Edexcel A-Level Chemistry Paper 1, June 2017: Question 4
9 marks · Medium difficulty · Open Response
Answer questions on the properties and reactions of iron and zinc transition metal complexes, including electronic configuration, colour, complex structures, entropy changes and catalysis.
Practise this questionQuestion
Question text
4 Iron and zinc are in the d-block of the Periodic Table.
(a) Which of these is the electronic configuration of an iron(II) ion, Fe2+?
(1)
3d 4s
A [Ar] np np np
B [Ar] np n n n n
C [Ar] np np np
D [Ar] n n n n np
(b) Iron(II) ions, [Fe(H O) ]2+, form a pale green solution but zinc ions, [Zn(H O) ]2+,
26 2 6
form a colourless solution.
Explain why zinc ions are colourless.
(2)
(c) Hydrated iron(II) ions react with ethanedioate ions, C O42–, to form a complex ion.
[Fe(H O) ]2+ + 2C O2– U [Fe(C2O4)2(H O)2]2– + 4H2O
26 2 4 2
(i) Draw a structure of the [Fe(C O4)2(H O) ]2– ion, showing all of the bonds.
22 2
(2)
(ii) Explain, in terms of entropy, why this reaction is feasible.
(2)
(d) Iodide ions, I–, react with peroxodisulfate(VI) ions, S O2–
8 – 2– 2–
*P48058A0828*2I(aq) + S2O8(aq)rI2(aq) + 2SO4(aq)
This reaction is catalysed by iron(II) ions, Fe2+(aq).
Write two ionic equations to show how iron(II) ions act as a catalyst in this reaction.
State symbols are not required.
(2)
(Total for Question 4 = 9 marks)
Mark scheme
Show the mark scheme
Question
Answer Mark
Number
4(a) The only correct answer is B (1)
A is not correct because 4 of the 3d electrons should be unpaired
C is not correct because there should not be any electrons in the 4s orbital
D is not correct because there should not be any electrons in the 4s orbital
Question
Answer Additional Guidance Mark
Number
4(b) An explanation that makes reference to the following points: (2)
(zinc (ions) / Zn2+) has / have a full (3)d sub-shell / 3d10 / Allow zinc (ions) / Zn2+ do not have a
all (3)d orbitals are full (1) partially filled / incomplete (3)d (sub-)
shell / no empty (3)d orbitals
Do not allow zinc atoms
so d-d transitions cannot take place Ignore omission of ‘d’ in the ‘or’s, if it
or is included in M1
electrons cannot move between (3)d orbitals
or Do not allow the (3)d orbitals do not
electrons cannot be promoted / excited to higher (3)d split / the (3)d subshell does not split
orbitals (1)
Ignore just ‘movement to different
energy level’
Question
Answer Additional Guidance Mark
Number
4(c)(i) Example of structure (2)
2 water ligands joined between O and Fe (1)
2 ethanedioate ligands drawn correctly showing all
the bonds
and
joined between single-bonded O atoms and Fe as
shown (1) Allow water ligands arranged as cis or trans
Allow delocalised bonds in ethanedioate ions
Allow bonds not shown in H2O, provided the
ligands are attached to Fe2+ through oxygen
atoms
Ignore bond lengths and angles
Ignore wedges and dotted lines to show shape
Ignore missing lone pairs and arrowheads
Ignore missing square brackets and charge /
incorrect charge
Ignore –ve charges on ethanedioate ions / +ve
charge on Fe
Question
Answer Additional Guidance Mark
Number
4(c)(ii) An explanation that makes reference to the following (2)
points:
(there are) more particles / moles / species on the Do not allow incorrect numbers of particles
right of the equation (than on the left)
or Do not allow 3 molecules on the left and 5
(there is an increase from) 3 particles on the left of molecules on the right
the equation to 5 on the right (1)
so ∆Ssystem increases / is positive (and ∆Ssurroundings is Allow ∆Stotal is positive / increasing
unchanged so ∆Stotal increases ) (1)
Allow entropy / ∆S increases
Allow there is a positive entropy change
Ignore just there is an increase in disorder
(from left to right)
Ignore ∆Ssurroundings changes
Ignore just ‘entropy is positive’
Ignore references to free energy
Question Answer Additional Guidance Mark
Number
4(d) Examples of equations (2)
Fe2+ oxidised to Fe3+ in reaction with S O 2− (1) 2Fe2+ + S O 2− → 2Fe3+ + 2SO 2−
28 2 8 4
Fe3+ reduced to Fe2+ in reaction with I− (1) 2Fe3+ + 2I− → 2Fe2+ + I
Ignore state symbols
Allow equations in either order
Allow multiples
Penalise uncancelled electrons once only
Note
If no other mark is awarded, allow (1) for all
correct species in 2 unbalanced equations
(Total for Question 4 = 9 marks)
How to answer it
Transition Metals, Colour, Entropy & Catalysis
This question assesses core Edexcel A-Level transition metal chemistry: electron configurations of ions, the origin of colour in complex ions (d-d transitions), ligand substitution and stereochemistry, entropy changes during complex formation reactions, and homogeneous catalysis (specifically redox cycles involving iron ions).
