AQA GCSE Physics Physics Paper 1 (Higher), November 2021: Question 6

8 marks · Standard Demand difficulty · Short Answer

Use mass and atomic number data to find neutron count and isotopes, represent alpha decay on a graph, define random decay, and explain a radioactive decay chain.

Practise this question

Question

Question 06 features Figure 6, a grid plotting Mass number (222 to 240) against Atomic number (85 to 93), showing five nuclei: A (atomic number 86, mass number 234), B (88, 226), C (90, 234), D (92, 238), and E (92, 235). Questions follow: 06.1 asks for the number of neutrons in atom A. 06.2 asks which two atoms are the same element with multiple-choice checkboxes. 06.3 provides Figure 7 showing nucleus B on a similar grid and asks to draw an arrow representing alpha decay. 06.4 asks for the meaning of the random nature of radioactive decay. 06.5 provides three nuclear equations (Po to Pb + alpha, Pb to Bi + beta, Bi to Po + beta) and asks candidates to explain how these three decays result in a nucleus of the original element polonium.
Question text

06 Figure 6 shows the mass number and the atomic number for the nuclei of five

different atoms.

Figure 6

06.1 How many neutrons are there in a nucleus of atom A?

[1 mark]

06.2 Which two atoms in Figure 6 are the same element?

[1 mark]

Tick ( ) one box.

A and B

A and C

C and D

D and E 22

06.3 Nucleus B decays by emitting an alpha particle.

*20* Draw an arrow on Figure 7 to represent the alpha decay.

[2 marks]

Figure 7

06.4 What is meant by the ‘random nature of radioactive decay’?

[1 mark]

06.5 A polonium (Po) nucleus decays by emitting an alpha particle and forming a

lead (Pb) nucleus.

Po → Pb + α

The lead (Pb) nucleus then decays by emitting a beta particle and forms a bismuth

(Bi) nucleus.

Pb → Bi + β

The bismuth (Bi) nucleus then decays by emitting a beta particle and forms a

polonium (Po) nucleus.

Bi → Po + β

*22* Explain how these three decays result in a nucleus of the original element, polonium.

[3 marks]

Mark scheme

Show the mark scheme Mark scheme for Question 6: 06.1 gives 148 (1 mark, AO1); 06.2 gives D and E (1 mark, AO1); 06.3 awards 1 mark for a line between B and 86 protons, and 1 mark for the same line between B and 222 mass number (AO2); 06.4 awards 1 mark for cannot predict which nucleus will decay next or cannot predict when a particular nucleus will decay (AO1); 06.5 awards 1 mark for one alpha decay decreasing proton number by 2, 1 mark for two beta decays increasing proton number by 2, and 1 mark for stating that the proton/atomic number of the final nucleus is the same as the original (dependent on scoring the first two marks). Total = 8 marks.

Question 6

AO /

Question Answers Extra information Mark

Spec. Ref.

06.1 148 1 AO1

4.4.1.2

06.2 D and E 1 AO1

4.4.1.2

line between B and 86 protons 1

06.3 AO2

4.4.2.2

same line between B and 222

mass number 1

06.4 can’t predict which nucleus will 1 AO1

decay next 4.4.2.3

or

can’t predict when a (particular)

nucleus will decay

06.5 one alpha decay would 1 AO1

decrease proton number by 2 4.4.2.2

two beta decays would increase 1

proton number by 2

so the proton / atomic number of this mark is dependent on 1

the final nucleus is the same as scoring the first two marks

the proton / atomic number of

the original nucleus

Total 8

How to answer it

Nuclear Structure & Radioactive Decay Modes

What this question tests

This question assesses fundamental recall and graphical skills from AQA Physics topic 4.4 (Atomic Structure):

  • Calculating neutron numbers from mass number and atomic number ( A - Z ).
  • Defining isotopes and recognising that atomic (proton) number determines the element identity.
  • Representing alpha (α) decay graphically on an atomic number vs. mass number plot.
  • Recalling the exact meaning of the random nature of radioactive decay.
  • Explaining consecutive alpha and beta (β) decays and their net effect on nuclear charge.
Question 06.1

Number of Neutrons in Atom A

1 Mark • Assessment Objective: AO1

📐 Step-by-Step Calculation

1 Read values for A from Figure 6:
• Mass number ( A ) = 234
• Atomic number ( Z ) = 86
2 Apply formula:
Neutrons = Mass Number - Atomic Number
3 Compute:
234 - 86 = 148

✅ Correct Answer

148

Mark allocation: 1 mark for the exact integer value 148 .

