AQA GCSE Physics Physics Paper 1 (Higher), June 2022: Question 11
9 marks · Standard Demand difficulty · Short Answer
Analyze hair straighteners circuits by drawing an LED symbol, explaining switch function, calculating operating time from energy and power, and explaining the effect of closing switches on power output.
Practise this questionQuestion
Question text
11 Figure 12 shows some hair straighteners.
Hair straighteners contain heating elements.
Figure 12
11.1 When the hair straighteners reach normal operating temperature, an LED turns on.
Draw the circuit symbol for an LED in the box.
[1 mark]
Figure 13 shows the circuit diagram for the hair straighteners.
Each resistor represents a heating element.
The power output of the hair straighteners can be changed by closing different
switches.
Figure 13
11.2 Why do the hair straighteners not turn on when only switch S2 is closed?
[1 mark]
11.3 The hair straighteners have a maximum power output of 120 W.
The energy transferred to the hair straighteners to reach normal operating
temperature is 3.6 kJ.
Calculate the time taken for the hair straighteners to reach normal operating
temperature when operating at maximum power.
Use the Physics Equations Sheet.
[4 marks]
*31* 33
Time = seconds
11.4 Figure 14 shows the hair straighteners circuit with switch S1 closed.
Figure 14
Switch S2 and switch S3 are then closed at the same time.
Explain what happens to the power output of the power supply.
[3 marks]
Mark scheme
Show the mark scheme
AO /
Question Answers Extra information Mark
Spec. Ref.
11.1 allow: 1 AO1
4.2.1.1
AO /
Spec. Ref.
11.2 there is a gap in the circuit 1 AO1
or 4.2.2
S1 needs to be closed to
complete the circuit
or
S1 needs to be closed to turn the
hair straighteners on
AO /
Spec. Ref.
11.3 E = 3600 (J) 1 AO2
4.2.4.2
3600 = 120 × t this mark may score if E is 1
incorrectly / not converted
3600 this mark may score if E is 1
t = incorrectly / not converted
t = 30 (s) allow an answer consistent with 1
their value of–E HYSICS – –
AO /
Spec. Ref.
24 11.4 the total resistance of the circuit 1 AO1
decreases 4.2.4.1
4.2.2
so the current increases 1
which increases the power 1
output
Total Question 11 9
How to answer it
GCSE Physics Study Guide: Electric Circuits & Power
What this question tests
This question assesses your knowledge of standard circuit symbols, series and parallel switching logic, rearranging energy-power equations, and explaining the electrical effects of adding parallel branches to a circuit.
Drawing an LED Circuit Symbol
✅ Correct Answer
A diode symbol (triangle pointing right inside a circle, with a vertical line at the tip) accompanied by two outward-pointing arrows originating from the diode.
💡 Key Knowledge
Recall standard component symbols. A regular diode allows current in one direction; an LED (Light Emitting Diode) emits light when current flows, represented by the two arrows pointing diagonally away from it.
❌ Common Errors
Forgetting the arrows entirely (which just draws a standard semiconductor diode) or pointing the arrows inwards towards the diode.
Switching Logic in Circuits
✅ Correct Answer
"There is a gap in the circuit" OR "Switch S₁ needs to be closed to complete the circuit."
🧠 Exam Technique
Look at the position of the switches in Figure 13. Switch S₁ is on the main live/supply line. Even if S₂ is closed, the main loop remains incomplete because S₁ is open.
Calculating Time from Energy and Power
📐 Step-by-Step Calculation
- Identify the formula: Energy transferred = Power × time ( E = P × t )
- Convert units: Energy = 3.6 kJ = 3600 J (multiply by 1000). Power = 120 W .
- Rearrange the equation: t = E / P
- Substitute and solve: t = 3600 / 120 = 30 seconds .
❌ Common Calculation Traps
Forgetting to convert kilojoules (kJ) into joules (J). Writing 3.6 instead of 3600 will throw your final answer off by a factor of a thousand!
Explaining Power Changes in Parallel Branches
✅ Correct Answer
- The total resistance of the circuit decreases.
- So the current increases.
- Which increases the power output.
💡 Key Knowledge
Adding resistors in parallel decreases overall circuit resistance because more alternative pathways are opened up for charge to flow. Since P = I²R or P = V²/R , lowering resistance at a constant voltage increases current and power output.
🧠 Exam Technique
This is a classic 3-mark causal chain question. Make sure you link the steps logically in order: Resistance down → Current up → Power up. Do not skip intermediate links!
Topics
Physics · P2: Electricity
Question and mark scheme from the AQA GCSE Physics examination, Physics Paper 1 (Higher), June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.