AQA GCSE Combined Science: Trilogy Chemistry Paper 2 (Higher), June 2025: Question 6
11 marks · Standard Demand difficulty · Short Answer
Calculate the total mass and number of atoms of gold in smartphones, and describe biological extraction methods such as bioleaching and phytomining.
Practise this questionQuestion
Question text
06 Gold is used in the printed circuit boards found in smartphones.
Figure 6 shows a printed circuit board.
Figure 6
A type of smartphone contains 1.73 × 10–4 moles of gold.
06.1 In one year, a manufacturer sold 2.48 million of this type of smartphone.
Calculate the total mass of gold contained in 2.48 million of these smartphones.
Give your answer in kilograms.
Relative atomic mass (Ar): Au = 197
[5 marks]
Total mass of gold =25 kg
06.2 What is the total number of gold atoms in one of this type of smartphone?
The Avogadro constant = 6.02 × 1023 per mole
[1 mark]
Tick ( ) one box.
2.87 × 10–28
1.04 × 1020
3.48 × 1027
06.3 The materials in printed circuit boards can be recycled.
Bioleaching is one method used to extract gold from printed circuit boards.
Describe how bioleaching is used to extract gold.
[3 marks]
06.4 Copper is also extracted using bioleaching.
Copper can also be extracted from low-grade ores using phytomining.
Phytomining has not been widely used to extract copper.
Suggest two reasons why.
[2 marks]
Mark scheme
Show the mark scheme
Question 6
AO /
Question Answers Extra information Mark
Spec. Ref.
06.1 (mass in one phone =) AO2
1.73 × 10–4 × 197 1 5.3.2.1
5.10.1.1
= 0.034081 (g) 1
(total mass =) allow (total mass =) 1
0.034081 × 2.48 × 106 0.034081 × 2 480 000
allow correct use of an
incorrectly determined mass in
one phone
= 84520.88 (g) 1
(conversion 84520.88 g =) 84.5 allow 84.52088 (kg) correctly 1
(kg) rounded to at least 2 significant
figures
allow conversion at MP2, MP3
allow correct conversion of an
incorrectly determined mass
using all numbers from the
question
alternative approach
(total moles =) allow (total moles =)
1.73 ×10–4 × 2.48 × 106 (1) 1.73 ×10–4 × 2 480 000
= 429.04 (1)
(total mass =) 429.04 × 197 (1) allow correct use of an
incorrectly determined total
moles
= 84520.88 (g) (1)
(conversion 84520.88 g =) 84.5 allow 84.52088 (kg) correctly
(kg) (1) rounded to at least 2 significant
figures
allow correct conversion of an
incorrectly determined mass
using all numbers from the
– questionSCIENCE: TRILOGY – –
20 AO /
Spec. Ref.
06.2 1.04 × 1020 1 AO2
5.3.2.1
5.10.1.1
AO /
Spec. Ref.
06.3 uses bacteria 1 AO1
5.10.1.4
5.10.2.2
to produce leachate / solutions 1
containing gold compounds
from which gold is obtained by 1
displacement / electrolysis
AO /
Spec. Ref.
06.4 any two from: 2 AO3
5.10.1.4
• high-grade ores still available
• land not available
• phytomining takes a long time
• very small yields produced
• new technology
Total Question 6 11
How to answer it
Gold Extraction & Mole Calculations in Smartphones
What this question tests
This question assesses higher-tier quantitative chemistry and sustainable metal extraction from Topic 3 (Quantitative Chemistry) and Topic 10 (Using Resources). Specifically: multi-step mass-mole conversions with standard form, conversion from grams to kilograms, the Avogadro constant, the biological extraction process of bioleaching, and limitations of phytomining.
Multi-Step Mole and Mass Calculation
Calculate the total mass of gold (in kg) contained in 2.48 million smartphones.
📐 Step-by-Step Calculation
- Mass of gold in one phone:
mass = moles × Aᵣ
1.73 × 10⁻⁴ mol × 197 = 0.034081 g - Convert total phones to standard number:
2.48 million = 2.48 × 10⁶ (or 2,480,000) - Total mass in grams:
0.034081 g × 2.48 × 10⁶ = 84,520.88 g - Convert grams to kilograms (÷ 1000):
84,520.88 ÷ 1000 = 84.52088 kg - Final rounded value:
84.5 kg (or 85 kg to 2 s.f.)