🧠 Exam Technique

Always double-check axis labels on Figure 6. The y-axis shows Mass number (total nucleons), not neutrons. Never stop at reading just one number off the graph!

❌ Common Errors

A frequent error is writing down 234 (the mass number) or 86 (the proton number) directly without subtracting.

Question 06.2

Identifying Atoms of the Same Element

1 Mark • Assessment Objective: AO1

💡 Key Knowledge

  • An element is defined purely by its atomic number (number of protons).
  • Atoms with the same atomic number but different mass numbers are isotopes of the same element.
  • On Figure 6, atoms of the same element lie on the same vertical line.

✅ Correct Answer

Tick the box for: D and E

  • D: Atomic number = 92, Mass number = 238
  • E: Atomic number = 92, Mass number = 235
Mark allocation: 1 mark for selecting D and E only.

❌ Common Errors

Confusing mass number with atomic number and choosing A and C because they share the same mass number (234). Remember: identical mass number does not mean the same element!

Question 06.3

Graphing Alpha (α) Decay on Figure 7

2 Marks • Assessment Objective: AO2

💡 Key Knowledge: Alpha Particle Properties

An alpha particle is a helium nucleus: ⁴₂He (or ⁴₂α).

  • Proton / Atomic number decreases by 2 ( ΔZ = -2 )
  • Mass number decreases by 4 ( ΔA = -4 )

✅ Correct Drawing / Answer

An arrow drawn starting at point B (88, 226) and pointing directly to the coordinates:

Atomic number = 86, Mass number = 222

Mark Scheme Breakdown:
• Mark 1: Arrow or line ending at an atomic number of 86 protons.
• Mark 2: Arrow or line ending at a mass number of 222.

🧠 Exam Technique & Diagram Details

Use a ruler and pencil. Draw an arrow with a clear arrowhead:

  • Start point: Exactly on dot B (88, 226) .
  • End point: Exactly on the intersection of vertical gridline 86 and horizontal gridline 222 .

❌ Common Errors

  • Decreasing mass number by 2 instead of 4 (confusing protons and neutrons).
  • Drawing an arrow that shifts right instead of left (increasing atomic number).
  • Omitting the arrowhead, which leaves ambiguity about the direction of decay.
Question 06.4

Meaning of 'Random Nature' of Decay

1 Mark • Assessment Objective: AO1

✅ Correct Answer (Either statement scores)

  • Cannot predict which nucleus will decay next
  • — OR —
  • Cannot predict when a (particular) nucleus will decay
Mark allocation: 1 mark for correctly stating unpredictable timing OR unpredictable nucleus.

❌ Common Errors & Examiner Traps

  • Vague wording: Writing "it happens randomly" or "it happens by chance" gains 0 marks as it simply repeats the question.
  • Confusing with half-life: Stating "we don't know how long half-life takes" is scientifically incorrect; half-life is predictable for large samples.
Question 06.5

Explaining the Decay Series Returning to Polonium

3 Marks • Assessment Objective: AO1

💡 The Decay Sequence Given

Po → Pb + α   |   Pb → Bi + β   |   Bi → Po + β

✅ Model Answer (Full 3 Marks)

  • Mark 1: One alpha decay decreases the proton number (atomic number) by 2.
  • Mark 2: Two beta decays each increase the proton number by 1, so together they increase the proton number by 2.
  • Mark 3: Therefore, the final proton / atomic number is the same as the original nucleus, making it the original element (polonium).
Examiner Condition: Mark 3 is dependent on scoring both Mark 1 and Mark 2.

🧠 How to Structure a 3-Mark Explanation

Break the decay sequence down mathematically:

1 Alpha step: ΔZ = -2
2 Two beta steps: ΔZ = +1 + 1 = +2
3 Conclusion: Overall change ΔZ = -2 + 2 = 0 . Since atomic number determines the element, it is polonium once again.

❌ Common Errors

  • Failing to mention protons or atomic number and only discussing mass numbers (the final polonium nucleus is an isotope of the original, with a different mass number: 4 units lighter!).
  • Thinking beta decay decreases protons (in beta decay, a neutron turns into a proton, so proton number increases by 1).

Topics

Physics · P4: Atomic Structure

Question and mark scheme from the AQA GCSE Physics examination, Physics Paper 1 (Higher), November 2021. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.