AQA GCSE Mathematics Paper 3 (Foundation), June 2025: Question 24
2 marks · Medium difficulty · Short Answer
Find the equation of a straight line parallel to a given line and identify the equation of a line with a given gradient passing through a given point.
Practise this questionQuestion
Mark scheme
Show the mark scheme
How to answer it
Straight Line Graphs: Parallel Lines & Equations
📌 What this question tests
This question assesses your ability to find equations of straight lines using y = mx + c . Specifically, it tests:
- Identifying the gradient of a line from an implicit form and writing a parallel equation.
- Understanding that parallel lines have identical gradients ( m ) but different y-intercepts ( c ).
- Finding the exact equation of a straight line given its gradient and a coordinate point on the line.
Question 24 (a)
Parallel Lines [1 mark]
✅ Correct Answers [1 Mark]
Any equation of the form y = 2x + c (or y - 2x = c ) where c ≠ 9.
Examples of full-mark answers:
- y = 2x
- y = 2x + 1
- y = 2x - 5
- y - 2x = 0
💡 Key Knowledge
- The standard form is y = mx + c , where m is the gradient and c is the y-intercept.
- Rearrange the given line into standard form:
y - 2x = 9 → y = 2x + 9 - The gradient is m = 2.
- Parallel lines have identical gradients, so your line must also have a gradient of 2.
📐 Step-by-Step Method
- Rearrange to find the gradient:
y - 2x = 9 ⇒ add 2x to both sides ⇒ y = 2x + 9 .
The gradient is 2 . - Choose a new intercept:
Keep m = 2 , but pick any number other than 9 for c (e.g., c = 3 ). - Write the final equation:
y = 2x + 3 .
❌ Common Errors to Avoid
- Writing literally y = 2x + c : You must choose an actual numerical value for the intercept. Writing the algebraic letter c scores 0 marks.
- Writing the same line: If you write y = 2x + 9 or y - 2x + 1 = 10 (which simplifies to y - 2x = 9 ), you score 0 marks because it is the exact same line, not a parallel line.
- Sign mistake on rearrangement: Thinking the gradient is -2 by incorrectly moving the 2x term.
Mark Scheme Breakdown: B1 for any correct linear equation with gradient 2 and a different y-intercept ( c ≠ 9 ).
Question 24 (b)
Finding the Equation of a Line [1 mark]
✅ Correct Answer [1 Mark]
Circle:
y = 5x - 8
🧠 Exam Technique: Elimination
- The question states the line has gradient 5.
- In y = mx + c , the number in front of x must be 5.
- Instantly eliminate options with gradient 3:
y = 3x - 2 and y = 3x + 7 . - Only two options remain: y = 5x or y = 5x - 8 .
📐 Step-by-Step Calculation
- Identify given information:
Gradient m = 5
Point (x, y) = (3, 7) - Substitute into y = mx + c :
7 = 5(3) + c - Solve for c :
7 = 15 + c
c = 7 - 15 = -8 - State the full equation:
y = 5x - 8
❌ Common Errors to Avoid
- Confusing the y-intercept with the y-coordinate: Some students mistakenly think that because the point has y = 7 , the equation must end in + 7 (choosing y = 3x + 7 ). The y-intercept is only equal to y when x = 0 !
- Swapping x and y: Calculating 3 = 5(7) + c instead of 7 = 5(3) + c .
- Guessing without testing: You can always test the point: 5(3) - 8 = 15 - 8 = 7 . This confirms the point (3, 7) lies on the line.
Mark Scheme Breakdown: B1 for selecting/circling y = 5x - 8 only.
Topics
Algebra · 3.2.2 Graphs
Question and mark scheme from the AQA GCSE Mathematics examination, Paper 3 (Foundation), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.