AQA GCSE Combined Science: Trilogy Chemistry Paper 1 (Higher), 2023: Question 6
10 marks · Standard Demand difficulty · Short Answer
Describe how to obtain solid magnesium chloride from the reaction mixture; explain what happens to the magnesium atoms in the redox reaction; calculate the concentration in g/dm3 of the MgCl2 solution produced when 0.72 g Mg is added to 100 cm3 HCl (acid in excess).
Practise this questionQuestion
Question text
06 Acids react with some metals to produce soluble salts.
A student adds magnesium to hydrochloric acid until no more acid reacts and
excess magnesium remains.
The equation for the reaction is:
Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(g)
06.1 Describe how solid magnesium chloride is obtained from the reaction mixture.
[2 marks]
06.2 The reaction between magnesium and hydrochloric acid is a redox reaction.
Explain what happens to the magnesium atoms in this reaction.
[2 marks]
06.3 0.72 g of magnesium is added to 100 cm3 of hydrochloric acid.
The hydrochloric acid is in excess.
Calculate the concentration of the magnesium chloride (MgCl2) solution produced
in g/dm3.
Relative atomic mass (Ar): Mg = 24
Relative formula mass (Mr): MgCl2 = 95
[6 marks]
Concentration = g/dm3
Mark scheme
Show the mark scheme
Question 6
AO /
Question Answers Extra information Mark
Spec. Ref.
06.1 filter (to remove excess 1 AO1
magnesium) 5.1.1.2
5.4.2.1
(then) crystallisation (of allow (then) evaporation (of 1 5.4.2.3
magnesium chloride solution) water from magnesium chloride RPA8
solution)
AO /
Spec. Ref.
06.2 (magnesium atoms are) AO2
oxidised 1 5.4.1.4
5.4.2.1
(because the atoms) lose (two) 1 5.4.2.3
electrons RPA8
AO /
Spec. Ref.
06.3 0.72
(moles Mg =) 1 AO2
24 5.3.1.1
= 0.03 5.3.2.2
5.4.2.1
5.4.2.3
RPA8
(moles Mg = moles MgCl2) allow a correct calculation using 1
(so mass MgCl2 =) 0.03 × 95 an incorrectly calculated value
of moles of magnesium
allow a correct calculation using
an incorrectly calculated value
of moles of magnesium chloride
= 2.85 (g) 1
(100.0 cm3 = 0.100 dm3
mass
concentration = )
volume
2.85
= allow correct use of incorrectly 1
0.100 calculated mass of magnesium
chloride
= 28.5 (g/dm3) 1
Total Question 6 10
How to answer it
Magnesium + Hydrochloric Acid: salt preparation, redox and concentration
- Required practical style steps to make a soluble salt (filtering + crystallisation/evaporation).
- Understanding redox in metal + acid reactions (oxidation = loss of electrons).
- Moles and concentration (g/dm³): using Ar/Mr, reacting ratios, and converting cm³ to dm³.
Key idea: hydrochloric acid is used up; excess Mg remains (so Mg is not the limiting reactant in part 6.1, but in 6.3 HCl is in excess so Mg limits).
Part (6.1) Obtaining solid magnesium chloride from the reaction mixture (2 marks)
✅ Correct answer (what to write)
- Filter the mixture to remove the excess magnesium.
- Then obtain the salt by crystallisation (allowing water to evaporate from the magnesium chloride solution).
💡 Key knowledge
- After the reaction, you have: MgCl₂(aq) (dissolved) + solid Mg (leftover) + water.
- Filtering separates an insoluble solid (Mg) from a liquid (salt solution).
- Crystallisation means concentrating the solution and letting crystals form as water evaporates.
🧠 Exam technique
- For 2-mark “how to obtain solid salt” questions, aim for a clear two-step method in the correct order.
- Use process verbs: filter → crystallise/evaporate.
- Be specific: state what you are removing (excess magnesium) and what you are making (solid MgCl₂ crystals).
❌ Common errors (why marks are lost)
- Saying “evaporate to dryness” with no mention of crystallisation—can lose the method mark because salts may decompose / it’s not the standard practical wording.
