AQA GCSE Combined Science: Trilogy Biology Paper 1 (Higher), 2023: Question 6
13 marks · Standard Demand difficulty · Extended Answer
Explain why starch must be digested, use a colorimeter graph to interpret starch concentration results, calculate mean rate of starch digestion, and predict the effect of pH 1 on amylase activity.
Practise this questionQuestion
Question text
06 Amylase is an enzyme that digests starch in the digestive system.
06.1 Explain why starch has to be digested.
[2 marks]
A student used a colorimeter to investigate the rate of starch digestion.
A colorimeter measures the percentage of light passing through a liquid.
The darker the colour of the liquid, the less light passes through.
The student:
• mixed 1 cm3 of starch suspension with 10 cm3 of iodine solution
• measured the percentage of light passing through the mixture
• repeated with different concentrations of starch suspension.
Figure 7 shows the results.
Figure 7
06.2 Suggest what liquid was used for the test with 0 g/dm3 starch concentration.
[1 mark]
06.3 Explain the change in the percentage of light passing through the different
concentrations of starch suspension in iodine solution.
Use Figure 7.
[3 marks]
The student then investigated the rate of starch digestion using amylase.
This is the method used.
1. Put 10 cm3 of starch suspension into a test tube.
2. Put 5 cm3 of amylase solution into a separate test tube.
3. Put both test tubes into a water bath at 37 °C for 10 minutes.
4. Mix the contents of both test tubes together in a beaker.
5. Put the beaker into the water bath.
6. Remove 1 cm3 of the mixture and add it to 10 cm3 of iodine solution.
7. Measure the percentage of light passing through the liquid.
8. Repeat steps 6 and 7 every minute for 5 minutes.
06.4 The starch suspension and the amylase solution were kept in the water bath for
10 minutes before being mixed together.
Give the reason why.
[1 mark]
Figure 8 shows the results.
Figure 8
06.5 The concentration of starch at 3 minutes was 0.3 g/dm3.
Calculate the mean rate of starch digestion for the first 3 minutes.
Use Figure 7 on page 18 and Figure 8 on page 22.
[4 marks]
Mean rate = g/dm3 per minute
06.6 The investigation was carried out at pH 7
Explain how the results would be different if the investigation was carried out at pH 1
Use Figure 8.
[3 marks]
Mark scheme
Show the mark scheme
Question 6
AO /
Question Answers Extra information Mark
Spec. Ref.
06.1 starch (molecules) are large / 1 AO1
insoluble 4.2.2.1
4.4.1.3
(so) cannot be absorbed (into allow (so) cannot pass through 1
the blood) the wall of the (small) intestine /
gut
allow (so) cannot diffuse into the
blood
allow sugar (molecules) are
small / soluble (1)
(so) can be absorbed into the
blood
or
(so) can pass through the wall of
the (small) intestine / gut (1)
AO /
Spec. Ref.
06.2 (10 cm3 dilute) iodine solution allow (10 cm3 dilute) iodine 1 AO3
and (1 cm3 of) water solution 4.2.2.1
allow water RPA3
ignore iodine unqualified
AO /
Spec. Ref.
06.3 percentage of light passing allow the more concentrated the 1 AO2
through the liquid decreased starch (suspension) the less 4.2.2.1
with increasing starch light could pass through RPA3
concentration
(because iodine) solution was allow (iodine) solution was 1
darker (in colour) blacker
allow the more (insoluble) starch
the more cloudy the mixture
(so) absorbed more light ignore less light passes through 1
AO /
Spec. Ref.
06.4 any one from: 1 AO3
• to allow them to reach 37 °C allow to allow them to reach 4.2.2.1
body temperature RPA4
• so they would be at the
optimum / same temperature
allow to equilibrate
AO /
Spec. Ref.
06.5 6.6 (g/dm3) allow answer in range 6.5 to 6.7 1 AO2
(g/dm3) 4.2.2.1
RPA3
6.6 – 0.3 allow correctly calculated value 1 RPA4
or consistent with range allowed in
6.3 (g/dm3) step 1
6.3 allow correct subtraction of 1
3 answer to step 1 minus 0.3 for
6.3 in this equation
2.1 (g/dm3 per minute) allow correctly calculated rate 1
using incorrectly calculated
22 value for 6.3
if no other marks awarded allow
1 mark for the concentrations
1.8 and 0.8 (g/dm3)
AO /
Spec. Ref.
06.6 (at pH 1) shape of active site allow (at pH 1) enzyme / 1 AO2
would be altered amylase would be denatured
(so) starch would not be allow (so) enzyme / amylase 1 AO2
digested would not work
allow (so) no reaction would
occur
allow (so) reaction would be (a
lot) slower
(so) percentage of light passing allow (so) percentage of light 1 AO3
through liquid would stay at 10 passing through liquid would
not change / increase 4.2.2.1
RPA3
RPA4
Total Question 6 14
How to answer it
Amylase, Starch Digestion and Colorimeter Data
Understanding why starch must be digested, interpreting a graph from a colorimeter investigation, explaining a change in results using scientific ideas, and carrying out a mean rate calculation with units.
