AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), 2023: Question 2

15 marks · Standard Demand difficulty · Short Answer

Use a circuit and graph about body fat analysis to calculate resistance and potential difference, then interpret a relationship between leg resistance and body water percentage to judge health categories.

Practise this question

Question

The question sheet shows a physics practical context about body analysis using electrical resistance. At the top is Figure 3, a drawing of a lower leg standing on a pair of foot pads connected to a body composition meter. Figure 4 shows a simple circuit with a cell, switch, ammeter, and two resistors in parallel, one labelled 20 ohms and the other labelled R. The sub-questions ask where a voltmeter should be connected, why an answer of 26 ohms is impossible, to write the equation linking current, resistance and potential difference, and to calculate the potential difference when current is 480 mA and total resistance is 7.5 ohms. Lower down there is Table 1 listing resistance of R values and total resistance values, and Figure 5 is a blank scatter graph for plotting those results and drawing a line of best fit. The final section shows Figure 6, a graph of body water percentage against total resistance of legs in kΩ for categories A, B and C, with a question asking whether a student with 650 kΩ resistance is in a healthy body water range and to explain using the graph.
Question text

02 Body analysis scales use the electrical resistance of a person’s legs to estimate the

percentage of water in the person’s body.

Figure 3 shows body analysis scales.

Figure 3

The person’s legs contain both solid tissue and water.

A student used resistors to model the solid tissue and water.

The student connected a 20 Ω resistor in parallel with a resistor, R.

Figure 4 shows the circuit diagram.

Figure 4

02.1 To determine the total resistance of both resistors, a voltmeter must be connected into

the circuit.

Complete Figure 4 to show where the voltmeter should be connected.

[1 mark]

02.2 The student calculated the total resistance of the two resistors.

The student’s answer was 26 Ω.

Explain why the student’s answer cannot be correct.

[2 marks]

Use the Physics Equations Sheet to answer questions 02.3 and 02.4.

02.3 Write down the equation that links current (I), resistance (R) and

potential difference (V).

[1 mark]

02.4 When the total resistance of the resistors was 7.5 Ω the current in the circuit

was 480 mA.

Calculate the potential difference across the two resistors.

[3 marks]

Potential difference = V

The student investigated how the resistance of R affected the total resistance of

the circuit.

Table 1 shows the results.

Table 1

Resistance of R Total resistance of the circuit

in ohms in ohms

5.0 4.0

10.0 6.7

15.0 8.6

20.0 10.0

25.0 11.1

Some of the results are plotted in Figure 5.

Figure 5

02.5 Complete Figure 5.

You should:

• label both axes

• plot the two remaining values from Table 1

• draw the line of best fit.

[3 marks]

02.6 What resistance of R would give a total resistance of 4.4 Ω?

Use Figure 5.

[1 mark]

Resistance of R = Ω

The body analysis scales initially show a reading of 0.0 kg.

When the student steps onto the scales the reading is 64.8 kg.

The student steps off the scales and then immediately steps back on.

The scales now show a reading of 64.1 kg.

02.7 Complete the sentence.

[1 mark]

The difference between the two values given by the scales is due

to a error.

02.8 The height of the student is programmed into the scales.

The scales place the student into a category, A, B or C, based on height and mass.

Figure 6 shows how the scales use the category and the total resistance of the legs

to determine the body water percentage.

Figure 6

The total resistance of the student’s legs is 600 kΩ. A healthy body water percentage

is between 45% and 65%.

*10* The different measurements of the mass of the student mean that the student could

be in either category A or category B.

Evaluate if the student has a healthy body water percentage.

[3 marks]

Mark scheme

Show the mark scheme Mark scheme for AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), 2023: Question 2

Question 2

AO /

Question Answers Extra information Mark

Spec. Ref.

02.1 voltmeter symbol correct and 1 AO1

connected across the resistors 6.2.1.3

6.2.1.1

6.2.1.4

RPA15

AO /

Spec. Ref.

02.2 the total resistance must be less allow the total resistance cannot 1 AO2

than 20 be more than 20

because the total resistance of allow the total resistance of the 1 AO1

the resistors (in parallel) is less resistors (in parallel) is less than

than the resistance of the either resistor 6.2.2

smallest resistor 6.2.1.3

RPA15

AO /

Spec. Ref.