- Missing filtering (you must remove the unreacted magnesium first).
- Writing “decant” instead of filter: decanting may leave solid Mg behind, so it’s less secure than the mark-scheme method.
Part (6.2) Redox: what happens to magnesium atoms? (2 marks)
✅ Correct answer (2 marks)
- Magnesium atoms are oxidised.
- Because magnesium atoms lose two electrons (forming Mg²⁺ ions).
💡 Key knowledge
- Oxidation = loss of electrons (OIL).
- Magnesium becomes a 2+ ion, so it must lose 2 electrons.
- In metal + acid reactions, the metal is usually oxidised and hydrogen ions are reduced to H₂.
🧠 Exam technique
- For “explain” redox questions, always include both:
- the redox word (oxidised / reduced)
- the electron idea (loss/gain + number of electrons)
- Link charge to electrons: Mg²⁺ means “lost 2 electrons”.
❌ Common errors
- Writing “magnesium is reduced” (wrong direction).
- Saying “gains electrons” or missing the number of electrons.
- Confusing oxidation with “gain of oxygen” only—here you must use the electron definition to score.
Part (6.3) Calculate concentration of MgCl₂ produced in g/dm³ (6 marks)
Statement: HCl is in excess ⇒ Mg is the limiting reactant.
📐 Calculations (step-by-step, with marks)
- Work out moles of Mg (1 mark):
moles = mass ÷ Ar
moles Mg = 0.72 ÷ 24 = 0.03 mol - Use the equation ratio (1 mark):
From Mg + 2HCl → MgCl₂ + H₂ , the ratio is 1 mol Mg : 1 mol MgCl₂
So moles MgCl₂ = 0.03 mol - Convert moles of MgCl₂ to mass (1 mark):
mass = moles × Mr
mass MgCl₂ = 0.03 × 95 = 2.85 g - Convert volume into dm³ (1 mark):
100 cm³ = 0.100 dm³ - Concentration in g/dm³ (1 mark):
concentration = mass ÷ volume
= 2.85 ÷ 0.100 = 28.5 g/dm³
✅ Final answer
💡 Key knowledge
- If a reactant is in excess, it does not limit the amount of product. Here, Mg limits.
- Always read coefficients: Mg : MgCl₂ is 1 : 1.
- g/dm³ uses volume in dm³. Convert: 1 dm³ = 1000 cm³.
🧠 Exam technique (how to secure the 6 marks)
- Write the key formula each time: moles = mass ÷ Mr/Ar , mass = moles × Mr , conc = mass ÷ volume .
- Show units clearly: g, mol, cm³, dm³, g/dm³.
- Keep 2–3 significant figures through the working, then round at the end. (28.5 is fine.)
❌ Common calculation traps
- Forgetting cm³ to dm³: using 100 instead of 0.100 makes the answer 1000× too small.
- Using Mr of Mg (24) instead of Mr of MgCl₂ (95) when finding the product mass.
- Wrong ratio from the equation: some students think “2 HCl” means “2 MgCl₂”. It doesn’t—coefficients show the reacting ratio for each substance.
- Writing the correct number but missing g/dm³ can lose the final mark in many mark schemes—always include units.
Quick full-mark checklist (Question 6 total = 10 marks)
🧠 What top responses do
- Use the standard salt-prep sequence: filter then crystallise.
- State redox with electron detail: oxidised because lose 2e⁻.
- Set out calculations in a clean chain with conversions and units.
💡 Key facts to memorise
- Oxidation = loss of electrons.
- 100 cm³ = 0.100 dm³.
- Concentration (g/dm³) = mass (g) ÷ volume (dm³).
✅ Final answers summary
- 6.1 Filter (remove excess Mg); then crystallisation/evaporation to get solid MgCl₂.
- 6.2 Mg is oxidised; Mg atoms lose 2 electrons.
- 6.3 Concentration = 28.5 g/dm³.
Topics
Chemistry · Required Practicals · C3: Quantitative Chemistry · C4: Chemical Changes
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 1 (Higher), 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.