AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), 2024: Question 1

12 marks · Standard Demand difficulty · Short Answer

Answer a set of short questions about an electric whisk involving energy stores, power equations, electrical power calculations, mains potential difference, and how resistance changes with speed.

Practise this question

Question

The question page shows a labelled photograph of a handheld electric whisk plugged into the mains, with arrows pointing to the whisk body and the metal beater. Beneath it are seven short-answer parts: give two energy stores that increase when the whisk is switched on; write the equation linking power, time and work done; calculate the time for 23 000 J of work at a power of 92 W; choose from four boxed equations the one linking current, power and resistance; calculate power for a whisk with current 500 mA and resistance 640 ohms; state the mains potential difference between live and neutral wires; and complete a sentence explaining that when beater speed increases, current increases because the whisk resistance changes. Answer lines and tick boxes are provided, and the total marks across the question are 12.
Question text

01 Figure 1 shows an electric whisk that plugs into the mains electricity supply.

The whisk can mix food by spinning a beater.

Figure 1

01.1 Give two energy stores that increase when the whisk is switched on.

[2 marks]

Use the Physics Equations Sheet to answer questions 01.2 and 01.3.

01.2 Work is done by the whisk when it is used to mix food.

Write down the equation that links power (P), time (t) and work done (W).

[1 mark]

01.3 The power output of the whisk is 92 W.

Calculate the time for the whisk to do 23 000 J of work.

[3 marks]

Time = s

Use the Physics Equations Sheet to answer questions 01.4 and 01.5.

01.4 Which equation links current (I), power (P) and resistance (R)?

[1 mark]

Tick ( ) one box.

I

P = 2

R

P = I R2

I2

P =

R

P = I2 R

01.5 The current in the whisk is 500 mA.

The resistance of the whisk is 640 Ω.

Calculate the power of the whisk.

[3 marks]

Power = W

The whisk has several settings that allow the beater to spin at different speeds.

A faster beater speed needs a greater power input from the mains electricity supply.

01.6 What is the potential difference between the live wire and neutral wire in the

mains electricity supply?

[1 mark]

*04* V

01.7 Changing the beater speed does not change the potential difference between the live

wire and neutral wire.

The power input to the whisk changes because the current in the whisk changes.

Complete the sentence.

[1 mark]

When the beater speed increases, the current in the whisk increases because the

resistance of the whisk .

Mark scheme

Show the mark scheme Mark scheme for AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), 2024: Question 1

Question 1

AO /

Question Answers Extra information Mark

Spec. Ref.

01.1 ignore sound AO1

6.2.4.2

kinetic energy (of the beater / 1 6.1.2.1

food) 6.1.1.1

internal / thermal energy (of the 1

surroundings / whisk / food)

AO /

Spec. Ref.

01.2 work done 1 AO1

power =

time 6.1.1.4

or

W

P =

t

AO /

Spec. Ref.

01.3 23 000 1 AO2

92 =

time 6.1.1.4

23 000

time = 1

250 (s) 1

AO /

Spec. Ref.

01.4 P = I2 R 1 AO1

– – – 6.2.4.1

AO /

Spec. Ref.

01.5 I = 0.500 A 1 AO2

6.2.4.1 7

P = 0.5002 × 640

allow a correct substitution of an 1

incorrectly / not converted

current

P = 160 (W) allow a correct calculation using 1

an incorrectly / not converted

current

AO /

Spec. Ref.

01.6 230 (V) 1 AO1

6.2.3.2

AO /

Spec. Ref.

01.7 decreases 1 AO1

6.2.4.1

Total Question 1 12

How to answer it

Electric Whisk: Energy, Power and Mains Electricity

What this question tests

You need to recall energy stores, use the equation P = W / t , rearrange it to find time, use P = I²R , convert units correctly, and remember the mains potential difference in the UK is 230 V .

Question overview

This question is a short GCSE Physics calculation and recall set about an electric whisk. It mainly checks direct knowledge and accurate substitution into equations. The marks are spread across several simple parts, so full marks come from giving the exact physics phrase, choosing the correct equation, and showing the calculation clearly.

Part (a): Energy stores that increase when the whisk is switched on

01.1 Give two energy stores that increase. [2 marks]

✅ Correct answers

  • Kinetic energy of the beater or food
  • Internal energy / thermal energy of the surroundings, whisk or food

💡 Key knowledge

  • The beater starts moving, so its kinetic energy increases.
  • Some electrical energy is wasted as heat, so internal energy increases.
  • The mark scheme ignores sound, so do not use sound energy here.

