 4.9 J directly for position B instead of the updated 8.1 J.
  • Mixing up extension and total length.
  • Leaving the answer in cm or forgetting the unit.
  • Not squaring the extension before rearranging.

✅ What distinguished top answers

  • They used the equation correctly and rearranged it neatly.
  • They showed the working for k and then for e .
  • They gave a final answer rounded sensibly to 0.072 m.

Question 03.3 — What is the work done by the child equal to?

✅ Correct answer

The total energy transferred by the child

💡 Key knowledge

  • Work done is the same as energy transferred.
  • In this question, the child transfers energy to the trampoline and surroundings.

🧠 Exam technique

  • This is a tick box question: only one option is correct.
  • Choose the response that matches the definition of work done most closely: energy transferred.

❌ Common errors

  • Choosing the average force or maximum force — these are not what work done equals.
  • Picking “total energy store of the child” — work done is about transfer, not just the store.
Examiner note: This is a straight recall point. The correct tick is the total energy transferred by the child.

Quick revision summary

✅ Remember these facts

  • Gravitational potential energy decreases as the child falls.
  • Kinetic energy increases then falls to zero at the lowest point.
  • Elastic potential energy in the springs increases.
  • Some energy is dissipated to the surroundings as thermal energy.
  • Use E = 0.5 × k × e² for elastic energy.

🧠 Final exam tip

GCSE energy questions often reward clear store names and step-by-step calculations. If you name the stores accurately and show your working with units, you are much more likely to secure full marks.

Topics

Physics · P1: Energy · P5: Forces

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 1 (Higher), 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.