AQA GCSE Combined Science: Trilogy Physics Paper 2 (Higher), 2023: Question 3

8 marks · Standard Demand difficulty · Short Answer

Calculate a wavelength from a ripple tank scale, complete a mean calculation from repeated measurements, identify what shows precision, and describe the difference between longitudinal and transverse waves.

Practise this question

Question

The question is about a ripple tank demonstration of water waves. A diagram shows several evenly spaced vertical grey bars representing the shadow image of waves on a screen, labelled Figure 4. The text says that 1.0 mm on Figure 4 represents 5.0 mm on the screen, and asks the student to determine an accurate value for the wavelength in mm and show working. Below, Table 2 lists five wavelength measurements in millimetres: 96, 99, 97, X, and 97, with the mean given as 97. The remaining parts ask the student to calculate X, choose which statement supports the claim that the results are very precise, and describe the difference between longitudinal and transverse waves.
Question text

03 A teacher used a ripple tank to demonstrate water waves.

The teacher used a lamp to project a shadow of the water waves onto a screen below

the ripple tank.

03.1 Figure 4 represents the shadow of the water waves seen on the screen.

Figure 4

1.0 mm on Figure 4 represents 5.0 mm on the screen.

Determine an accurate value for the wavelength of the waves on the screen.

Give your answer in mm.

Show how you work out your answer.

[3 marks]

Wavelength = mm

The teacher adjusted the frequency of the waves produced in the ripple tank.

The teacher measured the wavelength five times.

Table 2 shows the results.

Table 2

Measurement 1 2 3 4 5 Mean

Wavelength in millimetres 96 99 97 X 97 97

03.2 Calculate value X in Table 2.

[2 marks]

X = mm

03.3 The teacher states that the results are very precise.

Which of the following supports the statement made by the teacher?

[1 mark]

Tick ( ) one box.

The mean value is very close to the true value.

The spread of values about the mean is very small.

The values are all given to the nearest millimetre.

The wavelength measurement was taken five times.12

03.4 Describe the difference between longitudinal waves and transverse waves.

[2 marks]

Mark scheme

Show the mark scheme The mark scheme shows four separate marking sections for questions 03.1 to 03.4. For 03.1, it awards marks for finding the distance across all 8 wavelengths as 113 mm, multiplying by 5.0, and giving a wavelength of 70 mm, with an accepted range of 68 to 72 mm. For 03.2, it shows the mean calculation 97 × 5 = 96 + 99 + 97 + X + 97 and gives X = 96. For 03.3, the correct statement is that the spread of values about the mean is very small. For 03.4, it states that oscillations in longitudinal waves are parallel to the direction of energy transfer, whereas oscillations in transverse waves are perpendicular to the direction of energy transfer.

Question 3

AO /

Question Answers Extra information Mark

Spec. Ref.

03.1 distance across all 8 allow a range from 108 (mm) to 1 AO2

wavelengths = 113 (mm) 118 (mm) 6.6.1.2

RPA20

their distance × 5.0 1

wavelength = 70 (mm) allow a range from 68 mm to 1

72 mm

AO /

Spec. Ref.

03.2 97 × 5 = (96 + 99 + 97 + X + 97) allow X = (97 × 5) – (96 + 99 + 1 AO2

97 + 97) 6.6.1.2

RPA20

X = 96 1

AO /

Spec. Ref.

03.3 the spread of values about the 1 AO3

mean is very small 6.6.1.2

RPA20

AO /

Spec. Ref.

03.4 the oscillations / vibrations in 1 AO1

longitudinal waves are parallel 6.6.1.1

to the direction of energy

transfer allow direction of wave travel for

direction of energy transfer

(whereas) the oscillations / 1

vibrations in transverse waves

are perpendicular to the

direction of energy transfer

if no other mark awarded allow 1

mark for oscillations / vibrations

in longitudinal waves are parallel

and oscillations / vibrations in

transverse waves are

perpendicular

Total Question 3 8

How to answer it

AQA GCSE Combined Science: Trilogy

Ripple Tank Waves

What this question tests

  • Measuring wavelength accurately from a diagram using a scale.
  • Using the mean to find a missing value in a results table.
  • Understanding what precision means in experimental data.
  • Describing the difference between longitudinal and transverse waves.

Part 03.1 – Determining the wavelength from the wave pattern

3 marks

✅ Correct answer

  • Measure across 8 wavelengths on Figure 4.
  • Distance on Figure 4 is about 113 mm (mark scheme allows 108 mm to 118 mm).
  • Convert using the scale: distance × 5.0
  • Screen distance across 8 wavelengths = 113 × 5.0 = 565 mm
  • One wavelength = 565 ÷ 8 = 70.6 mm
  • Wavelength = 70 mm
Mark breakdown: 1 mark for a sensible total measurement across 8 wavelengths, 1 mark for using the ×5.0 scale, 1 mark for a final wavelength in the allowed range 68–72 mm.

📐 Calculation steps

  1. Measure the total distance across 8 wavelengths on the figure.
  2. Example measurement: 113 mm .
  3. Convert to actual screen distance: 113 × 5.0 = 565 mm .
  4. Find one wavelength: 565 ÷ 8 = 70.6 mm .
  5. Round appropriately: 70 mm (or a value in the allowed range).

