Edexcel A-Level Chemistry Paper 1, June 2017: Question 4

9 marks · Medium difficulty · Open Response

Answer questions on the properties and reactions of iron and zinc transition metal complexes, including electronic configuration, colour, complex structures, entropy changes and catalysis.

Practise this question

Question

Exam question with four parts about iron and zinc transition metal chemistry. Part (a) is a multiple-choice question asking for the electronic configuration of an Fe2+ ion with electron box diagrams for 3d and 4s orbitals. Part (b) asks to explain why zinc ions are colourless. Part (c) presents an equation for the reaction between hydrated iron(II) and ethanedioate ions, asking to draw the structure of the complex ion in (i) and explain why the reaction is feasible in terms of entropy in (ii). Part (d) provides a redox equation between iodide and peroxodisulfate ions catalysed by iron(II) and asks to write two ionic equations for the catalytic steps.
Question text

4 Iron and zinc are in the d-block of the Periodic Table.

(a) Which of these is the electronic configuration of an iron(II) ion, Fe2+?

(1)

3d 4s

A [Ar] np np np

B [Ar] np n n n n

C [Ar] np np np

D [Ar] n n n n np

(b) Iron(II) ions, [Fe(H O) ]2+, form a pale green solution but zinc ions, [Zn(H O) ]2+,

26 2 6

form a colourless solution.

Explain why zinc ions are colourless.

(2)

(c) Hydrated iron(II) ions react with ethanedioate ions, C O42–, to form a complex ion.

[Fe(H O) ]2+ + 2C O2– U [Fe(C2O4)2(H O)2]2– + 4H2O

26 2 4 2

(i) Draw a structure of the [Fe(C O4)2(H O) ]2– ion, showing all of the bonds.

22 2

(2)

(ii) Explain, in terms of entropy, why this reaction is feasible.

(2)

(d) Iodide ions, I–, react with peroxodisulfate(VI) ions, S O2–

8 – 2– 2–

*P48058A0828*2I(aq) + S2O8(aq)rI2(aq) + 2SO4(aq)

This reaction is catalysed by iron(II) ions, Fe2+(aq).

Write two ionic equations to show how iron(II) ions act as a catalyst in this reaction.

State symbols are not required.

(2)

(Total for Question 4 = 9 marks)

Mark scheme

Show the mark scheme Mark scheme for Question 4. Part (a) indicates answer B is correct with brief rationale. Part (b) awards 2 marks for stating zinc has a full 3d sub-shell so d-d transitions cannot take place. Part (c)(i) awards 2 marks for the correct structure showing water and ethanedioate ligands attached to Fe. Part (c)(ii) awards 2 marks for noting an increase in particles/moles leading to increased system entropy. Part (d) awards 2 marks for the two correct equations representing the iron(II) catalytic cycle.

Question

Answer Mark

Number

4(a) The only correct answer is B (1)

A is not correct because 4 of the 3d electrons should be unpaired

C is not correct because there should not be any electrons in the 4s orbital

D is not correct because there should not be any electrons in the 4s orbital

Question

Answer Additional Guidance Mark

Number

4(b) An explanation that makes reference to the following points: (2)

(zinc (ions) / Zn2+) has / have a full (3)d sub-shell / 3d10 / Allow zinc (ions) / Zn2+ do not have a

all (3)d orbitals are full (1) partially filled / incomplete (3)d (sub-)

shell / no empty (3)d orbitals

Do not allow zinc atoms

so d-d transitions cannot take place Ignore omission of ‘d’ in the ‘or’s, if it

or is included in M1

electrons cannot move between (3)d orbitals

or Do not allow the (3)d orbitals do not

electrons cannot be promoted / excited to higher (3)d split / the (3)d subshell does not split

orbitals (1)

Ignore just ‘movement to different

energy level’

Question

Answer Additional Guidance Mark

Number

4(c)(i) Example of structure (2)

2 water ligands joined between O and Fe (1)

2 ethanedioate ligands drawn correctly showing all

the bonds

and

joined between single-bonded O atoms and Fe as

shown (1) Allow water ligands arranged as cis or trans

Allow delocalised bonds in ethanedioate ions

Allow bonds not shown in H2O, provided the

ligands are attached to Fe2+ through oxygen

atoms

Ignore bond lengths and angles

Ignore wedges and dotted lines to show shape

Ignore missing lone pairs and arrowheads

Ignore missing square brackets and charge /

incorrect charge

Ignore –ve charges on ethanedioate ions / +ve

charge on Fe

Question

Answer Additional Guidance Mark

Number

4(c)(ii) An explanation that makes reference to the following (2)

points:

(there are) more particles / moles / species on the Do not allow incorrect numbers of particles

right of the equation (than on the left)

or Do not allow 3 molecules on the left and 5

(there is an increase from) 3 particles on the left of molecules on the right

the equation to 5 on the right (1)

so ∆Ssystem increases / is positive (and ∆Ssurroundings is Allow ∆Stotal is positive / increasing

unchanged so ∆Stotal increases ) (1)

Allow entropy / ∆S increases

Allow there is a positive entropy change

Ignore just there is an increase in disorder

(from left to right)

Ignore ∆Ssurroundings changes

Ignore just ‘entropy is positive’

Ignore references to free energy

Question Answer Additional Guidance Mark

Number

4(d) Examples of equations (2)

Fe2+ oxidised to Fe3+ in reaction with S O 2− (1) 2Fe2+ + S O 2− → 2Fe3+ + 2SO 2−

28 2 8 4

Fe3+ reduced to Fe2+ in reaction with I− (1) 2Fe3+ + 2I− → 2Fe2+ + I

Ignore state symbols

Allow equations in either order

Allow multiples

Penalise uncancelled electrons once only

Note

If no other mark is awarded, allow (1) for all

correct species in 2 unbalanced equations

(Total for Question 4 = 9 marks)

How to answer it

Transition Metals, Colour, Entropy & Catalysis

What this question tests

This question assesses core Edexcel A-Level transition metal chemistry: electron configurations of ions, the origin of colour in complex ions (d-d transitions), ligand substitution and stereochemistry, entropy changes during complex formation reactions, and homogeneous catalysis (specifically redox cycles involving iron ions).