02.3 potential difference = current × 1 AO1

resistance 6.2.1.3

RPA15

or

V = IR – OMBINED SCIENCE: TRILOGY – –

AO /

Spec. Ref.

02.4 480 mA = 0.48 A 1 AO2

6.2.1.3

V = 0.48 × 7.5 allow a correct substitution of an 1 RPA15

incorrectly / not converted value

for current

V = 3.6 (V) allow an answer consistent with 1

their incorrectly / not converted

value for current

AO /

Spec. Ref.

02.5 x-axis labelled resistance of R in 1 AO2

and y-axis labelled total 6.2.1.3

resistance (of resistors) in RPA15

both points plotted correctly points must be plotted within ½ 1

small square

curved line of best fit drawn allow a curved line of best fit 1

which ignores an outlier

AO /

Spec. Ref.

02.6 reading from graph consistent allow an answer within ½ small 1 AO3

with their line of best fit square 6.2.1.3

RPA15

AO /

Spec. Ref.

02.7 random 1 AO3

– OMBINED SCIENCE: TRILOGY – – 6.2.1.3

AO /

Spec. Ref.

02.8 in category A the body water allow a value for A between 1 AO3

percentage is 61% 60% and 62% 6.2.1.3

in category B the body water 1

percentage is 68%

if in category A they have a 1

healthy body water percentage

and if in category B they have

an unhealthy body water

percentage

Total Question 2 15

How to answer it

Body resistance, graph skills, and body water interpretation

What this question tests

Using the correct circuit ideas for resistors in parallel, applying V = IR, reading and drawing on a table and graph, and using data to make a scientific judgement. It also checks that you can explain a random error and interpret results from a body-water graph.

Question 02.1 — Connect the voltmeter

✅ Correct answer

Draw the voltmeter symbol V and connect it across the two resistors (in parallel with the resistor pair).

Mark idea: 1 mark for the voltmeter symbol correctly placed across the resistors.

💡 Key knowledge

  • A voltmeter measures potential difference.
  • It must be connected in parallel with the component(s) you want to measure.
  • Here, the question asks for the p.d. across the two resistors together.

🧠 Exam technique

  • Place the voltmeter across the whole resistor section, not in the main loop.
  • Make sure the circuit symbol is clear and recognisable.

❌ Common errors

  • Putting the voltmeter in series.
  • Connecting it across just one resistor when the question wants both.
  • Drawing an ammeter symbol instead of a voltmeter.

Question 02.2 — Why the answer cannot be 28 Ω

✅ Correct answer

The total resistance must be less than 20 Ω because the two resistors are connected in parallel, and the total resistance of resistors in parallel is less than the resistance of the smallest resistor.

Two separate marking points: one for “less than 20 Ω”, one for the parallel-resistance explanation.

💡 Key knowledge

  • For resistors in parallel, the total resistance is always smaller than the smallest branch resistance.
  • So if one resistor is 20 Ω, the combined resistance must be below 20 Ω.

🧠 Exam technique

  • Use the word parallel explicitly.
  • If you can, compare to the smallest resistor: that earns the reasoning mark.

❌ Common errors

  • Saying the total resistance is more than 20 Ω.
  • Just writing “because the resistors are in parallel” without explaining what that means.
  • Confusing this with series, where resistances add.

Question 02.3 — Equation linking current, resistance and p.d.

✅ Correct answer

potential difference = current × resistance

or V = IR

1 mark for the correct equation.

💡 Key knowledge

  • V = potential difference in volts (V)
  • I = current in amperes (A)
  • R = resistance in ohms (Ω)

🧠 Exam technique

If you forget symbols, write the full words: potential difference = current × resistance. That is fully acceptable.

❌ Common errors

  • Writing V = I ÷ R.
  • Mixing up current and resistance.
  • Using the wrong units.

Question 02.4 — Calculate the potential difference

📐 Calculations

  1. Convert current from mA to A: 480 mA = 0.48 A
  2. Use V = IR
  3. Substitute values: V = 0.48 × 7.5
  4. Calculate: V = 3.6 V

Final answer: 3.6 V

✅ Correct answer

3.6 V

Marking points were awarded for converting 480 mA to 0.48 A, substituting into the equation, and giving the correct final value.