🧠 Exam technique

  • Give two different energy stores.
  • Use the exact GCSE language: kinetic and internal/thermal.
  • “Energy is transferred to…” is fine, but name the store clearly for the mark.

❌ Common errors

  • Writing sound energy instead of internal energy.
  • Saying only “energy increases” without naming the store.
  • Repeating the same store in two different words.

Part (b): Equation linking power, work done and time

01.2 Write down the equation that links power, time and work done. [1 mark]

✅ Correct answer

power = work done / time

P = W / t

💡 Key knowledge

  • Power is the rate of energy transfer or work done.
  • Unit check: power is in W , work done in J , time in s .

🧠 Exam technique

  • You can write the words or symbols.
  • If using symbols, make sure the letter is correct: P , W , t .

Part (c): Calculating time from power and work done

01.3 The power output is 92 W. Calculate the time for the whisk to do 23 000 J of work. [3 marks]

📐 Calculations: step-by-step

  1. Start with P = W / t
  2. Substitute the values: 92 = 23 000 / t
  3. Rearrange: t = 23 000 / 92
  4. Calculate: t = 250 s

Final answer: 250 s

🧠 Exam technique

  • Write the equation first to secure method marks.
  • Show the rearrangement, not just the final number.
  • Use the correct unit: s .

❌ Common calculation traps

  • Using t = P / W by mistake.
  • Forgetting to rearrange the equation before substituting.
  • Writing the answer without units.
  • Using 23 000 as 23.0 or 2300 by accident.
How marks are awarded: 1 mark for using the correct equation, 1 mark for correct substitution/rearrangement, 1 mark for the correct final answer with units.

Part (d): Equation linking current, power and resistance

01.4 Which equation links current, power and resistance? [1 mark]

✅ Correct answer

P = I²R

💡 Key knowledge

  • This is the standard electrical power equation for a component.
  • It shows power depends on current squared and resistance.

❌ Common errors

  • Choosing a wrong rearrangement, such as P = I / R .
  • Mixing up this equation with V = IR .

Part (e): Calculating power from current and resistance

01.5 Current = 500 mA, resistance = 640 Ω. Calculate the power. [3 marks]

📐 Calculations: step-by-step

  1. Convert the current: 500 mA = 0.500 A
  2. Use the equation: P = I²R
  3. Substitute: P = 0.500² × 640
  4. Calculate: P = 160 W

Final answer: 160 W

🧠 Exam technique

  • Convert mA to A before calculating.
  • Square the current first: 0.500² , not the resistance.
  • Include units in the final answer.
  • The mark scheme allows correct working even if the current is not converted, but the safest method is to convert first.

❌ Common calculation traps

  • Using 500 instead of 0.500 .
  • Using P = I R or P = V I incorrectly.
  • Forgetting the square on the current.
  • Giving the answer with no unit or the wrong unit.
How marks are awarded: 1 mark for converting the current, 1 mark for correct substitution, 1 mark for the correct answer of 160 W.

Part (f): Mains potential difference

01.6 What is the potential difference between the live wire and neutral wire? [1 mark]

✅ Correct answer

230 V

💡 Key knowledge

  • The UK mains electricity supply is 230 V .
  • This is the potential difference between live and neutral.

❌ Common errors

  • Writing a different value from memory.
  • Writing the unit incorrectly or forgetting it.

Part (g): Effect of increasing speed on current and resistance

01.7 Complete the sentence: when the beater speed increases, the current increases because the resistance of the whisk ________. [1 mark]

✅ Correct answer

decreases

💡 Key knowledge

  • At a fixed mains potential difference, if current increases, resistance must decrease.
  • This links to P = I²R : more current means more power.

🧠 Exam technique

  • Read the sentence carefully and complete it with one physics word.
  • The mark is for the correct direction of change.

❌ Common errors

  • Writing increases.
  • Trying to explain too much and accidentally contradicting the answer.

Final examiner insight

💡 What top answers did well

  • Used the exact required energy stores in 01.1.
  • Wrote the correct equation before working out the answer in calculations.
  • Converted mA to A correctly.
  • Kept units attached to final answers.

🧠 Best strategy in the exam

  • For recall questions, give the standard GCSE phrasing.
  • For calculations, always write the equation first.
  • Check whether the question wants a value, a unit, or a completed sentence.

Topics

Physics · P1: Energy · P2: Electricity

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 1 (Higher), 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.