Edexcel A-Level Chemistry Paper 1, June 2018: Question 2
8 marks · Medium difficulty · Short Open Response
Deduce subatomic particle numbers for lithium isotopes, identify element X and formulas of species in a mass spectrum of X2, and state maximum electron capacities for specific atomic regions.
Practise this questionQuestion
Question text
2 This question is about atoms, molecules and ions.
(a) Lithium exists as two isotopes.
Complete the table to show the numbers of subatomic particles in a 6Li atom and
a 7Li+ ion.
(2)
Particle Protons Neutrons Electrons
6Li
7Li+
(b) The mass spectrum of a diatomic molecule, X2, has peaks at the following
m / z values for the X + ion:
32, 33, 34, 35, 36
Deduce the formulae of all the species responsible for each of the peaks in the
mass spectrum of X2, identifying element X and showing clearly the isotopes present.
(3)
(c) Complete the table to show the maximum number of electrons which can fill
each region of an atom.
(3)
Region Maximum number of electrons
the 1s orbital
the 2p subshell
the third quantum shell
(Total for Question 2 = 8 marks)
Mark scheme
Show the mark scheme
Question
Acceptable Answer Additional Guidance Mark
Number
2(a) Example of table (2)
6Li – 3 protons and 3 neutrons and 3 electrons
(1)
7Li+ – 3 protons and 4 neutrons and 2 electrons (1)
If no oher mark is scored, allow (1) for any 4
correct numbers
Ignore + or - signs
Question
Acceptable Answer Additional Guidance Mark
Number
2(b) An answer that makes reference to the following points: Isotopes in ions at each m/z value: (3)
(32 –) 16O=16O+ / 16O +
identification of oxygen / O (1) (33 –) 16O=17O+
(34 –) 16O=18O+ and 17O=17O+ / 17O +
2 +
identification of isotopes corresponding to any 3 m/z (35 –) 17O=18O+
values (1) (36 –) 18O=18O+ / 18O +
Conditional on M2 awarded Allow single bonds
identification of isotopes corresponding to other 2 m/z
values (1) Allow any other unambiguous ways of
showing the masses of the isotopes for each
m/z value e.g. 16+16, O 16
Allow use of X / another symbol e.g. Cl
instead of O for M2 and M3
Ignore missing charges as given in question
Penalise negative charge once only
Question
Acceptable Answer Additional Guidance Mark
Number
2(c) Example of table (3)
1s orbital – 2 electrons (1)
2p subshell – 6 electrons (1)
third quantum shell – 18 electrons (1)
Allow 1s2 for 2
Allow 2p6 for 6
Ignore 3s23p63d10 for the third number
Do not award more than one number
written in the box e.g. 8 or 18 in the third
(Total for Question 2 = 8 marks)
How to answer it
Atoms, Molecules and Ions Study Guide
This question assesses fundamental atomic structure and mass spectrometry knowledge at A-Level. You are tested on subatomic particle accounting in neutral atoms vs. ions, interpreting mass spectra of diatomic molecules to deduce isotopic compositions, and recalling maximum electron capacities across orbitals, subshells, and principal quantum shells.
Subatomic Particles in Atoms and Ions
Determine numbers of protons, neutrons, and electrons for ⁶Li and ⁷Li⁺.
✅ Correct Answer
- ⁶Li atom: 3 protons, 3 neutrons, 3 electrons
- ⁷Li⁺ ion: 3 protons, 4 neutrons, 2 electrons
💡 Key Knowledge
- Atomic number (bottom number/periodic table number) = protons = 3 for Lithium.
- Mass number minus atomic number = neutrons ( 6 - 3 = 3 ; 7 - 3 = 4 ).
- Positive ions have fewer electrons than protons due to loss of outer electron(s) ( 3 - 1 = 2 ).
❌ Common Errors
- Confusing the mass number for the number of neutrons.
- Failing to adjust the electron count for the positive charge ( ⁷Li⁺ has 2 electrons, not 3).
Mass Spectrometry of Diatomic Molecules
Deduce formulae for species responsible for peaks at m/z values 32, 33, 34, 35, and 36 for X₂⁺.
✅ Correct Answer
- m/z 32: ⁴⁶O=¹⁶O⁺ (or ¹⁶O₂⁺)
- m/z 33: ¹⁶O=¹⁷O⁺
- m/z 34: ¹⁶O=¹⁸O⁺ AND ¹⁷O=¹⁷O⁺
- m/z 35: ¹⁷O=¹⁸O⁺
- m/z 36: ¹⁸O=¹⁸O⁺
🧠 Exam Technique & Strategy
- Identify the element: Dividing the lowest peak (32) by 2 gives 16, which corresponds to Oxygen (O).
- List common oxygen isotopes: ¹⁶O, ¹⁷O, and ¹⁸O.
- Combine isotope pairs: Systematically sum combinations to match each m/z value:
- 32 = 16 + 16
- 33 = 16 + 17
- 34 = 16 + 18 (or 17 + 17)
- 35 = 17 + 18
- 36 = 18 + 18
❌ Common Errors
- Omitting one of the two valid combinations for m/z 34 ( ¹⁶O=¹⁸O and ¹⁷O=¹⁷O ).
- Forgetting to include the positive charge symbol ( ⁺ ) on molecular ions when writing formulae.
Electron Capacities in Quantum Regions
Complete the table showing maximum electron capacities for specific atomic regions.
✅ Correct Answer
- 1s orbital: 2 electrons
- 2p subshell: 6 electrons
- Third quantum shell: 18 electrons
💡 Key Knowledge
- Orbitals: Hold a maximum of 2 electrons (with opposite spins).
- Subshells (s, p, d, f): Contain 1, 3, 5, and 7 orbitals respectively, giving maximum capacities of 2, 6, 10, and 14 electrons.
- Quantum Shells: Follow the formula 2n² . For the 3rd shell ( n = 3 ), capacity = 2(3)² = 18 electrons.
❌ Common Errors
- Confusing subshell capacity with principal shell capacity (e.g., thinking the 3rd shell only holds 8 electrons due to the octet rule in GCSE chemistry).
- Mixing up subshell names and orbital counts.
Topics
Physical Chemistry · Topic 1: Atomic Structure and the Periodic Table
Question and mark scheme from the Edexcel A-Level Chemistry examination, Paper 1, June 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.