AQA GCSE Physics Physics Paper 2 (Foundation), June 2022: Question 7

16 marks · Standard Demand difficulty · Short Answer

Answer a series of questions about sound waves including definitions, frequency conversions, calculations of period, wavelength, wave speed, distance, time, and wave interference effects.

Practise this question

Question

An exam question about sound waves with multiple parts (07.1 to 07.8). It includes word-selection boxes, multiple-choice options for frequency conversion, calculation spaces, and Figure 14 showing two loudspeakers A and B at a concert venue with a sound technician listening.
Question text

07 Sound travels as longitudinal waves.

07.1 Complete the sentences.

Choose the answers from the box.

[2 marks]

amplitude frequency speed wavelength

The distance between the centre of one compression of a sound wave and the centre

of the next compression is called the .

The number of waves passing a point each second is called the

.

07.2 Complete the sentence.

Choose the answer from the box.

[1 mark]

opposite perpendicular parallel

In a longitudinal wave, the oscillations are

to the direction of energy transfer.

07.3 A sound wave has a frequency of 8.0 kHz.

Which of the following is the same as 8.0 kHz?

[1 mark]

Tick ( ) one box.

0.0080 Hz

8.0 Hz

8000 Hz

800 000 Hz

07.4 Calculate the period of a sound wave with a frequency of 8.0 kHz.

Use the Physics Equations Sheet.

[2 marks]

Period = s

07.5 Calculate the wavelength of a sound wave with a frequency of 6600 Hz.

speed of sound = 330 m/s

Use the equation:

speed

wavelength =

frequency

Choose the unit from the box.

[3 marks]

kg m N

*30* 32

Wavelength = Unit

Figure 14 shows the arrangement of two loudspeakers at a concert venue.

Figure 14

The loudspeakers in Figure 14 are tested by playing the same song through both

loudspeakers.

A sound technician listens to the song.

Use the Physics Equations Sheet to answer questions 07.6 and 07.7.

07.6 Write down the equation which links distance (s), speed (v) and time (t).

[1 mark]

07.7 Distance A on Figure 14 is 13.2 m.

speed of sound = 330 m/s

Calculate the time taken for the sound to travel from loudspeaker A to the technician.

[3 marks]

Time taken = s

07.8 The sound from each loudspeaker travels at the same speed.

For the sound technician to hear the song clearly, the sound from loudspeaker B

*32* should be emitted slightly before the sound from loudspeaker A.

Explain why.

[3 marks]

Mark scheme

Show the mark scheme A detailed mark scheme table for Question 7, breaking down answers, extra information, marks, and specification references for sub-questions 07.1 through 07.8.

Question 7

AO /

Question Answers Extra information Mark

Spec. Ref.

07.1 this order only AO1

wavelength 1 4.6.1.2

frequency 1

AO /

Spec. Ref.

07.2 parallel 1 AO1

4.6.1.2

AO /

Spec. Ref.

07.3 8000 Hz 1 AO2

4.6.1.2

AO /

Spec. Ref.

07.4 period = allow ecf from question 07.3 1 AO2

8000 4.6.1.2

0.000125 (s) 1

AO /

Spec. Ref.

07.5 λ = 1 AO2

6600

λ = 0.050 allow 0.05 1 AO2

m 1 AO1

4.5.6.1.2

AO /

Spec. Ref.

07.6 distance (travelled) = speed × allow any correct rearrangement 1 AO2

time 4.5.6.1.2

or

s = vt

AO /

Spec. Ref.

07.7 13.2 = 330 × t 1 AO2

4.5.6.1.2

13.2

t = 1

t = 0.04 (s) allow 0.040 (s) 1

AO /

Spec. Ref.

07.8 loudspeaker B is further from ‘it’ means speaker B 1 AO3

the technician (than speaker A) 4.6.1.2

so the sound would take more 1

time to travel (to the technician)

so the sound from each speaker 1

arrives at the technician at the 21

same time

Total Question 7 16

How to answer it

AQA GCSE Physics: Waves & Sound Study Guide

What this question tests

This question assesses your understanding of wave properties (longitudinal waves, wavelength, frequency, amplitude, period), standard wave calculations (using v = f × lambda and T = 1 / f ), distance-speed-time relationships, and applying practical wave physics to real-world scenarios involving sound propagation and delays.

