AQA GCSE Physics Physics Paper 1 (Higher), June 2025: Question 2

10 marks · Standard Demand difficulty · Extended Answer

Describe an experimental method to determine the specific heat capacity of water, identify hazards and improvements, and calculate the percentage difference in the result.

Practise this question

Question

Question 2 with Figure 4 illustrating apparatus for measuring the specific heat capacity of water: a power supply connected to a digital joulemeter, which connects to an immersion heater placed in a beaker of water alongside a thermometer, and a separate digital balance showing 00.00 g. The question consists of four parts: 02.1 asks for one hazard in the investigation (1 mark); 02.2 asks to describe how to determine the specific heat capacity of water using this apparatus (6 marks); 02.3 asks for one change to the apparatus to reduce energy loss to the surroundings (1 mark); and 02.4 gives the student's value as 4410 J/kg °C and actual value as 4200 J/kg °C, asking to calculate the percentage difference (2 marks).

Mark scheme

Show the mark scheme Mark scheme for Question 2. 02.1 awards 1 mark for hot water, beaker, or heater. 02.2 provides a 3-level mark scheme (1–6 marks) with indicative content covering measuring the mass of empty and filled beaker, turning on heater, recording temperature change, reading energy from the joulemeter, and calculating specific heat capacity with E = m c Δθ. 02.3 awards 1 mark for insulating the beaker or adding a lid. 02.4 awards 1 mark for calculating the difference (210) or correct substitution into percentage difference equation, and 1 mark for 5%. Total Question 2 is 10 marks.

How to answer it

Determining the Specific Heat Capacity of Water

📋 What This Question Tests

This question assesses core skills from AQA Required Practical 1 (Specific Heat Capacity): identifying laboratory hazards, writing a logical step-by-step scientific method, evaluating experimental errors and improvements, and calculating percentage difference using standard experimental data.

Part 02.1 · 1 Mark

Lab Safety & Hazards

Identify a hazard in the investigation

✅ Acceptable Answers

  • Hot water or hot beaker
  • Heater (it gets very hot)
  • Also allowed: Spilt water (slipping hazard) or broken glass / beaker

❌ Common Errors & Examiner Trap

Do not confuse a hazard with a risk:

  • A hazard is the object or situation with potential to cause harm (e.g. hot heater, hot water).
  • A risk is the actual harm or injury (e.g. burns to skin). The mark scheme states: "ignore descriptions of risk". Writing just "getting burnt" scores 0.
Mark Breakdown: 1 mark for naming any valid hazard (heater, hot water, broken glass, spilt water).
Part 02.2 · 6 Marks

Extended Response: Experimental Method

Describe how to determine the specific heat capacity of water using the provided apparatus

💡 Governing Equation

The entire method must provide values for every variable in:

ΔE = m × c × Δθ

Rearranged to find specific heat capacity ( c ):

c = ΔE / (m × Δθ)

  • ΔE = energy transferred (measured by joulemeter)
  • m = mass of water (measured using the balance)
  • Δθ = temperature change (measured with thermometer)

🧠 Level 3 Marking Criteria (5–6 Marks)

To hit the top band, your answer must be a coherent, logically ordered method that would produce a valid outcome:

  • Mandatory: You must explain clearly how the mass of the water is measured (not just the beaker!).
  • Every piece of equipment from Figure 4 must have a clear purpose.

✅ Model 6-Mark Method

  1. Find mass of water: Place the empty beaker on the balance and record its mass. Pour water into the beaker and record the total mass. Subtract the empty beaker mass from the total mass to find the mass of water ( m ). (Alternative: Place empty beaker on balance and press tare / zero before adding water.)
  2. Initial temperature: Place the thermometer into the water and record the starting temperature.
  3. Setup & Heat: Submerge the immersion heater fully in the water and note the initial reading on the joulemeter (or reset it to zero). Turn on the power supply to heat the water.
  4. Final readings: After a suitable temperature rise, switch off the power supply. Stir gently and record the highest final temperature reached on the thermometer.
  5. Energy reading: Read and record the total energy transferred ( ΔE ) shown on the joulemeter.
  6. Calculation: Calculate temperature change ( Δθ = final temp - initial temp ), then calculate specific heat capacity using the formula c = ΔE / (m × Δθ) .

❌ Why Students Lost Marks

  • Vague mass measurement: Simply writing "weigh the beaker" without stating how the mass of the water alone is obtained caps the answer at Level 2 (max 4 marks).
  • Omitting the calculation: Forgetting to state how the recorded values are processed into a final value of specific heat capacity.
  • Using stopwatches: Some students described measuring time and calculating power, ignoring the fact that a joulemeter is already present in Figure 4 to measure energy directly!
Mark Breakdown: Level 3 (5–6 marks) requires all key steps logically ordered, explicitly detailing how the mass of water is determined and how specific heat capacity is calculated.
Part 02.3 · 1 Mark

Reducing Systematic Experimental Error

Suggest one change to the apparatus to reduce energy loss to the surroundings

✅ Acceptable Answers (Any 1)

  • Insulate the beaker (e.g. wrap beaker in bubble wrap, felt, or foam).
  • Add an insulating lid to reduce energy lost via convection and evaporation.
  • Replace the glass beaker with an insulating cup (e.g. a polystyrene / plastic cup).

❌ Common Errors

  • Writing "repeat and calculate an average" — repeating does not reduce heat loss to the room; heat loss is a systematic error, not a random one.
  • Saying "use more water" or "turn the heater up higher" — these do not stop energy dissipating into the surrounding air.
Mark Breakdown: 1 mark for mentioning insulation around the beaker, an insulating cup, or adding a lid.
Part 02.4 · 2 Marks

Percentage Difference Calculation

Calculate the percentage difference between the student's value (4410 J/kg °C) and the actual value (4200 J/kg °C)

📐 Step-by-Step Calculation

1 Find absolute difference:

Difference = 4410 - 4200 = 210 J/kg °C

2 Divide by the actual (true) value:

210 / 4200 = 0.05

3 Multiply by 100 to get a percentage:

0.05 × 100 = 5%

Final Answer: 5 %

❌ Calculation Traps & Examiner Warning

  • Dividing by the wrong number: Many students divided by the student's experimental value (4410) instead of the accepted reference value (4200):
    (210 / 4410) × 100 = 4.76%.
    The mark scheme explicitly states: do not accept 4.76 (%). Percentage differences / errors must be calculated relative to the actual / true value!
Mark Breakdown:
• Mark 1: Correct difference calculated ( 210 ) OR full substituted fraction [(4410 - 4200) / 4200] × 100 .
• Mark 2: Correct final answer of 5 (or 5% ).

Topics

Physics · Required Practicals · P1: Energy · P3: Particle Model of Matter · Required Practicals

Question and mark scheme from the AQA GCSE Physics examination, Physics Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.