AQA GCSE Combined Science: Trilogy Physics Paper 2 (Higher), 2024: Question 6

13 marks · Standard Demand difficulty · Extended Answer

Calculate the rocket’s velocity after accelerating to 40 km and explain changes in its weight, its deceleration after fuel stops burning, and how parachutes reduce terminal velocity.

Practise this question

Question

The question page shows Question 6 about a rocket carrying space tourists, with a labelled photograph of a rocket launching. Labels identify the passenger module and propulsion module, and the text states that the propulsion module burns a large volume of fuel. Part 06.1 says the rocket starts stationary, accelerates upwards with constant acceleration 6.48 m/s² to a height of 40 km, and asks for the velocity at 40 km using the Physics Equations Sheet for 4 marks. Part 06.2 asks for 3 marks to explain how the rocket’s weight changed as it accelerated upwards; part 06.3 states that at 40 km the rocket stopped burning fuel and continued to 60 km, asking for 3 marks to explain why velocity decreased between 40 km and 60 km; part 06.4 shows a labelled photograph of a passenger module descending under two parachutes and asks for 3 marks to explain how parachutes allow a lower terminal velocity.
Question text

06 Rockets have been developed so that people who are not trained astronauts can pay

to travel to space.

Figure 9 shows the passenger module and the propulsion module of a rocket.

The propulsion module burns a large volume of fuel.

Figure 9

06.1 The rocket was initially stationary on the ground.

Then the rocket accelerated upwards until it reached a height of 40 km.

The constant acceleration of the rocket was 6.48 m/s2.

Calculate the velocity of the rocket at a height of 40 km.

Use the Physics Equations Sheet.

[4 marks]

Velocity = m/s

06.2 Explain how the weight of the rocket changed as it accelerated upwards.

[3 marks]

06.3 At a height of 40 km, the rocket stopped burning fuel.

The rocket continued upwards to its maximum height of 60 km.

Explain why the velocity of the rocket decreased between a height of 40 km and

a height of 60 km.

[3 marks]

06.4 At a height of 60 km the two modules of the rocket separated and the passenger

module fell back to Earth.

Figure 10 shows the passenger module falling towards the Earth’s surface.

Figure 10

Using parachutes causes the passenger module to fall with a lower terminal velocity

than if parachutes were not used.

Explain why the parachutes allow the passenger module to fall with a lower

terminal velocity.

*24* [3 marks]

Mark scheme

Show the mark scheme The mark scheme is presented as tables for Questions 06.1 to 06.4 with columns for answers, extra information, marks, and AO/spec references. For 06.1 it awards marks for converting 40 km to 40 000 m, substituting into v squared minus u squared equals 2as, rearranging to v equals square root of 2 times 6.48 times 40 000, and giving 720 m/s. For 06.2 it credits that weight depends on mass and gravitational field strength, that mass decreases as fuel is burned or gravitational field strength decreases, and therefore weight decreases. For 06.3 it credits that gravitational force, or air resistance, acts opposite the motion, there is no force in the direction of motion after fuel stops, so the resultant force is towards Earth. For 06.4 it credits that parachutes increase effective area, giving the same air resistance at a lower speed, so resultant force becomes zero at a lower speed; the total for Question 6 is 13 marks.

AO /

Question Answers Extra information Mark

Spec. Ref.

06.1 s = 40 000 1 AO2

6.5.4.1.5

v2 (- 02) = 2 × 6.48 × 40 000 allow v2 = 518 400 1

allow a correct substitution using

an incorrectly / not converted

value of height

v = √(2 × 6.48 × 40 000) allow a correct rearrangement 1

using an incorrectly / not

converted value of height

v = 720 (m/s) allow a correct calculation using 1

an incorrectly / not converted

value of height

AO /

Spec. Ref.

06.2 weight depends on mass and allow weight = mass × 1 AO1

gravitational field strength gravitational field strength

allow W = mg

AO3

mass decreases (as fuel is 1

burned)

or

gravitational field strength AO3

decreases

6.5.1.3

therefore the weight decreases dependent on MP2 1

if no other marks are awarded

allow 1 mark for the weight

decreases because the fuel is

– used – –

AO /

Answers Extra information Mark

Spec. Ref.

06.3 gravitational force acts on the allow air resistance acts on the 1 AO1

rocket (in the opposite direction rocket (in the opposite direction

to the motion of the rocket) to the motion of the rocket)

18 AO2

(and) there are no forces in the 1

direction that the rocket is

moving

AO2

(so) resultant force is towards allow so the rocket decelerates 1

the Earth if MP1 or MP2 awarded 6.5.5.1

6.5.4.2.2

AO /

Spec. Ref.

06.4 parachutes increase the 1 AO3

effective area

(so) there is the same air 1 AO1

resistance at a lower speed

AO1

(so) resultant force is zero at a allow air resistance is equal to 1

lower speed (with the weight at a lower speed (with 6.5.1.2

parachutes open) the parachutes open) 6.5.4.1.5

Total Question 6 13

How to answer it

Rocket Motion and Parachutes

What this question tests

Using motion equations with constant acceleration, explaining how weight depends on mass and gravity, and describing how forces affect motion and terminal velocity. You must show correct units, convert km to m, and give clear physics explanations.