Part 07.1

Wave Definitions

✅ Correct Answers

  • 1st blank: wavelength
  • 2nd blank: frequency
Awarded: 2 marks (must be in this exact order).

💡 Key Knowledge

  • Wavelength: The distance from one point on a wave to the equivalent point on the next wave (e.g., compression to compression).
  • Frequency: The number of complete waves passing a point per second, measured in Hertz (Hz).
Part 07.2

Nature of Longitudinal Waves

✅ Correct Answer

In a longitudinal wave, the oscillations are parallel to the direction of energy transfer.

Awarded: 1 mark.

❌ Common Errors

Students frequently confuse longitudinal waves with transverse waves and write "perpendicular". Remember: longitudinal = par-all-el (both contain parallel structures).

Part 07.3

Unit Conversions (kHz to Hz)

✅ Correct Answer

8000 Hz (Tick the third box down)

Awarded: 1 mark.

💡 Key Knowledge

The prefix kilo (k) means 1,000. To convert from kilohertz (kHz) to hertz (Hz), multiply the value by 1,000.

8.0 kHz × 1000 = 8000 Hz

Part 07.4

Calculating Wave Period

📐 Step-by-Step Calculation

  1. Equation: Period = 1 / frequency ( T = 1 / f )
  2. Substitute values: Period = 1 / 8000
  3. Calculate: = 0.000125 s
Awarded: 2 marks (1 for correct equation/substitution, 1 for correct answer). ECF (Error Carried Forward) allowed from 07.3.

🧠 Exam Technique

Always check your standard form or decimal place count carefully when working with small fractions. Writing 0.000125 s clearly ensures full marks.

Part 07.5

Wavelength Calculation and Units

📐 Step-by-Step Calculation

  1. Equation given: wavelength = speed / frequency
  2. Substitute: wavelength = 330 / 6600
  3. Calculate: = 0.05 m
  4. Unit selection: m (metres) from the box.
Awarded: 3 marks (1 for substitution, 1 for calculation value, 1 for the unit 'm').

❌ Common Errors

Selecting kg or N because they are familiar physics units. Always match the quantity being calculated to its SI unit: wavelength is a distance, measured in metres (m).

Part 07.6

Distance, Speed, and Time Equation

✅ Correct Answer

distance = speed × time OR s = v × t (or any correct rearrangement like v = s / t )

Awarded: 1 mark.

💡 Key Knowledge

This is a fundamental equation from the Physics Equations Sheet. Memorise the speed triangle ( s = v × t ) to instantly recall alternative rearrangements.

Part 07.7

Calculating Travel Time

📐 Step-by-Step Calculation

  1. Rearrange equation: time = distance / speed ( t = s / v )
  2. Substitute: t = 13.2 / 330
  3. Calculate: 0.04 s (or 0.040 s)
Awarded: 3 marks (1 for substitution, 1 for rearrangement/working, 1 for final answer with unit).

🧠 Exam Technique

Always show your working out explicitly. Even if you make a calculator slip on the final decimal, method marks are often awarded for correct substitution.

Part 07.8

Real-World Sound Delay Analysis

✅ Correct Answer (3-point bullet logic)

  • Loudspeaker B is further away from the technician than loudspeaker A.
  • Therefore, the sound from B takes more time to travel to the technician.
  • Hence, sound B must be emitted slightly earlier so that the sounds from both speakers arrive at the same time.
Awarded: 3 marks (1 mark per distinct marking point).

❌ Common Errors & Examiner Insights

Top-level responses clearly reference relative distances and link them directly to travel times. A common student mistake is discussing sound wave interference or frequency changes instead of focusing purely on travel time differences across varying distances.

Topics

Physics · P6: Waves · P5: Forces

Question and mark scheme from the AQA GCSE Physics examination, Physics Paper 2 (Foundation), June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.