AQA GCSE Combined Science: Trilogy Biology Paper 2 (Higher), June 2025: Question 3
15 marks · Standard Demand difficulty · Short Answer
Investigate the distribution and percentage cover of buttercup plants at different distances from a tree using gridded quadrats and point quadrats.
Practise this questionQuestion
Question text
03 Buttercups are small plants.
Students investigated the distribution of buttercup plants at different distances from
a tree.
Figure 2 shows quadrats being used to sample two areas.
Figure 2
03.1 What was the independent variable in this investigation?
[1 mark]
03.2 Students counted every small square in the quadrat that was at least half covered
by buttercup plants.
Determine the percentage cover of buttercup plants 10 metres away from the tree.
Use Figure 2.
[3 marks]
Percentage cover = %
03.3 The students placed:
• several quadrats 1 metre away from the tree
• several quadrats 10 metres away from the tree.
Give two factors the students should consider when deciding how many times to
place a quadrat at each distance.
Do not refer to time available.
[2 marks]
03.4 Figure 3 shows two different quadrats.
Figure 3
Explain two advantages of using quadrat B instead of quadrat A in the investigation.
You should include calculations in your answer.
[4 marks]
A point quadrat can also be used to estimate the percentage cover of plants in
an area.
Figure 4 shows a point quadrat.
Figure 4
When using a point quadrat, the pins are pushed down to the soil.
The number of pins that touch a buttercup plant is counted.
03.5 What are two advantages of using a point quadrat compared with using
a square quadrat?
[2 marks]
Tick ( ) two boxes.
With a point quadrat, a plant that is smaller than half a square
is more likely to be counted.
With a point quadrat, each species of plant is easier to identify.
With a point quadrat, no judgement of cover is needed.
With a square quadrat, a buttercup plant covering other plants cannot
be counted.
With a square quadrat, the results are less likely to be biased.14
03.6 The percentage cover of buttercup plants can be estimated using the equation:
number of times a pin touched a buttercup plant
*13percentage cover = * × 100
total number of pins used
30 students each collected results from 50 pins.
The students then put all their results together.
Buttercup plants had a percentage cover of 7%.
Calculate the number of times a pin touched a buttercup plant.
[3 marks]
Number of times a pin touched a buttercup plant =
Mark scheme
Show the mark scheme
Question 3
AO /
Question Answers Extra information Mark
Spec. Ref.
03.1 distance from the tree allow distance 1 AO2
4.7.2.1
RPA7
AO /
Spec. Ref.
03.2 7 (squares) 1 AO2
× 100 allow 0.28 × 100
allow correct working shown
from an incorrect attempt at 1 AO3
counting squares (in the range 6
to 10) covered by buttercups
28 (%) allow a correct calculation from 1 AO2
an incorrect attempt at counting
squares (in the range 6 to 10)
covered by buttercups 4.7.2.1
RPA7
alternative route
(percentage cover of one small
square)
( =) 4
7 × 4
allow correct working shown
with incorrectly calculated
percentage cover of one small
square
28 (%)
allow a correct calculation from
an incorrect attempt at counting
squares (in the range 6 to 10)
covered by buttercups
AO /
Spec. Ref.
03.3 any two from: 2 AO3
• whether the sample is 4.7.2.1
representative RPA7
• the size of the quadrat
• the number of students allow the number of quadrats
(available)
• how many quadrats fit around allow size of tree
the tree at 1 m allow if the same (quadrat) area
is being sampled repeatedly
• factors such as buildings or
other tree(s)
AO /
Spec. Ref.
03.4 allow converse if clearly AO3
referring to quadrat A 4.7.2.1
RPA7
ignore references to time
(quadrat B) samples a larger allow (quadrat B) is larger / 1
area wider
(because) 0.25 (m2) rather than 1 2 1 2 1
allow (m ) rather than (m )
0.0625 (m2) 4 16
allow 2500 cm2 rather than 625
cm2
allow by 4 times
(quadrat B) gives more accurate allow (quadrat B) is more 1
/ precise results representative
allow (quadrat B) has greater
resolution
allow need to use quadrat A
4 times (as many times) to have
the same accuracy / precision
as quadrat B
ignore (quadrat B) is more
reliable / valid / repeatable
(because) to the nearest 1% (of allow (because) quadrat B has 1 15
the quadrat) rather than nearest 100 (small) squares rather than
4% 25 (small) squares
do not accept quadrat B has
smaller squares (within quadrat)
AO /
Spec. Ref.
03.5 with a point quadrat, a plant that 1 AO3
is smaller than half a square is 4.7.2.1
more likely to be counted RPA7
with a point quadrat, no 1
judgement of cover is needed
16 AO /
Spec. Ref.
03.6 n n 1 AO2
7 = × 100 allow 7 = × 100
30 × 50 1500 4.7.2.1
7 allow n = 0.07 × 1500 1
n = × 1500
100 allow n = 7 × 15
allow a correct rearrangement
using 50 pins as total number of
pins used
allow correct rearrangement
with an incorrect calculation of
number of pins used
n = 105 allow a correct calculation using 1
50 pins as total number of pins
used
allow correct calculation with an
incorrect calculation of number
of pins used
allow 2 marks for:
( × 50 =) 3.5
Total Question 3 15
How to answer it
Sampling Plant Populations: Quadrats & Point Frames
This question assesses practical ecology skills from Topic 4.7 (Ecology):
- Identifying experimental variables (independent, dependent, control) in fieldwork.