Marks are mainly for: giving the correct biological explanation, reading data from graphs accurately, and showing a clear calculation method.
Part (a) 06.1 — Why starch has to be digested [2 marks]
✅ Correct answer
Starch molecules are large and insoluble, so they cannot be absorbed into the blood (or pass through the wall of the small intestine).
💡 Key knowledge
- Starch is too big to pass through the gut wall.
- Digestion breaks starch into smaller sugar molecules.
- Sugars are small/soluble, so they can be absorbed into the blood.
🧠 Exam technique
For 2 marks, you needed two linked ideas: one about starch being large/insoluble, and one about absorption not being possible.
❌ Common errors
- Saying only “starch is broken down” without explaining why.
- Writing “it is absorbed” instead of “it cannot be absorbed”.
- Confusing starch with sugar.
Part (b) 06.2 — Liquid used at 0 g/dm³ starch concentration [1 mark]
✅ Correct answer
10 cm³ dilute iodine solution and 1 cm³ water
💡 Key knowledge
At 0 g/dm³ starch, there is no starch present, so the test mixture should contain the same volume of liquid, but without starch. Water is used to replace the starch suspension.
🧠 Exam technique
Use the details from the question. The mark scheme accepts water or the full answer describing the diluted iodine mixture.
❌ Common errors
- Saying just “iodine” without showing it is diluted.
- Forgetting the water.
- Confusing the starch suspension with the iodine solution.
Part (c) 06.3 — Explain the graph in Figure 7 [3 marks]
✅ Correct answer
The percentage of light passing through decreased as starch concentration increased. This is because the iodine mixture became darker / more cloudy, so more light was absorbed.
💡 Key knowledge
- More starch makes the mixture darker/more cloudy.
- Darker liquids let less light through.
- Colorimeters measure percentage of light transmitted.
🧠 Exam technique
To get all 3 marks, make a cause → effect chain:
more starch → darker mixture → less light passes through / more light absorbed.
❌ Common errors
- Describing the graph without explaining why it changes.
- Saying “less light passes through because the starch is darker” without linking it to the iodine mixture.
- Writing “light is made” or “light disappears”.
Part (d) 06.4 — Why keep the solutions in the water bath for 10 minutes? [1 mark]
✅ Correct answer
To allow them to reach 37 °C / equilibrate / be at the optimum temperature.
💡 Key knowledge
Amylase works fastest near body temperature, around 37 °C. Temperature needs to be controlled so the test is fair.
🧠 Exam technique
For one mark, a short, direct answer is enough. Mention the temperature target or the idea of equilibration.
❌ Common errors
- Talking about “mixing” instead of temperature control.
- Saying “to make it warm” without stating why.
- Giving a vague answer like “to make the reaction better”.
Part (e) 06.5 — Calculate the mean rate of starch digestion in the first 3 minutes [4 marks]
📐 Calculations: step-by-step
- Read the starch concentration at 0 minutes from Figure 8: 6.6 g/dm³ (accept 6.5 to 6.7 g/dm³)
- Read the starch concentration at 3 minutes from the question: 0.3 g/dm³
- Find the change in concentration: 6.6 - 0.3 = 6.3 g/dm³
- Divide by time: 6.3 ÷ 3 = 2.1 g/dm³ per minute
✅ Correct answer
Mean rate = 2.1 g/dm³ per minute
🧠 Exam technique
- Use the correct units: g/dm³ per minute.
- Show both values used in the calculation.
- Use the graph accurately: 0 min is not exactly 6.0, it is about 6.6.
❌ Common errors
- Using 6.0 instead of 6.6 from the graph.
- Forgetting to subtract first.
- Writing the unit as just g/dm³, without “per minute”.
- Using percentage light values instead of starch concentration.
Part (f) 06.6 — What would happen at pH 1? [3 marks]
✅ Correct answer
At pH 1, the shape of the active site would be altered because the enzyme would be denatured. So starch would not be digested, and the percentage of light passing through would stay at 10 (or not change / increase).
💡 Key knowledge
- Enzymes have an optimum pH.
- Very acidic conditions can denature enzymes.
- If amylase does not work, starch remains in the mixture, so the light reading stays low.
🧠 Exam technique
This is a chain of 3 ideas: acid changes active site → enzyme stops working → result on the graph stays the same.
❌ Common errors
- Only saying “enzymes work best at pH 7” without applying it to this question.
- Missing the idea of denaturation or active site shape.
- Not linking the biology to the graph result.
Quick revision summary
💡 Key facts to remember
- Starch is large and insoluble.
- Amylase digests starch into sugars.
- Temperature and pH affect enzyme activity.
- Colorimeter: darker solution = less light passes through.
- Rate = change ÷ time.
🧠 How to score full marks
- Use the exact evidence from the graph.
- Write clear cause-and-effect statements.
- Include units in calculations.
- For enzyme questions, mention active site, denaturation, and the result.
❌ Biggest traps
- Mixing up starch and sugar.
- Describing a graph without explaining it.
- Forgetting the unit “per minute”.
- Not linking pH to enzyme shape.
Topics
Biology · Required Practicals · B2: Organisation · Biology Required Practicals
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Biology Paper 1 (Higher), 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.