AQA GCSE Mathematics Paper 1 (Higher), June 2025: Question 24
4 marks · Hard difficulty · Proof
Prove algebraically that the product of algebraic fractions (60x^4 - 15x^2)/(-2x - 1) and 1/(6x - 3) can never be positive.
Practise this questionQuestion
Question text
60x4 −15x2 1
24 Prove that × can never be positive.
−2x −1 6x − 3
[4 marks]
Mark scheme
Show the mark scheme
Q Answer Mark Comments
Partially or fully factorises eg 15x(4x3 – x) or x2(60x2 – 15)
numerator M1
or 15x2(2x – 1)(2x + 1)
Factorises at least one eg –(2x + 1) and/or 3(2x – 1)
denominator
or M1
eg –12x2 + (6x – 6x +) 3
correct multiplication of the
denominators may be in a grid
Converts numerators and dep on M1M1
denominators into terms which can 2
be fully cancelled 15x (2x −1)(2x +1)
eg
−(2x +1)3(2x −1)
15x2(2x − 1)(2x + 1) 1
or ×
M1dep −(2x +1) 3(2x −1)
5x2(12x2 − 3)
or 2
−(12x − 3)
factorisation and cancelling may be done
in stages
15x2
or –5x2 with M3 awarded oe with full cancelling of algebraic terms
−3
and A1
2 condone explanation that x2 must be
explanation that x cannot be
negative positive
Additional Guidance
20x4 − 5x2 20x4 − 5x2
or 2 implies M1M1 as 3 has been cancelled
( 2−x −1)(2x −1) −4x +1 M1M1
from both
5x2(2x + 1)
implies complete factorisation of numerator and denominator
−(2x +1) M1M1M1
as 3 and (2x – 1) have been cancelled from both
How to answer it
Algebraic Proof: Fractions & Non-Positive Expressions
What this question tests
This question assesses advanced algebraic manipulation at Grade 8/9 level, specifically:
- Factorising polynomials completely: Taking out a common algebraic factor and spotting a difference of two squares.
- Factorising linear expressions: Factoring out numerical terms and handling negative signs carefully (e.g. taking out −1).
- Multiplying and simplifying algebraic fractions: Dividing out common binomial factors between numerators and denominators.
- Constructing a formal algebraic proof: Explaining why an expression such as −5x² can never be positive by referencing the property that squares of real numbers cannot be negative (x² ≥ 0).
Question 24 Walkthrough
Prove that (60x⁴ − 15x²) / (−2x − 1) × 1 / (6x − 3) can never be positive. [4 marks]
📐 Step-by-Step Solution
1 Factorise the numerator completely:
Notice that (4x² − 1) is a difference of two squares:
= 15x²(2x − 1)(2x + 1)
2 Factorise both denominators:
Second denominator: 6x − 3 = 3(2x − 1)
3 Combine into a single fraction and cancel common terms:
Cancel the common brackets (2x − 1) and (2x + 1):
= 15x² / (−1 × 3)
= 15x² / (−3)
= −5x²
4 Complete the proof with a reasoned conclusion:
For all real numbers, x² ≥ 0 (any real number squared cannot be negative).
Therefore, multiplying a non-negative number by −5 gives a value that is less than or equal to 0:
✅ Mark Scheme Breakdown
- M1: Partially or fully factorises numerator.
15x(4x³ − x) , x²(60x² − 15) , or 15x²(2x − 1)(2x + 1) . - M1: Factorises at least one denominator OR correctly expands product of denominators.
e.g. −(2x + 1) and/or 3(2x − 1) , or expands to −12x² + 3 . - M1 (dep): Converts numerator and denominator into forms that allow full algebraic cancellation.
Dependent on previous M1 M1. - A1: Reaches −5x² (or 15x² / −3 ) AND provides a clear statement that x² cannot be negative (or x² ≥ 0 ).
💡 Key Knowledge
- Difference of Two Squares:
a² − b² = (a − b)(a + b)
Recognise 4x² − 1 = (2x − 1)(2x + 1) immediately. - Extracting a Negative Sign:
Expressions like −2x − 1 can be written as −(2x + 1) or −1(2x + 1) to reveal shared factors. - Properties of Squared Numbers:
For any real number x, x² ≥ 0 . Since x² is always 0 or positive, −5 × (non-negative) ≤ 0 . It can be zero, but never positive.
🧠 Exam Technique
- Look for matching brackets: When multiplying algebraic fractions, you should anticipate brackets cancelling. Seeing 6x − 3 suggests a factor of (2x − 1) might be lurking in the numerator!
- Don't skip the conclusion: Reaching −5x² is only worth 3 marks. You must write a written explanation about x² being non-negative to earn the final 4th mark.
- Maintain equivalence: Keep negative signs clearly visible. Don't lose a minus sign when cancelling fractions.
❌ Common Errors
- Incomplete Factorisation: Stopping at 15x²(4x² − 1) and failing to spot that 4x² − 1 factors further into (2x − 1)(2x + 1) .
- Sign Errors with Negatives: Forgetting the minus sign when dealing with −2x − 1 , incorrectly simplifying to 5x² instead of −5x² .
- Missing Explanation: Reaching −5x² and simply stopping without explaining why this proves the expression can never be positive.
- Incorrect Reason: Saying "it is negative because it has a minus sign" is incomplete without specifying that x² itself is never negative.
Topics
Algebra · 3.2.1 Notation, vocabulary and manipulation
Question and mark scheme from the AQA GCSE Mathematics examination, Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.