💡 Key knowledge

  • Wavelength is the distance from one wave to the next matching point.
  • On this image, it is more accurate to measure across several wavelengths and then divide.
  • The scale says 1.0 mm on Figure 4 represents 5.0 mm on the screen, so you must multiply by 5.

🧠 Exam technique

  • Show every stage of working, because this is how the method marks are awarded.
  • Always measure across several waves, not just one gap.
  • State the final answer with units: mm.
  • Top answers clearly showed: total measured distance, scale conversion, then divide by 8.

❌ Common errors

  • Forgetting to use the scale factor of 5.0.
  • Measuring only one wavelength, which is less accurate.
  • Dividing by the wrong number of wavelengths.
  • Giving the measured figure distance instead of the actual screen wavelength.
  • Missing off the unit mm.

Part 03.2 – Calculating the missing value X

2 marks

✅ Correct answer

The mean is 97 mm for 5 measurements, so:

97 × 5 = 96 + 99 + 97 + X + 97

485 = 389 + X

X = 96

X = 96 mm

Mark breakdown: 1 mark for setting up the correct equation using the mean, 1 mark for X = 96.

📐 Calculation steps

  1. Use mean = total ÷ number of values.
  2. Total of all 5 values = 97 × 5 = 485 .
  3. Add the known values: 96 + 99 + 97 + 97 = 389 .
  4. Find the missing value: 485 - 389 = 96 .

💡 Key knowledge

  • Mean = total of values ÷ number of values.
  • So total = mean × number of values.

🧠 Exam technique

  • If a mean and one missing value are given, first find the total.
  • Write the equation before solving it. This helps secure the method mark.
  • Keep units consistent: here everything is in mm.

❌ Common calculation traps

  • Adding the known values incorrectly.
  • Dividing by 5 instead of multiplying by 5.
  • Using only 4 values when finding the total from the mean.
  • Forgetting that the mean includes the missing value too.

Part 03.3 – Identifying evidence for precision

1 mark

✅ Correct answer

Tick: The spread of values about the mean is very small.

1 mark for choosing the statement linked to precision.

💡 Key knowledge

  • Precision means repeated values are close together.
  • Accuracy means close to the true value.

🧠 Exam technique

  • This is a common science vocabulary test: know the difference between precision and accuracy.
  • If values are tightly grouped, that supports precision.

❌ Common errors

  • Choosing “the mean value is very close to the true value” — that describes accuracy, not precision.
  • Thinking “taken five times” automatically means precise. Repeats help, but precision is about how close the results are to each other.
  • Thinking “nearest millimetre” proves precision. That only tells you the resolution used.

Part 03.4 – Longitudinal vs transverse waves

2 marks

✅ Correct answer

  • In longitudinal waves, the oscillations / vibrations are parallel to the direction of energy transfer.
  • In transverse waves, the oscillations / vibrations are perpendicular to the direction of energy transfer.
1 mark for correctly describing longitudinal waves, 1 mark for correctly describing transverse waves. The mark scheme also allows direction of wave travel instead of direction of energy transfer.

💡 Key knowledge

  • Parallel means in the same direction.
  • Perpendicular means at 90° to the direction.
  • Longitudinal examples include sound waves.
  • Transverse examples include light waves and ripples on water at GCSE level.

🧠 Exam technique

  • For 2 marks, make sure you compare both wave types.
  • Use the key words parallel and perpendicular.
  • Link your description to the direction of energy transfer to match the mark scheme exactly.

❌ Common errors

  • Saying one wave moves “up and down” and the other “side to side” without linking to energy transfer.
  • Mixing up parallel and perpendicular.
  • Only describing one type of wave, which would lose a mark.

Examiner insight across the whole question

💡 What separated strong answers?

  • Clear working in the wavelength and mean calculations.
  • Accurate use of science vocabulary: precision, parallel, perpendicular.
  • Correct units written in final answers.

❌ Where students lost marks

  • Not converting the measured diagram distance using the scale.
  • Confusing precision with accuracy.
  • Giving vague wave definitions instead of using the accepted wording.

🧠 Best quick strategy

  1. For measurements, measure across multiple waves.
  2. For means, find the total first.
  3. For multiple-choice science terms, check whether the question is about accuracy or precision.
  4. For definitions, use exact comparison words from the specification.

Full-mark answers in one place

✅ Model answers

  • 03.1 Measure across 8 wavelengths, for example 113 mm on the figure. Actual distance on screen = 113 × 5.0 = 565 mm. Wavelength = 565 ÷ 8 = 70.6 mm, so 70 mm.
  • 03.2 97 × 5 = 96 + 99 + 97 + X + 97, so X = 96 mm.
  • 03.3 The spread of values about the mean is very small.
  • 03.4 In longitudinal waves, the vibrations are parallel to the direction of energy transfer. In transverse waves, the vibrations are perpendicular to the direction of energy transfer.

Total for Question 3: 8 marks

Topics

Physics · P6: Waves · Physics Required Practicals

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 2 (Higher), 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.