AQA GCSE Physics Physics Paper 2 (Foundation), November 2021: Question 2

11 marks · Standard Demand difficulty · Short Answer

Analyze forces, moments, motion graphs, and displacement for a cyclist using multiple short-answer and calculation questions.

Practise this question

Question

A multi-part physics question about a cyclist, featuring diagrams of a cyclist with force arrows, a pedal moment diagram, a bicycle drive mechanism, a velocity-time graph, and a curved route displacement map.
Question text

02 Figure 3 shows a cyclist on a bicycle.

The cyclist is moving at a constant velocity.

Arrows A and B represent the horizontal forces acting on the bicycle and cyclist.

Figure 3

02.1 What is force A?

[1 mark]

Tick ( ) one box.

Air resistance

Friction

Tension

Upthrust 7

02.2 What is force B?

[1 mark]

Tick ( ) one box.

Air resistance

Magnetic

Tension

Upthrust

02.3 What is the relationship between force A and force B when the cyclist travels at a

constant velocity?

[1 mark]

Tick ( ) one box.

A = B

A > B

A < B 8

02.4 The cyclist applies a force of 150 N to one of the bicycle pedals.

Figure 4 shows the distance between the force applied and the pivot.

Figure 4

Calculate the moment about the pivot caused by the force applied to the

pedal in Figure 4.

Use the equation:

moment of a force = force × distance

[2 marks]

Moment = N m

02.5 Figure 5 shows how the pedal is connected to the back wheel of the bicycle.

Figure 5

Complete the sentence.

Choose the answer from the box.

[1 mark]

axle chain cog

The force from the cyclist pushing down on the pedal is transmitted to the back wheel

by the .

Figure 6 shows how the velocity of the cyclist changes during a journey.

Figure 6

02.6 What is the change in velocity of the cyclist in the first 20 seconds of the journey?

[1 mark]

Tick ( ) one box.

5.2 m/s

5.4 m/s

5.6 m/s

5.8 m/s 11

02.7 Determine the acceleration of the cyclist during the first 20 seconds of the journey.

Use your answer from Question 02.6

Use the equation:

change in velocity

acceleration =

time taken

[2 marks]

Acceleration of the cyclist = m/s2

02.8 Complete the sentence.

Choose the answer from the box.

[1 mark]

deceleration speed velocity

Between 30 and 40 seconds the cyclist moves with

a constant .

02.9 The cyclist travels from home to school.

Figure 7 shows the route the cyclist followed.

Figure 7

Draw an arrow on Figure 7 to show the displacement of the cyclist.

[1 mark]

Mark scheme

Show the mark scheme Mark scheme table detailing the correct answers, marks, and specification references for questions 02.1 through 02.9, totaling 11 marks.

Question 2

AO /

Question Answers Extra information Mark

Spec. Ref.

02.1 friction 1 AO1

4.5.1.2

02.2 air resistance 1 AO1

4.5.1.2

02.3 A = B 1 AO1

4.5.6.2.2

02.4 M = 150 × 0.24 1 AO2

4.5.4

M = 36 (Nm) 1

02.5 chain 1 AO2

4.5.4

02.6 5.8 m/s 1 AO2

4.5.6.1.5

02.7 a = 5.8 allow their v from question 02.6 1 AO2

20 4.5.6.1.5

a = 0.29 (m/s2) allow a correctly calculated 1

value using their v from

question 02.6

02.8 Deceleration 1 AO3

4.5.6.1.5

02.9 straight arrow drawn between 1 AO1

home and school pointing 4.5.6.1.1

towards school.

Total 11

How to answer it

Forces, Moments and Motion Study Guide

AQA GCSE Physics • Exam Question Breakdown

What this question tests

This question assesses core mechanics topics including contact and non-contact forces, Newton's first law (terminal velocity/constant speed), calculating moments of forces, interpreting velocity-time graphs to calculate acceleration, and distinguishing between vector quantities (displacement) and scalar quantities.

Part 02.1 & 02.2: Identifying Forces

Identifying force A (tyre/ground interaction) and force B (air resistance)

✅ Correct Answers

  • 02.1: Friction
  • 02.2: Air resistance

💡 Key Knowledge

  • Force A acts upwards/backwards at the point where the tyre touches the road. This is contact friction between the tyre and road surface.
  • Force B acts horizontally backwards against the motion of the cyclist, caused by air particles colliding with the rider and bicycle.
Mark: 1 mark for 02.1 | 1 mark for 02.2

Part 02.3: Constant Velocity & Forces

Relating force A and force B at constant velocity

✅ Correct Answer

A = B

🧠 Exam Technique & Knowledge

According to Newton's First Law, when an object travels at a constant velocity (steady speed in a straight line), the resultant force on the object must be zero. Therefore, the forward driving forces must exactly balance the backward resistive forces.

Mark: 1 mark

Part 02.4: Calculating Moments

Calculating the turning effect on the pedal

📐 Step-by-Step Calculation

  1. State the formula: Moment = force × distance
  2. Substitute values: 150 N × 0.24 m
  3. Calculate final answer: 36 N m

❌ Common Errors

  • Forgetting to include or miscalculating the units (N m).
  • Inverting multiplication or dividing values instead of multiplying force by perpendicular distance from the pivot.
Mark: 2 marks total (1 mark for substitution, 1 mark for correct value with unit)

Part 02.5: Transmission of Forces

Completing the sentence about mechanical systems

✅ Correct Answer

chain

💡 Key Knowledge

Bicycles use gears and a chain to transmit rotational force (moments) from the front pedals to the back wheel.

Mark: 1 mark

Part 02.6 & 02.7: Velocity-Time Graphs & Acceleration

Reading values from a graph and calculating acceleration

✅ Correct Answers

  • 02.6: 5.8 m/s (change in velocity from t = 0 to t = 20 s)
  • 02.7: 0.29 m/s²

📐 Step-by-Step Calculation (02.7)

  1. State equation: acceleration = change in velocity / time taken
  2. Substitute values: 5.8 / 20
  3. Calculate: 0.29 m/s²

🧠 ECF (Error Carried Forward) Note

If you misread 02.6, examiners will allow a correctly calculated acceleration based on whatever velocity value you brought forward from 02.6! Always read graph grid lines carefully (each small square on the vertical axis represents 0.2 m/s).

Mark: 1 mark for 02.6 | 2 marks for 02.7

Part 02.8: Interpreting Motion Graphs

Completing the sentence for the 30 to 40 second interval

✅ Correct Answer

Deceleration

💡 Knowledge & Analysis

Looking at Figure 6, between 30 and 40 seconds the line slopes downwards from a velocity of nearly 6 m/s down to 0 m/s. A downward slope on a velocity-time graph indicates negative acceleration, known as deceleration.

Mark: 1 mark

Part 02.9: Displacement

Drawing an arrow to represent displacement

✅ Correct Answer Description

A single straight arrow drawn directly from the starting point labelled "Home" to the end point labelled "School", pointing towards "School".

❌ Common Errors

Students often trace the curved path shown on the map. Remember that displacement is defined as the distance in a given direction—it is always a straight line from start to finish, regardless of the actual route taken!

Mark: 1 mark

Topics

Physics · P5: Forces

Question and mark scheme from the AQA GCSE Physics examination, Physics Paper 2 (Foundation), November 2021. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.