AQA GCSE Physics Physics Paper 1 (Higher), November 2020: Question 6

10 marks · Standard Demand difficulty · Short Answer

Calculate the mass of a rider from gravitational potential energy change and vertical height, and explain why riders have similar speeds at the bottom of a water slide.

Practise this question

Question

Figure 9 shows a theme park ride called AquaShute with a rider on a sled sliding down a water slide. Question 06.1 asks to select two measurements needed to determine speed using a light gate and data logger. Question 06.2 asks to calculate the mass of a rider given gravitational potential energy decrease, vertical height, and gravitational field strength. Question 06.3 asks to explain why all riders and sleds have approximately the same speed at the bottom of the slide.
Question text

06 Figure 9 shows a theme park ride called AquaShute.

Riders of the AquaShute sit on a sled and move down a slide.

Figure 9

06.1 A light gate and data logger can be used to determine the speed of each rider and

sled.

What two measurements are needed to determine the speed of a rider and sled?

[2 marks]

Tick ( ) two boxes.

Gravitational field strength

Length of sled

Mass of rider and sled

Temperature of surroundings

Time for sled to pass light gate 21

06.2 The decrease in gravitational potential energy of one rider on the slide was 8.33 kJ.

*20* The rider moved through a vertical height of 17.0 m.

gravitational field strength = 9.8 N/kg

Calculate the mass of the rider.

[4 marks]

Mass of rider = kg

06.3 At the bottom of the slide, all riders and their sleds have approximately the same

speed.

Explain why.

[4 marks]

Mark scheme

Show the mark scheme Mark scheme for Question 6 outlining required answers and marks for 06.1 (length of sled and time to pass light gate), 06.2 (converting units, substitution, rearrangement, and calculating 50.0 kg), and 06.3 (equating kinetic and gravitational potential energy, showing mass cancels out, and explaining speed depends on vertical height).

Question 6

AO /

Question Answers Extra information Mark

Spec. Ref.

06.1 Length of sled 1 AO2

4.1.1.2

Time for sled to pass light gate 1

06.2 AO2

Ep = 8330 (J) 1 4.1.1.2

8330 = m × 9.8 × 17.0 allow a correct substitution using 1

an incorrectly/not converted

value of Ep

8330 allow a correct rearrangement 1

m = using an incorrectly/not

9.8 ×17.0

converted value of Ep

m = 50.0 (kg) allow a correct calculation using 1

an incorrectly/not converted

value of Ep

06.3 ½ mv2 = mgh 1 AO1

or 4.1.1.2

decrease in Ep = increase in Ek

masses cancel on both sides of 1

the equation

or

v2 = 2gh

(final) speed only depends on 1

vertical height (and gravitational

field strength)

variations will be due to air 1

resistance/friction

or

different initial speed

Total 10

How to answer it

Energy Changes & Speed on a Theme Park Ride

What this question tests

This question assesses your understanding of energy stores, the conservation of energy, and practical methods for measuring speed in the laboratory or field. You will need to recall and apply equations for gravitational potential energy ( E_p = mgh ) and kinetic energy ( E_k = 0.5mv² ), rearrange formulas, convert metric units (kilojoules to joules), and explain physical principles logically.

Question 06.1

Measuring Speed with a Light Gate

What two measurements are needed to determine the speed of a rider and sled?

✅ Correct Answers (Tick Two)

  • Length of sled
  • Time for sled to pass light gate

💡 Key Knowledge

Speed is calculated using the formula speed = distance / time . As the sled breaks the infrared beam of a light gate, the "distance" is the physical length of the moving object (the sled), and the "time" is how long the light beam is blocked.

❌ Common Errors

Students often incorrectly select "Mass of rider and sled" or "Gravitational field strength", confusing variables needed for energy calculations with the kinematic definition of speed.

Marks: 2 marks (1 mark for each correct box ticked).
Question 06.2

Calculating Mass from Gravitational Potential Energy

The decrease in E_p of one rider was 8.33 kJ, vertical height was 17.0 m, and g = 9.8 N/kg. Calculate the mass.

📐 Step-by-Step Calculation

  1. Convert units: Convert kilojoules to joules.
    8.33 kJ = 8330 J (Multiply by 1000).
  2. State the equation:
    E_p = m × g × h
  3. Substitute values:
    8330 = m × 9.8 × 17.0
  4. Rearrange and solve:
    m = 8330 / (9.8 × 17.0)
    m = 8330 / 166.6 = 50.0 kg

❌ Common Calculation Traps

  • Unit Neglect: Forgetting to convert 8.33 kJ into 8330 J results in a mass calculation that is off by a factor of a thousand!
  • Significant Figures: The data is given to 3 significant figures, so your final answer should ideally match ( 50.0 kg ).

🧠 Exam Technique

Always write out the un-rearranged formula first, even if you are confident with algebra. Examiners award method marks for correct substitution even if a minor arithmetic error occurs later in the calculation.

Marks: 4 marks total (1 for correct E_p in Joules, 1 for correct substitution, 1 for rearrangement, 1 for final answer of 50.0 kg ).
Question 06.3

Explaining Equal Speeds

At the bottom of the slide, all riders and sleds have approximately the same speed. Explain why.

✅ Marking Points Required

  • State energy conservation: Loss in E_p = Gain in E_k (or mgh = 0.5mv² ).
  • Explain that mass ( m ) appears on both sides and cancels out.
  • Derive or state that final speed depends only on vertical height ( h ) and gravitational field strength ( g ).
  • Acknowledge real-world factors: Variations in speed are due to friction/air resistance or different starting speeds.

💡 Key Physics Principle

By equating gravitational potential energy to kinetic energy:
mgh = 0.5mv²
Dividing both sides by mass leaves:
gh = 0.5v² , which rearranges to v = √(2gh) . Notice mass ( m ) has completely disappeared from the formula!

🧠 Examiner Commentary

Higher-tier candidates instantly recognised the algebraic cancellation of mass. To secure full marks, students must also mention why speeds aren't completely identical in reality—referencing non-conservative forces like air resistance, friction with the water, or differing initial pushes at the top.

Marks: 4 marks. Structured around energy equations, mass cancellation, dependency on height/g, and real-world exceptions.

Topics

Physics · P1: Energy

Question and mark scheme from the AQA GCSE Physics examination, Physics Paper 1 (Higher), November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.