Edexcel A-Level Chemistry AS Paper 1, June 2016: Question 6
5 marks · Medium difficulty · Open Response
Explain the differences in bond angles between ammonia and water, and compare the O-H and S-H bond lengths.
Practise this questionQuestion
Question text
6 (a) The diagram shows bond angles in ammonia and water.
N O
H 107° H H 104.5° H
H
Explain why the bond angle in water is less than the bond angle in ammonia.
(2)
(b) Explain why the O–H and S–H bond lengths are different.
S O
133.6 pm 95.7 pm
H H H H
(3)
(Total for Question 6 = 5 marks)
Mark scheme
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How to answer it
Shapes of Molecules and Covalent Bond Lengths
This question assesses your understanding of Electron Pair Repulsion Theory (VSEPR)—specifically how lone pairs affect bond angles—alongside periodic trends in atomic radius, shielding, and how these factors determine covalent bond length.
Part (a): Explaining Bond Angles in Water vs. Ammonia
Question 6 (a) — 2 Marks
✅ Correct Answer
- Water (H₂O) has two lone pairs on the central oxygen atom, whereas ammonia (NH₃) only has one lone pair on the central nitrogen atom.
- Lone pair–lone pair repulsion is greater than lone pair–bonding pair repulsion, resulting in greater compression of the bond angle in water (104.5°) compared to ammonia (107°).
💡 Key Knowledge
- Repulsion hierarchy: Lone pair–lone pair > Lone pair–bonding pair > Bonding pair–bonding pair.
- Each lone pair reduces the bond angle by approximately 2.5°.
🧠 Exam Technique
- Always explicitly compare both molecules: state how many lone pairs each species has.
- Use precise terminology: refer to repulsion between electron pairs rather than vague phrasing.
❌ Common Errors
- Saying atoms are "pushed together" instead of explaining that electron pairs repel.
- Forgetting to mention the difference in the number of lone pairs between the two molecules.
Part (b): Explaining O–H and S–H Bond Length Differences
Question 6 (b) — 3 Marks
✅ Correct Answer
- Sulfur is a larger atom than oxygen / has a larger atomic radius / has more electron shells.
- Sulfur has greater inner-shell shielding compared to oxygen.
- This results in a weaker nuclear attraction for the shared bonding electrons, producing a longer bond length (133.6 pm vs. 95.7 pm).
💡 Key Knowledge
- Down Group 16, atomic radius increases due to the addition of principal quantum shells.
- Inner shells shield the outer valence electrons and bonding pairs from the attractive pull of the positive nucleus.
🧠 Exam Technique
- Structure your answer causally: Size/Shells ➔ Shielding ➔ Attraction ➔ Bond Length.
- Treat each marking point as independent—make sure you explicitly write out each step of the chain.
❌ Common Errors
- Referring to "ionic radius" or "ions" (these are covalent molecules, not ions).
- Mentioning "nuclear charge" alone without linking it to shielding or distance (sulfur actually has a higher nuclear charge than oxygen, but distance and shielding override it).
- Discussing electronegativity instead of atomic size and shielding.
Topics
Physical Chemistry · Topic 2: Bonding and Structure
Question and mark scheme from the Edexcel A-Level Chemistry examination, AS Paper 1, June 2016. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.