AQA GCSE Combined Science: Trilogy Physics Paper 2 (Foundation), 2023: Question 5

11 marks · Standard Demand difficulty · Short Answer

Calculate work done and mass of an engineer climbing a ladder, identifying energy stores and using the weight equation.

Practise this question

Question

A multi-part physics question about an engineer climbing a ladder. Figure 13 shows a photo of an engineer on a ladder with a rung labeled. The text states the distance between rungs is 30 cm. Part 05.1 asks to convert 30 cm to metres from a multiple-choice list. Part 05.2 asks to calculate work done for one rung given a weight of 710 N using the provided equation: work done = force x distance. Part 05.3 asks for a reason why carrying equipment increases the work done. Part 05.4 asks to identify two energy stores that increase as the engineer climbs. Part 05.5 asks for the equation linking gravitational field strength, mass, and weight. Part 05.6 asks to calculate the mass of the engineer to 2 significant figures given a weight of 710 N and g = 9.8 N/kg.
Question text

05 Figure 13 shows an engineer climbing up a ladder.

Figure 13

The distance between each rung on the ladder is 30 cm.

05.1 What is 30 cm in metres?

[1 mark]

Tick ( ) one box.

0.030 m 0.30 m 25 3.0 m 30 m

05.2 The engineer has a weight of 710 N.

Calculate the work done when climbing up one rung of the ladder.

Use your answer to Question 05.1 and the equation:

work done = force × distance

[2 marks]

*24* Work done = Nm

05.3 The engineer climbs the ladder carrying some equipment.

Give the reason why carrying equipment increases the work done by the engineer

when climbing the ladder.

[1 mark]

05.4 The engineer is stationary at the top of the ladder.

Which energy stores of the engineer increase due to the engineer climbing

the ladder?

[2 marks]

Tick ( ) two boxes.

Chemical

Elastic potential

Gravitational potential

Kinetic

Thermal 27

Use the Physics Equations Sheet to answer questions 05.5 and 05.6.

05.5 Write down the equation that links gravitational field strength (g), mass (m)

and weight (W).

[1 mark]

05.6 The engineer has a weight of 710 N.

gravitational field strength = 9.8 N/kg

Calculate the mass of the engineer.

Give your answer to 2 significant figures.

[4 marks]

Mass (2 significant figures) = kg

Mark scheme

Show the mark scheme The mark scheme for question 5. 05.1: 0.30 (m) (1 mark). 05.2: W = 710 x 0.30 = 213 Nm (2 marks). 05.3: force / weight is greater (1 mark). 05.4: gravitational potential and thermal (2 marks). 05.5: weight = mass x gravitational field strength or W = mg (1 mark). 05.6: substitution 710 = m x 9.8 (1 mark), rearrangement m = 710 / 9.8 (1 mark), calculation 72.4... (1 mark), and final answer 72 (kg) for 2 significant figures (1 mark).

Question 5

AO /

Question Answers Extra information Mark

Spec. Ref.

05.1 0.30 (m) 1 AO2

6.5.2

AO /

Spec. Ref.

05.2 W = 710 × 0.30 1 AO2

6.5.2

W = 213 Nm 1

allow ecf from question 05.1

AO /

Spec. Ref.

05.3 force / weight is greater 1 AO3

6.5.2

AO /

Spec. Ref.

05.4 gravitational potential 1 AO2

6.5.2

thermal 1

AO /

Spec. Ref.

05.5 weight = mass × gravitational 1 AO1

field strength 6.5.1.3

or

W = mg – OMBINED SCIENCE: TRILOGY – –

AO /

Spec. Ref.

05.6 710 = m × 9.8 1 AO2

6.5.1.3

m = 1

9.8

m = 72.4… 1 13

m = 72 (kg) this mark can only be awarded if 1

the correct equation is used and

a value of m is calculated

Total Question 5 11

How to answer it

Work, Energy, and Weight on a Ladder

What this question tests

This question assesses your ability to convert units, calculate work done, identify energy store changes, and rearrange the weight equation. It specifically looks for precision in significant figures and the application of Error Carried Forward (ECF).

Part 05.1 & 05.2

Calculating Work Done

Unit Conversion and Substitution

Correct Answers

  • 05.1: 0.30 m
  • 05.2: 213 Nm

Exam Technique

In 05.2, the question says "Use your answer to Question 05.1". If you got 05.1 wrong, you can still get full marks in 05.2 by using your incorrect number correctly. This is called Error Carried Forward.

Calculation Steps for 05.2

  1. Identify Force: Weight is the force, which is 710 N.
  2. Identify Distance: Use the converted distance from 05.1 (0.30 m).
  3. Apply Equation: Work done = 710 N × 0.30 m
  4. Final Answer: 213 Nm
Part 05.3 & 05.4

Forces and Energy Stores

Conceptual Understanding

Key Knowledge

Work Done: To move an object, you must overcome a force. If the equipment adds mass, the total weight (force) increases, so more work must be done to move the same distance.

Correct Answers

05.3: The force (or weight) is greater.

05.4: Gravitational potential AND Thermal.

Common Errors

  • 05.3: Students often say "it's harder" or "it takes more energy." While true, the examiner wants the scientific reason: the force/weight has increased.
  • 05.4: Many students forget Thermal. As the engineer climbs, muscles produce heat, and friction in joints/ladder rungs increases the thermal store.
Part 05.5 & 05.6

Mass and Weight

Rearranging Equations and Significant Figures

The Equation (05.5)

Weight = mass × gravitational field strength

W = m × g

Calculation Steps for 05.6

  1. Substitute values: 710 = m × 9.8
  2. Rearrange for m: m = 710 / 9.8
  3. Calculate: m = 72.4489...
  4. Round to 2 Sig Figs: Look at the third digit (4). Since it is less than 5, keep the 72.
  5. Final Answer: 72 kg

Significant Figures Trap

This question specifically asks for 2 significant figures. Even if your calculation is perfect, you lose the final mark if you write "72.4" or "72.45".

Common Misconception

Don't confuse mass (kg) with weight (N). Weight is a force caused by gravity acting on mass. On Earth, g is always 9.8 N/kg.

Total Marks Available: 11 marks

Topics

Physics · P1: Energy · P5: Forces

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 2 (Foundation), 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.