Part (a): Electronic Configuration of Fe²⁺

Question Part (a)

✅ Correct Answer

B

[Ar] with 3d orbitals containing (↑↓, ↑, ↑, ↑, ↑) and 4s empty.

💡 Key Knowledge

Neutral iron (Fe) has the configuration [Ar] 3d⁶ 4s² . When forming positive ions, electrons are always removed from the 4s orbital first before the 3d orbitals. For Fe²⁺, two electrons are lost from 4s, leaving [Ar] 3d⁶ . Hund's rule states electrons fill degenerate orbitals singly before pairing up.

❌ Common Errors

Students often incorrectly remove electrons from the 3d sub-shell instead of the 4s sub-shell, or fail to apply Hund's rule correctly when distributing electrons across the five degenerate 3d boxes.

🎯 1 Mark: Awarded for selecting option B.

Part (b): Colourless Zinc Complexes

Question Part (b)

✅ Correct Answer

  1. Zinc ions (Zn²⁺) have a full 3d sub-shell ( 3d¹⁰ / all 3d orbitals are full).
  2. Therefore, d-d transitions cannot take place because electrons cannot be promoted or move between 3d orbitals.

🧠 Exam Technique

To secure full marks in explanations of transition metal colour, you must explicitly mention: (1) the specific electronic state of the d-subshell (full/empty), and (2) the consequence on d-d electron transitions. Vague references to "no electrons to move" will lose marks.

❌ Common Errors

Referring to zinc atoms rather than zinc ions (Zn²⁺), or stating that the d-subshell "does not split" (the orbitals do split in a ligand field, but transitions cannot occur because the sub-shell is completely full).

🎯 2 Marks: 1 mark for stating Zn²⁺ has a full 3d sub-shell / 3d¹⁰, and 1 mark for explaining that d-d transitions cannot take place.

Part (c)(i): Structure of Complex Ion

Question Part (c)(i)

✅ Correct Answer

A drawn octahedral complex ion [Fe(C₂O₄)₂(H₂O)₂]²⁻ showing:

  • Two water ligands ( H₂O ) coordinated to the central Fe through their oxygen atoms (can be cis or trans).
  • Two bidentate ethanedioate ligands ( C₂O₄²⁻ ) correctly bonded through two single-bonded oxygen atoms each, forming 5-membered chelate rings.
  • Overall enclosed in square brackets with a 2- charge.

💡 Key Knowledge

Ethanedioate ( C₂O₄²⁻ ) is a bidentate ligand. Since each ethanedioate donates two lone pairs and water donates one, the coordination number is 6 (octahedral geometry). Bidentate ligands must show bonds connecting from the donor oxygen atoms to the central Fe atom.

❌ Common Errors

Connecting ethanedioate to the iron via the double-bonded oxygens instead of the single-bonded (carboxylate oxygen) atoms, or failing to show the bidentate bite correctly.

🎯 2 Marks: 1 mark for the two water ligands joined correctly via O to Fe; 1 mark for two ethanedioate ligands drawn showing all bonds and joined via single-bonded oxygen atoms to Fe.

Part (c)(ii): Entropy and Feasibility

Question Part (c)(ii)

✅ Correct Answer

  1. There is an increase in the number of particles/moles from left to right (from 3 particles on the left to 5 particles on the right).
  2. Therefore, ΔSsystem increases (becomes more positive), making the reaction feasible.

🧠 Exam Technique

Always structure your entropy answers by first quoting the mole/particle change on both sides of the equation, linking this directly to the sign of ΔSsystem, and explaining how that contributes to reaction feasibility (ΔStotal > 0).

❌ Common Errors

Stating simply that "disorder increases" without linking it explicitly to the number of moles or particles specified in the balanced equation.

🎯 2 Marks: 1 mark for noting the increase in moles/particles (3 to 5), and 1 mark for stating ΔSsystem increases / is positive.

Part (d): Homogeneous Catalysis Equations

Question Part (d)

✅ Correct Answer

Two ionic equations showing the redox catalytic cycle of Fe²⁺:

1) 2Fe²⁺ + S₂O₈²⁻ → 2Fe³⁺ + 2SO₄²⁻

2) 2Fe³⁺ + 2I⁻ → 2Fe²⁺ + I₂

Note: Equations can be in either order, and multiples are accepted. State symbols are not required.

💡 Key Knowledge

In homogeneous catalysis, the catalyst reacts with one reactant to form an intermediate (oxidising Fe²⁺ to Fe³⁺), which then reacts with the second reactant in a subsequent step, regenerating the original catalyst (reducing Fe³⁺ back to Fe²⁺).

❌ Common Errors

Writing incorrect chemical formulas for peroxodisulfate ( S₂O₈²⁻ ) or iodide ( I⁻ ), or failing to balance the charges and stoichiometry properly across both equations.

🎯 2 Marks: 1 mark for the oxidation step of Fe²⁺ to Fe³⁺ by peroxodisulfate; 1 mark for the reduction step of Fe³⁺ back to Fe²⁺ by iodide. (If no other mark is awarded, 1 mark can be given for 2 correct unbalanced equations).

Topics

Physical Chemistry · Inorganic Chemistry · Topic 13: Energetics II · Topic 15: Transition Metals

Question and mark scheme from the Edexcel A-Level Chemistry examination, Paper 1, June 2017. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.