🧠 Exam technique

  • Always convert mA to A before calculating.
  • Check your answer has the correct unit: V.
  • Use a sensible number of significant figures: here 3.6 V matches the data.

❌ Common errors

  • Using 480 instead of 0.48.
  • Forgetting the unit conversion from mA to A.
  • Giving the answer in Ω instead of V.

Question 02.5 — Complete the graph from Table 1

✅ Correct answer

Label the axes:

  • x-axis: resistance of R in Ω
  • y-axis: total resistance (of resistors) in Ω

Plot the two missing points from Table 1 correctly and draw a curved line of best fit.

💡 Key knowledge

  • Graph axes must include quantity + unit.
  • For these results, the relationship is not a straight line, so a curve is needed.
  • The plotted points from the table are:
    (5, 4.0), (10, 6.7), (15, 8.6), (20, 10.0), (25, 11.1)

🧠 Exam technique

  • Plot points carefully, aiming within ½ small square.
  • Draw a smooth curve through the trend, not point-to-point straight lines.
  • If there were an outlier, ignore it only if the question allows it; here all table values should be used.

❌ Common errors

  • Forgetting to label axes.
  • Swapping x and y axes.
  • Plotting the wrong coordinates.
  • Drawing a straight line when the data clearly curves.

Question 02.6 — Read from the graph

✅ Correct answer

A resistance of about 14 Ω gives a total resistance of 4.4 Ω.

The mark scheme accepts a value consistent with the line of best fit, within ½ small square.

💡 Key knowledge

  • Read across from 4.4 Ω on the y-axis to the curve, then down to the x-axis.
  • This is an estimate, not an exact table value.

🧠 Exam technique

  • Use a ruler to read the graph carefully.
  • Answer with a value that fits the curve, not necessarily a neat whole number.

❌ Common errors

  • Reading from the wrong axis.
  • Ignoring the line of best fit and using the nearest plotted point instead.
  • Giving a value far from the curve.

Question 02.7 — Why did the scales give different readings?

✅ Correct answer

The difference between the two values is due to a random error.

1 mark for “random”.

💡 Key knowledge

  • A random error causes measurements to vary without a fixed pattern.
  • Small changes in how a person stands on the scales can change the reading slightly.

🧠 Exam technique

If the question asks for the type of error, use the exact term: random error.

❌ Common errors

  • Saying systematic error.
  • Writing just “error” without naming it.
  • Describing the equipment instead of the type of error.

Question 02.8 — Evaluate whether the student is healthy

✅ Correct answer

From the graph, category A has a body water percentage of about 61%, and category B has about 68%.

The student’s body water percentage is 64.1%, which is between 45% and 65%, so:

  • if the student is in category A, they have a healthy body water percentage
  • if the student is in category B, they have an unhealthy body water percentage

Therefore, the student could be in category A or category B, but the health judgement is different for each category.

💡 Key knowledge

  • Read values from the graph carefully.
  • Use the given healthy range: 45% to 65%.
  • Then compare the student’s value of 64.1% to that range.

🧠 Exam technique

  • Top-level answers use evidence from the graph plus the health range.
  • Say what happens for both categories because the student could fit either one.
  • State a clear conclusion rather than leaving the answer as a list of numbers.

❌ Common errors

  • Not using the graph values for category A and B.
  • Forgetting the healthy range is 45%–65%.
  • Saying the student is definitely healthy without checking category B.
  • Not explaining that category A is healthy but category B is not.

Key takeaways for full marks

💡 Remember

  • Voltmeter goes in parallel.
  • Parallel resistance is less than the smallest resistor.
  • V = IR is essential for calculations.
  • Convert mA to A before calculating.
  • Graphs need correct labels, points, and line of best fit.
  • Use the word random for an unpredictable measurement difference.

🧠 How marks were earned

  • Short factual answers were enough for the 1-mark recall questions.
  • Explanations gained marks when they included the physics reason, not just the answer.
  • Calculation marks came from correct method, conversion, and final unit.
  • Graph questions needed accuracy and a sensible curve, not a rushed straight line.

Topics

Physics · P2: Electricity

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 1 (Higher), 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.