- Estimating percentage ground cover using gridded square quadrats based on standard counting rules.
- Evaluating fieldwork sampling design, sample size, and factors affecting quadrat placement.
- Comparing sampling apparatus (calculating area and grid resolution of different quadrats).
- Comparing square quadrats with point quadrats and rearranging equations to calculate frequencies from pooled class data.
Identifying the Independent Variable
Identifying what is changed by the investigator
✅ Correct Answer
Distance from the tree (or simply distance).
💡 Key Knowledge
- Independent Variable: The factor deliberately changed by the experimenter (here: 1 m vs 10 m).
- Dependent Variable: What is measured (buttercup distribution / % cover).
- Control Variables: Factors kept constant to ensure valid results.
Calculating Percentage Cover in a Gridded Quadrat
Counting squares "at least half covered" and converting to a percentage
📐 Step-by-Step Calculation
- Count qualifying squares: Inspect the 10 m quadrat (5 × 5 grid = 25 total squares). Count squares that are at least half (≥ 50%) covered by buttercups.
Count = 7 squares - Calculate fraction of total area:
(7 ÷ 25) × 100 or each square is worth 100% ÷ 25 = 4% , so 7 × 4% . - Calculate final percentage:
Percentage cover = 28%
[1 mark] for correct formula: (7 ÷ 25) × 100.
[1 mark] for 28%.
❌ Common Errors & Traps
- Counting squares with tiny patches: The rule states at least half covered. Counting squares with only tiny tips (e.g. counting 9 or 10) loses mark 1, though error carried forward (ECF) is allowed for math working if in range 6–10.
- Dividing by 100 instead of 25: The grid is 5 × 5 (25 squares total), not 100 squares!
Fieldwork Planning & Sample Size
Factors to consider when deciding sample size (excluding time)
✅ Any TWO from the Mark Scheme
- Whether the sample is representative (large enough sample size).
- The size of the quadrat used.
- The number of students (or number of quadrats available).
- How many quadrats physically fit around the tree at 1 m (circumference / area limit).
- Obstacles / environmental factors such as buildings, paths, or other trees.
🧠 Exam Technique: Read the Restrictions!
The question explicitly says: "Do not refer to time available."
Any mention of "not having enough time" or "how long the lesson lasts" scores 0 marks. Focus on biological and physical constraints (representativeness, spatial limits around the tree, or equipment).
Comparing Quadrats: Area & Grid Resolution
Explaining two advantages of Quadrat B over Quadrat A using calculations
📐 Calculations Required
Advantage 1: Quadrat B covers a larger total area
- Area of Quadrat A = 0.25 m × 0.25 m = 0.0625 m² (or 625 cm²)
- Area of Quadrat B = 0.5 m × 0.5 m = 0.25 m² (or 2500 cm²)
- Quadrat B samples 4 times larger area!
Advantage 2: Quadrat B gives higher precision / resolution
- Quadrat A: 5 × 5 = 25 squares → each square = 4%
- Quadrat B: 10 × 10 = 100 squares → each square = 1%
- Quadrat B estimates cover to the nearest 1% instead of 4%.
✅ Mark Breakdown (4 Marks)
- Mark 1: Quadrat B samples a larger area (or is more representative).
- Mark 2: Calculation showing 0.25 m² vs 0.0625 m² (or 4 times larger).
- Mark 3: Quadrat B gives more accurate / precise results (or higher resolution).
- Mark 4: Calculation showing percentage resolution: to the nearest 1% rather than nearest 4% (or 100 squares vs 25 squares).
❌ Common Errors
- Confusing terms: Do not claim Quadrat B is "more reliable" or "valid" by itself without linking it to sample area or precision.
- Vague statements: Saying "it has smaller squares" without quoting numbers or calculating percentage resolution (1% vs 4%) loses mark 4.
Point Quadrat vs Frame Quadrat
Evaluating the advantages of using pins
✅ Two Correct Statements (Tick Boxes)
- ☑️ With a point quadrat, a plant that is smaller than half a square is more likely to be counted.
- ☑️ With a point quadrat, no judgement of cover is needed.
💡 Why Are These True?
- No subjective judgement: A pin either physically touches a leaf or it doesn't (objective binary data). With square quadrats, students must estimate whether a plant covers ≥ 50% of a square.
- Detecting small plants: Tiny leaves that never fill half a square are ignored in standard square quadrats, but can easily touch a needle-thin pin.
Formula Rearrangement: Point Quadrat Data
Rearranging the percentage cover formula to find the number of pin touches
📐 Step-by-Step Calculation
Given formula:
Percentage cover = (number of touches ÷ total pins used) × 100
- Find the total number of pins used:
30 students each used 50 pins:
Total pins = 30 × 50 = 1500 pins[1 mark] for substituting 1500 into equation - Rearrange the formula to make "touches (n)" the subject:
7 = (n ÷ 1500) × 100
n = (7 ÷ 100) × 1500 → n = 0.07 × 1500[1 mark] for correct rearrangement - Calculate final answer:
n = 105[1 mark] for final answer of 105
❌ Common Trap: Forgetting the 30 Students
Many students calculate 7% of 50 pins: (7 ÷ 100) × 50 = 3.5 .
The question states 30 students put ALL their results together. If you calculate 3.5, you only score 2 marks (partial credit for using 50 instead of 1500). Always underline total sample quantities!
Topics
Biology · B7: Ecology
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Biology Paper 2 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.