AQA GCSE Physics Physics Paper 2 (Foundation), June 2023: Question 6

11 marks · Standard Demand difficulty · Short Answer

Investigate the refraction of light through a glass block, including experimental accuracy, ray tracing, calculating mean angle, wave equation recall, and wave speed calculations.

Practise this question

Question

A multi-part exam question about refraction containing a photograph of a ray box setup (Figure 14), diagrams of ray paths through a rectangular glass block (Figure 15), a protractor diagram showing markings (Figure 16), and several written sub-questions involving multiple choice, drawing ray diagrams, calculating a mean, completing a sentence about color filters, recalling the wave equation, and calculating wavelength.
Question text

06 A student investigated the refraction of light through a glass block.

Figure 14 shows the ray box used.

The student aimed the beam of light from the ray box towards a glass block.

The student measured the angle of incidence at the point where the light entered the

glass block.

Figure 14

06.1 Why is using a wide beam of light less likely to give accurate results than using a

narrow beam?

[1 mark]

Tick ( ) one box.

It will be harder to judge where the centre of the beam is.

It will cause a smaller uncertainty in the measurements.

The angle of refraction will be larger than it should be.24

06.2 Figure 15 shows the beam of light incident on the glass block.

Figure 15

Complete Figure 15 to show the path taken by the beam of light through the glass

block and back into the air. 25

[3 marks]

Figure 16 shows the protractor used by the student.

Figure 16

06.3 What is the resolution of the protractor?

*24* [1 mark]

Tick ( ) one box.

1 degree

10 degrees

180 degrees

06.4 For one angle of incidence the student measured the angle of refraction three times.

The three measurements were:

35° 31° 33°

Calculate the mean angle of refraction.

[1 mark]

Mean angle of refraction = °

The student placed a red filter in front of the white beam of light.

Only red light passes through the filter.

06.5 Complete the sentence.

[1 mark]

When white light is incident on the red filter, all colours except for red are

by the filter.

Use the Physics Equations Sheet to answer questions 06.6 and 06.7.

06.6 Write down the equation which links frequency (f), wave speed (v) and wavelength (λ).

[1 mark]

06.7 Light has a wave speed of 3.0 × 108 m/s in air.

The frequency of the red light is 4.0 × 1014 Hz.

Calculate the wavelength of the red light in air.

[3 marks]

Wavelength = m

Mark scheme

Show the mark scheme Mark scheme for question 6, providing correct answers, acceptable alternative phrasings, ray tracing guidelines with specific refraction and emergence criteria, mean calculation, and structured calculation steps with standard form values for the wavelength question, totaling 11 marks.

Question 6

AO /

Question Answers Extra information Mark

Spec. Ref.

06.1 it is harder to judge where the 1 AO3

centre of the beam is 4.6.1.3

AO /

Spec. Ref.

06.2 ray shown refracted to the right 1 AO1

of the normal as it enters the 4.6.2.2

glass block

refraction towards the normal

emergent ray parallel to incident do not accept a continuation of

ray the incident ray through the

glass block

ignore arrows

AO /

Spec. Ref.

06.3 1 degree 1 AO2

4.6.1.3

AO /

Spec. Ref.

06.4 33 (°) 1 AO2

4.6.1.3

AO /

Spec. Ref.

06.5 absorbed 1 AO1

4.6.2.6

AO /

Spec. Ref.

06.6 wave speed = frequency × allow correct re-arrangement 1 AO1

wavelength 4.6.1.2

or

v = f λ

AO /

Spec. Ref.

06.7 3.0 × 108 = 4.0 × 1014 × λ 1 AO2

4.6.1.2

3.0 × 108

𝜆𝜆 = 14

4.0 × 10

λ = 7.5 × 10−7 (m)

allow 0.000 000 75 (m) 1

Total Question 6 11

How to answer it

Refraction of Light and Wave Calculations Study Guide

What this question tests

This exam question assesses your practical understanding of light refraction through a glass block, data analysis skills (instrument resolution and calculating means), colour filtration theory, and the application of the wave speed equation. Success requires clear ray-tracing abilities and careful calculation management.

Part 06.1 [1 mark]

Accuracy of Ray Widths in Refraction

✅ Correct Answer

Tick: It will be harder to judge where the centre of the beam is.

💡 Key Knowledge

When measuring angles of incidence and refraction, rays must be as thin as possible to pinpoint the exact centre of the beam relative to the normal line.

Part 06.2 [3 marks]

Ray Tracing Through a Glass Block

✅ Correct Answer

  • Ray shown refracted to the right (bending towards the normal) as it enters the glass block.
  • Ray refracted away from the normal as it exits the block back into the air.
  • Emergent ray must be perfectly parallel to the original incident ray.

🧠 Exam Technique

Use a sharp pencil and a ruler. Remember that light slows down moving from air (less dense) into glass (more dense), bending towards the normal. When exiting back into the air, it speeds up and bends away from the normal by the exact same angle.

❌ Common Errors

Students often draw the light ray continuing straight through the block without changing direction, or they fail to make the emerging ray parallel to the incident ray.

Mark breakdown: 1 mark for refraction towards normal at entry, 1 mark for refraction away from normal at exit, 1 mark for parallel emergent ray.
Part 06.3 [1 mark]

Resolution of a Protractor

✅ Correct Answer

Tick: 1 degree

💡 Key Knowledge

The resolution of a measuring instrument is the smallest change in the quantity being measured that causes a perceptible change in the reading. On a standard school protractor, the smallest scale division is 1 degree.

Part 06.4 [1 mark]

Calculating a Mean Angle

📐 Calculation Steps

  1. Add the repeated measurements together: 35 + 31 + 33 = 99
  2. Divide by the number of measurements (3): 99 / 3 = 33

Mean angle of refraction = 33°

❌ Common Errors

Do not include anomalous data points blindly. In this set, all three values are close, so none are discarded. Always check if a mean requires rounding to a sensible number of significant figures.

Part 06.5 [1 mark]

Colour Filtration Theory

✅ Correct Answer

Missing word: absorbed (or filtered out / stopped )

💡 Key Knowledge

Colour filters work by transmission and absorption. A red filter transmits red light waves while absorbing all other wavelengths of light present in the white light spectrum.

Part 06.6 [1 mark]

Wave Speed Equation Recall

✅ Correct Answer

wave speed = frequency × wavelength (or v = f × λ )

🧠 Exam Technique

Always memorize core equations from the physics equation sheet. You can write words or accepted standard symbols ( v , f , λ ).

Part 06.7 [3 marks]

Calculating Wavelength

📐 Step-by-Step Calculation

  1. State the equation: v = f × λ
  2. Substitute known values: 3.0 × 10⁸ = 4.0 × 10¹⁴ × λ
  3. Rearrange for wavelength (λ): λ = (3.0 × 10⁸) / (4.0 × 10¹⁴)
  4. Calculate final value: λ = 7.5 × 10⁻⁷ m (or 0.00000075 m )

Wavelength = 7.5 × 10⁻⁷ m

❌ Common Errors & Traps

  • Forgetting to rearrange the equation properly before substituting numbers.
  • Entering standard form numbers incorrectly into calculators (use the EXP or ×10ˣ button, not multiplication by 10 manually).
  • Omitting standard units or writing incorrect powers of ten.
Mark breakdown: 1 mark for correct substitution, 1 mark for correct rearrangement/calculation layout, 1 mark for final correct answer with units.

Topics

Physics · Required Practicals · Required Practicals · P6: Waves

Question and mark scheme from the AQA GCSE Physics examination, Physics Paper 2 (Foundation), June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.