Question 06 overview

A rocket reaches 40 km, then coasts higher, then returns with parachutes.

Total marks: 13

💡 Key knowledge

  • Use v² = u² + 2as for constant acceleration.
  • Weight depends on mass and gravitational field strength: W = mg .
  • At maximum height, the rocket is still moving upwards before it starts to fall.
  • Parachutes increase air resistance and reduce terminal velocity.

🧠 Exam technique

  • Always convert km to m in physics calculations.
  • State the equation first, then substitute numbers, then calculate.
  • For explanation questions, link cause → effect → result.
  • Use the wording from the physics ideas: force, resultant force, air resistance, terminal velocity.

❌ Common errors

  • Using 40 instead of 40 000.
  • Forgetting the rocket starts from rest, so u = 0 .
  • Saying weight changes because “gravity changes” without mentioning altitude or mass.
  • Mixing up mass and weight.

Part (a) / 06.1 — Calculate the velocity at 40 km

✅ Correct answer

Velocity = 720 m/s

Awarded marks for: correct distance conversion, correct equation, correct substitution/rearrangement, correct final answer.

📐 Calculations step-by-step

  1. Convert height: 40 km = 40 000 m
  2. Use the equation: v² = u² + 2as
  3. Substitute values: u = 0 , a = 6.48 m/s² , s = 40 000 m
  4. v² = 0² + 2 × 6.48 × 40 000
  5. v² = 518 400
  6. v = √518 400 = 720
  7. Final answer with unit: 720 m/s

🧠 How marks are awarded

  • 1 mark for using s = 40 000 .
  • 1 mark for a correct equation/substitution.
  • 1 mark for rearranging correctly.
  • 1 mark for the final velocity.

❌ Calculation traps

  • Leaving height as 40 instead of 40 000.
  • Forgetting to square root the final value.
  • Writing the answer without units.
  • Using the wrong equation such as v = u + at when no time is given.

Part (b) / 06.2 — Explain how the weight of the rocket changed as it accelerated upwards

✅ Correct answer

Weight depends on mass and gravitational field strength.

As the rocket burned fuel, its mass decreased, so its weight decreased.

Alternatively, as it moved higher, gravitational field strength decreased, so weight decreased.

💡 Key knowledge

  • W = mg
  • Mass decreases when fuel is used up.
  • Weight is a force, so it changes if mass or gravitational field strength changes.

🧠 Examiner insight

  • Top answers did three things: named the relationship, identified the change, and concluded weight decreased.
  • Simple “it got lighter” answers sometimes gained only partial credit unless linked to mass or gravity.

❌ Common errors

  • Saying mass decreases because weight decreases — backwards reasoning.
  • Talking only about “force” without naming weight.
  • Saying weight changes because of speed.

Part (c) / 06.3 — Explain why the velocity decreased between 40 km and 60 km

✅ Correct answer

  • Gravitational force acts on the rocket in the opposite direction to its motion.
  • There are no forces upwards once the fuel has stopped burning.
  • So the resultant force is towards the Earth, causing the rocket to decelerate.

💡 Key knowledge

  • If the rocket is still moving upwards, gravity acts downwards.
  • When the engine stops, thrust is removed.
  • A force opposite to motion makes an object slow down.

🧠 What the best answers included

  • They clearly stated the force direction.
  • They identified that the resultant force is downward.
  • They used the word decelerates or “slows down”.

❌ Common errors

  • Saying “no forces act” — gravity still acts.
  • Confusing speed with acceleration.
  • Saying the rocket slows because it is “getting higher” with no force explanation.

Part (d) / 06.4 — Explain why parachutes give a lower terminal velocity

✅ Correct answer

  • Parachutes increase the effective area.
  • This increases air resistance.
  • So air resistance balances weight at a lower speed, meaning the terminal velocity is lower.

💡 Key knowledge

  • Terminal velocity happens when resultant force is zero.
  • With parachutes open, a larger surface area catches more air.
  • More air resistance means the downward force is balanced sooner.

🧠 Diagram/description advice

  • If you had to sketch it, draw a large parachute canopy above the module with many lines showing the straps.
  • Show a big downward weight arrow and a big upward air resistance arrow.
  • Label the arrows clearly; this is what examiners expect to see in force questions.

❌ Common errors

  • Saying parachutes “reduce gravity”. They do not.
  • Only saying “it slows down” without explaining air resistance.
  • Forgetting that terminal velocity means forces are balanced.

Quick full-mark answer summary

06.1

v = 720 m/s

06.2

Weight decreases because mass decreases as fuel is burned, or because gravitational field strength decreases with height.

06.3

Gravity acts downward, there is no upward thrust, so the resultant force is downward and the rocket decelerates.

06.4

Parachutes increase effective area, increasing air resistance, so terminal velocity is lower because balance is reached at a lower speed.

Topics

Physics · P5: Forces

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 2 (Higher), 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.