Edexcel A-Level Chemistry Paper 2, June 2017: Question 1

6 marks · Medium difficulty · Short Open Response

Identify reaction mechanisms, name branched alkanes from skeletal structures, explain fractional distillation of crude oil, and complete equations for cracking and reforming of alkanes.

Practise this question

Question

Question 1 about alkanes with five parts. Part (a) asks for the reaction mechanism when ethane reacts with chlorine in UV light, with multiple choice options A to D. Part (b) asks to name the alkane shown as a skeletal formula, with multiple choice options A to D. Part (c)(i) asks to explain why different alkanes in crude oil can be separated by fractional distillation (2 marks). Part (c)(ii) asks to complete the cracking equation for octane to produce ethene and one other organic compound. Part (c)(iii) asks to write the equation for reforming hexane into cyclohexane using displayed formulae.
Question text

1 This is a question about alkanes.

(a) What is the reaction mechanism when ethane and chlorine react in UV light?

(1)

A electrophilic addition

B electrophilic substitution

C free radical addition

D free radical substitution

(b) What is the name of this alkane?

(1)

A 2-ethyl-3-propylpentane

B 4-ethyl-3-methylheptane

C 3-methyl-4-propylhexane

D 4-methyl-3-propylhexane

(c) Alkanes are obtained by processing crude oil.

(i) Explain why different alkanes in crude oil can be separated by fractional distillation.

(2)

(ii) Complete the equation for the cracking of octane to produce ethene and only

2 one other organic compound. State symbols are not required.

*P48059A0224* (1)

C8H18 r … + …

(iii) Write the equation for the reforming of hexane into cyclohexane, using

displayed formulae for the organic compounds. State symbols are not required.

(1)

(Total for Question 1 = 6 marks)

Mark scheme

Show the mark scheme Mark scheme for Question 1 showing answers for parts (a) to (c). Part (a) awards 1 mark for D (free radical substitution). Part (b) awards 1 mark for B (4-ethyl-3-methylheptane). Part (c)(i) awards 2 marks: one for mentioning different boiling temperatures/points and one for linking this to chain length, molar mass, or intermolecular forces. Part (c)(ii) awards 1 mark for a balanced cracking equation such as C8H18 -> C2H4 + C6H14. Part (c)(iii) awards 1 mark for the displayed formula equation for the reforming of hexane into cyclohexane and hydrogen.

Question

Answer Mark

Number

1(a) The only correct answer is D (free radical substitution) (1)

A is not correct because electrophilic addition would be the reaction mechanism between alkenes,

such as ethene, and chlorine but the substance in the question is the alkane, ethane

B is not correct because electrophilic substitution involves the reactions of aromatic systems but this

question refers to the reaction of the alkane, ethane

C is not correct because the mechanism of reaction between an alkane such as ethane and chlorine

involves substitution and not addition

Question

Answer Mark

Number

1(b) The only correct answer is B (4-ethyl-3-methylheptane) (1)

A is not correct because the longest consecutive carbon chain involves the seven carbon atoms from

the top left of the molecular drawing down to the bottom right which means that the stem of the

name is not pentane but heptane, with the consequential effect on the numbering and length of side

chains

C is not correct because the longest consecutive carbon chain involves the seven carbon atoms from

the top left of the molecular drawing down to the bottom right which means that the stem of the

name is not hexane but heptane, with the consequential effect on the numbering and length of side

chains

D is not correct because the longest consecutive carbon chain involves the seven carbon atoms

from the top left of the molecular drawing down to the bottom right which means that the stem of

the name is not hexane but heptane, with the consequential effect on the numbering and length of

side chains

Question

Answer Additional Guidance Mark

Number

1(c)(i) An explanation that makes reference to the following (2)

points:

different alkanes have different Allow

boiling temperatures/points (1) Volatility for boiling temperature

Allow

Different alkanes condense at different

temperatures

Ignore melting temperatures if given with

boiling temperatures

Ignore densities

because of (different) chain length/molar mass Accept London /dispersion /van der Waals

/strength of intermolecular forces/ forces

number of electrons (1) Allow reference to size

A comparison such as ‘longer alkanes have

higher boiling points’ scores 2

Ignore any reference to surface area

Do not award references to cracking

Do not award reference to just weight/mass

Do not award incorrect trend

Question

Answer Additional Guidance Mark

Number

1(c)(ii) (1)

Correct equation Example of equation:

C8H18 → C2H4 + C6H14

OR

C8H18 → 2C2H4 + C4H10

OR

C8H18 → 3C2H4 + C2H6

Allow

CH2=CH2 for C2H4

Products can be given in either order

Do not award equations forming H2

Question

Answer Additional Guidance Mark

Number

1(c)(iii) (1)

Correct equation Example of equation:

Accept bonds to hydrogen atoms inside the ring, e.g.