🧠 Exam Technique & Alternative Method
You can also calculate the total moles first:
- Total moles = 1.73 × 10⁻⁴ × 2.48 × 10⁶ = 429.04 mol
- Total mass (g) = 429.04 × 197 = 84,520.88 g
- Convert to kg = 84,520.88 ÷ 1000 = 84.5 kg
[1] Moles × 197
[1] Correct mass in 1 phone (0.034081 g)
[1] Multiplying by 2.48 × 10⁶
[1] Correct total in grams (84,520.88 g)
[1] Dividing by 1000 to give final answer in kg (84.5 kg)
❌ Common Errors & Traps
- Forgetting unit conversion: Leaving the answer as 84,520.88 g loses the final mark. Always re-read the required unit at the answer line ( kg ).
- Mishandling "million": Entering 2.48 × 10³ or 2.48 × 10⁵ instead of 2.48 × 10⁶.
- Calculator syntax errors: Forgetting brackets around powers of ten when multiplying standard form values.
Number of Atoms & Avogadro Constant
What is the total number of gold atoms in one smartphone?
✅ Correct Answer
Tick the 2nd box:
1.04 × 10²⁰
💡 Key Knowledge
Recall the relationship between particles and moles:
Number of atoms = moles × Avogadro constant (Nₐ)
= 1.73 × 10⁻⁴ mol × 6.02 × 10²³ mol⁻¹
= 1.04146 × 10²⁰ ≈ 1.04 × 10²⁰ atoms
❌ Why the Distractors are Wrong
- 2.87 × 10⁻²⁸ : Result of incorrectly dividing moles by Avogadro's constant.
- 3.48 × 10²⁷ : Incorrect power calculation (adding exponents without negative sign).
Process of Bioleaching
Describe how bioleaching is used to extract gold.
✅ Marking Points (3 Marks)
- Point 1: Uses bacteria [1 mark]
- Point 2: To produce a leachate (or solution containing gold / metal compounds) [1 mark]
- Point 3: Gold is then extracted/obtained by displacement or electrolysis [1 mark]
🧠 Exam Technique: The 3-Step Bioleaching Description
Whenever an exam asks you to describe bioleaching, structure your response chronologically:
- The agent: State that bacteria are used.
- The intermediate: State they break down the material to form an acidic solution called a leachate containing metal ions.
- The final product: State how the solid pure metal is extracted from the solution (displacement using scrap iron or electrolysis).
❌ Common Errors
- Confusing bioleaching with phytomining: Mentioning plants, roots, or burning to ash gets zero marks for bioleaching. Phytomining uses plants; bioleaching uses bacteria.
- Stopping at "leachate": Many students forget to explain how the metal is actually recovered at the end (electrolysis or displacement).
Evaluating Phytomining
Suggest two reasons why phytomining has not been widely used to extract copper.
✅ Acceptable Answers (Any Two)
- High-grade ores are still available (traditional mining is still economically viable) [1 mark]
- Takes a long time (slow process because plants have to grow) [1 mark]
- Land is not available (competes with land needed for agriculture/food production) [1 mark]
- Very small yields produced / low quantity of copper extracted [1 mark]
- New technology / still in developmental or unproven commercial stages [1 mark]
💡 Key Knowledge: How Phytomining Works
Plants absorb metal compounds through their roots from low-grade ore. The plants are harvested and burned to produce ash containing metal compounds. The metal is then leached with sulfuric acid to make a solution, which undergoes displacement or electrolysis.
❌ Examiner Pitfalls
- Vague answers: Simply writing "it's expensive" or "it's bad" does not get credit without qualifying (e.g., low yields make it economically uncompetitive).
- Saying it damages the environment: Phytomining actually causes less environmental damage than traditional mining, so this is scientifically incorrect.
Topics
Chemistry · C3: Quantitative Chemistry · C10: Using Resources
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 2 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.