AQA GCSE Mathematics Paper 3 (Foundation), June 2025: Question 18
3 marks · Medium difficulty · Multi-step Problem
Calculate the number of matches lost using information given in a pie chart where 30 matches correspond to the won sector.
Practise this questionQuestion
Mark scheme
Show the mark scheme
How to answer it
Calculating Quantities from a Pie Chart
📋 What this question tests
- Angles in a circle & on a straight line: Knowing a full circle contains 360° and a straight line/semicircle contains 180°.
- Proportional reasoning: Linking a known sector frequency (30 matches) to its sector angle to find the scale factor (degrees per match or matches per degree).
- Calculating sector frequencies: Using ratio or proportion to determine the frequency of another sector ("Lost").
Question 18 (3 Marks)
Results of team matches represented in a pie chart
💡 Key Knowledge
- A complete pie chart totals 360°.
- The line between "Won" and the other two sectors is a straight diameter line:
132° + 48° = 180° - Therefore, the angle for "Won" is:
360° - 180° = 180° (or a half of the chart). - The Core Relationship:
180° represents 30 matches.
🧠 Exam Technique
- Read carefully: 30 is the number of matches won, not the total number of matches played!
- Find the unit rate:
- Degrees per match: 180° ÷ 30 = 6° per match
- Matches per degree: 30 ÷ 180 = 1/6 match per degree
- Once you know 1 match = 6° , divide any angle by 6 to get its frequency immediately.
📐 Step-by-Step Solutions
Method 1: Unitary Method (Degrees per Match) – Recommended
- Calculate the angle for "Won":
Angle = 360° - (132° + 48°) = 180°
[1 mark (M1)] - Find how many degrees represent 1 match:
180° ÷ 30 matches = 6° per match - Calculate the number of lost matches:
132° ÷ 6° = 22 matches
[1 method mark (M1dep) + 1 accuracy mark (A1)]
Method 2: Fractional Proportion
- Set up the fraction of won matches:
Lost matches are in proportion to won matches by their angles:
Lost / Won = 132° / 180°
[1 mark (M1)] - Multiply by the frequency of won matches:
Number of lost matches = (132 / 180) × 30
[1 mark (M1dep)] - Simplify:
(132 ÷ 6) = 22 matches
[1 mark (A1)]
✅ Correct Answer & Mark Breakdown
Answer: 22
Mark Scheme Allocation:
- M1: For finding the angle for Won ( 180° ) and calculating degrees per match ( 180 ÷ 30 or 6 ), OR for setting up a correct ratio/fraction such as 132/180 or 30/180 .
- M1dep: For completing the calculation: 132 ÷ 6 or (132/180) × 30 .
- A1: For the final answer of 22.
❌ Common Misconceptions & Examiner Traps
- Assuming 30 was the total number of matches:
A very common student error was computing (132 ÷ 360) × 30 = 11 .
Examiner Note: The mark scheme awards a Special Case mark (SC1) for 11, but you lose 2 marks for misreading the question! - Premature rounding:
Using decimal approximations like 30 ÷ 180 ≈ 0.17 and multiplying: 0.17 × 132 = 22.44 . Even if rounded to 22 at the end, examiners often penalise premature rounding if not clearly justified ( M1 M1 A0 ). Always keep exact fractions! - Finding "Drew" instead of "Lost":
48 ÷ 6 = 8 matches were drawn. Double-check you are answering for lost matches.
Topics
Statistics · Ratio, proportion and rates of change · 3.6 Statistics · 3.3 Ratio, proportion and rates of change
Question and mark scheme from the AQA GCSE Mathematics examination, Paper 3 (Foundation), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.