AQA GCSE Mathematics Paper 2 (Higher), June 2025: Question 24
3 marks ยท Hard difficulty ยท Multi-step Problem
Work out the percentage increase in a student's exam mark if their exam mark is directly proportional to the cube root of total revision time and they double their revision time.
Practise this questionQuestion
Mark scheme
Show the mark scheme
How to answer it
Direct Proportion with Cube Roots: Percentage Change
๐ What this question tests
This question assesses higher-tier algebraic proportionality and proportional change:
- Setting up a direct proportion equation involving a non-linear term: m = k ร โt .
- Understanding how changing an independent variable (doubling t to 2t ) affects the dependent variable.
- Calculating a percentage increase using the ratio of new to original values or picking test numbers.
Question 24 (3 Marks)
A study suggests a student's exam mark, m, is directly proportional to the cube root of total revision time, t hours. A student doubles their total revision time. Work out the percentage increase in their exam mark.
โ Correct Answer
Any value in the range:
25.99% to 26%
A1 Accept any value in the inclusive range [25.9, 26].
๐ก Key Knowledge
- Direct proportion: m โ โt converts to an equation using constant k :
m = kโt - Scale Factor: Doubling time replaces t with 2t :
mโ = kโ(2t) = โ2 ร (kโt) = โ2 ร mโ - Multiplier: โ2 โ 1.25992...
- Percentage Increase:
(Multiplier - 1) ร 100%
๐ Step-by-Step Solutions
Method 1: Algebraic Multiplier (Most Efficient)
- Set up the relationship: Let original mark be mโ = kโt . M1 Awarded for writing m = kโt or equivalent.
- Find the new mark after doubling time: Substitute 2t for t :
mโ = kโ(2t) = k ร โ2 ร โt = โ2 ร mโ - Calculate percentage change:
Ratio = mโ / mโ = (kโ(2t)) / (kโt) = โ2 โ 1.25992M1 dep Dependent on M1: setting up an expression for mโ / mโ ร 100 or (mโ - mโ) / mโ ร 100 . - Convert multiplier to percentage increase:
(1.25992 - 1) ร 100% = 25.992% โ 26%A1 Correct answer in range [25.9, 26].
Method 2: Choosing Friendly Values (Alternative Full-Mark Method)
- Pick values that fit a cube root: Let k = 1 and initial time tโ = 1 (or 8, or 125).
mโ = โ1 = 1 - Double the time:
tโ = 2
mโ = โ2 โ 1.2599 - Work out percentage increase:
Percentage increase = [(1.2599 - 1) / 1] ร 100 = 25.99%
๐ง Exam Technique & Examiner Tips
- Pick smart numbers if stuck: If abstract algebra confuses you, choose concrete numbers. Picking t = 1 and k = 1 gives mโ = 1 and mโ = โ2 immediately.
- Always write an equation: The mark scheme specifically notes that just writing m โ โt earns M0. You must replace the proportionality symbol with an equals sign and a constant k (e.g., m = kโt ) to secure the first method mark.
- Show intermediate values: Write down 1.2599... or 25.99% so you are covered if you round to 26%.
โ Common Student Pitfalls
- Confusing square root and cube root: Writing โt instead of โt leads to calculating โ2 โ 1.414 (giving 41.4%), which scores zero unless explicitly corrected.
- Assuming linear proportionality: Thinking doubling revision time doubles the mark (+100%). Proportionality only means direct multiplying when the power is 1.
- Stopping at the multiplier: Giving 126% or 1.26 instead of subtracting 100% to give the increase (26%).
- Squaring/cubing the wrong term: Writing 2โt instead of โ(2t) . The time doubles, so the 2 belongs inside the cube root!
Topics
Ratio, proportion and rates of change ยท 3.3 Ratio, proportion and rates of change
Question and mark scheme from the AQA GCSE Mathematics examination, Paper 2 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.