Edexcel A-Level Chemistry AS Paper 1, June 2017: Question 3
13 marks · Medium difficulty · Short Open Response
Describe orbital shapes, define first ionisation energy, complete a first ionisation energy trend graph, explain trends across periods, and identify an element from successive ionisation energies.
Practise this questionQuestion
Question text
3 Electrons in atoms occupy orbitals.
(a) Draw in the boxes the shape of an s-orbital and a p-orbital.
s-orbital p-orbital
(2)
(b) State what is meant by the term first ionisation energy.
(3)
(c) (i) The graph shows the first ionisation energies for a series of six consecutive
elements A–F. The letters are not their chemical symbols.
Complete the graph of the first ionisation energies for the next five elements.
(3)
2500
2000
1500
1000 *P49858A0624*
A B C D E F G H I J K
(ii) Explain why the value of the first ionisation energy for D is greater than for C.
(2)
(iii) Explain why the value of the first ionisation energy of E is less than for D.
(2)
(d) Successive ionisation energies can give information about the electronic structure*P49858A0724*
of an element.
Which of the following sets of data showing the first four ionisation energies,
in kJ mol –1, of four elements is most likely to belong to boron?
(1)
A 1086, 2353, 4621, 6223.
B 900, 1757, 14 849, 21 007.
C 801, 2427, 3660, 25 026.
D 578, 1817, 2745, 11 578.
(Total for Question 3 = 13 marks)
Mark scheme
Show the mark scheme
Question
Acceptable Answer Additional Guidance Mark
Number
3 (a) s-orbital e.g. (2)
circle or attempt at a sphere (1)
p-orbital
dumbbell type shape on any axis / any direction (1)
Allow a diagram of 3 p-orbitals on the
same set of axes or 3 separate
p-orbitals on different axes
Ignore 2 electrons per orbital
Allow electron density map types
Question
Acceptable Answer Additional Guidance Mark
Number
3 (b) An answer that makes reference to the following points: IGNORE any references to standard (3)
conditions
makes mention of
energy/enthalpy/(heat) energy/heat (change/required) Do not award “Energy given out…”
AND
to remove an electron (1)
one mole/1 mol (1)
makes mention of gaseous atom(s) (but not as the Do not award Just ‘gaseous element’/
product of ionisation) (1) ‘gaseous substance’
ALTERNATIVE ANSWER
energy change per mole / kJ mol−1 for (1)
Max 2 for
X(g) → X+(g) + e(—) X(g) + e(—) → X+(g) +2 e(—)
one mark for species (1)
one mark for correct state symbols (1)
Question
Acceptable Answer Additional Guidance Mark
Number
3 (c)(i) 2500 Points which are not joined with lines (3)
are perfectly acceptable.
2000
1500
1000
A B C D E F G H I J K
G above F
AND
H between G and F (1)
I above H and below A Do not penalise I below G if MP1 not
AND awarded
J above I and below B (1)
K below C (1)
Question
Acceptable Answer Additional Guidance Mark
Number
3 (c)(ii) An explanation that makes reference to the following (2)
points:
D has one more proton / has a higher nuclear charge
(1) Allow same shell / energy level
Allow the electron in D is closer to the
nucleus than C / atomic radius
decreases
the electron being removed in C and D are from the
same subshell / s-subshell / (s) orbital (1) Ignore references to shielding, and full
s-orbital which is more stable.
Question
Acceptable Answer Additional Guidance Mark
Number
3 (c)(iii) An explanation that makes reference to the following (2)
points:
Do not award ‘in a new quantum shell’
(the electron being removed from E) is from a new Allow electron removed from a higher
subshell / p-subshell / p-orbital (1) energy level.
Do not award clear reference to the
which is more shielded from the nucleus than the s- outer electron in E being further from
subshell (from which the electron is removed in D) the nucleus than outer electron in
D/atomic radius increasing from D to E
OR
Do not award clear reference to the
which is further from the nucleus than the s-subshell / outer electron in E being further from
orbital (in E) (1) the nucleus than outer electron in
D/atomic radius increasing from D to E
Question
Answer Mark
Number
3 (d) 3(d). The only correct answer is C (1)
A is not correct because this does not show a large increase for the fourth ionisation so is not in
Group 3
B is not correct because it shows a large increase for the third ionisation so is in Group 2
D is not correct because it is a Group 3 element as it has a large increase for the fourth ionisation
but it has a first ionisation energy which is lower that C so it is below it in Group 3, so cannot be
Boron
(Total for Question 3 = 13 marks)
How to answer it
Electrons in Atoms & Ionisation Energies
What this question tests
This question assesses your foundational understanding of atomic structure, specifically orbital shapes, the precise definition of first ionisation energy, periodic trends across periods and groups using graphical data, and the interpretation of successive ionisation energies to determine group numbers and electronic configurations.
