AQA GCSE Combined Science: Trilogy Chemistry Paper 1 (Higher), June 2025: Question 3
12 marks · Standard Demand difficulty · Short Answer
Answer questions on the alpha particle scattering experiment, atomic structure and isotopic notation of a halide ion, and physical and chemical trends in Group 7 elements.
Practise this questionQuestion
Question text
03 This question is about atoms, ions and elements.
03.1 Figure 3 shows the results of the alpha particle scattering experiment.
In the experiment, alpha particles were fired at gold foil.
Alpha particles are positively charged.
Figure 3
What two conclusions were made from the results?
[2 marks]
Tick ( ) two boxes.
Atoms are very small.
Atoms have a charged nucleus.
Electrons orbit the nucleus at specific distances.
Isotopes of an element have a different number of neutrons.
The mass of an atom is concentrated in the nucleus.
Particle X consists of:
*09*•35 protons
• 44 neutrons
• 36 electrons.
03.2 Why is particle X not an atom?
Answer in terms of subatomic particles.
[1 mark]
03.3 Which is the correct representation of particle X?
Use the periodic table.
[1 mark]
Tick ( ) one box.
79 +
Br
79 −
Br
79 +
Se
79 −
Se 11
Group 7 elements are known as the halogens.
03.4 Table 2 shows the boiling points of some Group 7 elements.
Table 2
Element Boiling point in °C
Fluorine −188
Chlorine −35
Bromine 59
Iodine 184
Explain the increase in the boiling points of the Group 7 elements going
down the group.
[3 marks]
03.5 Chlorine reacts with fluorine to form a compound with the formula ClF3
What is the type of bonding in the compound ClF3?
[1 mark]
03.6 Chlorine reacts with a solution of sodium bromide.
Complete the word equation for the reaction.
[1 mark]
chlorine*11+*sodium bromide → +
03.7 Explain why Group 7 elements become less reactive going down the group.
[3 marks]
Mark scheme
Show the mark scheme
Question 3
AO /
Question Answers Extra information Mark
Spec. Ref.
03.1 atoms have a charged nucleus 1 AO1
5.1.1.3
the mass of an atom is 1
concentrated in the nucleus
AO /
Spec. Ref.
03.2 (particle X) has more electrons allow (particle X) has a different 1 AO3
than protons number of protons and electrons 5.1.1.4
allow because atoms have the
same number of protons and
electrons
do not accept (particle X) has a
different number of neutrons
AO /
Spec. Ref.
03.3 79 − 1 AO2
Br – TRILOGY – 8464/C/1H –
35 5.1.1.5
AO /
Spec. Ref.
03.4 (going down the group) allow (going down the group) 1 AO1
molecules increase in size atoms increase in size 5.1.2.6
5.2.2.4
(so the) forces between the 1
molecules increase
or
(so the) intermolecular forces
increase
(so) more energy is needed to allow (so) more energy is 1
break the intermolecular forces needed to separate the
molecules
AO /
Spec. Ref.
03.5 covalent ignore intermolecular forces 1 AO1
12 5.1.2.6
5.2.1.1
AO /
Question Answers Mark
Spec. Ref.
03.6 chlorine + sodium bromide → bromine + sodium chloride 1 AO2
5.1.2.6
– allow Br2 for bromine – 8464/C/1H –
allow NaCl for sodium chloride
AO /
Spec. Ref.
03.7 allow energy level for shell AO1
5.1.2.6
(going down the group the)
the outer shell / electrons allow the atoms become larger 1
become further from the nucleus
allow the atoms have more
shells
(so) there is less (electrostatic) allow (so) there is more 1
attraction between the nucleus shielding between the outer
and the outer electron(s) electron(s) and the nucleus
(so) gaining an electron is more 1
difficult
Total Question 3 12
How to answer it
Atomic Structure and the Halogens (Group 7)
This question assesses fundamental ideas about the Rutherford alpha scattering experiment, deducing atomic structure and ion symbols from subatomic particles, explaining physical trends (boiling points) using intermolecular forces, identifying covalent bonding, predicting products of a halogen displacement reaction, and constructing an explanation for the trend in reactivity down Group 7.
Alpha Scattering Experiment Conclusions
Identifying deductions from Rutherford's experiment
✅ Correct Selections
Tick the two following boxes:
- Atoms have a charged nucleus. [1 mark]
- The mass of an atom is concentrated in the nucleus. [1 mark]
💡 Key Knowledge
- Most went straight through: atom is mostly empty space.
- Some deflected at large angles: the nucleus is positively charged (repelled the positive alpha particles).
