AQA GCSE Physics Physics Paper 1 (Foundation), June 2024: Question 3

11 marks · Standard Demand difficulty · Short Answer

Calculate elastic potential energy, kinetic energy, maximum height, and explain energy dissipation for a theme park bungee ride.

Practise this question

Question

A multi-part physics question about a theme park ride where a pod is attached to two bungee cords, showing diagrams before and after release. It includes calculations for extension, elastic potential energy, kinetic energy, gravitational potential energy, maximum height, and identifying reasons for energy loss using multiple-choice tick boxes.
Question text

03 In a ride at a theme park, a person is strapped into a pod that is attached to two

stretched bungee cords.

The bungee cords behave like springs.

Figure 7 shows a person using the ride.

Figure 7

03.1 How is the extension of each bungee cord calculated?

[1 mark]

Tick ( ) one box.

stretched length + original length

stretched length – original length

stretched length × original length

stretched length ÷ original length

03.2 Before the pod is released, the extension of each bungee cord is 7.5 m.

spring constant of the bungee cord = 800 N/m

Calculate the elastic potential energy stored in each stretched bungee cord.

Use the equation:

*13* elastic potential energy = 0.5 × spring constant × (extension)2

[2 marks]

Elastic potential energy = J

03.3 The maximum speed of the pod is 15 m/s.

The mass of the pod is 240 kg.

Calculate the maximum kinetic energy of the pod.

Use the equation:

kinetic energy = 0.5 × mass × (speed)2

[2 marks]

Maximum kinetic energy = J

Use the Physics Equations Sheet to answer questions 03.4 and 03.5.

03.4 Which equation links gravitational field strength (g), gravitational potential energy (Ep),

height (h) and mass (m)?

[1 mark]

Tick ( ) one box.

m × g

Ep =

h

m

Ep =

g × h

Ep = m × g × h

03.5 The pod has 24 000 J of gravitational potential energy when at its maximum height.

The mass of the pod is 240 kg.

gravitational field strength = 9.8 N/kg

Calculate the maximum height reached by the pod.

[3 marks]

Maximum height = m

03.6 Why is the maximum gravitational potential energy of the pod less than the initial

elastic potential energy of the bungee cords?

[2 marks]

Tick ( ) two boxes.

Energy is created.

Energy is destroyed.

Energy is transferred to the surroundings.

Work is done against air resistance.

Work is done by the force of gravity.

Work is done by the person in the pod.

Mark scheme

Show the mark scheme Mark scheme for question 3 detailing numerical answers and accepted tick box selections for each sub-question, allocating a total of 11 marks.

Question 3

AO /

Question Answers Extra information Mark

Spec. Ref.

03.1 stretched length – original length 1 AO2

4.1.1.2

AO /

Spec. Ref.

03.2 E = 0.5 × 800 × 7.52 1 AO2

e

4.1.1.2

Ee = 22 500 (J) 1

AO /

Spec. Ref.

03.3 kinetic energy = 0.5 × 240 × 152 1 AO2

4.1.1.2

kinetic energy = 27 000 (J) 1

AO /

Spec. Ref.

03.4 Ep = m × g × h 1 AO1

4.1.1.2

AO /

Spec. Ref.

03.5 24 000 = 240 × 9.8 × h 1 AO2

4.1.1.2

24 000 1

h =

(240 × 9.8)

h = 10.2 (m) allow 10 (m) 1

allow a correct answer given to

more than 3 s.f.– – –

AO /

Spec. Ref.

03.6 energy is transferred to the 1 AO1

surroundings 4.1.2.1

work is done against air 1

resistance

Total Question 3 11

How to answer it

Energy Transfers in a Bungee Ride

What this question tests

This question assesses your understanding of energy stores and transfers, specifically focusing on elastic potential energy, kinetic energy, and gravitational potential energy. You will need to recall standard physics equations, rearrange formulas to calculate missing values (like height), and apply the principle of conservation of energy to real-world scenarios involving dissipative forces such as air resistance.

Part 03.1

Definition of Extension

✅ Correct Answer

stretched length − original length

💡 Key Knowledge

Extension is defined as the increase in length of a stretchy object (like a spring or bungee cord) when a force is applied. It is always found by taking the final stretched length away from the initial unstretched (original) length.

Mark allocation: 1 mark
Part 03.2

Calculating Elastic Potential Energy

📐 Step-by-Step Calculation

  1. Identify the given values: Spring constant ( k ) = 800 N/m , Extension ( e ) = 7.5 m .
  2. State the formula: Eₑ = 0.5 × k × e²
  3. Substitute values: Eₑ = 0.5 × 800 × 7.5²
  4. Calculate extension squared: 7.5² = 56.25
  5. Multiply through: 0.5 × 800 × 56.25 = 22,500 J

❌ Common Errors

A very common student mistake is forgetting to square the extension ( e² ). Always calculate the square of the extension before multiplying by the spring constant and 0.5.

Mark allocation: 2 marks (1 mark for correct substitution, 1 mark for correct final answer)
Part 03.3

Calculating Kinetic Energy

📐 Step-by-Step Calculation

  1. Identify the given values: Mass ( m ) = 240 kg , Speed ( v ) = 15 m/s .
  2. State the formula: Eₖ = 0.5 × m × v²
  3. Substitute values: Eₖ = 0.5 × 240 × 15²
  4. Square the speed: 15² = 225
  5. Multiply through: 0.5 × 240 × 225 = 27,000 J

🧠 Exam Technique

Even though the question gives you the equation on the paper, always write it out in symbol or word form before substituting numbers. This guarantees you pick up the substitution mark even if your calculator arithmetic goes wrong.

Mark allocation: 2 marks
Part 03.4

Gravitational Potential Energy Equation

✅ Correct Answer

Eₚ = m × g × h

💡 Key Knowledge

You must recall standard equations from memory for your GCSE exams. Gravitational potential energy depends on mass ( m ), gravitational field strength ( g ), and vertical height ( h ).

Mark allocation: 1 mark
Part 03.5

Calculating Maximum Height

📐 Step-by-Step Calculation

  1. Identify values: Eₚ = 24,000 J , m = 240 kg , g = 9.8 N/kg .
  2. Rearrange Eₚ = m × g × h to find height: h = Eₚ ÷ (m × g)
  3. Substitute numbers: h = 24,000 ÷ (240 × 9.8)
  4. Calculate denominator: 240 × 9.8 = 2,352
  5. Divide: 24,000 ÷ 2,352 = 10.204... m
  6. Round appropriately: 10.2 m (Examiners also accept 10 m if g=10 was used, or more significant figures).

❌ Common Errors

Students often fail when rearranging equations with multiple terms on the bottom. Always calculate the product of the bottom terms ( m × g ) first as a single number before dividing the top number by it.

Mark allocation: 3 marks
Part 03.6

Energy Dissipation and Conservation

✅ Correct Two Boxes to Tick

  • ✔ Energy is transferred to the surroundings.
  • ✔ Work is done against air resistance.

💡 Key Knowledge

In the real world, energy is never 100% efficient due to resistive forces. As the pod moves upward, it pushes air out of the way. This means work is done against air resistance, dissipating thermal energy into the surrounding atmosphere.

Mark allocation: 2 marks (1 mark for each correct box ticked)

Topics

Physics · P1: Energy · P5: Forces

Question and mark scheme from the AQA GCSE Physics examination, Physics Paper 1 (Foundation), June 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.