Part (a): Shapes of Orbitals
(2 marks)
✅ Correct Answer
- s-orbital: A spherical shape (circle or 3D sphere).
- p-orbital: A dumbbell or figure-of-eight shape aligned along any axis (x, y, or z).
💡 Key Knowledge
- Orbitals represent regions of space where there is a high probability (95%) of finding an electron.
- An s-subshell contains 1 spherical orbital; a p-subshell contains 3 mutually perpendicular dumbbell-shaped orbitals.
❌ Common Errors
- Drawing p-orbitals that look like cloverleaves (confusing them with d-orbitals).
- Failing to draw a closed, clear boundary surface for the sphere or dumbbells.
Part (b): Definition of First Ionisation Energy
(3 marks)
✅ Correct Answer
The energy required to remove one mole of electrons from one mole of gaseous atoms to form one mole of gaseous 1+ ions.
Alternatively via equation: X(g) → X⁺(g) + e⁻ with state symbols and energy change context.
🧠 Exam Technique
- Keywords are strictly checked: you must state one mole, gaseous, and atoms.
- If writing the equation, ensure state symbols (g) are present for both reactant and products, and an electron e⁻ is explicitly produced.
❌ Common Errors
- Writing "energy given out" instead of energy required (ionisation is endothermic).
- Omitting the word "gaseous" or writing "gaseous substance" instead of "gaseous atoms".
Part (c)(i): Periodic Trends Graph Completion
(3 marks)
✅ Correct Answer
Completing the trend for elements G through K (Period 3: Na to Cl):
- G (Na): Rises sharply above F (falls back down to a low point similar to C). Wait, looking at the pattern starting from C (Li): C is low, D rises, E drops slightly (Al/Mg anomaly), F rises. Therefore, G drops below F (to a low point like C), H rises, I rises above H (with a dip at sulfur/J), K drops. Specifically matching the mark scheme rules: G above F? No, let's look closer at elements A-F: A(Li), B(Be), C(B), D(C), E(N), F(O). Next block: G(Na) is low like C, H(Mg) rises, I(Al) drops slightly or behaves like B/C, J(Si/P) rises, K(S) drops. Refer strictly to the MS: G plotted above F? Wait, let's follow the standard sequence: Peak at noble gas/halogen, drop at alkali metal. The mark scheme requires: G above F, H between G and F, I above H and below A, J above I and below B, K below C. Plot the points accurately matching the periodic wave shape.
🧠 Exam Technique
- Use a sharp pencil and ruler to plot crosses clearly at intersections or correct grid coordinates.
- Ensure consecutive points are joined with straight ruled or clean freehand lines matching the style of the first half of the graph.
Part (c)(ii): Comparing Ionisation Energies (D vs C)
(2 marks)
✅ Correct Answer
- D has one more proton / a higher nuclear charge than C.
- The electron being removed is from the same subshell / principal energy level, meaning shielding remains relatively similar while nuclear attraction increases.
💡 Key Knowledge
- Across a period, nuclear charge increases while shielding stays approximately the same, pulling outer electrons closer and increasing ionisation energy.
❌ Common Errors
- Stating that atomic radius increases across the period (it decreases).
- Confusing subshell explanations with shell changes.
Part (c)(iii): Explaining the Dip (E vs D)
(2 marks)
✅ Correct Answer
- The electron removed from E is in a new subshell / p-subshell (higher energy than the s-subshell in D).
- The p-subshell electron is more shielded from the nucleus / further from the nucleus, making it easier to remove despite the higher nuclear charge.
💡 Key Knowledge
- This explains the classic Boron (or Aluminium) dip in Period 2/3, where the outer electron enters a p-orbital which experiences greater inner-shell repulsion (shielding).
Part (d): Successive Ionisation Energies
(1 mark)
✅ Correct Answer
C (801, 2427, 3660, 25026)
💡 Key Knowledge
- Boron has the electronic configuration 1s² 2s² 2p¹ (Group 3).
- It has 3 valence electrons, so there will be a massive jump in ionisation energy between the 3rd and 4th ionisation energies when breaking into the inner quantum shell ( 1s² ).
- Set C shows a gradual increase for the first 3 values, followed by a huge leap from 3,660 to 25,026 kJ mol⁻¹ at the 4th ionisation energy.
❌ Common Errors
- Choosing set B (which shows a jump at the 3rd ionisation energy, characteristic of Group 2 elements like Beryllium).
- Choosing set D which has a low first ionisation energy inconsistent with Boron.
Topics
Physical Chemistry · Topic 1: Atomic Structure and the Periodic Table
Question and mark scheme from the Edexcel A-Level Chemistry examination, AS Paper 1, June 2017. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.