- A very small fraction bounced straight back: the nucleus contains almost all the mass.
❌ Common Errors
- Ticking "Electrons orbit the nucleus at specific distances" — this was deduced later by Niels Bohr, not Rutherford.
- Ticking "Isotopes of an element have a different number of neutrons" — neutrons were discovered much later by James Chadwick (1932).
🧠 Exam Technique
Pay close attention to historical discoveries. Even though statements like "atoms are very small" or "electrons orbit in shells" are true scientific facts, they were not the direct conclusions from Rutherford's gold foil experiment.
Subatomic Particles in Atoms vs. Ions
Particle X has: 35 protons, 44 neutrons, 36 electrons
✅ Correct Answer
Particle X has more electrons than protons (or "a different number of protons and electrons" / "atoms have equal numbers of protons and electrons"). [1 mark]
💡 Key Knowledge
- In any neutral atom: Number of protons = Number of electrons .
- When protons ≠ electrons, the particle has an overall charge and is an ion.
- Here, 36 electrons > 35 protons, so it has an overall 1− charge.
❌ Common Errors
Stating that it is not an atom because it has "a different number of neutrons". Neutrons have no charge; an imbalance between protons and neutrons just means it is an isotope, not an ion!
Representing Particle X
Deducing isotope and ion notation from the periodic table
✅ Correct Answer
Tick the second box: ⁷⁹₃₅Br⁻ [1 mark]
📐 Step-by-Step Breakdown
- Atomic Number (bottom number): 35 protons → element is Bromine (Br), so bottom number = 35 .
- Mass Number (top number): protons + neutrons = 35 + 44 = 79 .
- Charge: 35 protons (+35) and 36 electrons (−36) = −1 charge ( Br⁻ ).
Trend in Boiling Points Down Group 7
Explaining boiling points using intermolecular forces
✅ Mark Scheme Model Answer
- Point 1: Going down the group, the molecules increase in size (or atoms increase in size). [1 mark]
- Point 2: The forces between the molecules (intermolecular forces) increase. [1 mark]
- Point 3: Therefore, more energy is needed to break the intermolecular forces (or separate the molecules). [1 mark]
🧠 3-Step Structure for Melting/Boiling Point Questions
- State what happens to particle/molecule size.
- State how the intermolecular forces change strength.
- State the amount of energy needed to overcome them.
❌ Common Misconception: Breaking Covalent Bonds
Never write that "covalent bonds are broken" when boiling or melting simple molecular substances like halogens. The strong covalent bonds inside the molecules remain completely intact; only the weak intermolecular forces between molecules are overcome.
Type of Bonding in ClF₃
Chlorine trifluoride
✅ Correct Answer
Covalent [1 mark]
💡 Key Knowledge
- Both chlorine (Cl) and fluorine (F) are non-metals.
- Non-metal + non-metal bond by sharing electrons = covalent bonding.
- Metal + non-metal = ionic bonding; metal + metal = metallic bonding.
Halogen Displacement Reaction
Completing the word equation
✅ Correct Word Equation
chlorine + sodium bromide → bromine + sodium chloride [1 mark]
🧠 Why does this reaction happen?
Chlorine is more reactive than bromine. A more reactive halogen displaces a less reactive halogen from an aqueous solution of its halide salt.
❌ Common Errors
- Writing "bromide" instead of bromine for the element produced.
- Writing "sodium chlorine" instead of sodium chloride for the salt.
Explaining Reactivity Down Group 7
Why halogens become less reactive down the group
✅ 3-Mark Complete Explanation
- Mark 1: Going down the group, the outer shell (outer electrons) is further from the nucleus (or the atom has more shells / is larger).
- Mark 2: There is less electrostatic attraction between the nucleus and the incoming outer electron (or there is more shielding).
- Mark 3: Therefore, gaining an electron is more difficult.
🧠 How to Perfect Group 7 Explanations
Always link atomic structure to the halogen's "job":
- Halogens need to gain 1 electron to get a full outer shell.
- Distance & shielding increase → positive attraction from the nucleus weakens → harder to pull in that 1 extra electron.
❌ Common Errors & Group 1 Confusion
- Confusing Group 1 with Group 7: Students often say "easier to lose an electron". Group 7 non-metals gain electrons; Group 1 metals lose electrons.
- Vague statements: Saying "it's harder to react" without stating why (i.e. gaining an electron is more difficult).
Topics
Chemistry · Physics · C1: Atomic Structure and the Periodic Table · C2: Bonding, Structure and the Properties of Matter · P4: Atomic Structure
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.