Allow skeletal or structural formulae

for hexane and for cyclohexane

or CH3(CH2)4CH3 or (CH2)6

Ignore

C6H14 → C6H12 + H2

(Total for Question 1 = 6 marks)

How to answer it

Alkanes: Reactions, Nomenclature & Processing

📋 What this question tests

This question assesses core organic chemistry knowledge regarding alkanes. Specifically, it tests your understanding of radical substitution mechanisms, IUPAC nomenclature rules for branched alkanes, fractional distillation principles based on intermolecular forces, and writing balanced equations for cracking and reforming reactions.

Part (a): Halogenation Mechanism

What is the reaction mechanism when ethane and chlorine react in UV light? (1 mark)

✅ Correct Answer

D: free radical substitution

💡 Key Knowledge

  • Alkanes are unreactive due to strong, non-polar C-C and C-H sigma bonds.
  • UV light provides the energy (homolytic fission) to break Cl-Cl bonds into free radicals.

❌ Common Errors

Confusing alkanes with alkenes. Alkenes undergo electrophilic addition, whereas alkanes undergo free radical substitution in the presence of UV light.

🎯 Mark Breakdown: 1 mark awarded for selecting option D.

Part (b): IUPAC Nomenclature

What is the name of this alkane? (1 mark)

✅ Correct Answer

B: 4-ethyl-3-methylheptane

🧠 Exam Technique

Always find the longest continuous carbon chain first. In this structure, tracing from the top-left ethyl group down to the bottom-right carbon chain gives a chain of 7 carbons (heptane), not 5 or 6. Number from the end that gives the substituents the lowest locants (3,4 rather than 4,5).

❌ Common Errors

Choosing a straight-line horizontal or vertical path instead of the longest continuous chain. This leads to incorrect stem names like pentane or hexane.

🎯 Mark Breakdown: 1 mark awarded for selecting option B.

Part (c)(i): Fractional Distillation

Explain why different alkanes in crude oil can be separated by fractional distillation. (2 marks)

✅ Correct Answers

1. Different alkanes have different boiling points (or volatilities).
2. This is due to differing chain lengths / molecular masses / strength of London (dispersion) forces.

💡 Key Knowledge

As molecular chain length increases, the number of electrons increases, leading to stronger London forces between molecules which require more thermal energy to overcome.

❌ Common Errors

Mentioning breaking of covalent bonds inside the molecules (fractional distillation only overcomes intermolecular forces, not covalent bonds). Vague references to "weight" or "size" without linking to intermolecular forces or boiling points often lose marks.

🎯 Mark Breakdown: 1 mark for stating different boiling points, 1 mark for linking this to chain length/molar mass/intermolecular forces.

Part (c)(ii): Cracking of Alkanes

Complete the equation for the cracking of octane to produce ethene and only one other organic compound. (1 mark)

✅ Correct Answer

C₈H₁₈ → C₂H₄ + C₆H₁₄

Accept alternative valid cracking ratios such as 2C₂H₄ + C₄H₁₀ or 3C₂H₄ + C₂H₆ depending on the specific pairing, provided mass balance is maintained.

🧠 Exam Technique

Check your balancing by adding the subscript carbons and hydrogens of the products to ensure they equal the reactant (C = 8, H = 18 for octane).

❌ Common Errors

Including hydrogen gas ( H₂ ) as a product when the question specifically stipulates producing "ethene and only one other organic compound."

🎯 Mark Breakdown: 1 mark for a fully balanced equation producing ethene and a single valid alkane.

Part (c)(iii): Reforming of Alkanes

Write the equation for the reforming of hexane into cyclohexane, using displayed formulae for the organic compounds. (1 mark)

✅ Correct Answer

A balanced equation showing straight-chain hexane ( C₆H₁₄ ) drawn out fully with all C-H and C-C bonds displayed, reacting to form cyclohexane (a ring structure with all C-H and C-C bonds fully displayed) plus H₂ .

💡 Key Knowledge

Reforming involves converting straight-chain alkanes into cycloalkanes or branched chains, releasing hydrogen gas in the process to aromatize or cyclicize the structure.

❌ Common Errors

Using molecular or structural formulas (like C₆H₁₄ ) instead of fully displayed formulae. Every single bond and atom must be explicitly shown for the organic structures to gain the mark.

🎯 Mark Breakdown: 1 mark for the correct balanced equation with fully displayed formulae for both organic reactants and products, including H₂ .

Topics

Organic Chemistry · Topic 6: Organic Chemistry I

Question and mark scheme from the Edexcel A-Level Chemistry examination, Paper 2, June 2017. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.