Part (a): Electronic Configuration of Fe²⁺
Question Part (a)
✅ Correct Answer
B
[Ar] with 3d orbitals containing (↑↓, ↑, ↑, ↑, ↑) and 4s empty.
💡 Key Knowledge
Neutral iron (Fe) has the configuration [Ar] 3d⁶ 4s² . When forming positive ions, electrons are always removed from the 4s orbital first before the 3d orbitals. For Fe²⁺, two electrons are lost from 4s, leaving [Ar] 3d⁶ . Hund's rule states electrons fill degenerate orbitals singly before pairing up.
❌ Common Errors
Students often incorrectly remove electrons from the 3d sub-shell instead of the 4s sub-shell, or fail to apply Hund's rule correctly when distributing electrons across the five degenerate 3d boxes.
Part (b): Colourless Zinc Complexes
Question Part (b)
✅ Correct Answer
- Zinc ions (Zn²⁺) have a full 3d sub-shell ( 3d¹⁰ / all 3d orbitals are full).
- Therefore, d-d transitions cannot take place because electrons cannot be promoted or move between 3d orbitals.
🧠 Exam Technique
To secure full marks in explanations of transition metal colour, you must explicitly mention: (1) the specific electronic state of the d-subshell (full/empty), and (2) the consequence on d-d electron transitions. Vague references to "no electrons to move" will lose marks.
❌ Common Errors
Referring to zinc atoms rather than zinc ions (Zn²⁺), or stating that the d-subshell "does not split" (the orbitals do split in a ligand field, but transitions cannot occur because the sub-shell is completely full).
Part (c)(i): Structure of Complex Ion
Question Part (c)(i)
✅ Correct Answer
A drawn octahedral complex ion [Fe(C₂O₄)₂(H₂O)₂]²⁻ showing:
- Two water ligands ( H₂O ) coordinated to the central Fe through their oxygen atoms (can be cis or trans).
- Two bidentate ethanedioate ligands ( C₂O₄²⁻ ) correctly bonded through two single-bonded oxygen atoms each, forming 5-membered chelate rings.
- Overall enclosed in square brackets with a 2- charge.
💡 Key Knowledge
Ethanedioate ( C₂O₄²⁻ ) is a bidentate ligand. Since each ethanedioate donates two lone pairs and water donates one, the coordination number is 6 (octahedral geometry). Bidentate ligands must show bonds connecting from the donor oxygen atoms to the central Fe atom.
❌ Common Errors
Connecting ethanedioate to the iron via the double-bonded oxygens instead of the single-bonded (carboxylate oxygen) atoms, or failing to show the bidentate bite correctly.
Part (c)(ii): Entropy and Feasibility
Question Part (c)(ii)
✅ Correct Answer
- There is an increase in the number of particles/moles from left to right (from 3 particles on the left to 5 particles on the right).
- Therefore, ΔSsystem increases (becomes more positive), making the reaction feasible.
🧠 Exam Technique
Always structure your entropy answers by first quoting the mole/particle change on both sides of the equation, linking this directly to the sign of ΔSsystem, and explaining how that contributes to reaction feasibility (ΔStotal > 0).
❌ Common Errors
Stating simply that "disorder increases" without linking it explicitly to the number of moles or particles specified in the balanced equation.
Part (d): Homogeneous Catalysis Equations
Question Part (d)
✅ Correct Answer
Two ionic equations showing the redox catalytic cycle of Fe²⁺:
1) 2Fe²⁺ + S₂O₈²⁻ → 2Fe³⁺ + 2SO₄²⁻
2) 2Fe³⁺ + 2I⁻ → 2Fe²⁺ + I₂
Note: Equations can be in either order, and multiples are accepted. State symbols are not required.
💡 Key Knowledge
In homogeneous catalysis, the catalyst reacts with one reactant to form an intermediate (oxidising Fe²⁺ to Fe³⁺), which then reacts with the second reactant in a subsequent step, regenerating the original catalyst (reducing Fe³⁺ back to Fe²⁺).
❌ Common Errors
Writing incorrect chemical formulas for peroxodisulfate ( S₂O₈²⁻ ) or iodide ( I⁻ ), or failing to balance the charges and stoichiometry properly across both equations.
Topics
Physical Chemistry · Inorganic Chemistry · Topic 13: Energetics II · Topic 15: Transition Metals
Question and mark scheme from the Edexcel A-Level Chemistry examination, Paper 1, June 2017. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.