AQA GCSE Mathematics Paper 2 (Foundation), June 2025: Question 13
4 marks · Medium difficulty · Multi-step Problem
Calculate the range of mobile phone usage over four weeks, and determine the usage in a fifth week given the overall mean for all five weeks.
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Mark scheme
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How to answer it
Calculating the Range and Working Backwards from a Mean
This question assesses your ability to interpret and work with core statistical measures:
- Range: Identifying extreme values in a small data set and calculating the measure of spread.
- Reverse Mean Problem: Reconstructing the total sum from a known mean and number of values ( Total = Mean × n ), then finding a missing value.
Part (a): Finding the Range
Data values: 140, 168, 205, 192
📐 Step-by-Step Calculation
- Find the highest value: 205
- Find the lowest value: 140
- Subtract lowest from highest:
205 − 140 = 65
✅ Correct Answer
65 minutes
💡 Key Knowledge
- Range = Highest Value − Lowest Value
- Range is a single number showing the spread of data, not an average.
❌ Common Errors
- Writing the range as an interval (e.g. 140 to 205 or 140 − 205 ) instead of computing the difference.
- Accidentally picking 192 instead of 205 as the largest value.
Part (b): Finding the Missing Fifth Week
A fifth week is added. Mean for all five weeks = 178 minutes.
📐 Step-by-Step Method (Standard Method)
- Find the target total for all 5 weeks:
Total = Mean × Number of values = 178 × 5 = 890 - Find the sum of the first 4 weeks:
140 + 168 + 205 + 192 = 705 - Subtract the known total from the required total:
890 − 705 = 185 minutes
✅ Correct Answer
185 minutes
- M1: 178 × 5 (or 890 ) OR setting up an equation: (705 + x) ÷ 5 = 178
- M1dep: Complete method: 890 − 705
- A1: Correct answer of 185
🧠 Exam Technique & Alternative Methods
- The "Total First" Rule: Whenever an exam question states the mean and the count, multiply them immediately to find the total sum.
- Difference from Mean Method: Look at how far the 4 known values deviate from 178:
(140 − 178) = −38
(168 − 178) = −10
(205 − 178) = +27
(192 − 178) = +14
Total deviation = −7. Therefore, the 5th value must be 7 above the mean: 178 + 7 = 185 .
❌ Common Errors & Traps
- Dividing by 4 instead of 5: Forgetting that Ingrid now records data for five weeks in total.
- Adding 178 to the list: Confusing the new mean with the value of the fifth week itself.
- Time Conversion Pitfall: The answer line specifies "minutes". If converted to hours, write 3 hours 5 minutes (giving 3.08 hours or 3.05 hours will lose marks; the mark scheme allows a special case SC2 for exactly 3 hrs 5 mins ). Keep it simple and leave it as 185 .
💡 Examiner Commentary
Students who set up an algebraic equation (705 + x) ÷ 5 = 178 or clearly found 178 × 5 = 890 scored method marks easily even if they made a final subtraction slip. Always show the multiplication step explicitly on your paper.
Topics
Statistics · Number · 3.6 Statistics · 3.1.1 Structure and calculation
Question and mark scheme from the AQA GCSE Mathematics examination, Paper 2 (Foundation), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.